Get resources xml file from url in JAVA
Currently I am storing my resources files on local directory and I am calling them by:
Resources res = getResources();
final String docukrz = res.getStringArray(R.array.docukrz);
I wanted to move this online, so I have created a url: https://example/strings.xml
Now how I can get that file so I will call it from URL, not resources folder.
I am a total beginner and read a lot of different articles and tutorials but cannot pull that together. Sorry if that is a duplicate.
java
android xml asked Nov 14 '18 at 0:47
LukasLukas
72119
add a comment |
Currently I am storing my resources files on local directory and I am calling them by:
Resources res = getResources();
final String docukrz = res.getStringArray(R.array.docukrz);
I wanted to move this online, so I have created a url: https://example/strings.xml
Now how I can get that file so I will call it from URL, not resources folder.
I am a total beginner and read a lot of different articles and tutorials but cannot pull that together. Sorry if that is a duplicate.
java
android xml asked Nov 14 '18 at 0:47
LukasLukas
72119
1
The ID's in R.class are generated at compile time as int's. So, technically this is not possible. Perhaps if you can explain why you want to get the strings fromResourcesand not just your own object, we can help.
– Ali
Nov 14 '18 at 0:52
I would like to use the file the same way I am using it from resources, but instead storing it online. That is a String file, so i want to create some arrays containing strings from that file.
– Lukas
Nov 14 '18 at 7:42
Should I use this tutorial? docs.oracle.com/javase/tutorial/networking/urls/… All of it looks really complicated, and I thought this would be quite easy, but the more I read and ask the more questions I have. Maybe it is better to keep the xml file in my resources and just release a new version of the app whenever I will like to update it? It is just 1 simple file with strings.
– Lukas
Nov 14 '18 at 10:22
add a comment |
Currently I am storing my resources files on local directory and I am calling them by:
Resources res = getResources();
final String docukrz = res.getStringArray(R.array.docukrz);
I wanted to move this online, so I have created a url: https://example/strings.xml
Now how I can get that file so I will call it from URL, not resources folder.
I am a total beginner and read a lot of different articles and tutorials but cannot pull that together. Sorry if that is a duplicate.
java
android xml asked Nov 14 '18 at 0:47
LukasLukas
72119
Currently I am storing my resources files on local directory and I am calling them by:
Resources res = getResources();
final String docukrz = res.getStringArray(R.array.docukrz);
I wanted to move this online, so I have created a url: https://example/strings.xml
Now how I can get that file so I will call it from URL, not resources folder.
I am a total beginner and read a lot of different articles and tutorials but cannot pull that together. Sorry if that is a duplicate.
java
android xml java
android xml asked Nov 14 '18 at 0:47
LukasLukas
72119
asked Nov 14 '18 at 0:47
LukasLukas
72119
asked Nov 14 '18 at 0:47
LukasLukas
72119
asked Nov 14 '18 at 0:47
LukasLukas
72119
asked Nov 14 '18 at 0:47
LukasLukas
72119
72119
1
The ID's in R.class are generated at compile time as int's. So, technically this is not possible. Perhaps if you can explain why you want to get the strings fromResourcesand not just your own object, we can help.
– Ali
Nov 14 '18 at 0:52
I would like to use the file the same way I am using it from resources, but instead storing it online. That is a String file, so i want to create some arrays containing strings from that file.
– Lukas
Nov 14 '18 at 7:42
Should I use this tutorial? docs.oracle.com/javase/tutorial/networking/urls/… All of it looks really complicated, and I thought this would be quite easy, but the more I read and ask the more questions I have. Maybe it is better to keep the xml file in my resources and just release a new version of the app whenever I will like to update it? It is just 1 simple file with strings.
– Lukas
Nov 14 '18 at 10:22
add a comment |
1
The ID's in R.class are generated at compile time as int's. So, technically this is not possible. Perhaps if you can explain why you want to get the strings fromResourcesand not just your own object, we can help.
– Ali
Nov 14 '18 at 0:52
I would like to use the file the same way I am using it from resources, but instead storing it online. That is a String file, so i want to create some arrays containing strings from that file.
– Lukas
Nov 14 '18 at 7:42
Should I use this tutorial? docs.oracle.com/javase/tutorial/networking/urls/… All of it looks really complicated, and I thought this would be quite easy, but the more I read and ask the more questions I have. Maybe it is better to keep the xml file in my resources and just release a new version of the app whenever I will like to update it? It is just 1 simple file with strings.
– Lukas
Nov 14 '18 at 10:22
1
1
The ID's in R.class are generated at compile time as int's. So, technically this is not possible. Perhaps if you can explain why you want to get the strings from
Resources and not just your own object, we can help.– Ali
Nov 14 '18 at 0:52
The ID's in R.class are generated at compile time as int's. So, technically this is not possible. Perhaps if you can explain why you want to get the strings from
Resources and not just your own object, we can help.– Ali
Nov 14 '18 at 0:52
I would like to use the file the same way I am using it from resources, but instead storing it online. That is a String file, so i want to create some arrays containing strings from that file.
