Creating a zip arhcive in NodeJS
0
i am new to Node.JS and i want to do search in a folder for a specific string and add all the files that are found in a zip archive.
Example : I have the string "house" and in a folder i have house_1.txt house_2.txt and car.The archive must contain house_1.txt , house_2.txt. I searched something on Google but i couldn't do it .
node.js zip
asked Nov 15 '18 at 10:26
Chirica AndreiChirica Andrei
158
add a comment |
0
i am new to Node.JS and i want to do search in a folder for a specific string and add all the files that are found in a zip archive.
Example : I have the string "house" and in a folder i have house_1.txt house_2.txt and car.The archive must contain house_1.txt , house_2.txt. I searched something on Google but i couldn't do it .
node.js zip
asked Nov 15 '18 at 10:26
Chirica AndreiChirica Andrei
158
Can you please paste the code what you have tried so far? Also tell us at which step you get stucked. Please also explain which version ofnodejsdo you use and what framework if any.
– lependu
Nov 15 '18 at 10:31
no framework, version 8.12.0.Basically now i only return house.txt if exist . I don't know how to search file names to caontain house.Sorry if i didn;t explained very good.
– Chirica Andrei
Nov 15 '18 at 10:44
add a comment |
0
0
0
i am new to Node.JS and i want to do search in a folder for a specific string and add all the files that are found in a zip archive.
Example : I have the string "house" and in a folder i have house_1.txt house_2.txt and car.The archive must contain house_1.txt , house_2.txt. I searched something on Google but i couldn't do it .
node.js zip
asked Nov 15 '18 at 10:26
Chirica AndreiChirica Andrei
158
i am new to Node.JS and i want to do search in a folder for a specific string and add all the files that are found in a zip archive.
Example : I have the string "house" and in a folder i have house_1.txt house_2.txt and car.The archive must contain house_1.txt , house_2.txt. I searched something on Google but i couldn't do it .
node.js zip
node.js zip
asked Nov 15 '18 at 10:26
Chirica AndreiChirica Andrei
158
asked Nov 15 '18 at 10:26
Chirica AndreiChirica Andrei
158
asked Nov 15 '18 at 10:26
Chirica AndreiChirica Andrei
158
asked Nov 15 '18 at 10:26
Chirica AndreiChirica Andrei
158
asked Nov 15 '18 at 10:26
Chirica AndreiChirica Andrei
158
158
Can you please paste the code what you have tried so far? Also tell us at which step you get stucked. Please also explain which version ofnodejsdo you use and what framework if any.
– lependu
Nov 15 '18 at 10:31
no framework, version 8.12.0.Basically now i only return house.txt if exist . I don't know how to search file names to caontain house.Sorry if i didn;t explained very good.
– Chirica Andrei
Nov 15 '18 at 10:44
add a comment |
Can you please paste the code what you have tried so far? Also tell us at which step you get stucked. Please also explain which version ofnodejsdo you use and what framework if any.
– lependu
Nov 15 '18 at 10:31
no framework, version 8.12.0.Basically now i only return house.txt if exist . I don't know how to search file names to caontain house.Sorry if i didn;t explained very good.
– Chirica Andrei
Nov 15 '18 at 10:44
Can you please paste the code what you have tried so far? Also tell us at which step you get stucked. Please also explain which version of
nodejs do you use and what framework if any.– lependu
Nov 15 '18 at 10:31
Can you please paste the code what you have tried so far? Also tell us at which step you get stucked. Please also explain which version of
nodejs do you use and what framework if any.– lependu
Nov 15 '18 at 10:31
no framework, version 8.12.0.Basically now i only return house.txt if exist . I don't know how to search file names to caontain house.Sorry if i didn;t explained very good.
– Chirica Andrei
Nov 15 '18 at 10:44
no framework, version 8.12.0.Basically now i only return house.txt if exist . I don't know how to search file names to caontain house.Sorry if i didn;t explained very good.
