Round a number in Python
2
I have a very simple problem. I want to break an interval from 1e-6 to 10e-6 into ten values and append them to a list. For this reason, I made the program below,
start_value = 1e-6
stop_value = 10e-6
step_value = 10
step = (stop_value-start_value)/(step_value-9)
current_list = [start_value]
last_value = start_value
for i in range(step_value-1):
current_list.append(last_value + step)
last_value = last_value + step
print(current_list)
I get the following result,
[1e-06, 2e-06, 3e-06, 4e-06, 4.9999999999999996e-06, 5.999999999999999e-06, 6.999999999999999e-06, 8e-06, 9e-06, 1e-05].
Of course, the numbers 4.999999999e-6 and 6.999999999e-6 should be 5e-06 and 7e-06 respectively. For this purpose I used the round(**number** ,11) method.
start_value = 1e-6
stop_value = 10e-6
step_value = 10
step = (stop_value-start_value)/(step_value-9)
current_list = [start_value]
last_value = start_value
for i in range(step_value-1):
current_list.append(round(last_value + step, 11))
last_value = last_value + step
print(current_list)
Is there another way to make this?
python python-3.x
edited Nov 13 '18 at 11:46
Cheche
850218
asked Nov 13 '18 at 11:33
Jacob FuchsJacob Fuchs
7610
add a comment |
2
I have a very simple problem. I want to break an interval from 1e-6 to 10e-6 into ten values and append them to a list. For this reason, I made the program below,
start_value = 1e-6
stop_value = 10e-6
step_value = 10
step = (stop_value-start_value)/(step_value-9)
current_list = [start_value]
last_value = start_value
for i in range(step_value-1):
current_list.append(last_value + step)
last_value = last_value + step
print(current_list)
I get the following result,
[1e-06, 2e-06, 3e-06, 4e-06, 4.9999999999999996e-06, 5.999999999999999e-06, 6.999999999999999e-06, 8e-06, 9e-06, 1e-05].
Of course, the numbers 4.999999999e-6 and 6.999999999e-6 should be 5e-06 and 7e-06 respectively. For this purpose I used the round(**number** ,11) method.
start_value = 1e-6
stop_value = 10e-6
step_value = 10
step = (stop_value-start_value)/(step_value-9)
current_list = [start_value]
last_value = start_value
for i in range(step_value-1):
current_list.append(round(last_value + step, 11))
last_value = last_value + step
print(current_list)
Is there another way to make this?
python python-3.x
edited Nov 13 '18 at 11:46
Cheche
850218
asked Nov 13 '18 at 11:33
Jacob FuchsJacob Fuchs
7610
2
[round(1e-6 * i, 11) for i in range(1, 11)]? Ornp.linspace(1e-6, 10e-6, 10)? Despite what Python wants you to think, TIMTOWTDI.
– Amadan
Nov 13 '18 at 11:50
add a comment |
2
2
2
1
I have a very simple problem. I want to break an interval from 1e-6 to 10e-6 into ten values and append them to a list. For this reason, I made the program below,
start_value = 1e-6
stop_value = 10e-6
step_value = 10
step = (stop_value-start_value)/(step_value-9)
current_list = [start_value]
last_value = start_value
for i in range(step_value-1):
current_list.append(last_value + step)
last_value = last_value + step
print(current_list)
I get the following result,
[1e-06, 2e-06, 3e-06, 4e-06, 4.9999999999999996e-06, 5.999999999999999e-06, 6.999999999999999e-06, 8e-06, 9e-06, 1e-05].
Of course, the numbers 4.999999999e-6 and 6.999999999e-6 should be 5e-06 and 7e-06 respectively. For this purpose I used the round(**number** ,11) method.
start_value = 1e-6
stop_value = 10e-6
step_value = 10
step = (stop_value-start_value)/(step_value-9)
current_list = [start_value]
last_value = start_value
for i in range(step_value-1):
current_list.append(round(last_value + step, 11))
last_value = last_value + step
print(current_list)
Is there another way to make this?
python python-3.x
edited Nov 13 '18 at 11:46
Cheche
850218
asked Nov 13 '18 at 11:33
Jacob FuchsJacob Fuchs
7610
I have a very simple problem. I want to break an interval from 1e-6 to 10e-6 into ten values and append them to a list. For this reason, I made the program below,
start_value = 1e-6
stop_value = 10e-6
step_value = 10
step = (stop_value-start_value)/(step_value-9)
current_list = [start_value]
last_value = start_value
for i in range(step_value-1):
current_list.append(last_value + step)
last_value = last_value + step
print(current_list)
I get the following result,
[1e-06, 2e-06, 3e-06, 4e-06, 4.9999999999999996e-06, 5.999999999999999e-06, 6.999999999999999e-06, 8e-06, 9e-06, 1e-05].
