Merging multiple data frames by pasting alternative rows
0
I have spatial weather data of UK in Ascii text format for 7 years (each file/dataframe have monthly data of one year - 12 columns and 52201 rows as each row represents one location).
I want to merge data frames with alternative rows - 1st row of data frame 1 then 1st row of data frame 2 till 1st row of data frame 7 then 2nd row of data frame 1 till 2nd row of data frame 7 and continue ....
V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11 V12
-1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199
-1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299
-1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399
-9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999
-9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999
Here is my code:
n1<-read.table("data/y1call.txt", sep="")
n2<-read.table("data/y2call.txt", sep="")
n3<-read.table("data/y3call.txt", sep="")
c<-rbind(n1,n2,n3)
merge(n1,n2,n3)
I have tried merge, rbind, cbind but all failed.
r dataframe merge rbind cbind
edited Nov 14 '18 at 13:02
Sotos
30.7k51641
asked Nov 14 '18 at 12:43
NaveedNaveed
83
add a comment |
0
I have spatial weather data of UK in Ascii text format for 7 years (each file/dataframe have monthly data of one year - 12 columns and 52201 rows as each row represents one location).
I want to merge data frames with alternative rows - 1st row of data frame 1 then 1st row of data frame 2 till 1st row of data frame 7 then 2nd row of data frame 1 till 2nd row of data frame 7 and continue ....
V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11 V12
-1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199
-1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299
-1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399
-9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999
-9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999
Here is my code:
n1<-read.table("data/y1call.txt", sep="")
n2<-read.table("data/y2call.txt", sep="")
n3<-read.table("data/y3call.txt", sep="")
c<-rbind(n1,n2,n3)
merge(n1,n2,n3)
I have tried merge, rbind, cbind but all failed.
r dataframe merge rbind cbind
edited Nov 14 '18 at 13:02
Sotos
30.7k51641
asked Nov 14 '18 at 12:43
NaveedNaveed
83
add a comment |
0
0
0
I have spatial weather data of UK in Ascii text format for 7 years (each file/dataframe have monthly data of one year - 12 columns and 52201 rows as each row represents one location).
I want to merge data frames with alternative rows - 1st row of data frame 1 then 1st row of data frame 2 till 1st row of data frame 7 then 2nd row of data frame 1 till 2nd row of data frame 7 and continue ....
V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11 V12
-1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199
-1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299
-1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399
-9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999
-9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999
Here is my code:
n1<-read.table("data/y1call.txt", sep="")
n2<-read.table("data/y2call.txt", sep="")
n3<-read.table("data/y3call.txt", sep="")
c<-rbind(n1,n2,n3)
merge(n1,n2,n3)
I have tried merge, rbind, cbind but all failed.
r dataframe merge rbind cbind
edited Nov 14 '18 at 13:02
Sotos
30.7k51641
asked Nov 14 '18 at 12:43
NaveedNaveed
83
I have spatial weather data of UK in Ascii text format for 7 years (each file/dataframe have monthly data of one year - 12 columns and 52201 rows as each row represents one location).
I want to merge data frames with alternative rows - 1st row of data frame 1 then 1st row of data frame 2 till 1st row of data frame 7 then 2nd row of data frame 1 till 2nd row of data frame 7 and continue ....
V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11 V12
-1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199 -1199
-1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299 -1299
-1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399 -1399
-9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999
-9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999 -9999
Here is my code:
n1<-read.table("data/y1call.txt", sep="")
n2<-read.table("data/y2call.txt", sep="")
n3<-read.table("data/y3call.txt", sep="")
c<-rbind(n1,n2,n3)
merge(n1,n2,n3)
I have tried merge, rbind, cbind but all failed.
r dataframe merge rbind cbind
r dataframe merge rbind cbind
edited Nov 14 '18 at 13:02
Sotos
30.7k51641
asked Nov 14 '18 at 12:43
NaveedNaveed
83
edited Nov 14 '18 at 13:02
Sotos
30.7k51641
asked Nov 14 '18 at 12:43
NaveedNaveed
83
edited Nov 14 '18 at 13:02
Sotos
30.7k51641
edited Nov 14 '18 at 13:02
Sotos
30.7k51641
edited Nov 14 '18 at 13:02
Sotos
30.7k51641
30.7k51641
asked Nov 14 '18 at 12:43
NaveedNaveed
83
asked Nov 14 '18 at 12:43
NaveedNaveed
83
asked Nov 14 '18 at 12:43
NaveedNaveed
83
83
add a comment |
add a comment |
1 Answer
1
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oldest
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0
You can create a new column representing the rownames in each data frame, and sort on that variable after you rbind, i.e.