– Chirica Andrei
Nov 15 '18 at 10:44
add a comment |
1 Answer
1
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oldest
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0
This code doesn't pretend to be super fast, since it is synchronous, but it works.
const JSZip = require("jszip");
const path = require('path');
const fs = require('fs');
const isDirectory = (filePath) => fs.statSync(filePath).isDirectory();
const findFiles = (dir, fileNames, recursive = false) => {
const foundFiles = ;
fs.readdirSync(dir).forEach(file => {
const filePath = path.join(dir, file);
if(recursive && isDirectory(filePath)) {
foundFiles.push(...findFiles(filePath, fileNames, true));
} else if(fileNames.includes(file)){
foundFiles.push(filePath);
}
});
return foundFiles;
};
const getFileName = filePath => filePath.indexOf("/") !== -1 ?
filePath.substr(filePath.lastIndexOf("/")) : filePath;
const zipFiles = (filePaths, zipPath) => {
const zip = new JSZip();
filePaths.forEach(filePath => {
const fileName = getFileName(filePath) + "_" + Date.now();
const content = fs.readFileSync(filePath);
zip.file(fileName, content);
});
zip.generateNodeStream({type: 'nodebuffer', streamFiles: true})
.pipe(fs.createWriteStream(zipPath))
.on('finish', () => console.log(`${zipPath} has been created.`));
};
const filesDir = `${__dirname}/../resources`;
zipFiles(findFiles(filesDir, ["test1.txt"], true), `${filesDir}/out.zip`);
answered Nov 15 '18 at 13:46
Dmitrii PetrovDmitrii Petrov
383
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
This code doesn't pretend to be super fast, since it is synchronous, but it works.
const JSZip = require("jszip");
const path = require('path');
const fs = require('fs');
const isDirectory = (filePath) => fs.statSync(filePath).isDirectory();
const findFiles = (dir, fileNames, recursive = false) => {
const foundFiles = ;
fs.readdirSync(dir).forEach(file => {
const filePath = path.join(dir, file);
if(recursive && isDirectory(filePath)) {
foundFiles.push(...findFiles(filePath, fileNames, true));
} else if(fileNames.includes(file)){
foundFiles.push(filePath);
}
});
return foundFiles;
};
const getFileName = filePath => filePath.indexOf("/") !== -1 ?
filePath.substr(filePath.lastIndexOf("/")) : filePath;
const zipFiles = (filePaths, zipPath) => {
const zip = new JSZip();
filePaths.forEach(filePath => {
const fileName = getFileName(filePath) + "_" + Date.now();
const content = fs.readFileSync(filePath);
zip.file(fileName, content);
});
zip.generateNodeStream({type: 'nodebuffer', streamFiles: true})
.pipe(fs.createWriteStream(zipPath))
.on('finish', () => console.log(`${zipPath} has been created.`));
};
const filesDir = `${__dirname}/../resources`;
zipFiles(findFiles(filesDir, ["test1.txt"], true), `${filesDir}/out.zip`);
answered Nov 15 '18 at 13:46
Dmitrii PetrovDmitrii Petrov
383
add a comment |
0
This code doesn't pretend to be super fast, since it is synchronous, but it works.
const JSZip = require("jszip");
const path = require('path');
const fs = require('fs');
const isDirectory = (filePath) => fs.statSync(filePath).isDirectory();
const findFiles = (dir, fileNames, recursive = false) => {
const foundFiles = ;
fs.readdirSync(dir).forEach(file => {
const filePath = path.join(dir, file);
if(recursive && isDirectory(filePath)) {
foundFiles.push(...findFiles(filePath, fileNames, true));
} else if(fileNames.includes(file)){
foundFiles.push(filePath);
}
});
return foundFiles;
};
const getFileName = filePath => filePath.indexOf("/") !== -1 ?
