matplotlib polar streamplot vs quiver
0
I try to plot streamline then I see wrong result.
I check streamline with quiver then I get right result.
I use same data for both. Why plots is so different?
fig = plt.figure()
axs = plt.axes(polar=True)
axs.set_theta_zero_location("N")
axs.set_theta_direction(-1)
YL, ZL = zip(*list(zip(YLr,ZLr))/np.linalg.norm(list(zip(YLr,ZLr)),axis=1, keepdims=True))
YLi = scipy.interpolate.griddata(((np.radians(a_izogn), izogn)),YL,(a_izogn_rad_i[None,:], izogn_i[:,None]),method='cubic')
ZLi = scipy.interpolate.griddata(((np.radians(a_izogn), izogn)),ZL,(a_izogn_rad_i[None,:], izogn_i[:,None]),method='cubic')
r = izogn_i
phi = a_izogn_rad_i
r, phi = np.meshgrid(r, phi)
axs.streamplot(phi.transpose(), r.transpose(),ZLi, YLi, color='red',density=1, linewidth=0.5)
axs.quiver(phi.transpose(), r.transpose(), ZLi, YLi,units='xy',scale=10., zorder=3, color='blue',width=0.007, headwidth=3., headlength=4.)
axs.set_ylim([min(izogn_i), max(izogn_i)])
fig.show();
my data:
https://cloud.mail.ru/public/HzJX/YFc1cLGGR
python matplotlib
asked Nov 13 '18 at 21:03
AlexeyAlexey
204
add a comment |
0
I try to plot streamline then I see wrong result.
I check streamline with quiver then I get right result.
I use same data for both. Why plots is so different?
fig = plt.figure()
axs = plt.axes(polar=True)
axs.set_theta_zero_location("N")
axs.set_theta_direction(-1)
YL, ZL = zip(*list(zip(YLr,ZLr))/np.linalg.norm(list(zip(YLr,ZLr)),axis=1, keepdims=True))
YLi = scipy.interpolate.griddata(((np.radians(a_izogn), izogn)),YL,(a_izogn_rad_i[None,:], izogn_i[:,None]),method='cubic')
ZLi = scipy.interpolate.griddata(((np.radians(a_izogn), izogn)),ZL,(a_izogn_rad_i[None,:], izogn_i[:,None]),method='cubic')
r = izogn_i
phi = a_izogn_rad_i
r, phi = np.meshgrid(r, phi)
axs.streamplot(phi.transpose(), r.transpose(),ZLi, YLi, color='red',density=1, linewidth=0.5)
axs.quiver(phi.transpose(), r.transpose(), ZLi, YLi,units='xy',scale=10., zorder=3, color='blue',width=0.007, headwidth=3., headlength=4.)
axs.set_ylim([min(izogn_i), max(izogn_i)])
fig.show();
my data:
https://cloud.mail.ru/public/HzJX/YFc1cLGGR
python matplotlib
asked Nov 13 '18 at 21:03
AlexeyAlexey
204
add a comment |
0
0
0
I try to plot streamline then I see wrong result.
I check streamline with quiver then I get right result.
I use same data for both. Why plots is so different?
fig = plt.figure()
axs = plt.axes(polar=True)
axs.set_theta_zero_location("N")
axs.set_theta_direction(-1)
YL, ZL = zip(*list(zip(YLr,ZLr))/np.linalg.norm(list(zip(YLr,ZLr)),axis=1, keepdims=True))
YLi = scipy.interpolate.griddata(((np.radians(a_izogn), izogn)),YL,(a_izogn_rad_i[None,:], izogn_i[:,None]),method='cubic')
ZLi = scipy.interpolate.griddata(((np.radians(a_izogn), izogn)),ZL,(a_izogn_rad_i[None,:], izogn_i[:,None]),method='cubic')
r = izogn_i
phi = a_izogn_rad_i
r, phi = np.meshgrid(r, phi)
axs.streamplot(phi.transpose(), r.transpose(),ZLi, YLi, color='red',density=1, linewidth=0.5)
axs.quiver(phi.transpose(), r.transpose(), ZLi, YLi,units='xy',scale=10., zorder=3, color='blue',width=0.007, headwidth=3., headlength=4.)
axs.set_ylim([min(izogn_i), max(izogn_i)])
fig.show();
my data:
https://cloud.mail.ru/public/HzJX/YFc1cLGGR
python matplotlib
asked Nov 13 '18 at 21:03
AlexeyAlexey
204
I try to plot streamline then I see wrong result.
