How to encode labels from array in pyspark
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For example I have DataFrame with categorical features in name:
from pyspark.sql import SparkSession
spark = SparkSession.builder.master("local").appName("example")
.config("spark.some.config.option", "some-value").getOrCreate()
features = [(['a', 'b', 'c'], 1),
(['a', 'c'], 2),
(['d'], 3),
(['b', 'c'], 4),
(['a', 'b', 'd'], 5)]
df = spark.createDataFrame(features, ['name','id'])
df.show()
Out:
+---------+----+
| name| id |
+---------+----+
|[a, b, c]| 1|
| [a, c]| 2|
| [d]| 3|
| [b, c]| 4|
|[a, b, d]| 5|
+---------+----+
What I want to get:
+--------+--------+--------+--------+----+
| name_a | name_b | name_c | name_d | id |
+--------+--------+--------+--------+----+
| 1 | 1 | 1 | 0 | 1 |
+--------+--------+--------+--------+----+
| 1 | 0 | 1 | 0 | 2 |
+--------+--------+--------+--------+----+
| 0 | 0 | 0 | 1 | 3 |
+--------+--------+--------+--------+----+
| 0 | 1 | 1 | 0 | 4 |
+--------+--------+--------+--------+----+
| 1 | 1 | 0 | 1 | 5 |
+--------+--------+--------+--------+----+
I found the same queston but there is nothing helpful.
I tried to use VectorIndexer from PySpark.ML but I faced some problems with a transform of name field to vector type.
from pyspark.ml.feature import VectorIndexer
indexer = VectorIndexer(inputCol="name", outputCol="indexed", maxCategories=5)
indexerModel = indexer.fit(df)
I get the following error:
Column name must be of type org.apache.spark.ml.linalg.VectorUDT@3bfc3ba7 but was actually ArrayType
I found a solution here but it looks overcomplicated. However, I'm not sure if it can be done only with VectorIndexer.
python apache-spark pyspark pyspark-sql
add a comment |
For example I have DataFrame with categorical features in name:
from pyspark.sql import SparkSession
spark = SparkSession.builder.master("local").appName("example")
.config("spark.some.config.option", "some-value").getOrCreate()
features = [(['a', 'b', 'c'], 1),
(['a', 'c'], 2),
(['d'], 3),
(['b', 'c'], 4),
(['a', 'b', 'd'], 5)]
df = spark.createDataFrame(features, ['name','id'])
df.show()
Out:
+---------+----+
| name| id |
+---------+----+
|[a, b, c]| 1|
| [a, c]| 2|
| [d]| 3|
| [b, c]| 4|
|[a, b, d]| 5|
+---------+----+
What I want to get:
+--------+--------+--------+--------+----+
| name_a | name_b | name_c | name_d | id |
+--------+--------+--------+--------+----+
| 1 | 1 | 1 | 0 | 1 |
+--------+--------+--------+--------+----+
| 1 | 0 | 1 | 0 | 2 |
+--------+--------+--------+--------+----+
| 0 | 0 | 0 | 1 | 3 |
+--------+--------+--------+--------+----+
| 0 | 1 | 1 | 0 | 4 |
+--------+--------+--------+--------+----+
| 1 | 1 | 0 | 1 | 5 |
+--------+--------+--------+--------+----+
I found the same queston but there is nothing helpful.
I tried to use VectorIndexer from PySpark.ML but I faced some problems with a transform of name field to vector type.
from pyspark.ml.feature import VectorIndexer
indexer = VectorIndexer(inputCol="name", outputCol="indexed", maxCategories=5)
indexerModel = indexer.fit(df)
I get the following error:
Column name must be of type org.apache.spark.ml.linalg.VectorUDT@3bfc3ba7 but was actually ArrayType
I found a solution here but it looks overcomplicated. However, I'm not sure if it can be done only with VectorIndexer.
