Grep for a variable in a file
I want to grep the following patterns in the file /root/scripts/list.txt:
'^"123"^'
'^"456"^'
'^"789"^'
So I write code like below in my shell script
myvar=-F -e '^"123"^' -e '^"456"^' -e '^"789"^'
grep $myvar /root/scripts/list.txt
(Pattern will change every time, so I created a string with myvar)
It is giving a null output, but when I run the command below I'm getting the required output:
grep -F -e '^"123"^' -e '^"456"^' -e '^"789"^' /root/scripts/list.txt
Can some one please help me?
Thanks in advance.
shell
add a comment |
I want to grep the following patterns in the file /root/scripts/list.txt:
'^"123"^'
'^"456"^'
'^"789"^'
So I write code like below in my shell script
myvar=-F -e '^"123"^' -e '^"456"^' -e '^"789"^'
grep $myvar /root/scripts/list.txt
(Pattern will change every time, so I created a string with myvar)
It is giving a null output, but when I run the command below I'm getting the required output:
grep -F -e '^"123"^' -e '^"456"^' -e '^"789"^' /root/scripts/list.txt
Can some one please help me?
Thanks in advance.
shell
The problem is your use of quotes, but you haven't accurately shown how you're setting myvar. (I assume you're not writingmyvar=-f -e '^..., since that would try to run a command named-eand you would probably get an error of the form `-e: command not found.). Edit your question to show your code.
– William Pursell
Nov 15 '18 at 15:51
I suspect you just need to omit the single quotes around each term in the assignment of myvar, but it's difficult to say without more detail.
– William Pursell
Nov 15 '18 at 15:52
Trymyvar='-F -e ^"123"^ -e ^"456"^'
– William Pursell
Nov 15 '18 at 15:57
If you are using bash, consider using bash arrays:myvar=( -F -e '^"123"^' )andgrep ${myvar[@]}
– Samuel Kirschner
Nov 15 '18 at 15:58
Thanks William Pursell for your suggestion to omit single quotes around the id. I wonder how this is working in shell script and not working when I run that grep command in command prompt. Please explain.
– Dhanamunichandra Bhusham
Nov 18 '18 at 16:01
add a comment |
I want to grep the following patterns in the file /root/scripts/list.txt:
'^"123"^'
'^"456"^'
'^"789"^'
So I write code like below in my shell script
myvar=-F -e '^"123"^' -e '^"456"^' -e '^"789"^'
grep $myvar /root/scripts/list.txt
(Pattern will change every time, so I created a string with myvar)
It is giving a null output, but when I run the command below I'm getting the required output:
grep -F -e '^"123"^' -e '^"456"^' -e '^"789"^' /root/scripts/list.txt
Can some one please help me?
Thanks in advance.
shell
I want to grep the following patterns in the file /root/scripts/list.txt:
'^"123"^'
'^"456"^'
'^"789"^'
So I write code like below in my shell script
myvar=-F -e '^"123"^' -e '^"456"^' -e '^"789"^'
grep $myvar /root/scripts/list.txt
(Pattern will change every time, so I created a string with myvar)
It is giving a null output, but when I run the command below I'm getting the required output:
grep -F -e '^"123"^' -e '^"456"^' -e '^"789"^' /root/scripts/list.txt
Can some one please help me?
Thanks in advance.
shell
shell
edited Nov 15 '18 at 16:07
pushkin
4,073112753
4,073112753
asked Nov 15 '18 at 15:34
Dhanamunichandra BhushamDhanamunichandra Bhusham
1
1
The problem is your use of quotes, but you haven't accurately shown how you're setting myvar. (I assume you're not writingmyvar=-f -e '^..., since that would try to run a command named-eand you would probably get an error of the form `-e: command not found.). Edit your question to show your code.
– William Pursell
Nov 15 '18 at 15:51
I suspect you just need to omit the single quotes around each term in the assignment of myvar, but it's difficult to say without more detail.
– William Pursell
Nov 15 '18 at 15:52
Trymyvar='-F -e ^"123"^ -e ^"456"^'
– William Pursell
Nov 15 '18 at 15:57
If you are using bash, consider using bash arrays:myvar=( -F -e '^"123"^' )andgrep ${myvar[@]}
– Samuel Kirschner
Nov 15 '18 at 15:58
Thanks William Pursell for your suggestion to omit single quotes around the id. I wonder how this is working in shell script and not working when I run that grep command in command prompt. Please explain.
