How to dynamically import data in a nodejs app?

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I would like to use require in a node/express app with typescript to import a json. I tried it like this:

const url = `./data/${resource}.json`;

const data = require(url);

but I get the error Cannot find module './data/my-data.json'.

I'd like to use require instead of an import in order to create the data variable dynamically depending on the value of the resource variable.

edited Nov 17 '18 at 6:35

Gtm

asked Nov 16 '18 at 18:47

Alex

205

The most likely cause for your problem is the file path to your JSON file relative to your calling code. Can you verify and post the directory structure?

– Paul
Nov 17 '18 at 7:49

add a comment |

I would like to use require in a node/express app with typescript to import a json. I tried it like this:

const url = `./data/${resource}.json`;

const data = require(url);

but I get the error Cannot find module './data/my-data.json'.

I'd like to use require instead of an import in order to create the data variable dynamically depending on the value of the resource variable.

edited Nov 17 '18 at 6:35

Gtm

asked Nov 16 '18 at 18:47

Alex

205

The most likely cause for your problem is the file path to your JSON file relative to your calling code. Can you verify and post the directory structure?

– Paul
Nov 17 '18 at 7:49

add a comment |

I would like to use require in a node/express app with typescript to import a json. I tried it like this:

const url = `./data/${resource}.json`;

const data = require(url);

but I get the error Cannot find module './data/my-data.json'.

I'd like to use require instead of an import in order to create the data variable dynamically depending on the value of the resource variable.

edited Nov 17 '18 at 6:35

Gtm

asked Nov 16 '18 at 18:47

Alex

205

I would like to use require in a node/express app with typescript to import a json. I tried it like this:

const url = `./data/${resource}.json`;

const data = require(url);

but I get the error Cannot find module './data/my-data.json'.

I'd like to use require instead of an import in order to create the data variable dynamically depending on the value of the resource variable.

node.js json typescript express ejs

edited Nov 17 '18 at 6:35

Gtm

asked Nov 16 '18 at 18:47

Alex

205

edited Nov 17 '18 at 6:35

Gtm

asked Nov 16 '18 at 18:47

Alex

205

edited Nov 17 '18 at 6:35

Gtm

edited Nov 17 '18 at 6:35

Gtm

edited Nov 17 '18 at 6:35

Gtm

asked Nov 16 '18 at 18:47

Alex

205

asked Nov 16 '18 at 18:47

Alex

205

asked Nov 16 '18 at 18:47

Alex

205

The most likely cause for your problem is the file path to your JSON file relative to your calling code. Can you verify and post the directory structure?

– Paul
Nov 17 '18 at 7:49

add a comment |

The most likely cause for your problem is the file path to your JSON file relative to your calling code. Can you verify and post the directory structure?

– Paul
Nov 17 '18 at 7:49

The most likely cause for your problem is the file path to your JSON file relative to your calling code. Can you verify and post the directory structure?

– Paul
Nov 17 '18 at 7:49

add a comment |

3 Answers
3

active

oldest

votes

cost path = require('path');

const url = path.resolve(__dirname, `./data/${resource}.json`);   

const data = require(url);

answered Nov 17 '18 at 3:35

Biplab Malakar

43748

While this code snippet may be the solution, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion.

– Foo
Nov 17 '18 at 7:45

add a comment |

~~The require keyword is a special keyword in nodejs. It is used to load modules, and since your json file is not a module, hence the error. Try this, this way you can dynamically load your json.~~

import fs from 'fs';

const file = fs.readFileSync(`./data/${resource}.json`).toString();

const data = JSON.parse(file);

There may be better ways to write this function, read mode about the fs module here.

Edit: As someone had alredy pointed out, it is actually possible to dynamicallyrequire json file. Here's how,

import path from 'path';

const uri = path.resolve(__dirname, `<path_to_json_file>`);   

const data = require(uri);

However, as a standard practice, use the fs module to load static assets to your project.

edited Nov 17 '18 at 8:40

answered Nov 16 '18 at 19:06

Nishkal Kashyap

397311

add a comment |

-1

import fs from 'fs';



const file = fs.readFileSync(`./data/${resource}.json`).toString();

const data = JSON.parse(file);

edited Nov 17 '18 at 8:40

answered Nov 17 '18 at 4:51

Gtm

This answer is not only incorrect, it parrots an answer given 10 hours earlier

– Paul
Nov 17 '18 at 7:47

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

cost path = require('path');

const url = path.resolve(__dirname, `./data/${resource}.json`);   

const data = require(url);

answered Nov 17 '18 at 3:35

Biplab Malakar

43748

While this code snippet may be the solution, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion.

– Foo
Nov 17 '18 at 7:45

add a comment |

cost path = require('path');

const url = path.resolve(__dirname, `./data/${resource}.json`);   

const data = require(url);

answered Nov 17 '18 at 3:35

Biplab Malakar

43748

While this code snippet may be the solution, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion.

– Foo
Nov 17 '18 at 7:45

add a comment |

cost path = require('path');

const url = path.resolve(__dirname, `./data/${resource}.json`);   

const data = require(url);

answered Nov 17 '18 at 3:35

Biplab Malakar

43748

cost path = require('path');

const url = path.resolve(__dirname, `./data/${resource}.json`);   

const data = require(url);

answered Nov 17 '18 at 3:35

Biplab Malakar

43748

answered Nov 17 '18 at 3:35

Biplab Malakar

43748

answered Nov 17 '18 at 3:35

Biplab Malakar

43748

answered Nov 17 '18 at 3:35

Biplab Malakar

43748

While this code snippet may be the solution, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion.