python apache-spark pyspark pyspark-sql
add a comment |
For example I have DataFrame with categorical features in name:
from pyspark.sql import SparkSession
spark = SparkSession.builder.master("local").appName("example")
.config("spark.some.config.option", "some-value").getOrCreate()
features = [(['a', 'b', 'c'], 1),
(['a', 'c'], 2),
(['d'], 3),
(['b', 'c'], 4),
(['a', 'b', 'd'], 5)]
df = spark.createDataFrame(features, ['name','id'])
df.show()
Out:
+---------+----+
| name| id |
+---------+----+
|[a, b, c]| 1|
| [a, c]| 2|
| [d]| 3|
| [b, c]| 4|
|[a, b, d]| 5|
+---------+----+
What I want to get:
+--------+--------+--------+--------+----+
| name_a | name_b | name_c | name_d | id |
+--------+--------+--------+--------+----+
| 1 | 1 | 1 | 0 | 1 |
+--------+--------+--------+--------+----+
| 1 | 0 | 1 | 0 | 2 |
+--------+--------+--------+--------+----+
| 0 | 0 | 0 | 1 | 3 |
+--------+--------+--------+--------+----+
| 0 | 1 | 1 | 0 | 4 |
+--------+--------+--------+--------+----+
| 1 | 1 | 0 | 1 | 5 |
+--------+--------+--------+--------+----+
I found the same queston but there is nothing helpful.
I tried to use VectorIndexer from PySpark.ML but I faced some problems with a transform of name field to vector type.
from pyspark.ml.feature import VectorIndexer
indexer = VectorIndexer(inputCol="name", outputCol="indexed", maxCategories=5)
indexerModel = indexer.fit(df)
I get the following error:
Column name must be of type org.apache.spark.ml.linalg.VectorUDT@3bfc3ba7 but was actually ArrayType
I found a solution here but it looks overcomplicated. However, I'm not sure if it can be done only with VectorIndexer.
python apache-spark pyspark pyspark-sql
For example I have DataFrame with categorical features in name:
from pyspark.sql import SparkSession
spark = SparkSession.builder.master("local").appName("example")
.config("spark.some.config.option", "some-value").getOrCreate()
features = [(['a', 'b', 'c'], 1),
(['a', 'c'], 2),
(['d'], 3),
(['b', 'c'], 4),
(['a', 'b', 'd'], 5)]
df = spark.createDataFrame(features, ['name','id'])
df.show()
Out:
+---------+----+
| name| id |
+---------+----+
|[a, b, c]| 1|
| [a, c]| 2|
| [d]| 3|
| [b, c]| 4|
|[a, b, d]| 5|
+---------+----+
What I want to get:
+--------+--------+--------+--------+----+
| name_a | name_b | name_c | name_d | id |
+--------+--------+--------+--------+----+
| 1 | 1 | 1 | 0 | 1 |
+--------+--------+--------+--------+----+
| 1 | 0 | 1 | 0 | 2 |
+--------+--------+--------+--------+----+
| 0 | 0 | 0 | 1 | 3 |
+--------+--------+--------+--------+----+
| 0 | 1 | 1 | 0 | 4 |
+--------+--------+--------+--------+----+
| 1 | 1 | 0 | 1 | 5 |
+--------+--------+--------+--------+----+
I found the same queston but there is nothing helpful.
I tried to use VectorIndexer from PySpark.ML but I faced some problems with a transform of name field to vector type.
from pyspark.ml.feature import VectorIndexer
indexer = VectorIndexer(inputCol="name", outputCol="indexed", maxCategories=5)
indexerModel = indexer.fit(df)
I get the following error:
Column name must be of type org.apache.spark.ml.linalg.VectorUDT@3bfc3ba7 but was actually ArrayType
I found a solution here but it looks overcomplicated. However, I'm not sure if it can be done only with VectorIndexer.