– Lukas
Nov 14 '18 at 7:42
I would like to use the file the same way I am using it from resources, but instead storing it online. That is a String file, so i want to create some arrays containing strings from that file.
– Lukas
Nov 14 '18 at 7:42
Should I use this tutorial? docs.oracle.com/javase/tutorial/networking/urls/… All of it looks really complicated, and I thought this would be quite easy, but the more I read and ask the more questions I have. Maybe it is better to keep the xml file in my resources and just release a new version of the app whenever I will like to update it? It is just 1 simple file with strings.
– Lukas
Nov 14 '18 at 10:22
Should I use this tutorial? docs.oracle.com/javase/tutorial/networking/urls/… All of it looks really complicated, and I thought this would be quite easy, but the more I read and ask the more questions I have. Maybe it is better to keep the xml file in my resources and just release a new version of the app whenever I will like to update it? It is just 1 simple file with strings.
– Lukas
Nov 14 '18 at 10:22
add a comment |
2 Answers
2
active
oldest
votes
That is not how resources work. The resources framework is built around local storage, a specific set of directories and "qualifiers", and runtime determination of which resources should be available from the app.
You are welcome to download an xml file from the internet and parse it, but this will never be part of your app's resources.
answered Nov 14 '18 at 0:53
Ben P.Ben P.
23.6k32049
Thank you for your comment. If I will parse it from URL, can I create a String Array from the URL? URL link leads to an xml file actually.
– Lukas
Nov 14 '18 at 9:20
add a comment |
I can suggest you use Retrofit and Kripton (I'm the author of this library) libraries to download an XML file from a URL and convert it into a Java object (or objects).
The wiki page of Kripton tries to explain how to do: instead of use JSON parser, you need to use XMLParser:
// create retrofit using Kripton converter factory
Retrofit retrofit = new Retrofit.Builder()
.baseUrl(“https://jsonplaceholder.typicode.com/")
.addConverterFactory(KriptonBinderConverterFactory.create(BinderType.XML))
.build();
JsonPlaceHolderService service = Retrofit.create(JsonPlaceHolderService.class);
// consume service
Response<List<Post>> response = service.getAllPost().execute();
More information about Retrofit and Kripton Persistence Library:
- Retrofit
- Kripton Persistence Library
If you want to see a working example using Retrofit and Kripton Persistence Library, you can see my example app RSS Reader on GitHub.
answered Nov 14 '18 at 1:03
xcescoxcesco
1,9391533
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
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oldest
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oldest
votes
That is not how resources work. The resources framework is built around local storage, a specific set of directories and "qualifiers", and runtime determination of which resources should be available from the app.
You are welcome to download an xml file from the internet and parse it, but this will never be part of your app's resources.
answered Nov 14 '18 at 0:53
Ben P.Ben P.
23.6k32049
Thank you for your comment. If I will parse it from URL, can I create a String Array from the URL? URL link leads to an xml file actually.
– Lukas
Nov 14 '18 at 9:20
add a comment |
That is not how resources work. The resources framework is built around local storage, a specific set of directories and "qualifiers", and runtime determination of which resources should be available from the app.
You are welcome to download an xml file from the internet and parse it, but this will never be part of your app's resources.
answered Nov 14 '18 at 0:53
Ben P.Ben P.
23.6k32049
Thank you for your comment. If I will parse it from URL, can I create a String Array from the URL? URL link leads to an xml file actually.
– Lukas
Nov 14 '18 at 9:20
add a comment |
That is not how resources work. The resources framework is built around local storage, a specific set of directories and "qualifiers", and runtime determination of which resources should be available from the app.
You are welcome to download an xml file from the internet and parse it, but this will never be part of your app's resources.
answered Nov 14 '18 at 0:53
Ben P.Ben P.
23.6k32049
That is not how resources work. The resources framework is built around local storage, a specific set of directories and "qualifiers", and runtime determination of which resources should be available from the app.
You are welcome to download an xml file from the internet and parse it, but this will never be part of your app's resources.
answered Nov 14 '18 at 0:53
Ben P.Ben P.
23.6k32049
answered Nov 14 '18 at 0:53
Ben P.Ben P.
23.6k32049
answered Nov 14 '18 at 0:53
Ben P.Ben P.
23.6k32049
answered Nov 14 '18 at 0:53
Ben P.Ben P.
23.6k32049
23.6k32049
Thank you for your comment. If I will parse it from URL, can I create a String Array from the URL? URL link leads to an xml file actually.
– Lukas
Nov 14 '18 at 9:20
add a comment |
Thank you for your comment. If I will parse it from URL, can I create a String Array from the URL? URL link leads to an xml file actually.
– Lukas
Nov 14 '18 at 9:20
Thank you for your comment. If I will parse it from URL, can I create a String Array from the URL? URL link leads to an xml file actually.
– Lukas
Nov 14 '18 at 9:20
Thank you for your comment. If I will parse it from URL, can I create a String Array from the URL? URL link leads to an xml file actually.
