Vfrdtyky

Sample Input

20, 71146620

100, 26867616

10, 02513583

10, 52811698

100, 23859051

I read it in from a file as a command line argument to a list with

lin = [i.strip() for i in open(sys.argv[1]).readlines()]

that list looks like ['20, 71146620', '100, 26867616', '10, 02513583', '10, 52811698', '100, 23859051']

My hope is to find the most pythonic way to sort this list, first for the first value and then for the second so that it looks like:

['10, 02513583', '10, 52811698', '20, 71146620', '100, 23859051', '100, 26867616', ]

I'm currently trying to convert it to a list of key value pairs, but I'm not sure that's the right direction to take.

The easiest thing to do is to parse the pairs into lists and then just sort them:

lin = [i.strip().split(', ') for i in open(sys.argv[1]).readlines()]

lin = sorted(lin)

In case you want to sort numerically, just cast to numbers:

lin = [map(int, i.strip().split(', ')) for i in open(sys.argv[1]).readlines()]

lin = sorted(lin)

import sys

with open(sys.argv[1]) as f:

    lin = sorted([[int(j) for j in i.split(",")] for i in f])

print lin

You can sort the lines as strings, by using a key function

def two_ints(s):

    return map(int, s.split(","))



with open("num.txt") as f:

    for line in sorted(f, key=two_ints):

        print line

It really depends whether you want the result to be a list of strings, or a list of lists of ints.

Once you have converted to int, there is no way to recover the leading zero on "02513583", so leaving the result as strings may be preferable

why not just use the csv module and feed it to sort (with a string to integer conversion)

import csv



with open("test.csv") as f:

    cr = csv.reader(f)

    result = sorted(list(map(int,row)) for row in cr)

outcome:

>>> result

[[10, 2513583],

 [10, 52811698],

 [20, 71146620],

 [100, 23859051],

 [100, 26867616]]

sort does exactly what's asked here: it uses natural sorting order of lists