How to close a window if tk.Toplevel is in a different file
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how do I close my current window if I can't see the tk.Toplevel(root) from the method I am in?
Here a small example of what i mean:
file1.py:
import Tkinter as tk
import file2
class ExampleMain:
def __init__(self, root):
self.mainFrame = tk.Frame(root)
...
tk.Button(self.mainFrame, command=self.button_pressed)
...
def button_pressed(self):
self.whatever = tk.Toplevel(root)
self.app = file2.ExampleNotMain(self.whatever)
if __name__ == '__main__':
root = tk.Tk()
app = ExampleMain(root)
root.mainloop()
file2.py:
import tkinter as tk
class ExampleNotMain:
def __init__(self, root):
self.frame = tk.Frame(root)
...
tk.Button(self.frame, command=self.close_window)
...
def close_window(self):
=> missing_command_here
In this example I would like to close the second window created (and keep the first).
If all the code is in one file something like
self.whatever.destroy()
would do it. My problem is I can't see the object from the first file with the command being in the second file.
I found something like
execfile("file2.py")
but I don't like that solution.
Is there a better way to solve my problem?
I would realy apriciate your help.
Thanks in advance.
python tkinter
asked Nov 16 '18 at 18:36
Chris SChris S
182
add a comment |
how do I close my current window if I can't see the tk.Toplevel(root) from the method I am in?
Here a small example of what i mean:
file1.py:
import Tkinter as tk
import file2
class ExampleMain:
def __init__(self, root):
self.mainFrame = tk.Frame(root)
...
tk.Button(self.mainFrame, command=self.button_pressed)
...
def button_pressed(self):
self.whatever = tk.Toplevel(root)
self.app = file2.ExampleNotMain(self.whatever)
if __name__ == '__main__':
root = tk.Tk()
app = ExampleMain(root)
root.mainloop()
file2.py:
import tkinter as tk
class ExampleNotMain:
def __init__(self, root):
self.frame = tk.Frame(root)
...
tk.Button(self.frame, command=self.close_window)
...
def close_window(self):
=> missing_command_here
In this example I would like to close the second window created (and keep the first).
If all the code is in one file something like
self.whatever.destroy()
would do it. My problem is I can't see the object from the first file with the command being in the second file.
I found something like
execfile("file2.py")
but I don't like that solution.
Is there a better way to solve my problem?
I would realy apriciate your help.
Thanks in advance.
python tkinter
asked Nov 16 '18 at 18:36
Chris SChris S
182
You code does not show the creation of a second, non-root Toplevel.
– Terry Jan Reedy
Nov 16 '18 at 18:59
I counted the root as the first window and the non-root window as second. I want to close the non-root window
– Chris S
Nov 16 '18 at 19:08
I see it now and will answer.
– Terry Jan Reedy
Nov 16 '18 at 19:09
add a comment |
how do I close my current window if I can't see the tk.Toplevel(root) from the method I am in?
Here a small example of what i mean:
file1.py:
import Tkinter as tk
import file2
class ExampleMain:
def __init__(self, root):
self.mainFrame = tk.Frame(root)
...
tk.Button(self.mainFrame, command=self.button_pressed)
...
def button_pressed(self):
self.whatever = tk.Toplevel(root)
self.app = file2.ExampleNotMain(self.whatever)
if __name__ == '__main__':
root = tk.Tk()
app = ExampleMain(root)
root.mainloop()
file2.py:
import tkinter as tk
class ExampleNotMain:
def __init__(self, root):
self.frame = tk.Frame(root)
...
tk.Button(self.frame, command=self.close_window)
...
def close_window(self):
=> missing_command_here
In this example I would like to close the second window created (and keep the first).
If all the code is in one file something like
self.whatever.destroy()
would do it. My problem is I can't see the object from the first file with the command being in the second file.
I found something like
execfile("file2.py")
but I don't like that solution.
Is there a better way to solve my problem?
I would realy apriciate your help.
Thanks in advance.
python tkinter
asked Nov 16 '18 at 18:36
Chris SChris S
182
how do I close my current window if I can't see the tk.Toplevel(root) from the method I am in?
Here a small example of what i mean:
file1.py:
import Tkinter as tk
import file2
class ExampleMain:
def __init__(self, root):
self.mainFrame = tk.Frame(root)
...
tk.Button(self.mainFrame, command=self.button_pressed)
...
def button_pressed(self):
self.whatever = tk.Toplevel(root)
self.app = file2.ExampleNotMain(self.whatever)
if __name__ == '__main__':
root = tk.Tk()
app = ExampleMain(root)
root.mainloop()
file2.py:
import tkinter as tk
class ExampleNotMain:
def __init__(self, root):
self.frame = tk.Frame(root)
...
tk.Button(self.frame, command=self.close_window)
...
def close_window(self):
=> missing_command_here
In this example I would like to close the second window created (and keep the first).
If all the code is in one file something like
self.whatever.destroy()
would do it. My problem is I can't see the object from the first file with the command being in the second file.
I found something like
execfile("file2.py")
but I don't like that solution.
Is there a better way to solve my problem?
I would realy apriciate your help.
Thanks in advance.
python tkinter
python tkinter
asked Nov 16 '18 at 18:36
Chris SChris S
182
asked Nov 16 '18 at 18:36
Chris SChris S
182
asked Nov 16 '18 at 18:36
Chris SChris S
182
asked Nov 16 '18 at 18:36
Chris SChris S
182
asked Nov 16 '18 at 18:36
Chris SChris S
182
182
You code does not show the creation of a second, non-root Toplevel.