ddf_all <- do.call(rbind, lapply(list(df1, df2, df3), function(i)transform(i, new = rownames(i))))
ddf_all[order(ddf_all$new),]
which gives,
v1 v2 new
1 1 6 1
6 11 16 1
11 21 26 1
2 2 7 2
7 12 17 2
12 22 27 2
3 3 8 3
8 13 18 3
13 23 28 3
4 4 9 4
9 14 19 4
14 24 29 4
5 5 10 5
10 15 20 5
15 25 30 5
DATA:
df1 <- data.frame(v1 = c(1, 2, 3, 4, 5), V2 = c(6, 7, 8, 9, 10))
df2 <- data.frame(v1 = c(11, 12, 13, 14, 15), v2 = c(16, 17, 18, 19, 20))
df3 <- data.frame(v1 = c(21, 22, 23, 24, 25), v2 = c(26, 27, 28, 29, 30))
answered Nov 14 '18 at 13:01
SotosSotos
30.7k51641
Dear Sotos, Thanks for your input and its working well but it's still there is some unexpected change. As the row sequence/order should be 1,6,11 and then 2,7,12 and so on but here in my case it is 1,6,11 but no 2,7,12 and something different order. Do you know why this can happen or any other solution?
– Naveed
Nov 15 '18 at 14:42
I wouldn't know until I see an example that fails. I don't see anything flawed in the workflow. Are the individual data frames ordered? Do you need to order them individually before throwing them into a list?
– Sotos
Nov 15 '18 at 14:51
n1<-read.table("data/y1call.txt", sep="")n2<-read.table("data/y2call.txt", sep="")n3<-read.table("data/y3call.txt", sep="")ddf_all<-do.call(rbind,lapply(list(n1,n2,n3), function(i)transform(i,new=rownames(i))))change<- ddf_all[order(ddf_all$new),]
– Naveed
Nov 15 '18 at 15:17
Well, that does not help me. I do not have the filesdata/y1call.txt, ... :)
– Sotos
Nov 15 '18 at 15:19
Can I get your email to send files and the code? Thanks
– Naveed
Nov 15 '18 at 15:23
|
show 3 more comments
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You can create a new column representing the rownames in each data frame, and sort on that variable after you rbind, i.e.
ddf_all <- do.call(rbind, lapply(list(df1, df2, df3), function(i)transform(i, new = rownames(i))))
ddf_all[order(ddf_all$new),]
which gives,
v1 v2 new
1 1 6 1
6 11 16 1
11 21 26 1
2 2 7 2
7 12 17 2
12 22 27 2
3 3 8 3
8 13 18 3
13 23 28 3
4 4 9 4
9 14 19 4
14 24 29 4
5 5 10 5
10 15 20 5
15 25 30 5
DATA:
df1 <- data.frame(v1 = c(1, 2, 3, 4, 5), V2 = c(6, 7, 8, 9, 10))
df2 <- data.frame(v1 = c(11, 12, 13, 14, 15), v2 = c(16, 17, 18, 19, 20))
df3 <- data.frame(v1 = c(21, 22, 23, 24, 25), v2 = c(26, 27, 28, 29, 30))
answered Nov 14 '18 at 13:01
SotosSotos
30.7k51641
Dear Sotos, Thanks for your input and its working well but it's still there is some unexpected change. As the row sequence/order should be 1,6,11 and then 2,7,12 and so on but here in my case it is 1,6,11 but no 2,7,12 and something different order. Do you know why this can happen or any other solution?
– Naveed
Nov 15 '18 at 14:42
I wouldn't know until I see an example that fails. I don't see anything flawed in the workflow. Are the individual data frames ordered? Do you need to order them individually before throwing them into a list?
– Sotos
Nov 15 '18 at 14:51
n1<-read.table("data/y1call.txt", sep="")n2<-read.table("data/y2call.txt", sep="")n3<-read.table("data/y3call.txt", sep="")ddf_all<-do.call(rbind,lapply(list(n1,n2,n3), function(i)transform(i,new=rownames(i))))change<- ddf_all[order(ddf_all$new),]
– Naveed
Nov 15 '18 at 15:17
Well, that does not help me. I do not have the filesdata/y1call.txt, ... :)
– Sotos
Nov 15 '18 at 15:19
Can I get your email to send files and the code? Thanks
– Naveed
Nov 15 '18 at 15:23
|
show 3 more comments
0
You can create a new column representing the rownames in each data frame, and sort on that variable after you rbind, i.e.
