Sending JSON object to a tcp listener port in use Python





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I have a listener on a tcp localhost:



HOST = '127.0.0.1'  # The server's hostname or IP address
PORT = 8192 # The port used by the server
def client_socket():
while 1:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((TCP_IP,TCP_PORT))
s.listen(1)
while 1:
print 'Listening for client...'
conn, addr = s.accept()
print 'Connection address:', addr
data = conn.recv(BUFFER_SIZE)
if data == ";" :
conn.close()
print "Received all the data"
i=0
for x in param:
print x
#break
elif data:
print "received data: ", data
param.insert(i,data)
i+=1
#print "End of transmission"
s.close()


I am trying to send a JSON object to the same port on the local host:



HOST = '127.0.0.1'  # The server's hostname or IP address
PORT = 8192 # The port used by the server
def json_message(direction):

local_ip = socket.gethostbyname(socket.gethostname())
data = {
'sender' : local_ip,
'instruction' : direction
}

json_data = json.dumps(data, sort_keys=False, indent=2)
print("data %s" % json_data)

send_message(json_data)

return json_data



def send_message(data):
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.connect((HOST, PORT))
s.sendall(data)
data = s.recv(1024)

print('Received', repr(data))


However, I get a socket error:



socket.error: [Errno 98] Address already in use


What am I doing wrong? Will this work or do I need to serialize the JSON object?










share|improve this question




















  • 1





    Your error has nothing to do with JSON... Looks like you already have something running on that port

    – cricket_007
    Nov 17 '18 at 5:17











  • And youre just sending "a string", already serialized, which only happens to be parsable by a JSON parser...

    – cricket_007
    Nov 17 '18 at 5:19













  • Assuming you are running this on a Linux host execute sudo lsof -i :8192 to see if anything is using port 8192.

    – Red Cricket
    Nov 17 '18 at 5:32











  • The client_socket is listening on the port.

    – SSF
    Nov 17 '18 at 5:50


















0















I have a listener on a tcp localhost:



HOST = '127.0.0.1'  # The server's hostname or IP address
PORT = 8192 # The port used by the server
def client_socket():
while 1:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((TCP_IP,TCP_PORT))
s.listen(1)
while 1:
print 'Listening for client...'
conn, addr = s.accept()
print 'Connection address:', addr
data = conn.recv(BUFFER_SIZE)
if data == ";" :
conn.close()
print "Received all the data"
i=0
for x in param:
print x
#break
elif data:
print "received data: ", data
param.insert(i,data)
i+=1
#print "End of transmission"
s.close()


I am trying to send a JSON object to the same port on the local host:



HOST = '127.0.0.1'  # The server's hostname or IP address
PORT = 8192 # The port used by the server
def json_message(direction):

local_ip = socket.gethostbyname(socket.gethostname())
data = {
'sender' : local_ip,
'instruction' : direction
}

json_data = json.dumps(data, sort_keys=False, indent=2)
print("data %s" % json_data)

send_message(json_data)

return json_data



def send_message(data):
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.connect((HOST, PORT))
s.sendall(data)
data = s.recv(1024)

print('Received', repr(data))


However, I get a socket error:



socket.error: [Errno 98] Address already in use


What am I doing wrong? Will this work or do I need to serialize the JSON object?










share|improve this question




















  • 1





    Your error has nothing to do with JSON... Looks like you already have something running on that port

    – cricket_007
    Nov 17 '18 at 5:17











  • And youre just sending "a string", already serialized, which only happens to be parsable by a JSON parser...

    – cricket_007
    Nov 17 '18 at 5:19













  • Assuming you are running this on a Linux host execute sudo lsof -i :8192 to see if anything is using port 8192.

    – Red Cricket
    Nov 17 '18 at 5:32











  • The client_socket is listening on the port.

