How can I add a .dtd validation to an .xml file created by a .xq Query?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
So my query was working fine and I now need to verify the resulting .xml with a .dtd validation. My .xq looked like this before:
< root>
...
...
< /root>
Now it looks like this:
< !DOCTYPE root SYSTEM 'validation.dtd'>
< root>
...
...
< /root>
Running the .xq now, however, throws the following error:
XPST0003 XQuery syntax error near #...as xs:integer external; < !D#:
Expected '--' or '[CDATA[' after '< !'
Static error(s) in query
I don't know what this error means, and I'm unable to find how to fix it
Thanks in advance
xquery
asked Nov 17 '18 at 2:50
Francisco José LetterioFrancisco José Letterio
1396
add a comment |
So my query was working fine and I now need to verify the resulting .xml with a .dtd validation. My .xq looked like this before:
< root>
...
...
< /root>
Now it looks like this:
< !DOCTYPE root SYSTEM 'validation.dtd'>
< root>
...
...
< /root>
Running the .xq now, however, throws the following error:
XPST0003 XQuery syntax error near #...as xs:integer external; < !D#:
Expected '--' or '[CDATA[' after '< !'
Static error(s) in query
I don't know what this error means, and I'm unable to find how to fix it
Thanks in advance
xquery
asked Nov 17 '18 at 2:50
Francisco José LetterioFrancisco José Letterio
1396
add a comment |
So my query was working fine and I now need to verify the resulting .xml with a .dtd validation. My .xq looked like this before:
< root>
...
...
< /root>
Now it looks like this:
< !DOCTYPE root SYSTEM 'validation.dtd'>
< root>
...
...
< /root>
Running the .xq now, however, throws the following error:
XPST0003 XQuery syntax error near #...as xs:integer external; < !D#:
Expected '--' or '[CDATA[' after '< !'
Static error(s) in query
I don't know what this error means, and I'm unable to find how to fix it
Thanks in advance
xquery
asked Nov 17 '18 at 2:50
Francisco José LetterioFrancisco José Letterio
1396
So my query was working fine and I now need to verify the resulting .xml with a .dtd validation. My .xq looked like this before:
< root>
...
...
< /root>
Now it looks like this:
< !DOCTYPE root SYSTEM 'validation.dtd'>
< root>
...
...
< /root>
Running the .xq now, however, throws the following error:
XPST0003 XQuery syntax error near #...as xs:integer external; < !D#:
Expected '--' or '[CDATA[' after '< !'
Static error(s) in query
I don't know what this error means, and I'm unable to find how to fix it
Thanks in advance
xquery
xquery
asked Nov 17 '18 at 2:50
Francisco José LetterioFrancisco José Letterio
1396
asked Nov 17 '18 at 2:50
Francisco José LetterioFrancisco José Letterio
1396
edited Nov 17 '18 at 2:57
Francisco José Letterio
asked Nov 17 '18 at 2:50
Francisco José LetterioFrancisco José Letterio
1396
asked Nov 17 '18 at 2:50
Francisco José LetterioFrancisco José Letterio
1396
asked Nov 17 '18 at 2:50
Francisco José LetterioFrancisco José Letterio
1396
1396
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
To serialize an XML document with a document type declaration, use the fn:serialize() function with the doctype-system parameter:
xquery version "3.1";
fn:serialize(<root/>, map { "doctype-system": "validation.dtd" })
This produces the following string:
<!DOCTYPE root SYSTEM "validation.dtd">
<root/>
For more on this technique, see the function documentation for fn:serialize() at https://www.w3.org/TR/xpath-functions-31/#func-serialize and description of the doctype-system and doctype-public parameters in the XSLT and XQuery Serialization 3.1 Specification at https://www.w3.org/TR/xslt-xquery-serialization-31/#XML_DOCTYPE.
For processors that only support XPath 3.0 or that have not yet implemented the map(*) method of specifying serialization parameters, you can use this form:
xquery version "3.0";
declare namespace output="http://www.w3.org/2010/xslt-xquery-serialization";
fn:serialize(
<root/>,
<output:serialization-parameters>
<output:doctype-system value="validation.dtd"/>
</output:serialization-parameters>
)
answered Nov 17 '18 at 17:03
joewizjoewiz
4,0571220
I can only use XQuery 2, but thanks regardless
– Francisco José Letterio
Nov 17 '18 at 19:00
Which XQuery processor and version are you using? Many processors implemented their own version before this facility was added to the standard.
