How to Read XML in .NET?











up vote
26
down vote

favorite
7












XML noob here!
So I have some xml data:



<DataChunk>
<ResponseChunk>
<errors>
<error code="0">
Something happened here: Line 1, position 1.
</error>
</errors>
</ResponseChunk>
</DataChunk>


How would I get the a list of "errors" where I can get access to the "error code" and the text description following...?
Also, I'm using .net4.0 in c#...thanks!










share|improve this question




















  • 1




    I'm assuming this: ´<error code="0"> ´ isn't what your XML actually looks like? Those slashes will break it, is it just C# escaping you've cut and pasted?
    – James Walford
    Jan 20 '11 at 21:47












  • @james Yeah >.< I had the xml loaded into a string and copied heh
    – sringer
    Jan 20 '11 at 22:01















up vote
26
down vote

favorite
7












XML noob here!
So I have some xml data:



<DataChunk>
<ResponseChunk>
<errors>
<error code="0">
Something happened here: Line 1, position 1.
</error>
</errors>
</ResponseChunk>
</DataChunk>


How would I get the a list of "errors" where I can get access to the "error code" and the text description following...?
Also, I'm using .net4.0 in c#...thanks!










share|improve this question




















  • 1




    I'm assuming this: ´<error code="0"> ´ isn't what your XML actually looks like? Those slashes will break it, is it just C# escaping you've cut and pasted?
    – James Walford
    Jan 20 '11 at 21:47












  • @james Yeah >.< I had the xml loaded into a string and copied heh
    – sringer
    Jan 20 '11 at 22:01













up vote
26
down vote

favorite
7









up vote
26
down vote

favorite
7






7





XML noob here!
So I have some xml data:



<DataChunk>
<ResponseChunk>
<errors>
<error code="0">
Something happened here: Line 1, position 1.
</error>
</errors>
</ResponseChunk>
</DataChunk>


How would I get the a list of "errors" where I can get access to the "error code" and the text description following...?
Also, I'm using .net4.0 in c#...thanks!










share|improve this question















XML noob here!
So I have some xml data:



<DataChunk>
<ResponseChunk>
<errors>
<error code="0">
Something happened here: Line 1, position 1.
</error>
</errors>
</ResponseChunk>
</DataChunk>


How would I get the a list of "errors" where I can get access to the "error code" and the text description following...?
Also, I'm using .net4.0 in c#...thanks!







c# xml






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share|improve this question













share|improve this question




share|improve this question








edited Jan 20 '11 at 21:30









John Saunders

147k22202357




147k22202357










asked Jan 20 '11 at 21:27









sringer

3751414




3751414








  • 1




    I'm assuming this: ´<error code="0"> ´ isn't what your XML actually looks like? Those slashes will break it, is it just C# escaping you've cut and pasted?
    – James Walford
    Jan 20 '11 at 21:47












  • @james Yeah >.< I had the xml loaded into a string and copied heh
    – sringer
    Jan 20 '11 at 22:01














  • 1




    I'm assuming this: ´<error code="0"> ´ isn't what your XML actually looks like? Those slashes will break it, is it just C# escaping you've cut and pasted?
    – James Walford
    Jan 20 '11 at 21:47












  • @james Yeah >.< I had the xml loaded into a string and copied heh
    – sringer
    Jan 20 '11 at 22:01








1




1




I'm assuming this: ´<error code="0"> ´ isn't what your XML actually looks like? Those slashes will break it, is it just C# escaping you've cut and pasted?
– James Walford
Jan 20 '11 at 21:47






I'm assuming this: ´<error code="0"> ´ isn't what your XML actually looks like? Those slashes will break it, is it just C# escaping you've cut and pasted?
– James Walford
Jan 20 '11 at 21:47














@james Yeah >.< I had the xml loaded into a string and copied heh
– sringer
Jan 20 '11 at 22:01




@james Yeah >.< I had the xml loaded into a string and copied heh
– sringer
Jan 20 '11 at 22:01












4 Answers
4






active

oldest

votes

















up vote
48
down vote



accepted










Load the XML into an XmlDocument and then use xpath queries to extract the data you need.



