How to determine the ranges when fitting piecewise equation?
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I am currently giving a fitting equation in matlab for a scatter plot like this:
It seems that we'd better make it a piecewise equation
But how should I determine the ranges of those segmented funtions? Is there an api in matlab for this?
matlab curve-fitting data-fitting
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I am currently giving a fitting equation in matlab for a scatter plot like this:
It seems that we'd better make it a piecewise equation
But how should I determine the ranges of those segmented funtions? Is there an api in matlab for this?
matlab curve-fitting data-fitting
Don't know about matlab, but if possible I'd fit x(y) rather than y(x), on that data Otherwise you could place the split point as parameter in a least square. In this particular case, however it wouldn't help very much either---at least in y(x)---as points belonging to the middle part are left of where the first graph ends. Here an EMA may help.
– mikuszefski
Nov 12 at 7:25
It looks to me as if there are two different "Y" values at X = 5.5 on the scatterplot red lines. If you post a link to the data, I will run it through my zunzun.com web site's "function finder" and try to find a single equation.
– James Phillips
Nov 12 at 12:05
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up vote
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down vote
favorite
I am currently giving a fitting equation in matlab for a scatter plot like this:
It seems that we'd better make it a piecewise equation
But how should I determine the ranges of those segmented funtions? Is there an api in matlab for this?
matlab curve-fitting data-fitting
I am currently giving a fitting equation in matlab for a scatter plot like this:
It seems that we'd better make it a piecewise equation
But how should I determine the ranges of those segmented funtions? Is there an api in matlab for this?
matlab curve-fitting data-fitting
matlab curve-fitting data-fitting
asked Nov 12 at 6:56
Noah Zuo
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589
Don't know about matlab, but if possible I'd fit x(y) rather than y(x), on that data Otherwise you could place the split point as parameter in a least square. In this particular case, however it wouldn't help very much either---at least in y(x)---as points belonging to the middle part are left of where the first graph ends. Here an EMA may help.
– mikuszefski
Nov 12 at 7:25
It looks to me as if there are two different "Y" values at X = 5.5 on the scatterplot red lines. If you post a link to the data, I will run it through my zunzun.com web site's "function finder" and try to find a single equation.
– James Phillips
Nov 12 at 12:05
add a comment |
Don't know about matlab, but if possible I'd fit x(y) rather than y(x), on that data Otherwise you could place the split point as parameter in a least square. In this particular case, however it wouldn't help very much either---at least in y(x)---as points belonging to the middle part are left of where the first graph ends. Here an EMA may help.
– mikuszefski
Nov 12 at 7:25
It looks to me as if there are two different "Y" values at X = 5.5 on the scatterplot red lines. If you post a link to the data, I will run it through my zunzun.com web site's "function finder" and try to find a single equation.
– James Phillips
Nov 12 at 12:05
Don't know about matlab, but if possible I'd fit x(y) rather than y(x), on that data Otherwise you could place the split point as parameter in a least square. In this particular case, however it wouldn't help very much either---at least in y(x)---as points belonging to the middle part are left of where the first graph ends. Here an EMA may help.
– mikuszefski
Nov 12 at 7:25
Don't know about matlab, but if possible I'd fit x(y) rather than y(x), on that data Otherwise you could place the split point as parameter in a least square. In this particular case, however it wouldn't help very much either---at least in y(x)---as points belonging to the middle part are left of where the first graph ends. Here an EMA may help.
– mikuszefski
Nov 12 at 7:25
It looks to me as if there are two different "Y" values at X = 5.5 on the scatterplot red lines. If you post a link to the data, I will run it through my zunzun.com web site's "function finder" and try to find a single equation.
– James Phillips
Nov 12 at 12:05
It looks to me as if there are two different "Y" values at X = 5.5 on the scatterplot red lines. If you post a link to the data, I will run it through my zunzun.com web site's "function finder" and try to find a single equation.
– James Phillips
Nov 12 at 12:05
add a comment |
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Don't know about matlab, but if possible I'd fit x(y) rather than y(x), on that data Otherwise you could place the split point as parameter in a least square. In this particular case, however it wouldn't help very much either---at least in y(x)---as points belonging to the middle part are left of where the first graph ends. Here an EMA may help.
– mikuszefski
Nov 12 at 7:25
It looks to me as if there are two different "Y" values at X = 5.5 on the scatterplot red lines. If you post a link to the data, I will run it through my zunzun.com web site's "function finder" and try to find a single equation.
– James Phillips
Nov 12 at 12:05