Clang-Tidy: Redundant 'operator<<' declaration












1















I was trying to write a friend operator<< to my class and I got this warning of redundant. And can't figure how to fix it.



Thank you in advance.



#include <iostream>
using namespace std;

template<class T>
class test
{
public:
explicit test(T a) noexcept : m_{ a } {}
template <class Y>

//line below shows that warning.
friend std::ostream& operator<<(std::ostream& out, const test<Y>& lhs);
private:
T m_;
};

template<class Y>
std::ostream& operator<<(std::ostream& out, const test<Y>& lhs)
{
out << lhs.m_ << endl;
return out;
}


int main()
{
test<int> p {25};
test<double> q {17.5};

std::cout << "By Friend " << p;
std::cout << "By Friend " << q;
return 0;
}


Edit 1
//Removed template Y from the operator<< int he class declaration



template<class  T>
class test
{
public:
explicit test(T a) noexcept : m_{ a } {}
friend std::ostream& operator<< (std::ostream&, const test<T>&);
private:
T m_;
};

template<class T>
std::ostream& operator<<(std::ostream& out, const test<T>& lhs)
{
out << lhs.m_ << endl;
return out;
}


now I got a Warning




warning: friend declaration 'std::ostream& operator<<(std::ostream&, const test&)' declares a non-template function [-Wnon-template-friend]




PS : in Visual Studio I got Error Links



EDIT 1.2 //edit done for EDIT 1



I changed the Edit 1 as follow :



....
friend std::ostream& operator<< <> (std::ostream&, const test<T>&);
....


So warnings and error links are resolved.










share|improve this question




















  • 1





    So it's clang-tidy, and not clang? What rule triggers this?

    – Matthieu Brucher
    Nov 13 '18 at 11:38






  • 1





    @Useless : the actual warning says : Clang-Tidy: Redundant 'operator<<' declaration in the operator<< funct declared in the class

    – Blood-HaZaRd
    Nov 13 '18 at 11:39






  • 1





    @paddy : it is the case where all friend template instanciations are friend with all class template instansiation. Edit : So I removed the templated Y and I got a warning warning: friend declaration 'std::ostream& operator<<(std::ostream&, const test<T>&)' declares a non-template function [-Wnon-template-friend]

    – Blood-HaZaRd
    Nov 13 '18 at 11:50








  • 1





    Have you tried removing template <class Y> from the class declaration? (Use T instead of Y at the implementation)

    – JVApen
    Nov 13 '18 at 11:55






  • 1





    @JVApen : Please look at Edit 1 (hope did what you meant)

    – Blood-HaZaRd
    Nov 13 '18 at 11:59
















1















I was trying to write a friend operator<< to my class and I got this warning of redundant. And can't figure how to fix it.



Thank you in advance.



#include <iostream>
using namespace std;

template<class T>
class test
{
public:
explicit test(T a) noexcept : m_{ a } {}
template <class Y>

//line below shows that warning.
friend std::ostream& operator<<(std::ostream& out, const test<Y>& lhs);
private:
T m_;
};

template<class Y>
std::ostream& operator<<(std::ostream& out, const test<Y>& lhs)
{
out << lhs.m_ << endl;
return out;
}


int main()
{
test<int> p {25};
test<double> q {17.5};

std::cout << "By Friend " << p;
std::cout << "By Friend " << q;
return 0;
}


Edit 1
//Removed template Y from the operator<< int he class declaration



template<class  T>
class test
{
public:
explicit test(T a) noexcept : m_{ a } {}
friend std::ostream& operator<< (std::ostream&, const test<T>&);
private:
T m_;
};

template<class T>
std::ostream& operator<<(std::ostream& out, const test<T>& lhs)
{
out << lhs.m_ << endl;
return out;
}


now I got a Warning




warning: friend declaration 'std::ostream& operator<<(std::ostream&, const test&)' declares a non-template function [-Wnon-template-friend]




PS : in Visual Studio I got Error Links



EDIT 1.2 //edit done for EDIT 1



I changed the Edit 1 as follow :



....
friend std::ostream& operator<< <> (std::ostream&, const test<T>&);
....