    – SSF
    Nov 17 '18 at 5:50














0












0








0








I have a listener on a tcp localhost:



HOST = '127.0.0.1'  # The server's hostname or IP address
PORT = 8192 # The port used by the server
def client_socket():
while 1:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((TCP_IP,TCP_PORT))
s.listen(1)
while 1:
print 'Listening for client...'
conn, addr = s.accept()
print 'Connection address:', addr
data = conn.recv(BUFFER_SIZE)
if data == ";" :
conn.close()
print "Received all the data"
i=0
for x in param:
print x
#break
elif data:
print "received data: ", data
param.insert(i,data)
i+=1
#print "End of transmission"
s.close()


I am trying to send a JSON object to the same port on the local host:



HOST = '127.0.0.1'  # The server's hostname or IP address
PORT = 8192 # The port used by the server
def json_message(direction):

local_ip = socket.gethostbyname(socket.gethostname())
data = {
'sender' : local_ip,
'instruction' : direction
}

json_data = json.dumps(data, sort_keys=False, indent=2)
print("data %s" % json_data)

send_message(json_data)

return json_data



def send_message(data):
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.connect((HOST, PORT))
s.sendall(data)
data = s.recv(1024)

print('Received', repr(data))


However, I get a socket error:



socket.error: [Errno 98] Address already in use


What am I doing wrong? Will this work or do I need to serialize the JSON object?










share|improve this question
















I have a listener on a tcp localhost:



HOST = '127.0.0.1'  # The server's hostname or IP address
PORT = 8192 # The port used by the server
def client_socket():
while 1:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((TCP_IP,TCP_PORT))
s.listen(1)
while 1:
print 'Listening for client...'
conn, addr = s.accept()
print 'Connection address:', addr
data = conn.recv(BUFFER_SIZE)
if data == ";" :
conn.close()
print "Received all the data"
i=0
for x in param:
print x
#break
elif data:
print "received data: ", data
param.insert(i,data)
i+=1
#print "End of transmission"
s.close()


I am trying to send a JSON object to the same port on the local host:



HOST = '127.0.0.1'  # The server's hostname or IP address
PORT = 8192 # The port used by the server
def json_message(direction):

local_ip = socket.gethostbyname(socket.gethostname())
data = {
'sender' : local_ip,
'instruction' : direction
}

json_data = json.dumps(data, sort_keys=False, indent=2)
print("data %s" % json_data)

send_message(json_data)

return json_data



def send_message(data):
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.connect((HOST, PORT))
s.sendall(data)
data = s.recv(1024)

print('Received', repr(data))


However, I get a socket error:



socket.error: [Errno 98] Address already in use


What am I doing wrong? Will this work or do I need to serialize the JSON object?







python json sockets tcp






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 17 '18 at 5:17









cricket_007

84.6k1147120




84.6k1147120










asked Nov 17 '18 at 5:06









SSFSSF

195217




195217








  • 1





    Your error has nothing to do with JSON... Looks like you already have something running on that port

    – cricket_007
    Nov 17 '18 at 5:17











  • And youre just sending "a string", already serialized, which only happens to be parsable by a JSON parser...

    – cricket_007
    Nov 17 '18 at 5:19













  • Assuming you are running this on a Linux host execute sudo lsof -i :8192 to see if anything is using port 8192.

    – Red Cricket
    Nov 17 '18 at 5:32











  • The client_socket is listening on the port.

    – SSF
    Nov 17 '18 at 5:50














  • 1





    Your error has nothing to do with JSON... Looks like you already have something running on that port

    – cricket_007
    Nov 17 '18 at 5:17











  • And youre just sending "a string", already serialized, which only happens to be parsable by a JSON parser...

    – cricket_007
    Nov 17 '18 at 5:19













  • Assuming you are running this on a Linux host execute sudo lsof -i :8192 to see if anything is using port 8192.

    – Red Cricket
    Nov 17 '18 at 5:32











  • The client_socket is listening on the port.

    – SSF
    Nov 17 '18 at 5:50








1




1





Your error has nothing to do with JSON... Looks like you already have something running on that port

– cricket_007
Nov 17 '18 at 5:17





Your error has nothing to do with JSON... Looks like you already have something running on that port

– cricket_007
Nov 17 '18 at 5:17













And youre just sending "a string", already serialized, which only happens to be parsable by a JSON parser...

– cricket_007
Nov 17 '18 at 5:19







And youre just sending "a string", already serialized, which only happens to be parsable by a JSON parser...

