R loops with indices











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I am refreshing my R loops skills. How can I write a loop for the below codes. The column indices are 10:14.



   length(data[which(data$subject == "notcoded"),"subject"])/length(data[,"subject"])


here:



  for (i in 10:14){
length(data[which(data[i] == "notcoded")[[i]]])/length(data[i])
}


I kept getting errors about undefined column. I have tried multiple ways to use and []










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  • You are subsetting your data but not specifying a column. Use data[,i]
    – Michael Harper
    Nov 10 at 16:07






  • 3




    Possible duplicate of Undefined columns selected when subsetting data frame
    – Michael Harper
    Nov 10 at 16:09










  • Thank you Michael.
    – mchsu
    Nov 11 at 16:00















up vote
0
down vote

favorite












I am refreshing my R loops skills. How can I write a loop for the below codes. The column indices are 10:14.



   length(data[which(data$subject == "notcoded"),"subject"])/length(data[,"subject"])


here:



  for (i in 10:14){
length(data[which(data[i] == "notcoded")[[i]]])/length(data[i])
}


I kept getting errors about undefined column. I have tried multiple ways to use and []










share|improve this question






















  • You are subsetting your data but not specifying a column. Use data[,i]
    – Michael Harper
    Nov 10 at 16:07






  • 3




    Possible duplicate of Undefined columns selected when subsetting data frame
    – Michael Harper
    Nov 10 at 16:09










  • Thank you Michael.
    – mchsu
    Nov 11 at 16:00













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I am refreshing my R loops skills. How can I write a loop for the below codes. The column indices are 10:14.



   length(data[which(data$subject == "notcoded"),"subject"])/length(data[,"subject"])


here:



  for (i in 10:14){
length(data[which(data[i] == "notcoded")[[i]]])/length(data[i])
}


I kept getting errors about undefined column. I have tried multiple ways to use and []










share|improve this question













I am refreshing my R loops skills. How can I write a loop for the below codes. The column indices are 10:14.



   length(data[which(data$subject == "notcoded"),"subject"])/length(data[,"subject"])


here:



  for (i in 10:14){
length(data[which(data[i] == "notcoded")[[i]]])/length(data[i])
}


I kept getting errors about undefined column. I have tried multiple ways to use and []







r






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share|improve this question











share|improve this question




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asked Nov 10 at 16:03









mchsu

163




163












  • You are subsetting your data but not specifying a column. Use data[,i]
    – Michael Harper
    Nov 10 at 16:07






  • 3




    Possible duplicate of Undefined columns selected when subsetting data frame
    – Michael Harper
    Nov 10 at 16:09










  • Thank you Michael.
    – mchsu
    Nov 11 at 16:00


















  • You are subsetting your data but not specifying a column. Use data[,i]
    – Michael Harper
    Nov 10 at 16:07






  • 3




    Possible duplicate of Undefined columns selected when subsetting data frame
    – Michael Harper
    Nov 10 at 16:09










  • Thank you Michael.
    – mchsu
    Nov 11 at 16:00
















You are subsetting your data but not specifying a column. Use data[,i]
– Michael Harper
Nov 10 at 16:07




You are subsetting your data but not specifying a column. Use data[,i]
– Michael Harper
Nov 10 at 16:07




3




3




Possible duplicate of Undefined columns selected when subsetting data frame
– Michael Harper
Nov 10 at 16:09




Possible duplicate of Undefined columns selected when subsetting data frame
– Michael Harper
Nov 10 at 16:09












Thank you Michael.
– mchsu
Nov 11 at 16:00




Thank you Michael.
– mchsu
Nov 11 at 16:00

















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