For example



XmlDocument doc = new XmlDocument();
doc.LoadXml(xmlstring);

XmlNode errorNode = doc.DocumentElement.SelectSingleNode("/DataChunk/ResponseChunk/Errors/error");

string errorCode = errorNode.Attributes["code"].Value;
string errorMessage = errorNode.InnerText;


If there is potential for the XML having multiple error elements you can use SelectNodes to get an XmlNodeList that contains all elements at that xpath. For example:



XmlDocument doc = new XmlDocument();
doc.LoadXml(xmlstring);

XmlNodeList errorNodes = doc.DocumentElement.SelectNodes("/DataChunk/ResponseChunk/Errors/error");

foreach(XmlNode errorNode in errorNodes)
{
string errorCode = errorNode.Attributes["code"].Value;
string errorMessage = errorNode.InnerText;
}


Option 2



If you have a XML schema for the XML you could bind the schema to a class (using the .NET xsd.exe tool). Once you have that you can deserialise the XML into an object and work with it from that object rather than the raw XML. This is an entire subject in itself so if you do have the schema it is worth looking into.






share|improve this answer























  • You have SelectSingleNode, while the OP wants a list of the error nodes.
    – Gabe
    Jan 20 '11 at 21:44










  • @Gabe : But I also have "If there is potential for the XML having multiple error elements you can use SelectNodes to get an XmlNodeList that contains all elements at that xpath." - however added sample code for multiple error nodes.
    – MrEyes
    Jan 20 '11 at 21:46










  • @joey : thats what I get for half posting on SO half watching television from the sofa :)
    – MrEyes
    Jan 20 '11 at 21:48










  • +1 for a good answer after edits
    – James Walford
    Jan 20 '11 at 22:22










  • And that's why TV is bad ;-)
    – Joey
    Jan 20 '11 at 22:50


















up vote
23
down vote













You can use Linq to XML:



var doc = XDocument.Parse(xml);
var errors = from e in doc.Descendants("error")
select new
{
code = e.Attribute("code").Value,
msg = e.Value.Trim()
};

foreach (var e in errors)
{
// use e.code & e.msg
}


If your input XML is very large however, it might be better to go through the document with an XMLReader.






share|improve this answer






























    up vote
    3
    down vote













    XmlReader xmlReader = XmlReader.Create(new StringReader(response));
    AmortizationCalculatorBE amortization = new AmortizationCalculatorBE();
    List<PaymentCalculator> paymentList = new List<PaymentCalculator>();
    XmlDocument xmlDoc = new XmlDocument();
    xmlDoc.Load(new StringReader(response));
    XmlNodeList nodeList = xmlDoc.DocumentElement.SelectNodes("response/amortizationschedule/payment");
    XmlNodeList nodeList2 = xmlDoc.DocumentElement.SelectNodes("response");
    foreach (XmlNode node in nodeList)
    {
    PaymentCalculator payment = new PaymentCalculator();
    payment.beginningbalance = node.SelectSingleNode("beginningbalance").InnerText;
    payment.principal = node.SelectSingleNode("principal").InnerText;
    payment.interest = node.SelectSingleNode("interest").InnerText;
    paymentList.Add(payment);

    }
    amortization._PaymentCalculator = paymentList;
    foreach (XmlNode node in nodeList2)
    {
    amortization.totalprincipal = node.SelectSingleNode("totalprincipal").InnerText;
    amortization.totalinterest = node.SelectSingleNode("totalinterest").InnerText;

    }





    share|improve this answer




























      up vote
      0
      down vote













      using SelectNodes with Cast to IEnumerable<XmlElement> type collection. then you can try to use linq get your value.