I check streamline with quiver then I get right result.
I use same data for both. Why plots is so different?
fig = plt.figure()
axs = plt.axes(polar=True)
axs.set_theta_zero_location("N")
axs.set_theta_direction(-1)
YL, ZL = zip(*list(zip(YLr,ZLr))/np.linalg.norm(list(zip(YLr,ZLr)),axis=1, keepdims=True))
YLi = scipy.interpolate.griddata(((np.radians(a_izogn), izogn)),YL,(a_izogn_rad_i[None,:], izogn_i[:,None]),method='cubic')
ZLi = scipy.interpolate.griddata(((np.radians(a_izogn), izogn)),ZL,(a_izogn_rad_i[None,:], izogn_i[:,None]),method='cubic')
r = izogn_i
phi = a_izogn_rad_i
r, phi = np.meshgrid(r, phi)
axs.streamplot(phi.transpose(), r.transpose(),ZLi, YLi, color='red',density=1, linewidth=0.5)
axs.quiver(phi.transpose(), r.transpose(), ZLi, YLi,units='xy',scale=10., zorder=3, color='blue',width=0.007, headwidth=3., headlength=4.)
axs.set_ylim([min(izogn_i), max(izogn_i)])
fig.show();
my data:
https://cloud.mail.ru/public/HzJX/YFc1cLGGR
python matplotlib
python matplotlib
asked Nov 13 '18 at 21:03
AlexeyAlexey
204
asked Nov 13 '18 at 21:03
AlexeyAlexey
204
asked Nov 13 '18 at 21:03
AlexeyAlexey
204
asked Nov 13 '18 at 21:03
AlexeyAlexey
204
asked Nov 13 '18 at 21:03
AlexeyAlexey
204
204
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
0
solved. just plot contour in polar, streamline in cartesian
answered Nov 18 '18 at 20:26
AlexeyAlexey
204
add a comment |
0
plot contour in polar, streamline in cartesian.
in result you can see:
answered Nov 20 '18 at 19:35
AlexeyAlexey
204
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53289461%2fmatplotlib-polar-streamplot-vs-quiver%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
solved. just plot contour in polar, streamline in cartesian
answered Nov 18 '18 at 20:26
AlexeyAlexey
204
add a comment |
0
solved. just plot contour in polar, streamline in cartesian
answered Nov 18 '18 at 20:26
AlexeyAlexey
204
add a comment |
0
0
0
solved. just plot contour in polar, streamline in cartesian
answered Nov 18 '18 at 20:26
AlexeyAlexey
204
solved. just plot contour in polar, streamline in cartesian
answered Nov 18 '18 at 20:26
AlexeyAlexey
204
answered Nov 18 '18 at 20:26
AlexeyAlexey
204
answered Nov 18 '18 at 20:26
AlexeyAlexey
204
answered Nov 18 '18 at 20:26
AlexeyAlexey
204
204
add a comment |
add a comment |
0
plot contour in polar, streamline in cartesian.
in result you can see:
answered Nov 20 '18 at 19:35
AlexeyAlexey
204
add a comment |
0
plot contour in polar, streamline in cartesian.
in result you can see:
answered Nov 20 '18 at 19:35
AlexeyAlexey
204
add a comment |
0
0
0
plot contour in polar, streamline in cartesian.
in result you can see:
answered Nov 20 '18 at 19:35
AlexeyAlexey
204
plot contour in polar, streamline in cartesian.
in result you can see:
answered Nov 20 '18 at 19:35
AlexeyAlexey
204
answered Nov 20 '18 at 19:35
AlexeyAlexey
204
answered Nov 20 '18 at 19:35
AlexeyAlexey
204
answered Nov 20 '18 at 19:35
AlexeyAlexey
204
204
add a comment |
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53289461%2fmatplotlib-polar-streamplot-vs-quiver%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
