Vfrdtyky

So this is what happens: I enter a number and what happens is that it writes out only 1 number: 324, like the variable c is getting this value for no reason..

class Program

{

    static void Main(string args)

    {

        Console.WriteLine("enter a number with change");

        double num = double.Parse(Console.ReadLine());

        num = (int)num;

        int c = 0;

        Console.WriteLine(num);

        while (num != 0)

        {

            num /= 10;

            c++;

        }

        Console.WriteLine(c);

    }

}

This program should loop infinitely if double could represent every real number. Say you enter in 1. Then the loop will divide it by 10, leaving 0.1. Since 0.1 is not equal to 0, the loop will continue, resulting in 0.01, etc.

double, however, only can support a minimum value of about 5E-324, so if you get a number that small and try to divide it by 10, you'll get zero.

So your program loops about 324 times, and quits after it gets a small enough number.

Try printing out num inside the loop. You'll see it tries to divide by 10 (division like this can never end in 0) infinitely until it can no longer hold that small of a value and == 0 will return true.

Just because you set num to it's rounded value by using (int)num doesn't mean it'll behave like an int it'll still end up as a fractional when dividing, use an int if you want it to be:

Console.WriteLine("enter a number with change");

double num = double.Parse(Console.ReadLine());

int num2 = (int)num;

int c = 0;

Console.WriteLine(num2);

while (num2 != 0)

{

    num2 /= 10;

    c++;

}

Console.WriteLine(c);