      XmlDocument doc = new XmlDocument();
      doc.LoadXml(xml_str);
      var errors = doc
      .SelectNodes("/DataChunk/ResponseChunk/Errors/error")
      .Cast<XmlElement>()
      .Select(x => new {
      errorCode = x.Attributes["code"].Value,
      errorMessage = x.InnerText
      });

      foreach (var item in errors)
      {

      }





      share|improve this answer





















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        4 Answers
        4






        active

        oldest

        votes








        4 Answers
        4






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes








        up vote
        48
        down vote



        accepted










        Load the XML into an XmlDocument and then use xpath queries to extract the data you need.



        For example



        XmlDocument doc = new XmlDocument();
        doc.LoadXml(xmlstring);

        XmlNode errorNode = doc.DocumentElement.SelectSingleNode("/DataChunk/ResponseChunk/Errors/error");

        string errorCode = errorNode.Attributes["code"].Value;
        string errorMessage = errorNode.InnerText;


        If there is potential for the XML having multiple error elements you can use SelectNodes to get an XmlNodeList that contains all elements at that xpath. For example:



        XmlDocument doc = new XmlDocument();
        doc.LoadXml(xmlstring);

        XmlNodeList errorNodes = doc.DocumentElement.SelectNodes("/DataChunk/ResponseChunk/Errors/error");

        foreach(XmlNode errorNode in errorNodes)
        {
        string errorCode = errorNode.Attributes["code"].Value;
        string errorMessage = errorNode.InnerText;
        }


        Option 2



        If you have a XML schema for the XML you could bind the schema to a class (using the .NET xsd.exe tool). Once you have that you can deserialise the XML into an object and work with it from that object rather than the raw XML. This is an entire subject in itself so if you do have the schema it is worth looking into.






        share|improve this answer























        • You have SelectSingleNode, while the OP wants a list of the error nodes.
          – Gabe
          Jan 20 '11 at 21:44










        • @Gabe : But I also have "If there is potential for the XML having multiple error elements you can use SelectNodes to get an XmlNodeList that contains all elements at that xpath." - however added sample code for multiple error nodes.
          – MrEyes
          Jan 20 '11 at 21:46










        • @joey : thats what I get for half posting on SO half watching television from the sofa :)
          – MrEyes
          Jan 20 '11 at 21:48










        • +1 for a good answer after edits
          – James Walford
          Jan 20 '11 at 22:22










        • And that's why TV is bad ;-)
          – Joey
          Jan 20 '11 at 22:50















        up vote
        48
        down vote



        accepted










        Load the XML into an XmlDocument and then use xpath queries to extract the data you need.



        For example



        XmlDocument doc = new XmlDocument();
        doc.LoadXml(xmlstring);

        XmlNode errorNode = doc.DocumentElement.SelectSingleNode("/DataChunk/ResponseChunk/Errors/error");

        string errorCode = errorNode.Attributes["code"].Value;
        string errorMessage = errorNode.InnerText;


        If there is potential for the XML having multiple error elements you can use SelectNodes to get an XmlNodeList that contains all elements at that xpath. For example:



        XmlDocument doc = new XmlDocument();
        doc.LoadXml(xmlstring);

        XmlNodeList errorNodes = doc.DocumentElement.SelectNodes("/DataChunk/ResponseChunk/Errors/error");

        foreach(XmlNode errorNode in errorNodes)
        {
        string errorCode = errorNode.Attributes["code"].Value;
        string errorMessage = errorNode.InnerText;
        }


        Option 2



        If you have a XML schema for the XML you could bind the schema to a class (using the .NET xsd.exe tool). Once you have that you can deserialise the XML into an object and work with it from that object rather than the raw XML. This is an entire subject in itself so if you do have the schema it is worth looking into.






        share|improve this answer























        • You have SelectSingleNode, while the OP wants a list of the error nodes.
          – Gabe
          Jan 20 '11 at 21:44