– cricket_007
Nov 17 '18 at 5:19















Assuming you are running this on a Linux host execute sudo lsof -i :8192 to see if anything is using port 8192.

– Red Cricket
Nov 17 '18 at 5:32





Assuming you are running this on a Linux host execute sudo lsof -i :8192 to see if anything is using port 8192.

– Red Cricket
Nov 17 '18 at 5:32













The client_socket is listening on the port.

– SSF
Nov 17 '18 at 5:50





The client_socket is listening on the port.

– SSF
Nov 17 '18 at 5:50












1 Answer
1






active

oldest

votes


















1














There are a few problems with your code, but the one that will likely address your issue is setting the SO_REUSEADDR socket option with:



s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)


after you create the socket (with socket.socket(...) but before you attempt to bind to an address (with s.bind().



In terms of other things, the two "halves" of the code are pretty inconsistent -- like you copied and pasted code from two different places and tried to use them?
(One uses a context manager and Python 3 print syntax while the other uses Python 2 print syntax...)



But I've written enough socket programs that I can decipher pretty much anything, so here's a working version of your code (with some pretty suboptimal parameters e.g. a buffer size of 1, but how else would you expect to catch a single ;?)



Server:



import socket

HOST = '127.0.0.1' # The server's hostname or IP address
PORT = 8192 # The port used by the server
BUFFER_SIZE = 1

def server_socket():
data =
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
s.bind((HOST,PORT))
s.listen()
while 1: # Accept connections from multiple clients
print('Listening for client...')
conn, addr = s.accept()
print('Connection address:', addr)
while 1: # Accept multiple messages from each client
buffer = conn.recv(BUFFER_SIZE)
buffer = buffer.decode()
if buffer == ";":
conn.close()
print("Received all the data")
for x in data:
print(x)
break
elif buffer:
print("received data: ", buffer)
data.append(buffer)
else:
break

server_socket()


Client:



import socket
import json

HOST = '127.0.0.1' # The server's hostname or IP address
PORT = 8192 # The port used by the server

def json_message(direction):
local_ip = socket.gethostbyname(socket.gethostname())
data = {
'sender': local_ip,
'instruction': direction
}

json_data = json.dumps(data, sort_keys=False, indent=2)
print("data %s" % json_data)

send_message(json_data + ";")

return json_data



def send_message(data):
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.connect((HOST, PORT))
s.sendall(data.encode())
data = s.recv(1024)

print('Received', repr(data))

json_message("SOME_DIRECTION")





share|improve this answer
























  • Yes your observation is correct. Just trying a few things. I am trying to get the code running in python 2 first. The server is showing an error when I try to run it. "Traceback (most recent call last): File "src/directioncontroller/client.py", line 32, in <module> server_socket() File "src/directioncontroller/client.py", line 9, in server_socket with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s: AttributeError: exit "

    – SSF
    Nov 17 '18 at 6:17






  • 1





    @SSF Does client show the same issue? an AttributeError blaming __exit__? If so, I guess 2.7 doesn't support sockets as context managers and you'd want to replace with socket.socket(...) as s with s = socket.socket(...).

    – jedwards
    Nov 17 '18 at 6:19













  • Yes, it does. Any way to do this in python 2 only?

    – SSF
    Nov 17 '18 at 6:42











  • @SSF Sure, try replacing the with socket.socket() with the s = socket.socket(...) approach as I put in my last comment.

    – jedwards
    Nov 17 '18 at 6:43












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














There are a few problems with your code, but the one that will likely address your issue is setting the SO_REUSEADDR socket option with:



s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)


after you create the socket (with socket.socket(...) but before you attempt to bind to an address (with s.bind().



In terms of other things, the two "halves" of the code are pretty inconsistent -- like you copied and pasted code from two different places and tried to use them?
(One uses a context manager and Python 3 print syntax while the other uses Python 2 print syntax...)



But I've written enough socket programs that I can decipher pretty much anything, so here's a working version of your code (with some pretty suboptimal parameters e.g. a buffer size of 1, but how else would you expect to catch a single ;?)