filePath.substr(filePath.lastIndexOf("/")) : filePath;
const zipFiles = (filePaths, zipPath) => {
const zip = new JSZip();
filePaths.forEach(filePath => {
const fileName = getFileName(filePath) + "_" + Date.now();
const content = fs.readFileSync(filePath);
zip.file(fileName, content);
});
zip.generateNodeStream({type: 'nodebuffer', streamFiles: true})
.pipe(fs.createWriteStream(zipPath))
.on('finish', () => console.log(`${zipPath} has been created.`));
};
const filesDir = `${__dirname}/../resources`;
zipFiles(findFiles(filesDir, ["test1.txt"], true), `${filesDir}/out.zip`);
answered Nov 15 '18 at 13:46
Dmitrii PetrovDmitrii Petrov
383
add a comment |
0
0
0
This code doesn't pretend to be super fast, since it is synchronous, but it works.
const JSZip = require("jszip");
const path = require('path');
const fs = require('fs');
const isDirectory = (filePath) => fs.statSync(filePath).isDirectory();
const findFiles = (dir, fileNames, recursive = false) => {
const foundFiles = ;
fs.readdirSync(dir).forEach(file => {
const filePath = path.join(dir, file);
if(recursive && isDirectory(filePath)) {
foundFiles.push(...findFiles(filePath, fileNames, true));
} else if(fileNames.includes(file)){
foundFiles.push(filePath);
}
});
return foundFiles;
};
const getFileName = filePath => filePath.indexOf("/") !== -1 ?
filePath.substr(filePath.lastIndexOf("/")) : filePath;
const zipFiles = (filePaths, zipPath) => {
const zip = new JSZip();
filePaths.forEach(filePath => {
const fileName = getFileName(filePath) + "_" + Date.now();
const content = fs.readFileSync(filePath);
zip.file(fileName, content);
});
zip.generateNodeStream({type: 'nodebuffer', streamFiles: true})
.pipe(fs.createWriteStream(zipPath))
.on('finish', () => console.log(`${zipPath} has been created.`));
};
const filesDir = `${__dirname}/../resources`;
zipFiles(findFiles(filesDir, ["test1.txt"], true), `${filesDir}/out.zip`);
answered Nov 15 '18 at 13:46
Dmitrii PetrovDmitrii Petrov
383
This code doesn't pretend to be super fast, since it is synchronous, but it works.
const JSZip = require("jszip");
const path = require('path');
const fs = require('fs');
const isDirectory = (filePath) => fs.statSync(filePath).isDirectory();
const findFiles = (dir, fileNames, recursive = false) => {
const foundFiles = ;
fs.readdirSync(dir).forEach(file => {
const filePath = path.join(dir, file);
if(recursive && isDirectory(filePath)) {
foundFiles.push(...findFiles(filePath, fileNames, true));
} else if(fileNames.includes(file)){
foundFiles.push(filePath);
}
});
return foundFiles;
};
const getFileName = filePath => filePath.indexOf("/") !== -1 ?
filePath.substr(filePath.lastIndexOf("/")) : filePath;
const zipFiles = (filePaths, zipPath) => {
const zip = new JSZip();
filePaths.forEach(filePath => {
const fileName = getFileName(filePath) + "_" + Date.now();
const content = fs.readFileSync(filePath);
zip.file(fileName, content);
});
zip.generateNodeStream({type: 'nodebuffer', streamFiles: true})
.pipe(fs.createWriteStream(zipPath))
.on('finish', () => console.log(`${zipPath} has been created.`));
};
const filesDir = `${__dirname}/../resources`;
zipFiles(findFiles(filesDir, ["test1.txt"], true), `${filesDir}/out.zip`);
answered Nov 15 '18 at 13:46
Dmitrii PetrovDmitrii Petrov
383
answered Nov 15 '18 at 13:46
Dmitrii PetrovDmitrii Petrov
383
answered Nov 15 '18 at 13:46
Dmitrii PetrovDmitrii Petrov
383
answered Nov 15 '18 at 13:46
Dmitrii PetrovDmitrii Petrov
383
383
add a comment |
add a comment |
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Can you please paste the code what you have tried so far? Also tell us at which step you get stucked. Please also explain which version of
nodejsdo you use and what framework if any.– lependu
Nov 15 '18 at 10:31
no framework, version 8.12.0.Basically now i only return house.txt if exist . I don't know how to search file names to caontain house.Sorry if i didn;t explained very good.
– Chirica Andrei
Nov 15 '18 at 10:44