        • @Gabe : But I also have "If there is potential for the XML having multiple error elements you can use SelectNodes to get an XmlNodeList that contains all elements at that xpath." - however added sample code for multiple error nodes.
          – MrEyes
          Jan 20 '11 at 21:46










        • @joey : thats what I get for half posting on SO half watching television from the sofa :)
          – MrEyes
          Jan 20 '11 at 21:48










        • +1 for a good answer after edits
          – James Walford
          Jan 20 '11 at 22:22










        • And that's why TV is bad ;-)
          – Joey
          Jan 20 '11 at 22:50













        up vote
        48
        down vote



        accepted







        up vote
        48
        down vote



        accepted






        Load the XML into an XmlDocument and then use xpath queries to extract the data you need.



        For example



        XmlDocument doc = new XmlDocument();
        doc.LoadXml(xmlstring);

        XmlNode errorNode = doc.DocumentElement.SelectSingleNode("/DataChunk/ResponseChunk/Errors/error");

        string errorCode = errorNode.Attributes["code"].Value;
        string errorMessage = errorNode.InnerText;


        If there is potential for the XML having multiple error elements you can use SelectNodes to get an XmlNodeList that contains all elements at that xpath. For example:



        XmlDocument doc = new XmlDocument();
        doc.LoadXml(xmlstring);

        XmlNodeList errorNodes = doc.DocumentElement.SelectNodes("/DataChunk/ResponseChunk/Errors/error");

        foreach(XmlNode errorNode in errorNodes)
        {
        string errorCode = errorNode.Attributes["code"].Value;
        string errorMessage = errorNode.InnerText;
        }


        Option 2



        If you have a XML schema for the XML you could bind the schema to a class (using the .NET xsd.exe tool). Once you have that you can deserialise the XML into an object and work with it from that object rather than the raw XML. This is an entire subject in itself so if you do have the schema it is worth looking into.






        share|improve this answer














        Load the XML into an XmlDocument and then use xpath queries to extract the data you need.



        For example



        XmlDocument doc = new XmlDocument();
        doc.LoadXml(xmlstring);

        XmlNode errorNode = doc.DocumentElement.SelectSingleNode("/DataChunk/ResponseChunk/Errors/error");

        string errorCode = errorNode.Attributes["code"].Value;
        string errorMessage = errorNode.InnerText;


        If there is potential for the XML having multiple error elements you can use SelectNodes to get an XmlNodeList that contains all elements at that xpath. For example:



        XmlDocument doc = new XmlDocument();
        doc.LoadXml(xmlstring);

        XmlNodeList errorNodes = doc.DocumentElement.SelectNodes("/DataChunk/ResponseChunk/Errors/error");

        foreach(XmlNode errorNode in errorNodes)
        {
        string errorCode = errorNode.Attributes["code"].Value;
        string errorMessage = errorNode.InnerText;
        }


        Option 2



        If you have a XML schema for the XML you could bind the schema to a class (using the .NET xsd.exe tool). Once you have that you can deserialise the XML into an object and work with it from that object rather than the raw XML. This is an entire subject in itself so if you do have the schema it is worth looking into.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Feb 19 '15 at 15:43









        Kevin DiTraglia

        18.6k1377114




        18.6k1377114










        answered Jan 20 '11 at 21:37









        MrEyes

        8,21774061




        8,21774061












        • You have SelectSingleNode, while the OP wants a list of the error nodes.
          – Gabe
          Jan 20 '11 at 21:44










        • @Gabe : But I also have "If there is potential for the XML having multiple error elements you can use SelectNodes to get an XmlNodeList that contains all elements at that xpath." - however added sample code for multiple error nodes.
          – MrEyes
          Jan 20 '11 at 21:46










        • @joey : thats what I get for half posting on SO half watching television from the sofa :)
          – MrEyes
          Jan 20 '11 at 21:48










        • +1 for a good answer after edits
          – James Walford
          Jan 20 '11 at 22:22










