How do I view all of a user's orders in Rails?





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I have made a simple Rails app where users are able to add orders they have made to an Order model. I used Devise and I have been able to work out how to only allow a user to delete and edit their on orders. Now I would like for a user to be able to view all of the orders they have created. A user has many orders and orders belong to users.



I'd like to be able to go to localhost:3000/users/1/orders and see all of their orders.



Here is my current orders controller:



class OrdersController < ApplicationController
before_action :find_order, only: [:edit, :destroy, :update, :show]

def index
@orders = Order.all.order("created_at DESC")
end

def new
@order = current_user.orders.build
end

def update
if @order.update(order_params)
redirect_to root_path
else
render 'edit'
end
end

def show
end

def create
@order = current_user.orders.build(order_params)

if @order.save
redirect_to root_path
else
render 'new'
end
end

def edit
end

def destroy
@order.destroy
redirect_to root_path
end

private

def order_params
params.require(:order).permit(:start_point, :restaurant_location, :customer_location, :fee)
end

def find_order
@order = Order.find(params[:id])
end

end


Thanks in advance!










share|improve this question























  • This was also posted on Reddit: reddit.com/r/rails/comments/9xsdge/…

    – Dorian
    Nov 17 '18 at 4:41


















0















I have made a simple Rails app where users are able to add orders they have made to an Order model. I used Devise and I have been able to work out how to only allow a user to delete and edit their on orders. Now I would like for a user to be able to view all of the orders they have created. A user has many orders and orders belong to users.



I'd like to be able to go to localhost:3000/users/1/orders and see all of their orders.



Here is my current orders controller:



class OrdersController < ApplicationController
before_action :find_order, only: [:edit, :destroy, :update, :show]

def index
@orders = Order.all.order("created_at DESC")
end

def new
@order = current_user.orders.build
end

def update
if @order.update(order_params)
redirect_to root_path
else
render 'edit'
end
end

def show
end

def create
@order = current_user.orders.build(order_params)

if @order.save
redirect_to root_path
else
render 'new'
end
end

def edit
end

def destroy
@order.destroy
redirect_to root_path
end

private

def order_params
params.require(:order).permit(:start_point, :restaurant_location, :customer_location, :fee)
end

def find_order
@order = Order.find(params[:id])
end

end


Thanks in advance!










share|improve this question























  • This was also posted on Reddit: reddit.com/r/rails/comments/9xsdge/…

    – Dorian
    Nov 17 '18 at 4:41














0












0








0








I have made a simple Rails app where users are able to add orders they have made to an Order model. I used Devise and I have been able to work out how to only allow a user to delete and edit their on orders. Now I would like for a user to be able to view all of the orders they have created. A user has many orders and orders belong to users.



I'd like to be able to go to localhost:3000/users/1/orders and see all of their orders.



Here is my current orders controller:



class OrdersController < ApplicationController
before_action :find_order, only: [:edit, :destroy, :update, :show]

def index
@orders = Order.all.order("created_at DESC")
end

def new
@order = current_user.orders.build
end

def update
if @order.update(order_params)
redirect_to root_path
else
render 'edit'
end
end

def show
end

def create
@order = current_user.orders.build(order_params)

if @order.save
redirect_to root_path
else
render 'new'
end
end

def edit
end

def destroy
@order.destroy
redirect_to root_path
end

private

def order_params
params.require(:order).permit(:start_point, :restaurant_location, :customer_location, :fee)
end

def find_order
@order = Order.find(params[:id])
end

end


Thanks in advance!










share|improve this question














I have made a simple Rails app where users are able to add orders they have made to an Order model. I used Devise and I have been able to work out how to only allow a user to delete and edit their on orders. Now I would like for a user to be able to view all of the orders they have created. A user has many orders and orders belong to users.



I'd like to be able to go to localhost:3000/users/1/orders and see all of their orders.



Here is my current orders controller:



class OrdersController < ApplicationController
before_action :find_order, only: [:edit, :destroy, :update, :show]

def index
@orders = Order.all.order("created_at DESC")
end

def new
@order = current_user.orders.build
end

def update
if @order.update(order_params)
redirect_to root_path
else
render 'edit'
end
end

def show
end

def create
@order = current_user.orders.build(order_params)

if @order.save
redirect_to root_path
else
render 'new'
end
end

def edit
end

def destroy
@order.destroy
redirect_to root_path
end

private

def order_params
params.require(:order).permit(:start_point, :restaurant_location, :customer_location, :fee)
end

def find_order
@order = Order.find(params[:id])
end

end


Thanks in advance!







ruby-on-rails ruby






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asked Nov 17 '18 at 1:07







user10410465




















  • This was also posted on Reddit: reddit.com/r/rails/comments/9xsdge/…

    – Dorian
    Nov 17 '18 at 4:41



















  • This was also posted on Reddit: reddit.com/r/rails/comments/9xsdge/…

    – Dorian
    Nov 17 '18 at 4:41

















This was also posted on Reddit: reddit.com/r/rails/comments/9xsdge/…

– Dorian
Nov 17 '18 at 4:41





This was also posted on Reddit: reddit.com/r/rails/comments/9xsdge/…

– Dorian
Nov 17 '18 at 4:41












1 Answer
1






active

oldest

votes


















2














I would set it up like so:



resources :users, only:  do
resources :orders, module: :users, only: :index
end


This routes /users/:user_id/orders to Users::OrdersController#index.