Server:



import socket

HOST = '127.0.0.1' # The server's hostname or IP address
PORT = 8192 # The port used by the server
BUFFER_SIZE = 1

def server_socket():
data =
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
s.bind((HOST,PORT))
s.listen()
while 1: # Accept connections from multiple clients
print('Listening for client...')
conn, addr = s.accept()
print('Connection address:', addr)
while 1: # Accept multiple messages from each client
buffer = conn.recv(BUFFER_SIZE)
buffer = buffer.decode()
if buffer == ";":
conn.close()
print("Received all the data")
for x in data:
print(x)
break
elif buffer:
print("received data: ", buffer)
data.append(buffer)
else:
break

server_socket()


Client:



import socket
import json

HOST = '127.0.0.1' # The server's hostname or IP address
PORT = 8192 # The port used by the server

def json_message(direction):
local_ip = socket.gethostbyname(socket.gethostname())
data = {
'sender': local_ip,
'instruction': direction
}

json_data = json.dumps(data, sort_keys=False, indent=2)
print("data %s" % json_data)

send_message(json_data + ";")

return json_data



def send_message(data):
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.connect((HOST, PORT))
s.sendall(data.encode())
data = s.recv(1024)

print('Received', repr(data))

json_message("SOME_DIRECTION")





share|improve this answer
























  • Yes your observation is correct. Just trying a few things. I am trying to get the code running in python 2 first. The server is showing an error when I try to run it. "Traceback (most recent call last): File "src/directioncontroller/client.py", line 32, in <module> server_socket() File "src/directioncontroller/client.py", line 9, in server_socket with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s: AttributeError: exit "

    – SSF
    Nov 17 '18 at 6:17






  • 1





    @SSF Does client show the same issue? an AttributeError blaming __exit__? If so, I guess 2.7 doesn't support sockets as context managers and you'd want to replace with socket.socket(...) as s with s = socket.socket(...).

    – jedwards
    Nov 17 '18 at 6:19













  • Yes, it does. Any way to do this in python 2 only?

    – SSF
    Nov 17 '18 at 6:42











  • @SSF Sure, try replacing the with socket.socket() with the s = socket.socket(...) approach as I put in my last comment.

    – jedwards
    Nov 17 '18 at 6:43
















1














There are a few problems with your code, but the one that will likely address your issue is setting the SO_REUSEADDR socket option with:



s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)


after you create the socket (with socket.socket(...) but before you attempt to bind to an address (with s.bind().



In terms of other things, the two "halves" of the code are pretty inconsistent -- like you copied and pasted code from two different places and tried to use them?
(One uses a context manager and Python 3 print syntax while the other uses Python 2 print syntax...)



But I've written enough socket programs that I can decipher pretty much anything, so here's a working version of your code (with some pretty suboptimal parameters e.g. a buffer size of 1, but how else would you expect to catch a single ;?)



Server:



import socket

HOST = '127.0.0.1' # The server's hostname or IP address
PORT = 8192 # The port used by the server
BUFFER_SIZE = 1

def server_socket():
data =
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
s.bind((HOST,PORT))
s.listen()
while 1: # Accept connections from multiple clients
print('Listening for client...')
conn, addr = s.accept()
print('Connection address:', addr)
while 1: # Accept multiple messages from each client
buffer = conn.recv(BUFFER_SIZE)
buffer = buffer.decode()
if buffer == ";":
conn.close()
print("Received all the data")
for x in data:
print(x)
break
elif buffer:
print("received data: ", buffer)
data.append(buffer)
else:
break

server_socket()


Client:



import socket
import json

HOST = '127.0.0.1' # The server's hostname or IP address
PORT = 8192 # The port used by the server

def json_message(direction):
local_ip = socket.gethostbyname(socket.gethostname())
data = {
'sender': local_ip,
'instruction': direction
}

json_data = json.dumps(data, sort_keys=False, indent=2)
print("data %s" % json_data)

send_message(json_data + ";")

return json_data



def send_message(data):
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.connect((HOST, PORT))
s.sendall(data.encode())
data = s.recv(1024)

print('Received', repr(data))

json_message("SOME_DIRECTION")





share|improve this answer
























  • Yes your observation is correct. Just trying a few things. I am trying to get the code running in python 2 first. The server is showing an error when I try to run it. "Traceback (most recent call last): File "src/directioncontroller/client.py", line 32, in <module> server_socket() File "src/directioncontroller/client.py", line 9, in server_socket with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s: AttributeError: exit "

    – SSF
    Nov 17 '18 at 6:17






  • 1





    @SSF Does client show the same issue? an AttributeError blaming __exit__? If so, I guess 2.7 doesn't support sockets as context managers and you'd want to replace with socket.socket(...) as s with s = socket.socket(...).