        • And that's why TV is bad ;-)
          – Joey
          Jan 20 '11 at 22:50


















        • You have SelectSingleNode, while the OP wants a list of the error nodes.
          – Gabe
          Jan 20 '11 at 21:44










        • @Gabe : But I also have "If there is potential for the XML having multiple error elements you can use SelectNodes to get an XmlNodeList that contains all elements at that xpath." - however added sample code for multiple error nodes.
          – MrEyes
          Jan 20 '11 at 21:46










        • @joey : thats what I get for half posting on SO half watching television from the sofa :)
          – MrEyes
          Jan 20 '11 at 21:48










        • +1 for a good answer after edits
          – James Walford
          Jan 20 '11 at 22:22










        • And that's why TV is bad ;-)
          – Joey
          Jan 20 '11 at 22:50
















        You have SelectSingleNode, while the OP wants a list of the error nodes.
        – Gabe
        Jan 20 '11 at 21:44




        You have SelectSingleNode, while the OP wants a list of the error nodes.
        – Gabe
        Jan 20 '11 at 21:44












        @Gabe : But I also have "If there is potential for the XML having multiple error elements you can use SelectNodes to get an XmlNodeList that contains all elements at that xpath." - however added sample code for multiple error nodes.
        – MrEyes
        Jan 20 '11 at 21:46




        @Gabe : But I also have "If there is potential for the XML having multiple error elements you can use SelectNodes to get an XmlNodeList that contains all elements at that xpath." - however added sample code for multiple error nodes.
        – MrEyes
        Jan 20 '11 at 21:46












        @joey : thats what I get for half posting on SO half watching television from the sofa :)
        – MrEyes
        Jan 20 '11 at 21:48




        @joey : thats what I get for half posting on SO half watching television from the sofa :)
        – MrEyes
        Jan 20 '11 at 21:48












        +1 for a good answer after edits
        – James Walford
        Jan 20 '11 at 22:22




        +1 for a good answer after edits
        – James Walford
        Jan 20 '11 at 22:22












        And that's why TV is bad ;-)
        – Joey
        Jan 20 '11 at 22:50




        And that's why TV is bad ;-)
        – Joey
        Jan 20 '11 at 22:50












        up vote
        23
        down vote













        You can use Linq to XML:



        var doc = XDocument.Parse(xml);
        var errors = from e in doc.Descendants("error")
        select new
        {
        code = e.Attribute("code").Value,
        msg = e.Value.Trim()
        };

        foreach (var e in errors)
        {
        // use e.code & e.msg
        }


        If your input XML is very large however, it might be better to go through the document with an XMLReader.






        share|improve this answer



























          up vote
          23
          down vote













          You can use Linq to XML:



          var doc = XDocument.Parse(xml);
          var errors = from e in doc.Descendants("error")
          select new
          {
          code = e.Attribute("code").Value,
          msg = e.Value.Trim()
          };

          foreach (var e in errors)
          {
          // use e.code & e.msg
          }


          If your input XML is very large however, it might be better to go through the document with an XMLReader.






          share|improve this answer

























            up vote
            23
            down vote










            up vote
            23
            down vote









            You can use Linq to XML:



            var doc = XDocument.Parse(xml);
            var errors = from e in doc.Descendants("error")
            select new
            {
            code = e.Attribute("code").Value,
            msg = e.Value.Trim()
            };

            foreach (var e in errors)
            {
            // use e.code & e.msg
            }


            If your input XML is very large however, it might be better to go through the document with an XMLReader.






            share|improve this answer














            You can use Linq to XML:



            var doc = XDocument.Parse(xml);
            var errors = from e in doc.Descendants("error")
            select new
            {
            code = e.Attribute("code").Value,
            msg = e.Value.Trim()
            };

            foreach (var e in errors)
            {
            // use e.code & e.msg
            }