Using the module option is a nifty trick that lets you disambiguate between nested and non nested resources. Meaning that it will not effect your existing orders index.



Creating the controller itself is very straight forward:



# app/controllers/users/orders_controller.rb
module Users
class OrdersController
# GET /users/:user_id/orders
def index
@user = User.includes(:orders).find(params[:user_id])
@orders = @user.orders
end
end
end


And a just create a view:



# app/views/users/orders/index.html.erb
<table>
<thead>
<tr>
<th>id</th>
<th>created_at</th>
</tr>
</thead>
<tbody>
<% @orders.each do |order|%>
<tr>
<td><%= order.id %></td>
<td><%= order.created_at %></td>
</tr>
<% end %>
</tbody>
</table>


Remember that partials are your friend if you want to share view code with the "normal" index.






share|improve this answer


























  • I don't understand... I'm new to Rails (and programming) so bear with me. Your example has an orders controller within a users module here: # app/controllers/users/orders_controller.rb Does this mean i generate a new orders controller? Or do I just add the users module to my existing orders controller?

    – user10410465
    Nov 22 '18 at 0:18











  • No - its a separate controller and you don't need to generate it since you already have the code.

    – max
    Nov 22 '18 at 3:27











  • Okay, this worked! Although I needed to make sure the controller class was inheriting from ApplicationController. Thanks!

    – user10410465
    Nov 22 '18 at 15:37












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














I would set it up like so:



resources :users, only:  do
resources :orders, module: :users, only: :index
end


This routes /users/:user_id/orders to Users::OrdersController#index.



Using the module option is a nifty trick that lets you disambiguate between nested and non nested resources. Meaning that it will not effect your existing orders index.



Creating the controller itself is very straight forward:



# app/controllers/users/orders_controller.rb
module Users
class OrdersController
# GET /users/:user_id/orders
def index
@user = User.includes(:orders).find(params[:user_id])
@orders = @user.orders
end
end
end


And a just create a view:



# app/views/users/orders/index.html.erb
<table>
<thead>
<tr>
<th>id</th>
<th>created_at</th>
</tr>
</thead>
<tbody>
<% @orders.each do |order|%>
<tr>
<td><%= order.id %></td>
<td><%= order.created_at %></td>
</tr>
<% end %>
</tbody>
</table>


Remember that partials are your friend if you want to share view code with the "normal" index.






share|improve this answer


























  • I don't understand... I'm new to Rails (and programming) so bear with me. Your example has an orders controller within a users module here: # app/controllers/users/orders_controller.rb Does this mean i generate a new orders controller? Or do I just add the users module to my existing orders controller?

    – user10410465
    Nov 22 '18 at 0:18











  • No - its a separate controller and you don't need to generate it since you already have the code.

    – max
    Nov 22 '18 at 3:27











  • Okay, this worked! Although I needed to make sure the controller class was inheriting from ApplicationController. Thanks!

    – user10410465
    Nov 22 '18 at 15:37
















2














I would set it up like so:



resources :users, only:  do
resources :orders, module: :users, only: :index
end


This routes /users/:user_id/orders to Users::OrdersController#index.



Using the module option is a nifty trick that lets you disambiguate between nested and non nested resources. Meaning that it will not effect your existing orders index.



Creating the controller itself is very straight forward:



# app/controllers/users/orders_controller.rb
module Users
class OrdersController
# GET /users/:user_id/orders
def index
@user = User.includes(:orders).find(params[:user_id])
@orders = @user.orders
end
end
end


And a just create a view:



# app/views/users/orders/index.html.erb
<table>
<thead>
<tr>
<th>id</th>
<th>created_at</th>
</tr>
</thead>
<tbody>
<% @orders.each do |order|%>
<tr>
<td><%= order.id %></td>
<td><%= order.created_at %></td>
</tr>
<% end %>
</tbody>
</table>


Remember that partials are your friend if you want to share view code with the "normal" index.






share|improve this answer


























  • I don't understand... I'm new to Rails (and programming) so bear with me. Your example has an orders controller within a users module here: # app/controllers/users/orders_controller.rb Does this mean i generate a new orders controller? Or do I just add the users module to my existing orders controller?