python apache-spark pyspark pyspark-sql
python apache-spark pyspark pyspark-sql
asked Dec 4 '18 at 19:54
Moris HuxleyMoris Huxley
15210
15210
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
If you want use the output with Spark ML it is best to use CountVectorizer:
from pyspark.ml.feature import CountVectorizer
# Add binary=True if needed
df_enc = (CountVectorizer(inputCol="name", outputCol="name_vector")
.fit(df)
.transform(df))
df_enc.show(truncate=False)
+---------+---+-------------------------+
|name |id |name_vector |
+---------+---+-------------------------+
|[a, b, c]|1 |(4,[0,1,2],[1.0,1.0,1.0])|
|[a, c] |2 |(4,[0,1],[1.0,1.0]) |
|[d] |3 |(4,[3],[1.0]) |
|[b, c] |4 |(4,[1,2],[1.0,1.0]) |
|[a, b, d]|5 |(4,[0,2,3],[1.0,1.0,1.0])|
+---------+---+-------------------------+
Otherwise collect distinct values:
from pyspark.sql.functions import array_contains, col, explode
names = [
x[0] for x in
df.select(explode("name").alias("name")).distinct().orderBy("name").collect()]
and select the columns with array_contains:
df_sep = df.select("*", *[
array_contains("name", name).alias("name_{}".format(name)).cast("integer")
for name in names]
)
df_sep.show()
+---------+---+------+------+------+------+
| name| id|name_a|name_b|name_c|name_d|
+---------+---+------+------+------+------+
|[a, b, c]| 1| 1| 1| 1| 0|
| [a, c]| 2| 1| 0| 1| 0|
| [d]| 3| 0| 0| 0| 1|
| [b, c]| 4| 0| 1| 1| 0|
|[a, b, d]| 5| 1| 1| 0| 1|
+---------+---+------+------+------+------+
add a comment |
With explode from the pyspark.sql.functions and pivot:
from pyspark.sql import functions as F
features = [(['a', 'b', 'c'], 1),
(['a', 'c'], 2),
(['d'], 3),
(['b', 'c'], 4),
(['a', 'b', 'd'], 5)]
df = spark.createDataFrame(features, ['name','id'])
df.show()
+---------+---+
| name| id|
+---------+---+
|[a, b, c]| 1|
| [a, c]| 2|
| [d]| 3|
| [b, c]| 4|
|[a, b, d]| 5|
+---------+---+
df = df.withColumn('exploded', F.explode('name'))
df.drop('name').groupby('id').pivot('exploded').count().show()
+---+----+----+----+----+
| id| a| b| c| d|
+---+----+----+----+----+
| 5| 1| 1|null| 1|
| 1| 1| 1| 1|null|
| 3|null|null|null| 1|
| 2| 1|null| 1|null|
| 4|null| 1| 1|null|
+---+----+----+----+----+
Sort by id and convert null to 0
df.drop('name').groupby('id').pivot('exploded').count().na.fill(0).sort(F.col('id').asc()).show()
+---+---+---+---+---+
| id| a| b| c| d|
+---+---+---+---+---+
| 1| 1| 1| 1| 0|
| 2| 1| 0| 1| 0|
| 3| 0| 0| 0| 1|
| 4| 0| 1| 1| 0|
| 5| 1| 1| 0| 1|
+---+---+---+---+---+
explode returns a new row for each element in the given array or map. You can then use pivot to "transpose" the new column.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you want use the output with Spark ML it is best to use CountVectorizer:
from pyspark.ml.feature import CountVectorizer
# Add binary=True if needed
df_enc = (CountVectorizer(inputCol="name", outputCol="name_vector")
.fit(df)
.transform(df))
df_enc.show(truncate=False)
+---------+---+-------------------------+
|name |id |name_vector |
+---------+---+-------------------------+
|[a, b, c]|1 |(4,[0,1,2],[1.0,1.0,1.0])|
|[a, c] |2 |(4,[0,1],[1.0,1.0]) |
|[d] |3 |(4,[3],[1.0]) |
|[b, c] |4 |(4,[1,2],[1.0,1.0]) |
|[a, b, d]|5 |(4,[0,2,3],[1.0,1.0,1.0])|
+---------+---+-------------------------+
Otherwise collect distinct values:
from pyspark.sql.functions import array_contains, col, explode
names = [
x[0] for x in