    – jedwards
    Nov 17 '18 at 6:19













  • Yes, it does. Any way to do this in python 2 only?

    – SSF
    Nov 17 '18 at 6:42











  • @SSF Sure, try replacing the with socket.socket() with the s = socket.socket(...) approach as I put in my last comment.

    – jedwards
    Nov 17 '18 at 6:43














1












1








1







There are a few problems with your code, but the one that will likely address your issue is setting the SO_REUSEADDR socket option with:



s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)


after you create the socket (with socket.socket(...) but before you attempt to bind to an address (with s.bind().



In terms of other things, the two "halves" of the code are pretty inconsistent -- like you copied and pasted code from two different places and tried to use them?
(One uses a context manager and Python 3 print syntax while the other uses Python 2 print syntax...)



But I've written enough socket programs that I can decipher pretty much anything, so here's a working version of your code (with some pretty suboptimal parameters e.g. a buffer size of 1, but how else would you expect to catch a single ;?)



Server:



import socket

HOST = '127.0.0.1' # The server's hostname or IP address
PORT = 8192 # The port used by the server
BUFFER_SIZE = 1

def server_socket():
data =
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
s.bind((HOST,PORT))
s.listen()
while 1: # Accept connections from multiple clients
print('Listening for client...')
conn, addr = s.accept()
print('Connection address:', addr)
while 1: # Accept multiple messages from each client
buffer = conn.recv(BUFFER_SIZE)
buffer = buffer.decode()
if buffer == ";":
conn.close()
print("Received all the data")
for x in data:
print(x)
break
elif buffer:
print("received data: ", buffer)
data.append(buffer)
else:
break

server_socket()


Client:



import socket
import json

HOST = '127.0.0.1' # The server's hostname or IP address
PORT = 8192 # The port used by the server

def json_message(direction):
local_ip = socket.gethostbyname(socket.gethostname())
data = {
'sender': local_ip,
'instruction': direction
}

json_data = json.dumps(data, sort_keys=False, indent=2)
print("data %s" % json_data)

send_message(json_data + ";")

return json_data



def send_message(data):
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.connect((HOST, PORT))
s.sendall(data.encode())
data = s.recv(1024)

print('Received', repr(data))

json_message("SOME_DIRECTION")





share|improve this answer













There are a few problems with your code, but the one that will likely address your issue is setting the SO_REUSEADDR socket option with:



s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)


after you create the socket (with socket.socket(...) but before you attempt to bind to an address (with s.bind().



In terms of other things, the two "halves" of the code are pretty inconsistent -- like you copied and pasted code from two different places and tried to use them?
(One uses a context manager and Python 3 print syntax while the other uses Python 2 print syntax...)



But I've written enough socket programs that I can decipher pretty much anything, so here's a working version of your code (with some pretty suboptimal parameters e.g. a buffer size of 1, but how else would you expect to catch a single ;?)



Server:



import socket

HOST = '127.0.0.1' # The server's hostname or IP address
PORT = 8192 # The port used by the server
BUFFER_SIZE = 1

def server_socket():
data =
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
s.bind((HOST,PORT))
s.listen()
while 1: # Accept connections from multiple clients
print('Listening for client...')
conn, addr = s.accept()
print('Connection address:', addr)
while 1: # Accept multiple messages from each client
buffer = conn.recv(BUFFER_SIZE)
buffer = buffer.decode()
if buffer == ";":
conn.close()
print("Received all the data")
for x in data:
print(x)
break
elif buffer:
print("received data: ", buffer)
data.append(buffer)
else:
break

server_socket()