– Terry Jan Reedy
Nov 16 '18 at 18:59
I counted the root as the first window and the non-root window as second. I want to close the non-root window
– Chris S
Nov 16 '18 at 19:08
I see it now and will answer.
– Terry Jan Reedy
Nov 16 '18 at 19:09
add a comment |
You code does not show the creation of a second, non-root Toplevel.
– Terry Jan Reedy
Nov 16 '18 at 18:59
I counted the root as the first window and the non-root window as second. I want to close the non-root window
– Chris S
Nov 16 '18 at 19:08
I see it now and will answer.
– Terry Jan Reedy
Nov 16 '18 at 19:09
You code does not show the creation of a second, non-root Toplevel.
– Terry Jan Reedy
Nov 16 '18 at 18:59
You code does not show the creation of a second, non-root Toplevel.
– Terry Jan Reedy
Nov 16 '18 at 18:59
I counted the root as the first window and the non-root window as second. I want to close the non-root window
– Chris S
Nov 16 '18 at 19:08
I counted the root as the first window and the non-root window as second. I want to close the non-root window
– Chris S
Nov 16 '18 at 19:08
I see it now and will answer.
– Terry Jan Reedy
Nov 16 '18 at 19:09
I see it now and will answer.
– Terry Jan Reedy
Nov 16 '18 at 19:09
add a comment |
1 Answer
1
active
oldest
votes
When you create ExampleNotMain, you pass the 2nd Toplevel self.whatever. In ExampleNotMain.__init__, it gets bound to root. (master or parent would be a better parameter name). In __init__, add self.top = root(or whatever you call the passed-in toplevel). Inclose_window, addself.top.destroy()`.
answered Nov 16 '18 at 19:17
Terry Jan ReedyTerry Jan Reedy
12.3k12140
It works. Thanks for your help.
– Chris S
Nov 16 '18 at 19:22
Then please accept and/or upvote the answer.
– Terry Jan Reedy
Nov 16 '18 at 19:31
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
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oldest
votes
active
oldest
votes
When you create ExampleNotMain, you pass the 2nd Toplevel self.whatever. In ExampleNotMain.__init__, it gets bound to root. (master or parent would be a better parameter name). In __init__, add self.top = root(or whatever you call the passed-in toplevel). Inclose_window, addself.top.destroy()`.
answered Nov 16 '18 at 19:17
Terry Jan ReedyTerry Jan Reedy
12.3k12140
It works. Thanks for your help.
– Chris S
Nov 16 '18 at 19:22
Then please accept and/or upvote the answer.
– Terry Jan Reedy
Nov 16 '18 at 19:31
add a comment |
When you create ExampleNotMain, you pass the 2nd Toplevel self.whatever. In ExampleNotMain.__init__, it gets bound to root. (master or parent would be a better parameter name). In __init__, add self.top = root(or whatever you call the passed-in toplevel). Inclose_window, addself.top.destroy()`.
answered Nov 16 '18 at 19:17
Terry Jan ReedyTerry Jan Reedy
12.3k12140
It works. Thanks for your help.
– Chris S
Nov 16 '18 at 19:22
Then please accept and/or upvote the answer.
– Terry Jan Reedy
Nov 16 '18 at 19:31
add a comment |
When you create ExampleNotMain, you pass the 2nd Toplevel self.whatever. In ExampleNotMain.__init__, it gets bound to root. (master or parent would be a better parameter name). In __init__, add self.top = root(or whatever you call the passed-in toplevel). Inclose_window, addself.top.destroy()`.
answered Nov 16 '18 at 19:17
Terry Jan ReedyTerry Jan Reedy
12.3k12140
When you create ExampleNotMain, you pass the 2nd Toplevel self.whatever. In ExampleNotMain.__init__, it gets bound to root. (master or parent would be a better parameter name). In __init__, add self.top = root(or whatever you call the passed-in toplevel). Inclose_window, addself.top.destroy()`.
answered Nov 16 '18 at 19:17
Terry Jan ReedyTerry Jan Reedy
12.3k12140
answered Nov 16 '18 at 19:17
Terry Jan ReedyTerry Jan Reedy
12.3k12140
answered Nov 16 '18 at 19:17
Terry Jan ReedyTerry Jan Reedy
12.3k12140
answered Nov 16 '18 at 19:17
Terry Jan ReedyTerry Jan Reedy
12.3k12140
12.3k12140
It works. Thanks for your help.
– Chris S
Nov 16 '18 at 19:22
Then please accept and/or upvote the answer.
– Terry Jan Reedy
Nov 16 '18 at 19:31
add a comment |
It works. Thanks for your help.
– Chris S
Nov 16 '18 at 19:22
Then please accept and/or upvote the answer.
– Terry Jan Reedy
Nov 16 '18 at 19:31
It works. Thanks for your help.
– Chris S
Nov 16 '18 at 19:22
It works. Thanks for your help.
– Chris S
Nov 16 '18 at 19:22
Then please accept and/or upvote the answer.
– Terry Jan Reedy
Nov 16 '18 at 19:31
Then please accept and/or upvote the answer.
– Terry Jan Reedy
Nov 16 '18 at 19:31
add a comment |
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You code does not show the creation of a second, non-root Toplevel.
– Terry Jan Reedy
Nov 16 '18 at 18:59
I counted the root as the first window and the non-root window as second. I want to close the non-root window
– Chris S
Nov 16 '18 at 19:08
I see it now and will answer.
– Terry Jan Reedy
Nov 16 '18 at 19:09