– joewiz
Nov 17 '18 at 20:59
I'm using the Saxon parser
– Francisco José Letterio
Nov 17 '18 at 21:00
Which version of Saxon?
– joewiz
Nov 17 '18 at 21:03
1
For serializing with Saxon in versions that did not yet support XPath 3.0, see thesaxon:serialize()function: saxonica.com/html/documentation/functions/saxon/serialize.html. But if you're using Saxon 7.1 or newer,fn:serialize()is supported. You may need an alternative form for specifying the serialization parameters. I'll amend the answer showing this alternate form.
– joewiz
Nov 17 '18 at 22:04
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
To serialize an XML document with a document type declaration, use the fn:serialize() function with the doctype-system parameter:
xquery version "3.1";
fn:serialize(<root/>, map { "doctype-system": "validation.dtd" })
This produces the following string:
<!DOCTYPE root SYSTEM "validation.dtd">
<root/>
For more on this technique, see the function documentation for fn:serialize() at https://www.w3.org/TR/xpath-functions-31/#func-serialize and description of the doctype-system and doctype-public parameters in the XSLT and XQuery Serialization 3.1 Specification at https://www.w3.org/TR/xslt-xquery-serialization-31/#XML_DOCTYPE.
For processors that only support XPath 3.0 or that have not yet implemented the map(*) method of specifying serialization parameters, you can use this form:
xquery version "3.0";
declare namespace output="http://www.w3.org/2010/xslt-xquery-serialization";
fn:serialize(
<root/>,
<output:serialization-parameters>
<output:doctype-system value="validation.dtd"/>
</output:serialization-parameters>
)
answered Nov 17 '18 at 17:03
joewizjoewiz
4,0571220
I can only use XQuery 2, but thanks regardless
– Francisco José Letterio
Nov 17 '18 at 19:00
Which XQuery processor and version are you using? Many processors implemented their own version before this facility was added to the standard.
– joewiz
Nov 17 '18 at 20:59
I'm using the Saxon parser
– Francisco José Letterio
Nov 17 '18 at 21:00
Which version of Saxon?
– joewiz
Nov 17 '18 at 21:03
1
For serializing with Saxon in versions that did not yet support XPath 3.0, see thesaxon:serialize()function: saxonica.com/html/documentation/functions/saxon/serialize.html. But if you're using Saxon 7.1 or newer,fn:serialize()is supported. You may need an alternative form for specifying the serialization parameters. I'll amend the answer showing this alternate form.
– joewiz
Nov 17 '18 at 22:04
add a comment |
To serialize an XML document with a document type declaration, use the fn:serialize() function with the doctype-system parameter:
xquery version "3.1";
fn:serialize(<root/>, map { "doctype-system": "validation.dtd" })
This produces the following string:
<!DOCTYPE root SYSTEM "validation.dtd">
<root/>
For more on this technique, see the function documentation for fn:serialize() at https://www.w3.org/TR/xpath-functions-31/#func-serialize and description of the doctype-system and doctype-public parameters in the XSLT and XQuery Serialization 3.1 Specification at https://www.w3.org/TR/xslt-xquery-serialization-31/#XML_DOCTYPE.
For processors that only support XPath 3.0 or that have not yet implemented the map(*) method of specifying serialization parameters, you can use this form:
xquery version "3.0";
declare namespace output="http://www.w3.org/2010/xslt-xquery-serialization";
fn:serialize(
<root/>,
<output:serialization-parameters>
<output:doctype-system value="validation.dtd"/>
</output:serialization-parameters>
)
answered Nov 17 '18 at 17:03
joewizjoewiz
4,0571220
I can only use XQuery 2, but thanks regardless
– Francisco José Letterio
Nov 17 '18 at 19:00
Which XQuery processor and version are you using? Many processors implemented their own version before this facility was added to the standard.
– joewiz
Nov 17 '18 at 20:59
I'm using the Saxon parser
– Francisco José Letterio
Nov 17 '18 at 21:00
Which version of Saxon?
– joewiz
Nov 17 '18 at 21:03
1
For serializing with Saxon in versions that did not yet support XPath 3.0, see thesaxon:serialize()function: saxonica.com/html/documentation/functions/saxon/serialize.html. But if you're using Saxon 7.1 or newer,fn:serialize()is supported. You may need an alternative form for specifying the serialization parameters. I'll amend the answer showing this alternate form.