Of course, the numbers 4.999999999e-6 and 6.999999999e-6 should be 5e-06 and 7e-06 respectively. For this purpose I used the round(**number** ,11) method.
start_value = 1e-6
stop_value = 10e-6
step_value = 10
step = (stop_value-start_value)/(step_value-9)
current_list = [start_value]
last_value = start_value
for i in range(step_value-1):
current_list.append(round(last_value + step, 11))
last_value = last_value + step
print(current_list)
Is there another way to make this?
python python-3.x
python python-3.x
edited Nov 13 '18 at 11:46
Cheche
850218
asked Nov 13 '18 at 11:33
Jacob FuchsJacob Fuchs
7610
edited Nov 13 '18 at 11:46
Cheche
850218
asked Nov 13 '18 at 11:33
Jacob FuchsJacob Fuchs
7610
edited Nov 13 '18 at 11:46
Cheche
850218
edited Nov 13 '18 at 11:46
Cheche
850218
edited Nov 13 '18 at 11:46
Cheche
850218
850218
asked Nov 13 '18 at 11:33
Jacob FuchsJacob Fuchs
7610
asked Nov 13 '18 at 11:33
Jacob FuchsJacob Fuchs
7610
asked Nov 13 '18 at 11:33
Jacob FuchsJacob Fuchs
7610
7610
2
[round(1e-6 * i, 11) for i in range(1, 11)]? Ornp.linspace(1e-6, 10e-6, 10)? Despite what Python wants you to think, TIMTOWTDI.
– Amadan
Nov 13 '18 at 11:50
add a comment |
2
[round(1e-6 * i, 11) for i in range(1, 11)]? Ornp.linspace(1e-6, 10e-6, 10)? Despite what Python wants you to think, TIMTOWTDI.
– Amadan
Nov 13 '18 at 11:50
2
2
[round(1e-6 * i, 11) for i in range(1, 11)]? Or np.linspace(1e-6, 10e-6, 10)? Despite what Python wants you to think, TIMTOWTDI.– Amadan
Nov 13 '18 at 11:50
[round(1e-6 * i, 11) for i in range(1, 11)]? Or np.linspace(1e-6, 10e-6, 10)? Despite what Python wants you to think, TIMTOWTDI.– Amadan
Nov 13 '18 at 11:50
add a comment |
2 Answers
2
active
oldest
votes
0
you could use numpy:
import numpy as np
np.arange(1,11,1)*1e-6
output:
array([1.e-06, 2.e-06, 3.e-06, 4.e-06, 5.e-06, 6.e-06, 7.e-06, 8.e-06,
9.e-06, 1.e-05])
answered Nov 13 '18 at 11:57
user7784503user7784503
474
add a comment |
1
You could take a look at the fractions module:
import fractions
start_value = fractions.Fraction(1, 1000000)
stop_value = fractions.Fraction(10, 1000000)
step_value = 10
step = fractions.Fraction(stop_value-start_value, (step_value - 1))
current_list =
for i in range(step_value):
current_list.append(start_value + i * step)
The default output maintains a list of Fraction types:
print(current_list)
[Fraction(1, 1000000), Fraction(1, 500000), Fraction(3, 1000000), Fraction(1, 250000), Fraction(1, 200000), Fraction(3, 500000), Fraction(7, 1000000), Fraction(1, 125000), Fraction(9, 1000000), Fraction(1, 100000)]
But it's simple enough to cast to native data types:
print([float(x) for x in current_list])
[1e-06, 2e-06, 3e-06, 4e-06, 5e-06, 6e-06, 7e-06, 8e-06, 9e-06, 1e-05]
answered Nov 13 '18 at 11:56
DatHydroGuyDatHydroGuy
6662313
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
you could use numpy:
import numpy as np
np.arange(1,11,1)*1e-6
output:
array([1.e-06, 2.e-06, 3.e-06, 4.e-06, 5.e-06, 6.e-06, 7.e-06, 8.e-06,
9.e-06, 1.e-05])
answered Nov 13 '18 at 11:57
user7784503user7784503
474
add a comment |
0
you could use numpy:
import numpy as np
np.arange(1,11,1)*1e-6
output:
array([1.e-06, 2.e-06, 3.e-06, 4.e-06, 5.e-06, 6.e-06, 7.e-06, 8.e-06,
9.e-06, 1.e-05])
answered Nov 13 '18 at 11:57
user7784503user7784503
474
add a comment |
0
0
0
you could use numpy:
import numpy as np
np.arange(1,11,1)*1e-6
output:
array([1.e-06, 2.e-06, 3.e-06, 4.e-06, 5.e-06, 6.e-06, 7.e-06, 8.e-06,
9.e-06, 1.e-05])
answered Nov 13 '18 at 11:57
user7784503user7784503
474
you could use numpy:
import numpy as np
np.arange(1,11,1)*1e-6
output:
array([1.e-06, 2.e-06, 3.e-06, 4.e-06, 5.e-06, 6.e-06, 7.e-06, 8.e-06,
9.e-06, 1.e-05])
answered Nov 13 '18 at 11:57
user7784503user7784503
474
answered Nov 13 '18 at 11:57
user7784503user7784503
474
answered Nov 13 '18 at 11:57
user7784503user7784503
474
answered Nov 13 '18 at 11:57