df.select(explode("name").alias("name")).distinct().orderBy("name").collect()]
and select the columns with array_contains:
df_sep = df.select("*", *[
array_contains("name", name).alias("name_{}".format(name)).cast("integer")
for name in names]
)
df_sep.show()
+---------+---+------+------+------+------+
| name| id|name_a|name_b|name_c|name_d|
+---------+---+------+------+------+------+
|[a, b, c]| 1| 1| 1| 1| 0|
| [a, c]| 2| 1| 0| 1| 0|
| [d]| 3| 0| 0| 0| 1|
| [b, c]| 4| 0| 1| 1| 0|
|[a, b, d]| 5| 1| 1| 0| 1|
+---------+---+------+------+------+------+
add a comment |
If you want use the output with Spark ML it is best to use CountVectorizer:
from pyspark.ml.feature import CountVectorizer
# Add binary=True if needed
df_enc = (CountVectorizer(inputCol="name", outputCol="name_vector")
.fit(df)
.transform(df))
df_enc.show(truncate=False)
+---------+---+-------------------------+
|name |id |name_vector |
+---------+---+-------------------------+
|[a, b, c]|1 |(4,[0,1,2],[1.0,1.0,1.0])|
|[a, c] |2 |(4,[0,1],[1.0,1.0]) |
|[d] |3 |(4,[3],[1.0]) |
|[b, c] |4 |(4,[1,2],[1.0,1.0]) |
|[a, b, d]|5 |(4,[0,2,3],[1.0,1.0,1.0])|
+---------+---+-------------------------+
Otherwise collect distinct values:
from pyspark.sql.functions import array_contains, col, explode
names = [
x[0] for x in
df.select(explode("name").alias("name")).distinct().orderBy("name").collect()]
and select the columns with array_contains:
df_sep = df.select("*", *[
array_contains("name", name).alias("name_{}".format(name)).cast("integer")
for name in names]
)
df_sep.show()
+---------+---+------+------+------+------+
| name| id|name_a|name_b|name_c|name_d|
+---------+---+------+------+------+------+
|[a, b, c]| 1| 1| 1| 1| 0|
| [a, c]| 2| 1| 0| 1| 0|
| [d]| 3| 0| 0| 0| 1|
| [b, c]| 4| 0| 1| 1| 0|
|[a, b, d]| 5| 1| 1| 0| 1|
+---------+---+------+------+------+------+
add a comment |
If you want use the output with Spark ML it is best to use CountVectorizer:
from pyspark.ml.feature import CountVectorizer
# Add binary=True if needed
df_enc = (CountVectorizer(inputCol="name", outputCol="name_vector")
.fit(df)
.transform(df))
df_enc.show(truncate=False)
+---------+---+-------------------------+
|name |id |name_vector |
+---------+---+-------------------------+
|[a, b, c]|1 |(4,[0,1,2],[1.0,1.0,1.0])|
|[a, c] |2 |(4,[0,1],[1.0,1.0]) |
|[d] |3 |(4,[3],[1.0]) |
|[b, c] |4 |(4,[1,2],[1.0,1.0]) |
|[a, b, d]|5 |(4,[0,2,3],[1.0,1.0,1.0])|
+---------+---+-------------------------+
Otherwise collect distinct values:
from pyspark.sql.functions import array_contains, col, explode
names = [
x[0] for x in
df.select(explode("name").alias("name")).distinct().orderBy("name").collect()]
and select the columns with array_contains:
df_sep = df.select("*", *[
array_contains("name", name).alias("name_{}".format(name)).cast("integer")
for name in names]
)
df_sep.show()
+---------+---+------+------+------+------+
| name| id|name_a|name_b|name_c|name_d|
+---------+---+------+------+------+------+
|[a, b, c]| 1| 1| 1| 1| 0|
| [a, c]| 2| 1| 0| 1| 0|
| [d]| 3| 0| 0| 0| 1|
| [b, c]| 4| 0| 1| 1| 0|
|[a, b, d]| 5| 1| 1| 0| 1|
+---------+---+------+------+------+------+
If you want use the output with Spark ML it is best to use CountVectorizer:
from pyspark.ml.feature import CountVectorizer
# Add binary=True if needed
df_enc = (CountVectorizer(inputCol="name", outputCol="name_vector")
.fit(df)
.transform(df))
df_enc.show(truncate=False)