            If your input XML is very large however, it might be better to go through the document with an XMLReader.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Jan 20 '11 at 21:49

























            answered Jan 20 '11 at 21:40









            Josef Pfleger

            67.1k148595




            67.1k148595






















                up vote
                3
                down vote













                XmlReader xmlReader = XmlReader.Create(new StringReader(response));
                AmortizationCalculatorBE amortization = new AmortizationCalculatorBE();
                List<PaymentCalculator> paymentList = new List<PaymentCalculator>();
                XmlDocument xmlDoc = new XmlDocument();
                xmlDoc.Load(new StringReader(response));
                XmlNodeList nodeList = xmlDoc.DocumentElement.SelectNodes("response/amortizationschedule/payment");
                XmlNodeList nodeList2 = xmlDoc.DocumentElement.SelectNodes("response");
                foreach (XmlNode node in nodeList)
                {
                PaymentCalculator payment = new PaymentCalculator();
                payment.beginningbalance = node.SelectSingleNode("beginningbalance").InnerText;
                payment.principal = node.SelectSingleNode("principal").InnerText;
                payment.interest = node.SelectSingleNode("interest").InnerText;
                paymentList.Add(payment);

                }
                amortization._PaymentCalculator = paymentList;
                foreach (XmlNode node in nodeList2)
                {
                amortization.totalprincipal = node.SelectSingleNode("totalprincipal").InnerText;
                amortization.totalinterest = node.SelectSingleNode("totalinterest").InnerText;

                }





                share|improve this answer

























                  up vote
                  3
                  down vote













                  XmlReader xmlReader = XmlReader.Create(new StringReader(response));
                  AmortizationCalculatorBE amortization = new AmortizationCalculatorBE();
                  List<PaymentCalculator> paymentList = new List<PaymentCalculator>();
                  XmlDocument xmlDoc = new XmlDocument();
                  xmlDoc.Load(new StringReader(response));
                  XmlNodeList nodeList = xmlDoc.DocumentElement.SelectNodes("response/amortizationschedule/payment");
                  XmlNodeList nodeList2 = xmlDoc.DocumentElement.SelectNodes("response");
                  foreach (XmlNode node in nodeList)
                  {
                  PaymentCalculator payment = new PaymentCalculator();
                  payment.beginningbalance = node.SelectSingleNode("beginningbalance").InnerText;
                  payment.principal = node.SelectSingleNode("principal").InnerText;
                  payment.interest = node.SelectSingleNode("interest").InnerText;
                  paymentList.Add(payment);

                  }
                  amortization._PaymentCalculator = paymentList;
                  foreach (XmlNode node in nodeList2)
                  {
                  amortization.totalprincipal = node.SelectSingleNode("totalprincipal").InnerText;
                  amortization.totalinterest = node.SelectSingleNode("totalinterest").InnerText;

                  }





                  share|improve this answer























                    up vote
                    3
                    down vote










                    up vote
                    3
                    down vote









                    XmlReader xmlReader = XmlReader.Create(new StringReader(response));
                    AmortizationCalculatorBE amortization = new AmortizationCalculatorBE();
                    List<PaymentCalculator> paymentList = new List<PaymentCalculator>();
                    XmlDocument xmlDoc = new XmlDocument();
                    xmlDoc.Load(new StringReader(response));
                    XmlNodeList nodeList = xmlDoc.DocumentElement.SelectNodes("response/amortizationschedule/payment");
                    XmlNodeList nodeList2 = xmlDoc.DocumentElement.SelectNodes("response");
                    foreach (XmlNode node in nodeList)
                    {
                    PaymentCalculator payment = new PaymentCalculator();
                    payment.beginningbalance = node.SelectSingleNode("beginningbalance").InnerText;
                    payment.principal = node.SelectSingleNode("principal").InnerText;
                    payment.interest = node.SelectSingleNode("interest").InnerText;
                    paymentList.Add(payment);

                    }
                    amortization._PaymentCalculator = paymentList;
                    foreach (XmlNode node in nodeList2)
                    {
                    amortization.totalprincipal = node.SelectSingleNode("totalprincipal").InnerText;
                    amortization.totalinterest = node.SelectSingleNode("totalinterest").InnerText;