user7784503user7784503
474
474
add a comment |
add a comment |
1
You could take a look at the fractions module:
import fractions
start_value = fractions.Fraction(1, 1000000)
stop_value = fractions.Fraction(10, 1000000)
step_value = 10
step = fractions.Fraction(stop_value-start_value, (step_value - 1))
current_list =
for i in range(step_value):
current_list.append(start_value + i * step)
The default output maintains a list of Fraction types:
print(current_list)
[Fraction(1, 1000000), Fraction(1, 500000), Fraction(3, 1000000), Fraction(1, 250000), Fraction(1, 200000), Fraction(3, 500000), Fraction(7, 1000000), Fraction(1, 125000), Fraction(9, 1000000), Fraction(1, 100000)]
But it's simple enough to cast to native data types:
print([float(x) for x in current_list])
[1e-06, 2e-06, 3e-06, 4e-06, 5e-06, 6e-06, 7e-06, 8e-06, 9e-06, 1e-05]
answered Nov 13 '18 at 11:56
DatHydroGuyDatHydroGuy
6662313
add a comment |
1
You could take a look at the fractions module:
import fractions
start_value = fractions.Fraction(1, 1000000)
stop_value = fractions.Fraction(10, 1000000)
step_value = 10
step = fractions.Fraction(stop_value-start_value, (step_value - 1))
current_list =
for i in range(step_value):
current_list.append(start_value + i * step)
The default output maintains a list of Fraction types:
print(current_list)
[Fraction(1, 1000000), Fraction(1, 500000), Fraction(3, 1000000), Fraction(1, 250000), Fraction(1, 200000), Fraction(3, 500000), Fraction(7, 1000000), Fraction(1, 125000), Fraction(9, 1000000), Fraction(1, 100000)]
But it's simple enough to cast to native data types:
print([float(x) for x in current_list])
[1e-06, 2e-06, 3e-06, 4e-06, 5e-06, 6e-06, 7e-06, 8e-06, 9e-06, 1e-05]
answered Nov 13 '18 at 11:56
DatHydroGuyDatHydroGuy
6662313
add a comment |
1
1
1
You could take a look at the fractions module:
import fractions
start_value = fractions.Fraction(1, 1000000)
stop_value = fractions.Fraction(10, 1000000)
step_value = 10
step = fractions.Fraction(stop_value-start_value, (step_value - 1))
current_list =
for i in range(step_value):
current_list.append(start_value + i * step)
The default output maintains a list of Fraction types:
print(current_list)
[Fraction(1, 1000000), Fraction(1, 500000), Fraction(3, 1000000), Fraction(1, 250000), Fraction(1, 200000), Fraction(3, 500000), Fraction(7, 1000000), Fraction(1, 125000), Fraction(9, 1000000), Fraction(1, 100000)]
But it's simple enough to cast to native data types:
print([float(x) for x in current_list])
[1e-06, 2e-06, 3e-06, 4e-06, 5e-06, 6e-06, 7e-06, 8e-06, 9e-06, 1e-05]
answered Nov 13 '18 at 11:56
DatHydroGuyDatHydroGuy
6662313
You could take a look at the fractions module:
import fractions
start_value = fractions.Fraction(1, 1000000)
stop_value = fractions.Fraction(10, 1000000)
step_value = 10
step = fractions.Fraction(stop_value-start_value, (step_value - 1))
current_list =
for i in range(step_value):
current_list.append(start_value + i * step)
The default output maintains a list of Fraction types:
print(current_list)
[Fraction(1, 1000000), Fraction(1, 500000), Fraction(3, 1000000), Fraction(1, 250000), Fraction(1, 200000), Fraction(3, 500000), Fraction(7, 1000000), Fraction(1, 125000), Fraction(9, 1000000), Fraction(1, 100000)]
But it's simple enough to cast to native data types:
print([float(x) for x in current_list])
[1e-06, 2e-06, 3e-06, 4e-06, 5e-06, 6e-06, 7e-06, 8e-06, 9e-06, 1e-05]
answered Nov 13 '18 at 11:56
DatHydroGuyDatHydroGuy
6662313
answered Nov 13 '18 at 11:56
DatHydroGuyDatHydroGuy
6662313
answered Nov 13 '18 at 11:56
DatHydroGuyDatHydroGuy
6662313
answered Nov 13 '18 at 11:56
DatHydroGuyDatHydroGuy
6662313
6662313
add a comment |
add a comment |
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2
[round(1e-6 * i, 11) for i in range(1, 11)]? Ornp.linspace(1e-6, 10e-6, 10)? Despite what Python wants you to think, TIMTOWTDI.– Amadan
Nov 13 '18 at 11:50