ddf_all <- do.call(rbind, lapply(list(df1, df2, df3), function(i)transform(i, new = rownames(i))))
ddf_all[order(ddf_all$new),]
which gives,
v1 v2 new
1 1 6 1
6 11 16 1
11 21 26 1
2 2 7 2
7 12 17 2
12 22 27 2
3 3 8 3
8 13 18 3
13 23 28 3
4 4 9 4
9 14 19 4
14 24 29 4
5 5 10 5
10 15 20 5
15 25 30 5
DATA:
df1 <- data.frame(v1 = c(1, 2, 3, 4, 5), V2 = c(6, 7, 8, 9, 10))
df2 <- data.frame(v1 = c(11, 12, 13, 14, 15), v2 = c(16, 17, 18, 19, 20))
df3 <- data.frame(v1 = c(21, 22, 23, 24, 25), v2 = c(26, 27, 28, 29, 30))
answered Nov 14 '18 at 13:01
SotosSotos
30.7k51641
Dear Sotos, Thanks for your input and its working well but it's still there is some unexpected change. As the row sequence/order should be 1,6,11 and then 2,7,12 and so on but here in my case it is 1,6,11 but no 2,7,12 and something different order. Do you know why this can happen or any other solution?
– Naveed
Nov 15 '18 at 14:42
I wouldn't know until I see an example that fails. I don't see anything flawed in the workflow. Are the individual data frames ordered? Do you need to order them individually before throwing them into a list?
– Sotos
Nov 15 '18 at 14:51
n1<-read.table("data/y1call.txt", sep="")n2<-read.table("data/y2call.txt", sep="")n3<-read.table("data/y3call.txt", sep="")ddf_all<-do.call(rbind,lapply(list(n1,n2,n3), function(i)transform(i,new=rownames(i))))change<- ddf_all[order(ddf_all$new),]
– Naveed
Nov 15 '18 at 15:17
Well, that does not help me. I do not have the filesdata/y1call.txt, ... :)
– Sotos
Nov 15 '18 at 15:19
Can I get your email to send files and the code? Thanks
– Naveed
Nov 15 '18 at 15:23
|
show 3 more comments
0
0
0
You can create a new column representing the rownames in each data frame, and sort on that variable after you rbind, i.e.
ddf_all <- do.call(rbind, lapply(list(df1, df2, df3), function(i)transform(i, new = rownames(i))))
ddf_all[order(ddf_all$new),]
which gives,
v1 v2 new
1 1 6 1
6 11 16 1
11 21 26 1
2 2 7 2
7 12 17 2
12 22 27 2
3 3 8 3
8 13 18 3
13 23 28 3
4 4 9 4
9 14 19 4
14 24 29 4
5 5 10 5
10 15 20 5
15 25 30 5
DATA:
df1 <- data.frame(v1 = c(1, 2, 3, 4, 5), V2 = c(6, 7, 8, 9, 10))
df2 <- data.frame(v1 = c(11, 12, 13, 14, 15), v2 = c(16, 17, 18, 19, 20))
df3 <- data.frame(v1 = c(21, 22, 23, 24, 25), v2 = c(26, 27, 28, 29, 30))
answered Nov 14 '18 at 13:01
SotosSotos
30.7k51641
You can create a new column representing the rownames in each data frame, and sort on that variable after you rbind, i.e.
ddf_all <- do.call(rbind, lapply(list(df1, df2, df3), function(i)transform(i, new = rownames(i))))
ddf_all[order(ddf_all$new),]
which gives,
v1 v2 new
1 1 6 1
6 11 16 1
11 21 26 1
2 2 7 2
7 12 17 2
12 22 27 2
3 3 8 3
8 13 18 3
13 23 28 3
4 4 9 4
9 14 19 4
14 24 29 4
5 5 10 5
10 15 20 5
15 25 30 5
DATA:
df1 <- data.frame(v1 = c(1, 2, 3, 4, 5), V2 = c(6, 7, 8, 9, 10))
df2 <- data.frame(v1 = c(11, 12, 13, 14, 15), v2 = c(16, 17, 18, 19, 20))
df3 <- data.frame(v1 = c(21, 22, 23, 24, 25), v2 = c(26, 27, 28, 29, 30))
answered Nov 14 '18 at 13:01
SotosSotos
30.7k51641
answered Nov 14 '18 at 13:01
SotosSotos
30.7k51641
answered Nov 14 '18 at 13:01
SotosSotos
30.7k51641
answered Nov 14 '18 at 13:01
SotosSotos
30.7k51641
30.7k51641
Dear Sotos, Thanks for your input and its working well but it's still there is some unexpected change. As the row sequence/order should be 1,6,11 and then 2,7,12 and so on but here in my case it is 1,6,11 but no 2,7,12 and something different order. Do you know why this can happen or any other solution?