So warnings and error links are resolved.










share|improve this question




















  • 1





    So it's clang-tidy, and not clang? What rule triggers this?

    – Matthieu Brucher
    Nov 13 '18 at 11:38






  • 1





    @Useless : the actual warning says : Clang-Tidy: Redundant 'operator<<' declaration in the operator<< funct declared in the class

    – Blood-HaZaRd
    Nov 13 '18 at 11:39






  • 1





    @paddy : it is the case where all friend template instanciations are friend with all class template instansiation. Edit : So I removed the templated Y and I got a warning warning: friend declaration 'std::ostream& operator<<(std::ostream&, const test<T>&)' declares a non-template function [-Wnon-template-friend]

    – Blood-HaZaRd
    Nov 13 '18 at 11:50








  • 1





    Have you tried removing template <class Y> from the class declaration? (Use T instead of Y at the implementation)

    – JVApen
    Nov 13 '18 at 11:55






  • 1





    @JVApen : Please look at Edit 1 (hope did what you meant)

    – Blood-HaZaRd
    Nov 13 '18 at 11:59














1












1








1








I was trying to write a friend operator<< to my class and I got this warning of redundant. And can't figure how to fix it.



Thank you in advance.



#include <iostream>
using namespace std;

template<class T>
class test
{
public:
explicit test(T a) noexcept : m_{ a } {}
template <class Y>

//line below shows that warning.
friend std::ostream& operator<<(std::ostream& out, const test<Y>& lhs);
private:
T m_;
};

template<class Y>
std::ostream& operator<<(std::ostream& out, const test<Y>& lhs)
{
out << lhs.m_ << endl;
return out;
}


int main()
{
test<int> p {25};
test<double> q {17.5};

std::cout << "By Friend " << p;
std::cout << "By Friend " << q;
return 0;
}


Edit 1
//Removed template Y from the operator<< int he class declaration



template<class  T>
class test
{
public:
explicit test(T a) noexcept : m_{ a } {}
friend std::ostream& operator<< (std::ostream&, const test<T>&);
private:
T m_;
};

template<class T>
std::ostream& operator<<(std::ostream& out, const test<T>& lhs)
{
out << lhs.m_ << endl;
return out;
}


now I got a Warning




warning: friend declaration 'std::ostream& operator<<(std::ostream&, const test&)' declares a non-template function [-Wnon-template-friend]




PS : in Visual Studio I got Error Links



EDIT 1.2 //edit done for EDIT 1



I changed the Edit 1 as follow :



....
friend std::ostream& operator<< <> (std::ostream&, const test<T>&);
....


So warnings and error links are resolved.










share|improve this question
















I was trying to write a friend operator<< to my class and I got this warning of redundant. And can't figure how to fix it.



Thank you in advance.



#include <iostream>
using namespace std;

template<class T>
class test
{
public:
explicit test(T a) noexcept : m_{ a } {}
template <class Y>

//line below shows that warning.
friend std::ostream& operator<<(std::ostream& out, const test<Y>& lhs);
private:
T m_;
};

template<class Y>
std::ostream& operator<<(std::ostream& out, const test<Y>& lhs)
{
out << lhs.m_ << endl;
return out;
}


int main()
{
test<int> p {25};
test<double> q {17.5};

std::cout << "By Friend " << p;
std::cout << "By Friend " << q;
return 0;
}


Edit 1
//Removed template Y from the operator<< int he class declaration



template<class  T>
class test
{
public:
explicit test(T a) noexcept : m_{ a } {}
friend std::ostream& operator<< (std::ostream&, const test<T>&);
private:
T m_;
};

template<class T>
std::ostream& operator<<(std::ostream& out, const test<T>& lhs)
{
out << lhs.m_ << endl;
return out;
}


now I got a Warning




warning: friend declaration 'std::ostream& operator<<(std::ostream&, const test&)' declares a non-template function [-Wnon-template-friend]




PS : in Visual Studio I got Error Links



EDIT 1.2 //edit done for EDIT 1



I changed the Edit 1 as follow :



....
friend std::ostream& operator<< <> (std::ostream&, const test<T>&);
....