– Lukas
Nov 14 '18 at 9:20
add a comment |
I can suggest you use Retrofit and Kripton (I'm the author of this library) libraries to download an XML file from a URL and convert it into a Java object (or objects).
The wiki page of Kripton tries to explain how to do: instead of use JSON parser, you need to use XMLParser:
// create retrofit using Kripton converter factory
Retrofit retrofit = new Retrofit.Builder()
.baseUrl(“https://jsonplaceholder.typicode.com/")
.addConverterFactory(KriptonBinderConverterFactory.create(BinderType.XML))
.build();
JsonPlaceHolderService service = Retrofit.create(JsonPlaceHolderService.class);
// consume service
Response<List<Post>> response = service.getAllPost().execute();
More information about Retrofit and Kripton Persistence Library:
- Retrofit
- Kripton Persistence Library
If you want to see a working example using Retrofit and Kripton Persistence Library, you can see my example app RSS Reader on GitHub.
answered Nov 14 '18 at 1:03
xcescoxcesco
1,9391533
add a comment |
I can suggest you use Retrofit and Kripton (I'm the author of this library) libraries to download an XML file from a URL and convert it into a Java object (or objects).
The wiki page of Kripton tries to explain how to do: instead of use JSON parser, you need to use XMLParser:
// create retrofit using Kripton converter factory
Retrofit retrofit = new Retrofit.Builder()
.baseUrl(“https://jsonplaceholder.typicode.com/")
.addConverterFactory(KriptonBinderConverterFactory.create(BinderType.XML))
.build();
JsonPlaceHolderService service = Retrofit.create(JsonPlaceHolderService.class);
// consume service
Response<List<Post>> response = service.getAllPost().execute();
More information about Retrofit and Kripton Persistence Library:
- Retrofit
- Kripton Persistence Library
If you want to see a working example using Retrofit and Kripton Persistence Library, you can see my example app RSS Reader on GitHub.
answered Nov 14 '18 at 1:03
xcescoxcesco
1,9391533
add a comment |
I can suggest you use Retrofit and Kripton (I'm the author of this library) libraries to download an XML file from a URL and convert it into a Java object (or objects).
The wiki page of Kripton tries to explain how to do: instead of use JSON parser, you need to use XMLParser:
// create retrofit using Kripton converter factory
Retrofit retrofit = new Retrofit.Builder()
.baseUrl(“https://jsonplaceholder.typicode.com/")
.addConverterFactory(KriptonBinderConverterFactory.create(BinderType.XML))
.build();
JsonPlaceHolderService service = Retrofit.create(JsonPlaceHolderService.class);
// consume service
Response<List<Post>> response = service.getAllPost().execute();
More information about Retrofit and Kripton Persistence Library:
- Retrofit
- Kripton Persistence Library
If you want to see a working example using Retrofit and Kripton Persistence Library, you can see my example app RSS Reader on GitHub.
answered Nov 14 '18 at 1:03
xcescoxcesco
1,9391533
I can suggest you use Retrofit and Kripton (I'm the author of this library) libraries to download an XML file from a URL and convert it into a Java object (or objects).
The wiki page of Kripton tries to explain how to do: instead of use JSON parser, you need to use XMLParser:
// create retrofit using Kripton converter factory
Retrofit retrofit = new Retrofit.Builder()
.baseUrl(“https://jsonplaceholder.typicode.com/")
.addConverterFactory(KriptonBinderConverterFactory.create(BinderType.XML))
.build();
JsonPlaceHolderService service = Retrofit.create(JsonPlaceHolderService.class);
// consume service
Response<List<Post>> response = service.getAllPost().execute();
More information about Retrofit and Kripton Persistence Library:
- Retrofit
- Kripton Persistence Library
If you want to see a working example using Retrofit and Kripton Persistence Library, you can see my example app RSS Reader on GitHub.
answered Nov 14 '18 at 1:03
xcescoxcesco
1,9391533
answered Nov 14 '18 at 1:03
xcescoxcesco
1,9391533
answered Nov 14 '18 at 1:03
xcescoxcesco
1,9391533
answered Nov 14 '18 at 1:03
xcescoxcesco
1,9391533
1,9391533
add a comment |
add a comment |
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1
The ID's in R.class are generated at compile time as int's. So, technically this is not possible. Perhaps if you can explain why you want to get the strings from
Resourcesand not just your own object, we can help.– Ali
Nov 14 '18 at 0:52
I would like to use the file the same way I am using it from resources, but instead storing it online. That is a String file, so i want to create some arrays containing strings from that file.
– Lukas
Nov 14 '18 at 7:42
Should I use this tutorial? docs.oracle.com/javase/tutorial/networking/urls/… All of it looks really complicated, and I thought this would be quite easy, but the more I read and ask the more questions I have. Maybe it is better to keep the xml file in my resources and just release a new version of the app whenever I will like to update it? It is just 1 simple file with strings.
– Lukas
Nov 14 '18 at 10:22