Sed to regex column names












0















I have a SQL logfile with lots of SELECT statements with lots of columns. I want to replace the column names with *.



So



want to change SELECT T.A, T.B, T.B, T.C FROM TABLE T to SELECT T.* FROM TABLE T



so I can to



s/T.[A-Z_]*//g


will get T. column names and replace them with nothing.



s/T.[A-Z_]*/T.*/g


Will do...



SELECT T.*, T.*, T.*, T.*


instead of



SELECT T.*


So how do I capture everything between the SELECT AND FROM and then replace it with T.*?



Thanks










share|improve this question























  • Try sed 's/<T.*( FROM)/T.*1/g', see demo.

    – Wiktor Stribiżew
    Nov 15 '18 at 15:41


















0















I have a SQL logfile with lots of SELECT statements with lots of columns. I want to replace the column names with *.



So



want to change SELECT T.A, T.B, T.B, T.C FROM TABLE T to SELECT T.* FROM TABLE T



so I can to



s/T.[A-Z_]*//g


will get T. column names and replace them with nothing.



s/T.[A-Z_]*/T.*/g


Will do...



SELECT T.*, T.*, T.*, T.*


instead of



SELECT T.*


So how do I capture everything between the SELECT AND FROM and then replace it with T.*?



Thanks










share|improve this question























  • Try sed 's/<T.*( FROM)/T.*1/g', see demo.

    – Wiktor Stribiżew
    Nov 15 '18 at 15:41
















0












0








0








I have a SQL logfile with lots of SELECT statements with lots of columns. I want to replace the column names with *.



So



want to change SELECT T.A, T.B, T.B, T.C FROM TABLE T to SELECT T.* FROM TABLE T



so I can to



s/T.[A-Z_]*//g


will get T. column names and replace them with nothing.



s/T.[A-Z_]*/T.*/g


Will do...



SELECT T.*, T.*, T.*, T.*


instead of



SELECT T.*


So how do I capture everything between the SELECT AND FROM and then replace it with T.*?



Thanks










share|improve this question














I have a SQL logfile with lots of SELECT statements with lots of columns. I want to replace the column names with *.



So



want to change SELECT T.A, T.B, T.B, T.C FROM TABLE T to SELECT T.* FROM TABLE T



so I can to



s/T.[A-Z_]*//g


will get T. column names and replace them with nothing.



s/T.[A-Z_]*/T.*/g


Will do...



SELECT T.*, T.*, T.*, T.*


instead of



SELECT T.*


So how do I capture everything between the SELECT AND FROM and then replace it with T.*?



Thanks







regex sed






share|improve this question













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asked Nov 15 '18 at 15:38









More Than FiveMore Than Five

3,126105188




3,126105188













  • Try sed 's/<T.*( FROM)/T.*1/g', see demo.

    – Wiktor Stribiżew
    Nov 15 '18 at 15:41





















  • Try sed 's/<T.*( FROM)/T.*1/g', see demo.

    – Wiktor Stribiżew
    Nov 15 '18 at 15:41



















Try sed 's/<T.*( FROM)/T.*1/g', see demo.

– Wiktor Stribiżew
Nov 15 '18 at 15:41







Try sed 's/<T.*( FROM)/T.*1/g', see demo.

– Wiktor Stribiżew
Nov 15 '18 at 15:41














2 Answers
2






active

oldest

votes


















0














You could maybe try:



sed 's/ ([A-Z].).*(FROM.*)/ 1* 2/g'


Output:



SELECT T.* FROM TABLE T





share|improve this answer































    0














    A better approach would be using a placeholder for an alias if it is possible for an alias to be something different than letter T:



    sed -r 's/([[:alnum:]_]+).[^ ,]+(, *1.[^ ,]+)+/1.*/g' file





    share|improve this answer























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

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      active

      oldest

      votes









      0














      You could maybe try:



      sed 's/ ([A-Z].).*(FROM.*)/ 1* 2/g'


      Output:



      SELECT T.* FROM TABLE T





      share|improve this answer




























        0














        You could maybe try:



        sed 's/ ([A-Z].).*(FROM.*)/ 1* 2/g'


        Output:



        SELECT T.* FROM TABLE T





        share|improve this answer


























          0












          0








          0







          You could maybe try:



          sed 's/ ([A-Z].).*(FROM.*)/ 1* 2/g'


          Output:



          SELECT T.* FROM TABLE T





          share|improve this answer













          You could maybe try:



          sed 's/ ([A-Z].).*(FROM.*)/ 1* 2/g'


          Output:



          SELECT T.* FROM TABLE T






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 15 '18 at 15:52









          l'L'll'L'l

          31k55096




          31k55096

























              0














              A better approach would be using a placeholder for an alias if it is possible for an alias to be something different than letter T:



              sed -r 's/([[:alnum:]_]+).[^ ,]+(, *1.[^ ,]+)+/1.*/g' file





              share|improve this answer




























                0














                A better approach would be using a placeholder for an alias if it is possible for an alias to be something different than letter T:



                sed -r 's/([[:alnum:]_]+).[^ ,]+(, *1.[^ ,]+)+/1.*/g' file





                share|improve this answer


























                  0












                  0








                  0







                  A better approach would be using a placeholder for an alias if it is possible for an alias to be something different than letter T:



                  sed -r 's/([[:alnum:]_]+).[^ ,]+(, *1.[^ ,]+)+/1.*/g' file





                  share|improve this answer













                  A better approach would be using a placeholder for an alias if it is possible for an alias to be something different than letter T:



                  sed -r 's/([[:alnum:]_]+).[^ ,]+(, *1.[^ ,]+)+/1.*/g' file






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 15 '18 at 20:33









                  revorevo

                  33.6k135086




                  33.6k135086






























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