Client:



import socket
import json

HOST = '127.0.0.1' # The server's hostname or IP address
PORT = 8192 # The port used by the server

def json_message(direction):
local_ip = socket.gethostbyname(socket.gethostname())
data = {
'sender': local_ip,
'instruction': direction
}

json_data = json.dumps(data, sort_keys=False, indent=2)
print("data %s" % json_data)

send_message(json_data + ";")

return json_data



def send_message(data):
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.connect((HOST, PORT))
s.sendall(data.encode())
data = s.recv(1024)

print('Received', repr(data))

json_message("SOME_DIRECTION")






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 17 '18 at 5:31









jedwardsjedwards

21.9k13464




21.9k13464













  • Yes your observation is correct. Just trying a few things. I am trying to get the code running in python 2 first. The server is showing an error when I try to run it. "Traceback (most recent call last): File "src/directioncontroller/client.py", line 32, in <module> server_socket() File "src/directioncontroller/client.py", line 9, in server_socket with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s: AttributeError: exit "

    – SSF
    Nov 17 '18 at 6:17






  • 1





    @SSF Does client show the same issue? an AttributeError blaming __exit__? If so, I guess 2.7 doesn't support sockets as context managers and you'd want to replace with socket.socket(...) as s with s = socket.socket(...).

    – jedwards
    Nov 17 '18 at 6:19













  • Yes, it does. Any way to do this in python 2 only?

    – SSF
    Nov 17 '18 at 6:42











  • @SSF Sure, try replacing the with socket.socket() with the s = socket.socket(...) approach as I put in my last comment.

    – jedwards
    Nov 17 '18 at 6:43



















  • Yes your observation is correct. Just trying a few things. I am trying to get the code running in python 2 first. The server is showing an error when I try to run it. "Traceback (most recent call last): File "src/directioncontroller/client.py", line 32, in <module> server_socket() File "src/directioncontroller/client.py", line 9, in server_socket with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s: AttributeError: exit "

    – SSF
    Nov 17 '18 at 6:17






  • 1





    @SSF Does client show the same issue? an AttributeError blaming __exit__? If so, I guess 2.7 doesn't support sockets as context managers and you'd want to replace with socket.socket(...) as s with s = socket.socket(...).

    – jedwards
    Nov 17 '18 at 6:19













  • Yes, it does. Any way to do this in python 2 only?

    – SSF
    Nov 17 '18 at 6:42











  • @SSF Sure, try replacing the with socket.socket() with the s = socket.socket(...) approach as I put in my last comment.

    – jedwards
    Nov 17 '18 at 6:43

















Yes your observation is correct. Just trying a few things. I am trying to get the code running in python 2 first. The server is showing an error when I try to run it. "Traceback (most recent call last): File "src/directioncontroller/client.py", line 32, in <module> server_socket() File "src/directioncontroller/client.py", line 9, in server_socket with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s: AttributeError: exit "

– SSF
Nov 17 '18 at 6:17





Yes your observation is correct. Just trying a few things. I am trying to get the code running in python 2 first. The server is showing an error when I try to run it. "Traceback (most recent call last): File "src/directioncontroller/client.py", line 32, in <module> server_socket() File "src/directioncontroller/client.py", line 9, in server_socket with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s: AttributeError: exit "

– SSF
Nov 17 '18 at 6:17




1




1





@SSF Does client show the same issue? an AttributeError blaming __exit__? If so, I guess 2.7 doesn't support sockets as context managers and you'd want to replace with socket.socket(...) as s with s = socket.socket(...).

– jedwards
Nov 17 '18 at 6:19







@SSF Does client show the same issue? an AttributeError blaming __exit__? If so, I guess 2.7 doesn't support sockets as context managers and you'd want to replace with socket.socket(...) as s with s = socket.socket(...).

– jedwards
Nov 17 '18 at 6:19















Yes, it does. Any way to do this in python 2 only?

– SSF
Nov 17 '18 at 6:42





Yes, it does. Any way to do this in python 2 only?

– SSF
Nov 17 '18 at 6:42













@SSF Sure, try replacing the with socket.socket() with the s = socket.socket(...) approach as I put in my last comment.

– jedwards
Nov 17 '18 at 6:43





@SSF Sure, try replacing the with socket.socket() with the s = socket.socket(...) approach as I put in my last comment.

– jedwards
Nov 17 '18 at 6:43




















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