Dynamic Variable creation and using the Same variable in a loop in Shell
I am stuck with a Requirement but stuck in a Scenario, tried out lot of alternatives from Google but looks like not serving my Purpose.
Below is my Requirement-
tablename=$1
This is a Variable for which the value i get from the command line.
Now my requirement is i want to create a variable with the Name which i received in the variable called tablename.
And i want to use that variable in a loop further.
For Example :
Say,
tablename = dept1
Now my loop will look something like-
for dept1 in .... do
...
done
Can someone please help me with this..
bash shell
asked Nov 14 '18 at 12:29
Samrat SahaSamrat Saha
156
add a comment |
I am stuck with a Requirement but stuck in a Scenario, tried out lot of alternatives from Google but looks like not serving my Purpose.
Below is my Requirement-
tablename=$1
This is a Variable for which the value i get from the command line.
Now my requirement is i want to create a variable with the Name which i received in the variable called tablename.
And i want to use that variable in a loop further.
For Example :
Say,
tablename = dept1
Now my loop will look something like-
for dept1 in .... do
...
done
Can someone please help me with this..
bash shell
asked Nov 14 '18 at 12:29
Samrat SahaSamrat Saha
156
eval "$tablename"=""dept1 variable value""? It is unclear what your're asking. Can you please rephrase the question? Add more details? Post some code that you've tried?
– Kamil Cuk
Nov 14 '18 at 12:41
I fail to see what link you need between the value oftablenameand the name of the index variable in theforloop.
– chepner
Nov 14 '18 at 13:34
I mean to say my piece of code will be called with different different parameter values with different different tablenames concurrently at the same time.. So i want my loop variable to be of different different names for each called instances
– Samrat Saha
Nov 15 '18 at 4:49
add a comment |
I am stuck with a Requirement but stuck in a Scenario, tried out lot of alternatives from Google but looks like not serving my Purpose.
Below is my Requirement-
tablename=$1
This is a Variable for which the value i get from the command line.
Now my requirement is i want to create a variable with the Name which i received in the variable called tablename.
And i want to use that variable in a loop further.
For Example :
Say,
tablename = dept1
Now my loop will look something like-
for dept1 in .... do
...
done
Can someone please help me with this..
bash shell
asked Nov 14 '18 at 12:29
Samrat SahaSamrat Saha
156
I am stuck with a Requirement but stuck in a Scenario, tried out lot of alternatives from Google but looks like not serving my Purpose.
Below is my Requirement-
tablename=$1
This is a Variable for which the value i get from the command line.
Now my requirement is i want to create a variable with the Name which i received in the variable called tablename.
And i want to use that variable in a loop further.
For Example :
Say,
tablename = dept1
Now my loop will look something like-
for dept1 in .... do
...
done
Can someone please help me with this..
bash shell
bash shell
asked Nov 14 '18 at 12:29
Samrat SahaSamrat Saha
156
asked Nov 14 '18 at 12:29
Samrat SahaSamrat Saha
156
asked Nov 14 '18 at 12:29
Samrat SahaSamrat Saha
156
asked Nov 14 '18 at 12:29
Samrat SahaSamrat Saha
156
asked Nov 14 '18 at 12:29
Samrat SahaSamrat Saha
156
156
eval "$tablename"=""dept1 variable value""? It is unclear what your're asking. Can you please rephrase the question? Add more details? Post some code that you've tried?
– Kamil Cuk
Nov 14 '18 at 12:41
I fail to see what link you need between the value oftablenameand the name of the index variable in theforloop.
– chepner
Nov 14 '18 at 13:34
I mean to say my piece of code will be called with different different parameter values with different different tablenames concurrently at the same time.. So i want my loop variable to be of different different names for each called instances
– Samrat Saha
Nov 15 '18 at 4:49
add a comment |
eval "$tablename"=""dept1 variable value""? It is unclear what your're asking. Can you please rephrase the question? Add more details? Post some code that you've tried?
– Kamil Cuk
Nov 14 '18 at 12:41
I fail to see what link you need between the value oftablenameand the name of the index variable in theforloop.
– chepner
Nov 14 '18 at 13:34
I mean to say my piece of code will be called with different different parameter values with different different tablenames concurrently at the same time.. So i want my loop variable to be of different different names for each called instances
– Samrat Saha
Nov 15 '18 at 4:49
eval "$tablename"=""dept1 variable value"" ? It is unclear what your're asking. Can you please rephrase the question? Add more details? Post some code that you've tried?– Kamil Cuk
Nov 14 '18 at 12:41
eval "$tablename"=""dept1 variable value"" ? It is unclear what your're asking. Can you please rephrase the question? Add more details? Post some code that you've tried?– Kamil Cuk
Nov 14 '18 at 12:41
I fail to see what link you need between the value of
tablename and the name of the index variable in the for loop.– chepner
Nov 14 '18 at 13:34
I fail to see what link you need between the value of
tablename and the name of the index variable in the for loop.– chepner
Nov 14 '18 at 13:34
I mean to say my piece of code will be called with different different parameter values with different different tablenames concurrently at the same time.. So i want my loop variable to be of different different names for each called instances
– Samrat Saha
Nov 15 '18 at 4:49
I mean to say my piece of code will be called with different different parameter values with different different tablenames concurrently at the same time.. So i want my loop variable to be of different different names for each called instances
– Samrat Saha
Nov 15 '18 at 4:49
add a comment |
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eval "$tablename"=""dept1 variable value""? It is unclear what your're asking. Can you please rephrase the question? Add more details? Post some code that you've tried?– Kamil Cuk
Nov 14 '18 at 12:41
I fail to see what link you need between the value of
tablenameand the name of the index variable in theforloop.– chepner
Nov 14 '18 at 13:34
I mean to say my piece of code will be called with different different parameter values with different different tablenames concurrently at the same time.. So i want my loop variable to be of different different names for each called instances
– Samrat Saha
Nov 15 '18 at 4:49