– Foo
Nov 17 '18 at 7:45

add a comment |

While this code snippet may be the solution, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion.

– Foo
Nov 17 '18 at 7:45

While this code snippet may be the solution, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion.

– Foo
Nov 17 '18 at 7:45

add a comment |

~~The require keyword is a special keyword in nodejs. It is used to load modules, and since your json file is not a module, hence the error. Try this, this way you can dynamically load your json.~~

import fs from 'fs';

const file = fs.readFileSync(`./data/${resource}.json`).toString();

const data = JSON.parse(file);

There may be better ways to write this function, read mode about the fs module here.

Edit: As someone had alredy pointed out, it is actually possible to dynamicallyrequire json file. Here's how,

import path from 'path';

const uri = path.resolve(__dirname, `<path_to_json_file>`);   

const data = require(uri);

However, as a standard practice, use the fs module to load static assets to your project.

edited Nov 17 '18 at 8:40

answered Nov 16 '18 at 19:06

Nishkal Kashyap

397311

add a comment |

~~The require keyword is a special keyword in nodejs. It is used to load modules, and since your json file is not a module, hence the error. Try this, this way you can dynamically load your json.~~

import fs from 'fs';

const file = fs.readFileSync(`./data/${resource}.json`).toString();

const data = JSON.parse(file);

There may be better ways to write this function, read mode about the fs module here.

Edit: As someone had alredy pointed out, it is actually possible to dynamicallyrequire json file. Here's how,

import path from 'path';

const uri = path.resolve(__dirname, `<path_to_json_file>`);   

const data = require(uri);

However, as a standard practice, use the fs module to load static assets to your project.

edited Nov 17 '18 at 8:40

answered Nov 16 '18 at 19:06

Nishkal Kashyap

397311

add a comment |

~~The require keyword is a special keyword in nodejs. It is used to load modules, and since your json file is not a module, hence the error. Try this, this way you can dynamically load your json.~~

import fs from 'fs';

const file = fs.readFileSync(`./data/${resource}.json`).toString();

const data = JSON.parse(file);

There may be better ways to write this function, read mode about the fs module here.

Edit: As someone had alredy pointed out, it is actually possible to dynamicallyrequire json file. Here's how,

import path from 'path';

const uri = path.resolve(__dirname, `<path_to_json_file>`);   

const data = require(uri);

However, as a standard practice, use the fs module to load static assets to your project.

edited Nov 17 '18 at 8:40

answered Nov 16 '18 at 19:06

Nishkal Kashyap

397311

~~The require keyword is a special keyword in nodejs. It is used to load modules, and since your json file is not a module, hence the error. Try this, this way you can dynamically load your json.~~

import fs from 'fs';

const file = fs.readFileSync(`./data/${resource}.json`).toString();

const data = JSON.parse(file);

There may be better ways to write this function, read mode about the fs module here.

Edit: As someone had alredy pointed out, it is actually possible to dynamicallyrequire json file. Here's how,

import path from 'path';

const uri = path.resolve(__dirname, `<path_to_json_file>`);   

const data = require(uri);

However, as a standard practice, use the fs module to load static assets to your project.

edited Nov 17 '18 at 8:40

answered Nov 16 '18 at 19:06

Nishkal Kashyap

397311

edited Nov 17 '18 at 8:40

answered Nov 16 '18 at 19:06

Nishkal Kashyap

397311

answered Nov 16 '18 at 19:06

Nishkal Kashyap

397311

answered Nov 16 '18 at 19:06

Nishkal Kashyap

397311

add a comment |

-1

import fs from 'fs';



const file = fs.readFileSync(`./data/${resource}.json`).toString();

const data = JSON.parse(file);

edited Nov 17 '18 at 8:40

answered Nov 17 '18 at 4:51

Gtm

This answer is not only incorrect, it parrots an answer given 10 hours earlier

– Paul
Nov 17 '18 at 7:47

add a comment |

-1

import fs from 'fs';



const file = fs.readFileSync(`./data/${resource}.json`).toString();

const data = JSON.parse(file);

edited Nov 17 '18 at 8:40

answered Nov 17 '18 at 4:51

Gtm

This answer is not only incorrect, it parrots an answer given 10 hours earlier

– Paul
Nov 17 '18 at 7:47

add a comment |

-1

import fs from 'fs';



const file = fs.readFileSync(`./data/${resource}.json`).toString();

const data = JSON.parse(file);

edited Nov 17 '18 at 8:40

answered Nov 17 '18 at 4:51

Gtm

import fs from 'fs';



const file = fs.readFileSync(`./data/${resource}.json`).toString();

const data = JSON.parse(file);

import fs from 'fs';



const file = fs.readFileSync(`./data/${resource}.json`).toString();

const data = JSON.parse(file);

import fs from 'fs';



const file = fs.readFileSync(`./data/${resource}.json`).toString();

const data = JSON.parse(file);

edited Nov 17 '18 at 8:40

answered Nov 17 '18 at 4:51

Gtm

edited Nov 17 '18 at 8:40

answered Nov 17 '18 at 4:51

Gtm

answered Nov 17 '18 at 4:51

Gtm

answered Nov 17 '18 at 4:51

Gtm

This answer is not only incorrect, it parrots an answer given 10 hours earlier

– Paul
Nov 17 '18 at 7:47

add a comment |

This answer is not only incorrect, it parrots an answer given 10 hours earlier

– Paul
Nov 17 '18 at 7:47

This answer is not only incorrect, it parrots an answer given 10 hours earlier

– Paul
Nov 17 '18 at 7:47

add a comment |

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