+---------+---+-------------------------+
|name |id |name_vector |
+---------+---+-------------------------+
|[a, b, c]|1 |(4,[0,1,2],[1.0,1.0,1.0])|
|[a, c] |2 |(4,[0,1],[1.0,1.0]) |
|[d] |3 |(4,[3],[1.0]) |
|[b, c] |4 |(4,[1,2],[1.0,1.0]) |
|[a, b, d]|5 |(4,[0,2,3],[1.0,1.0,1.0])|
+---------+---+-------------------------+
Otherwise collect distinct values:
from pyspark.sql.functions import array_contains, col, explode
names = [
x[0] for x in
df.select(explode("name").alias("name")).distinct().orderBy("name").collect()]
and select the columns with array_contains:
df_sep = df.select("*", *[
array_contains("name", name).alias("name_{}".format(name)).cast("integer")
for name in names]
)
df_sep.show()
+---------+---+------+------+------+------+
| name| id|name_a|name_b|name_c|name_d|
+---------+---+------+------+------+------+
|[a, b, c]| 1| 1| 1| 1| 0|
| [a, c]| 2| 1| 0| 1| 0|
| [d]| 3| 0| 0| 0| 1|
| [b, c]| 4| 0| 1| 1| 0|
|[a, b, d]| 5| 1| 1| 0| 1|
+---------+---+------+------+------+------+
edited Dec 4 '18 at 20:32
answered Dec 4 '18 at 20:12
user10465355user10465355
2,1392521
2,1392521
add a comment |
add a comment |
With explode from the pyspark.sql.functions and pivot:
from pyspark.sql import functions as F
features = [(['a', 'b', 'c'], 1),
(['a', 'c'], 2),
(['d'], 3),
(['b', 'c'], 4),
(['a', 'b', 'd'], 5)]
df = spark.createDataFrame(features, ['name','id'])
df.show()
+---------+---+
| name| id|
+---------+---+
|[a, b, c]| 1|
| [a, c]| 2|
| [d]| 3|
| [b, c]| 4|
|[a, b, d]| 5|
+---------+---+
df = df.withColumn('exploded', F.explode('name'))
df.drop('name').groupby('id').pivot('exploded').count().show()
+---+----+----+----+----+
| id| a| b| c| d|
+---+----+----+----+----+
| 5| 1| 1|null| 1|
| 1| 1| 1| 1|null|
| 3|null|null|null| 1|
| 2| 1|null| 1|null|
| 4|null| 1| 1|null|
+---+----+----+----+----+
Sort by id and convert null to 0
df.drop('name').groupby('id').pivot('exploded').count().na.fill(0).sort(F.col('id').asc()).show()
+---+---+---+---+---+
| id| a| b| c| d|
+---+---+---+---+---+
| 1| 1| 1| 1| 0|
| 2| 1| 0| 1| 0|
| 3| 0| 0| 0| 1|
| 4| 0| 1| 1| 0|
| 5| 1| 1| 0| 1|
+---+---+---+---+---+
explode returns a new row for each element in the given array or map. You can then use pivot to "transpose" the new column.
add a comment |
With explode from the pyspark.sql.functions and pivot:
from pyspark.sql import functions as F
features = [(['a', 'b', 'c'], 1),
(['a', 'c'], 2),
(['d'], 3),
(['b', 'c'], 4),
(['a', 'b', 'd'], 5)]
df = spark.createDataFrame(features, ['name','id'])
df.show()
+---------+---+
| name| id|
+---------+---+
|[a, b, c]| 1|
| [a, c]| 2|
| [d]| 3|
| [b, c]| 4|
|[a, b, d]| 5|
+---------+---+
df = df.withColumn('exploded', F.explode('name'))
df.drop('name').groupby('id').pivot('exploded').count().show()
+---+----+----+----+----+
| id| a| b| c| d|
+---+----+----+----+----+
| 5| 1| 1|null| 1|
| 1| 1| 1| 1|null|
| 3|null|null|null| 1|
| 2| 1|null| 1|null|
| 4|null| 1| 1|null|
+---+----+----+----+----+
Sort by id and convert null to 0
df.drop('name').groupby('id').pivot('exploded').count().na.fill(0).sort(F.col('id').asc()).show()
+---+---+---+---+---+
| id| a| b| c| d|
+---+---+---+---+---+
| 1| 1| 1| 1| 0|
| 2| 1| 0| 1| 0|
| 3| 0| 0| 0| 1|
| 4| 0| 1| 1| 0|
| 5| 1| 1| 0| 1|
+---+---+---+---+---+
explode returns a new row for each element in the given array or map. You can then use pivot to "transpose" the new column.