                    }





                    share|improve this answer












                    XmlReader xmlReader = XmlReader.Create(new StringReader(response));
                    AmortizationCalculatorBE amortization = new AmortizationCalculatorBE();
                    List<PaymentCalculator> paymentList = new List<PaymentCalculator>();
                    XmlDocument xmlDoc = new XmlDocument();
                    xmlDoc.Load(new StringReader(response));
                    XmlNodeList nodeList = xmlDoc.DocumentElement.SelectNodes("response/amortizationschedule/payment");
                    XmlNodeList nodeList2 = xmlDoc.DocumentElement.SelectNodes("response");
                    foreach (XmlNode node in nodeList)
                    {
                    PaymentCalculator payment = new PaymentCalculator();
                    payment.beginningbalance = node.SelectSingleNode("beginningbalance").InnerText;
                    payment.principal = node.SelectSingleNode("principal").InnerText;
                    payment.interest = node.SelectSingleNode("interest").InnerText;
                    paymentList.Add(payment);

                    }
                    amortization._PaymentCalculator = paymentList;
                    foreach (XmlNode node in nodeList2)
                    {
                    amortization.totalprincipal = node.SelectSingleNode("totalprincipal").InnerText;
                    amortization.totalinterest = node.SelectSingleNode("totalinterest").InnerText;

                    }






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Feb 19 '15 at 13:03









                    Mike Clark

                    1,433721




                    1,433721






















                        up vote
                        0
                        down vote













                        using SelectNodes with Cast to IEnumerable<XmlElement> type collection. then you can try to use linq get your value.



                        XmlDocument doc = new XmlDocument();
                        doc.LoadXml(xml_str);
                        var errors = doc
                        .SelectNodes("/DataChunk/ResponseChunk/Errors/error")
                        .Cast<XmlElement>()
                        .Select(x => new {
                        errorCode = x.Attributes["code"].Value,
                        errorMessage = x.InnerText
                        });

                        foreach (var item in errors)
                        {

                        }





                        share|improve this answer

























                          up vote
                          0
                          down vote













                          using SelectNodes with Cast to IEnumerable<XmlElement> type collection. then you can try to use linq get your value.



                          XmlDocument doc = new XmlDocument();
                          doc.LoadXml(xml_str);
                          var errors = doc
                          .SelectNodes("/DataChunk/ResponseChunk/Errors/error")
                          .Cast<XmlElement>()
                          .Select(x => new {
                          errorCode = x.Attributes["code"].Value,
                          errorMessage = x.InnerText
                          });

                          foreach (var item in errors)
                          {

                          }





                          share|improve this answer























                            up vote
                            0
                            down vote










                            up vote
                            0
                            down vote









                            using SelectNodes with Cast to IEnumerable<XmlElement> type collection. then you can try to use linq get your value.



                            XmlDocument doc = new XmlDocument();
                            doc.LoadXml(xml_str);
                            var errors = doc
                            .SelectNodes("/DataChunk/ResponseChunk/Errors/error")
                            .Cast<XmlElement>()
                            .Select(x => new {
                            errorCode = x.Attributes["code"].Value,
                            errorMessage = x.InnerText
                            });

                            foreach (var item in errors)
                            {

                            }





                            share|improve this answer












                            using SelectNodes with Cast to IEnumerable<XmlElement> type collection. then you can try to use linq get your value.



                            XmlDocument doc = new XmlDocument();
                            doc.LoadXml(xml_str);
                            var errors = doc
                            .SelectNodes("/DataChunk/ResponseChunk/Errors/error")
                            .Cast<XmlElement>()
                            .Select(x => new {
                            errorCode = x.Attributes["code"].Value,
                            errorMessage = x.InnerText
                            });

                            foreach (var item in errors)
                            {

                            }






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Nov 10 at 22:47









                            D-Shih

                            24.1k61331




                            24.1k61331






























                                 

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