    – user10410465
    Nov 22 '18 at 0:18











  • No - its a separate controller and you don't need to generate it since you already have the code.

    – max
    Nov 22 '18 at 3:27











  • Okay, this worked! Although I needed to make sure the controller class was inheriting from ApplicationController. Thanks!

    – user10410465
    Nov 22 '18 at 15:37














2












2








2







I would set it up like so:



resources :users, only:  do
resources :orders, module: :users, only: :index
end


This routes /users/:user_id/orders to Users::OrdersController#index.



Using the module option is a nifty trick that lets you disambiguate between nested and non nested resources. Meaning that it will not effect your existing orders index.



Creating the controller itself is very straight forward:



# app/controllers/users/orders_controller.rb
module Users
class OrdersController
# GET /users/:user_id/orders
def index
@user = User.includes(:orders).find(params[:user_id])
@orders = @user.orders
end
end
end


And a just create a view:



# app/views/users/orders/index.html.erb
<table>
<thead>
<tr>
<th>id</th>
<th>created_at</th>
</tr>
</thead>
<tbody>
<% @orders.each do |order|%>
<tr>
<td><%= order.id %></td>
<td><%= order.created_at %></td>
</tr>
<% end %>
</tbody>
</table>


Remember that partials are your friend if you want to share view code with the "normal" index.






share|improve this answer















I would set it up like so:



resources :users, only:  do
resources :orders, module: :users, only: :index
end


This routes /users/:user_id/orders to Users::OrdersController#index.



Using the module option is a nifty trick that lets you disambiguate between nested and non nested resources. Meaning that it will not effect your existing orders index.



Creating the controller itself is very straight forward:



# app/controllers/users/orders_controller.rb
module Users
class OrdersController
# GET /users/:user_id/orders
def index
@user = User.includes(:orders).find(params[:user_id])
@orders = @user.orders
end
end
end


And a just create a view:



# app/views/users/orders/index.html.erb
<table>
<thead>
<tr>
<th>id</th>
<th>created_at</th>
</tr>
</thead>
<tbody>
<% @orders.each do |order|%>
<tr>
<td><%= order.id %></td>
<td><%= order.created_at %></td>
</tr>
<% end %>
</tbody>
</table>


Remember that partials are your friend if you want to share view code with the "normal" index.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 17 '18 at 3:01

























answered Nov 17 '18 at 2:53









maxmax

47k1060106




47k1060106













  • I don't understand... I'm new to Rails (and programming) so bear with me. Your example has an orders controller within a users module here: # app/controllers/users/orders_controller.rb Does this mean i generate a new orders controller? Or do I just add the users module to my existing orders controller?

    – user10410465
    Nov 22 '18 at 0:18











  • No - its a separate controller and you don't need to generate it since you already have the code.

    – max
    Nov 22 '18 at 3:27











  • Okay, this worked! Although I needed to make sure the controller class was inheriting from ApplicationController. Thanks!

    – user10410465
    Nov 22 '18 at 15:37



















  • I don't understand... I'm new to Rails (and programming) so bear with me. Your example has an orders controller within a users module here: # app/controllers/users/orders_controller.rb Does this mean i generate a new orders controller? Or do I just add the users module to my existing orders controller?

    – user10410465
    Nov 22 '18 at 0:18











  • No - its a separate controller and you don't need to generate it since you already have the code.

    – max
    Nov 22 '18 at 3:27











  • Okay, this worked! Although I needed to make sure the controller class was inheriting from ApplicationController. Thanks!

    – user10410465
    Nov 22 '18 at 15:37

















I don't understand... I'm new to Rails (and programming) so bear with me. Your example has an orders controller within a users module here: # app/controllers/users/orders_controller.rb Does this mean i generate a new orders controller? Or do I just add the users module to my existing orders controller?

– user10410465
Nov 22 '18 at 0:18





I don't understand... I'm new to Rails (and programming) so bear with me. Your example has an orders controller within a users module here: # app/controllers/users/orders_controller.rb Does this mean i generate a new orders controller? Or do I just add the users module to my existing orders controller?

– user10410465
Nov 22 '18 at 0:18













No - its a separate controller and you don't need to generate it since you already have the code.

– max
Nov 22 '18 at 3:27





No - its a separate controller and you don't need to generate it since you already have the code.

– max
Nov 22 '18 at 3:27













Okay, this worked! Although I needed to make sure the controller class was inheriting from ApplicationController. Thanks!

– user10410465
Nov 22 '18 at 15:37





Okay, this worked! Although I needed to make sure the controller class was inheriting from ApplicationController. Thanks!

– user10410465
Nov 22 '18 at 15:37




















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