add a comment |
With explode from the pyspark.sql.functions and pivot:
from pyspark.sql import functions as F
features = [(['a', 'b', 'c'], 1),
(['a', 'c'], 2),
(['d'], 3),
(['b', 'c'], 4),
(['a', 'b', 'd'], 5)]
df = spark.createDataFrame(features, ['name','id'])
df.show()
+---------+---+
| name| id|
+---------+---+
|[a, b, c]| 1|
| [a, c]| 2|
| [d]| 3|
| [b, c]| 4|
|[a, b, d]| 5|
+---------+---+
df = df.withColumn('exploded', F.explode('name'))
df.drop('name').groupby('id').pivot('exploded').count().show()
+---+----+----+----+----+
| id| a| b| c| d|
+---+----+----+----+----+
| 5| 1| 1|null| 1|
| 1| 1| 1| 1|null|
| 3|null|null|null| 1|
| 2| 1|null| 1|null|
| 4|null| 1| 1|null|
+---+----+----+----+----+
Sort by id and convert null to 0
df.drop('name').groupby('id').pivot('exploded').count().na.fill(0).sort(F.col('id').asc()).show()
+---+---+---+---+---+
| id| a| b| c| d|
+---+---+---+---+---+
| 1| 1| 1| 1| 0|
| 2| 1| 0| 1| 0|
| 3| 0| 0| 0| 1|
| 4| 0| 1| 1| 0|
| 5| 1| 1| 0| 1|
+---+---+---+---+---+
explode returns a new row for each element in the given array or map. You can then use pivot to "transpose" the new column.
With explode from the pyspark.sql.functions and pivot:
from pyspark.sql import functions as F
features = [(['a', 'b', 'c'], 1),
(['a', 'c'], 2),
(['d'], 3),
(['b', 'c'], 4),
(['a', 'b', 'd'], 5)]
df = spark.createDataFrame(features, ['name','id'])
df.show()
+---------+---+
| name| id|
+---------+---+
|[a, b, c]| 1|
| [a, c]| 2|
| [d]| 3|
| [b, c]| 4|
|[a, b, d]| 5|
+---------+---+
df = df.withColumn('exploded', F.explode('name'))
df.drop('name').groupby('id').pivot('exploded').count().show()
+---+----+----+----+----+
| id| a| b| c| d|
+---+----+----+----+----+
| 5| 1| 1|null| 1|
| 1| 1| 1| 1|null|
| 3|null|null|null| 1|
| 2| 1|null| 1|null|
| 4|null| 1| 1|null|
+---+----+----+----+----+
Sort by id and convert null to 0
df.drop('name').groupby('id').pivot('exploded').count().na.fill(0).sort(F.col('id').asc()).show()
+---+---+---+---+---+
| id| a| b| c| d|
+---+---+---+---+---+
| 1| 1| 1| 1| 0|
| 2| 1| 0| 1| 0|
| 3| 0| 0| 0| 1|
| 4| 0| 1| 1| 0|
| 5| 1| 1| 0| 1|
+---+---+---+---+---+
explode returns a new row for each element in the given array or map. You can then use pivot to "transpose" the new column.
edited Dec 4 '18 at 22:01
answered Dec 4 '18 at 20:56
user2314737user2314737
15.5k115571
15.5k115571
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