– Dhanamunichandra Bhusham
Nov 18 '18 at 16:01
add a comment |
The problem is your use of quotes, but you haven't accurately shown how you're setting myvar. (I assume you're not writingmyvar=-f -e '^..., since that would try to run a command named-eand you would probably get an error of the form `-e: command not found.). Edit your question to show your code.
– William Pursell
Nov 15 '18 at 15:51
I suspect you just need to omit the single quotes around each term in the assignment of myvar, but it's difficult to say without more detail.
– William Pursell
Nov 15 '18 at 15:52
Trymyvar='-F -e ^"123"^ -e ^"456"^'
– William Pursell
Nov 15 '18 at 15:57
If you are using bash, consider using bash arrays:myvar=( -F -e '^"123"^' )andgrep ${myvar[@]}
– Samuel Kirschner
Nov 15 '18 at 15:58
Thanks William Pursell for your suggestion to omit single quotes around the id. I wonder how this is working in shell script and not working when I run that grep command in command prompt. Please explain.
– Dhanamunichandra Bhusham
Nov 18 '18 at 16:01
The problem is your use of quotes, but you haven't accurately shown how you're setting myvar. (I assume you're not writing
myvar=-f -e '^..., since that would try to run a command named -e and you would probably get an error of the form `-e: command not found.). Edit your question to show your code.– William Pursell
Nov 15 '18 at 15:51
The problem is your use of quotes, but you haven't accurately shown how you're setting myvar. (I assume you're not writing
myvar=-f -e '^..., since that would try to run a command named -e and you would probably get an error of the form `-e: command not found.). Edit your question to show your code.– William Pursell
Nov 15 '18 at 15:51
I suspect you just need to omit the single quotes around each term in the assignment of myvar, but it's difficult to say without more detail.
– William Pursell
Nov 15 '18 at 15:52
I suspect you just need to omit the single quotes around each term in the assignment of myvar, but it's difficult to say without more detail.
– William Pursell
Nov 15 '18 at 15:52
Try
myvar='-F -e ^"123"^ -e ^"456"^'– William Pursell
Nov 15 '18 at 15:57
Try
myvar='-F -e ^"123"^ -e ^"456"^'– William Pursell
Nov 15 '18 at 15:57
If you are using bash, consider using bash arrays:
myvar=( -F -e '^"123"^' ) and grep ${myvar[@]}– Samuel Kirschner
Nov 15 '18 at 15:58
If you are using bash, consider using bash arrays:
myvar=( -F -e '^"123"^' ) and grep ${myvar[@]}– Samuel Kirschner
Nov 15 '18 at 15:58
Thanks William Pursell for your suggestion to omit single quotes around the id. I wonder how this is working in shell script and not working when I run that grep command in command prompt. Please explain.
– Dhanamunichandra Bhusham
Nov 18 '18 at 16:01
Thanks William Pursell for your suggestion to omit single quotes around the id. I wonder how this is working in shell script and not working when I run that grep command in command prompt. Please explain.
– Dhanamunichandra Bhusham
Nov 18 '18 at 16:01
add a comment |
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The problem is your use of quotes, but you haven't accurately shown how you're setting myvar. (I assume you're not writing
myvar=-f -e '^..., since that would try to run a command named-eand you would probably get an error of the form `-e: command not found.). Edit your question to show your code.– William Pursell
Nov 15 '18 at 15:51
I suspect you just need to omit the single quotes around each term in the assignment of myvar, but it's difficult to say without more detail.
– William Pursell
Nov 15 '18 at 15:52
Try
myvar='-F -e ^"123"^ -e ^"456"^'– William Pursell
Nov 15 '18 at 15:57
If you are using bash, consider using bash arrays:
myvar=( -F -e '^"123"^' )andgrep ${myvar[@]}– Samuel Kirschner
Nov 15 '18 at 15:58
Thanks William Pursell for your suggestion to omit single quotes around the id. I wonder how this is working in shell script and not working when I run that grep command in command prompt. Please explain.
– Dhanamunichandra Bhusham
Nov 18 '18 at 16:01