So warnings and error links are resolved.







c++ templates clang-tidy






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 12:31







Blood-HaZaRd

















asked Nov 13 '18 at 11:34









Blood-HaZaRdBlood-HaZaRd

92621032




92621032








  • 1





    So it's clang-tidy, and not clang? What rule triggers this?

    – Matthieu Brucher
    Nov 13 '18 at 11:38






  • 1





    @Useless : the actual warning says : Clang-Tidy: Redundant 'operator<<' declaration in the operator<< funct declared in the class

    – Blood-HaZaRd
    Nov 13 '18 at 11:39






  • 1





    @paddy : it is the case where all friend template instanciations are friend with all class template instansiation. Edit : So I removed the templated Y and I got a warning warning: friend declaration 'std::ostream& operator<<(std::ostream&, const test<T>&)' declares a non-template function [-Wnon-template-friend]

    – Blood-HaZaRd
    Nov 13 '18 at 11:50








  • 1





    Have you tried removing template <class Y> from the class declaration? (Use T instead of Y at the implementation)

    – JVApen
    Nov 13 '18 at 11:55






  • 1





    @JVApen : Please look at Edit 1 (hope did what you meant)

    – Blood-HaZaRd
    Nov 13 '18 at 11:59














  • 1





    So it's clang-tidy, and not clang? What rule triggers this?

    – Matthieu Brucher
    Nov 13 '18 at 11:38






  • 1





    @Useless : the actual warning says : Clang-Tidy: Redundant 'operator<<' declaration in the operator<< funct declared in the class

    – Blood-HaZaRd
    Nov 13 '18 at 11:39






  • 1





    @paddy : it is the case where all friend template instanciations are friend with all class template instansiation. Edit : So I removed the templated Y and I got a warning warning: friend declaration 'std::ostream& operator<<(std::ostream&, const test<T>&)' declares a non-template function [-Wnon-template-friend]

    – Blood-HaZaRd
    Nov 13 '18 at 11:50








  • 1





    Have you tried removing template <class Y> from the class declaration? (Use T instead of Y at the implementation)

    – JVApen
    Nov 13 '18 at 11:55






  • 1





    @JVApen : Please look at Edit 1 (hope did what you meant)

    – Blood-HaZaRd
    Nov 13 '18 at 11:59








1




1





So it's clang-tidy, and not clang? What rule triggers this?

– Matthieu Brucher
Nov 13 '18 at 11:38





So it's clang-tidy, and not clang? What rule triggers this?

– Matthieu Brucher
Nov 13 '18 at 11:38




1




1





@Useless : the actual warning says : Clang-Tidy: Redundant 'operator<<' declaration in the operator<< funct declared in the class

– Blood-HaZaRd
Nov 13 '18 at 11:39





@Useless : the actual warning says : Clang-Tidy: Redundant 'operator<<' declaration in the operator<< funct declared in the class

– Blood-HaZaRd
Nov 13 '18 at 11:39




1




1





@paddy : it is the case where all friend template instanciations are friend with all class template instansiation. Edit : So I removed the templated Y and I got a warning warning: friend declaration 'std::ostream& operator<<(std::ostream&, const test<T>&)' declares a non-template function [-Wnon-template-friend]

– Blood-HaZaRd
Nov 13 '18 at 11:50







@paddy : it is the case where all friend template instanciations are friend with all class template instansiation. Edit : So I removed the templated Y and I got a warning warning: friend declaration 'std::ostream& operator<<(std::ostream&, const test<T>&)' declares a non-template function [-Wnon-template-friend]

– Blood-HaZaRd
Nov 13 '18 at 11:50






1




1





Have you tried removing template <class Y> from the class declaration? (Use T instead of Y at the implementation)

– JVApen
Nov 13 '18 at 11:55





Have you tried removing template <class Y> from the class declaration? (Use T instead of Y at the implementation)

– JVApen
Nov 13 '18 at 11:55




1




1





@JVApen : Please look at Edit 1 (hope did what you meant)

– Blood-HaZaRd
Nov 13 '18 at 11:59





@JVApen : Please look at Edit 1 (hope did what you meant)

– Blood-HaZaRd
Nov 13 '18 at 11:59












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