– Naveed
Nov 15 '18 at 14:42
I wouldn't know until I see an example that fails. I don't see anything flawed in the workflow. Are the individual data frames ordered? Do you need to order them individually before throwing them into a list?
– Sotos
Nov 15 '18 at 14:51
n1<-read.table("data/y1call.txt", sep="")n2<-read.table("data/y2call.txt", sep="")n3<-read.table("data/y3call.txt", sep="")ddf_all<-do.call(rbind,lapply(list(n1,n2,n3), function(i)transform(i,new=rownames(i))))change<- ddf_all[order(ddf_all$new),]
– Naveed
Nov 15 '18 at 15:17
Well, that does not help me. I do not have the filesdata/y1call.txt, ... :)
– Sotos
Nov 15 '18 at 15:19
Can I get your email to send files and the code? Thanks
– Naveed
Nov 15 '18 at 15:23
|
show 3 more comments
Dear Sotos, Thanks for your input and its working well but it's still there is some unexpected change. As the row sequence/order should be 1,6,11 and then 2,7,12 and so on but here in my case it is 1,6,11 but no 2,7,12 and something different order. Do you know why this can happen or any other solution?
– Naveed
Nov 15 '18 at 14:42
I wouldn't know until I see an example that fails. I don't see anything flawed in the workflow. Are the individual data frames ordered? Do you need to order them individually before throwing them into a list?
– Sotos
Nov 15 '18 at 14:51
n1<-read.table("data/y1call.txt", sep="")n2<-read.table("data/y2call.txt", sep="")n3<-read.table("data/y3call.txt", sep="")ddf_all<-do.call(rbind,lapply(list(n1,n2,n3), function(i)transform(i,new=rownames(i))))change<- ddf_all[order(ddf_all$new),]
– Naveed
Nov 15 '18 at 15:17
Well, that does not help me. I do not have the filesdata/y1call.txt, ... :)
– Sotos
Nov 15 '18 at 15:19
Can I get your email to send files and the code? Thanks
– Naveed
Nov 15 '18 at 15:23
Dear Sotos, Thanks for your input and its working well but it's still there is some unexpected change. As the row sequence/order should be 1,6,11 and then 2,7,12 and so on but here in my case it is 1,6,11 but no 2,7,12 and something different order. Do you know why this can happen or any other solution?
– Naveed
Nov 15 '18 at 14:42
Dear Sotos, Thanks for your input and its working well but it's still there is some unexpected change. As the row sequence/order should be 1,6,11 and then 2,7,12 and so on but here in my case it is 1,6,11 but no 2,7,12 and something different order. Do you know why this can happen or any other solution?
– Naveed
Nov 15 '18 at 14:42
I wouldn't know until I see an example that fails. I don't see anything flawed in the workflow. Are the individual data frames ordered? Do you need to order them individually before throwing them into a list?
– Sotos
Nov 15 '18 at 14:51
I wouldn't know until I see an example that fails. I don't see anything flawed in the workflow. Are the individual data frames ordered? Do you need to order them individually before throwing them into a list?
– Sotos
Nov 15 '18 at 14:51
n1<-read.table("data/y1call.txt", sep="") n2<-read.table("data/y2call.txt", sep="") n3<-read.table("data/y3call.txt", sep="") ddf_all<-do.call(rbind,lapply(list(n1,n2,n3), function(i)transform(i,new=rownames(i)))) change<- ddf_all[order(ddf_all$new),]– Naveed
Nov 15 '18 at 15:17
n1<-read.table("data/y1call.txt", sep="") n2<-read.table("data/y2call.txt", sep="") n3<-read.table("data/y3call.txt", sep="") ddf_all<-do.call(rbind,lapply(list(n1,n2,n3), function(i)transform(i,new=rownames(i)))) change<- ddf_all[order(ddf_all$new),]– Naveed
Nov 15 '18 at 15:17
Well, that does not help me. I do not have the files
data/y1call.txt, ... :)– Sotos
Nov 15 '18 at 15:19
Well, that does not help me. I do not have the files
data/y1call.txt, ... :)– Sotos
Nov 15 '18 at 15:19
Can I get your email to send files and the code? Thanks
– Naveed
Nov 15 '18 at 15:23
Can I get your email to send files and the code? Thanks
– Naveed
Nov 15 '18 at 15:23
|
show 3 more comments
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