Applying DDE23 to a simple Delayed Differential Equation
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Hello I am trying to apply dde23
to the Delayed Differential Equation
y'(t) = 3y(t - 2) with history h(t) = 1 when on the interval .
I have already solved this equation using the method of steps to obtain the piecewise solution
I am interested in comparing this solution using a numerically obtained result from dde23
on MATLAB but am having trouble understanding how to modify the default code given for my particular problem. So far I have modified the default Wiley and Baker Example 23 code:
sol = dde23(@ddex1de,[3, 2],@ddex1hist,[0, 3]);
figure;
plot(sol.x,sol.y)
title('MAT 5450 P5');
xlabel('time t');
ylabel('solution y');
function s = ddex1hist(t)
s = ones(3,1);
end
function dydt = ddex1de(t,y,Z)
ylag1 = Z(:,1);
ylag2 = Z(:,2);
dydt = [ ylag1(1)
ylag1(1) + ylag2(2)
y(2) ];
end
This code produces a graph figure but I am almost absolutely sure the code is not correctly adapted for my particular problem. I would appreciate any help in modifying this code for my problem so that I can compare my answer obtained without the use of MATLAB, thanks.
matlab differential-equations
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up vote
0
down vote
favorite
Hello I am trying to apply dde23
to the Delayed Differential Equation
y'(t) = 3y(t - 2) with history h(t) = 1 when on the interval .
I have already solved this equation using the method of steps to obtain the piecewise solution
I am interested in comparing this solution using a numerically obtained result from dde23
on MATLAB but am having trouble understanding how to modify the default code given for my particular problem. So far I have modified the default Wiley and Baker Example 23 code:
sol = dde23(@ddex1de,[3, 2],@ddex1hist,[0, 3]);
figure;
plot(sol.x,sol.y)
title('MAT 5450 P5');
xlabel('time t');
ylabel('solution y');
function s = ddex1hist(t)
s = ones(3,1);
end
function dydt = ddex1de(t,y,Z)
ylag1 = Z(:,1);
ylag2 = Z(:,2);
dydt = [ ylag1(1)
ylag1(1) + ylag2(2)
y(2) ];
end
This code produces a graph figure but I am almost absolutely sure the code is not correctly adapted for my particular problem. I would appreciate any help in modifying this code for my problem so that I can compare my answer obtained without the use of MATLAB, thanks.
matlab differential-equations
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Hello I am trying to apply dde23
to the Delayed Differential Equation
y'(t) = 3y(t - 2) with history h(t) = 1 when on the interval .
I have already solved this equation using the method of steps to obtain the piecewise solution
I am interested in comparing this solution using a numerically obtained result from dde23
on MATLAB but am having trouble understanding how to modify the default code given for my particular problem. So far I have modified the default Wiley and Baker Example 23 code:
sol = dde23(@ddex1de,[3, 2],@ddex1hist,[0, 3]);
figure;
plot(sol.x,sol.y)
title('MAT 5450 P5');
xlabel('time t');
ylabel('solution y');
function s = ddex1hist(t)
s = ones(3,1);
end
function dydt = ddex1de(t,y,Z)
ylag1 = Z(:,1);
ylag2 = Z(:,2);
dydt = [ ylag1(1)
ylag1(1) + ylag2(2)
y(2) ];
end
This code produces a graph figure but I am almost absolutely sure the code is not correctly adapted for my particular problem. I would appreciate any help in modifying this code for my problem so that I can compare my answer obtained without the use of MATLAB, thanks.
matlab differential-equations
Hello I am trying to apply dde23
to the Delayed Differential Equation
y'(t) = 3y(t - 2) with history h(t) = 1 when on the interval .
I have already solved this equation using the method of steps to obtain the piecewise solution
I am interested in comparing this solution using a numerically obtained result from dde23
on MATLAB but am having trouble understanding how to modify the default code given for my particular problem. So far I have modified the default Wiley and Baker Example 23 code:
sol = dde23(@ddex1de,[3, 2],@ddex1hist,[0, 3]);
figure;
plot(sol.x,sol.y)
title('MAT 5450 P5');
xlabel('time t');
ylabel('solution y');
function s = ddex1hist(t)
s = ones(3,1);
end
function dydt = ddex1de(t,y,Z)
ylag1 = Z(:,1);
ylag2 = Z(:,2);
dydt = [ ylag1(1)
ylag1(1) + ylag2(2)
y(2) ];
end
This code produces a graph figure but I am almost absolutely sure the code is not correctly adapted for my particular problem. I would appreciate any help in modifying this code for my problem so that I can compare my answer obtained without the use of MATLAB, thanks.
matlab differential-equations
matlab differential-equations
edited Nov 12 at 5:07
Banghua Zhao
794217
794217
asked Nov 10 at 22:49
Jmath99
32
32
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