– joewiz
Nov 17 '18 at 22:04
add a comment |
To serialize an XML document with a document type declaration, use the fn:serialize() function with the doctype-system parameter:
xquery version "3.1";
fn:serialize(<root/>, map { "doctype-system": "validation.dtd" })
This produces the following string:
<!DOCTYPE root SYSTEM "validation.dtd">
<root/>
For more on this technique, see the function documentation for fn:serialize() at https://www.w3.org/TR/xpath-functions-31/#func-serialize and description of the doctype-system and doctype-public parameters in the XSLT and XQuery Serialization 3.1 Specification at https://www.w3.org/TR/xslt-xquery-serialization-31/#XML_DOCTYPE.
For processors that only support XPath 3.0 or that have not yet implemented the map(*) method of specifying serialization parameters, you can use this form:
xquery version "3.0";
declare namespace output="http://www.w3.org/2010/xslt-xquery-serialization";
fn:serialize(
<root/>,
<output:serialization-parameters>
<output:doctype-system value="validation.dtd"/>
</output:serialization-parameters>
)
answered Nov 17 '18 at 17:03
joewizjoewiz
4,0571220
To serialize an XML document with a document type declaration, use the fn:serialize() function with the doctype-system parameter:
xquery version "3.1";
fn:serialize(<root/>, map { "doctype-system": "validation.dtd" })
This produces the following string:
<!DOCTYPE root SYSTEM "validation.dtd">
<root/>
For more on this technique, see the function documentation for fn:serialize() at https://www.w3.org/TR/xpath-functions-31/#func-serialize and description of the doctype-system and doctype-public parameters in the XSLT and XQuery Serialization 3.1 Specification at https://www.w3.org/TR/xslt-xquery-serialization-31/#XML_DOCTYPE.
For processors that only support XPath 3.0 or that have not yet implemented the map(*) method of specifying serialization parameters, you can use this form:
xquery version "3.0";
declare namespace output="http://www.w3.org/2010/xslt-xquery-serialization";
fn:serialize(
<root/>,
<output:serialization-parameters>
<output:doctype-system value="validation.dtd"/>
</output:serialization-parameters>
)
answered Nov 17 '18 at 17:03
joewizjoewiz
4,0571220
edited Nov 17 '18 at 22:09
answered Nov 17 '18 at 17:03
joewizjoewiz
4,0571220
answered Nov 17 '18 at 17:03
joewizjoewiz
4,0571220
answered Nov 17 '18 at 17:03
joewizjoewiz
4,0571220
4,0571220
I can only use XQuery 2, but thanks regardless
– Francisco José Letterio
Nov 17 '18 at 19:00
Which XQuery processor and version are you using? Many processors implemented their own version before this facility was added to the standard.
– joewiz
Nov 17 '18 at 20:59
I'm using the Saxon parser
– Francisco José Letterio
Nov 17 '18 at 21:00
Which version of Saxon?
– joewiz
Nov 17 '18 at 21:03
1
For serializing with Saxon in versions that did not yet support XPath 3.0, see thesaxon:serialize()function: saxonica.com/html/documentation/functions/saxon/serialize.html. But if you're using Saxon 7.1 or newer,fn:serialize()is supported. You may need an alternative form for specifying the serialization parameters. I'll amend the answer showing this alternate form.
– joewiz
Nov 17 '18 at 22:04
add a comment |
I can only use XQuery 2, but thanks regardless
– Francisco José Letterio
Nov 17 '18 at 19:00
Which XQuery processor and version are you using? Many processors implemented their own version before this facility was added to the standard.
– joewiz
Nov 17 '18 at 20:59
I'm using the Saxon parser
– Francisco José Letterio
Nov 17 '18 at 21:00
Which version of Saxon?
– joewiz
Nov 17 '18 at 21:03
1
For serializing with Saxon in versions that did not yet support XPath 3.0, see thesaxon:serialize()function: saxonica.com/html/documentation/functions/saxon/serialize.html. But if you're using Saxon 7.1 or newer,fn:serialize()is supported. You may need an alternative form for specifying the serialization parameters. I'll amend the answer showing this alternate form.
– joewiz
Nov 17 '18 at 22:04
I can only use XQuery 2, but thanks regardless
– Francisco José Letterio
Nov 17 '18 at 19:00
I can only use XQuery 2, but thanks regardless
– Francisco José Letterio
Nov 17 '18 at 19:00
Which XQuery processor and version are you using? Many processors implemented their own version before this facility was added to the standard.
– joewiz
Nov 17 '18 at 20:59
Which XQuery processor and version are you using? Many processors implemented their own version before this facility was added to the standard.
– joewiz
Nov 17 '18 at 20:59
I'm using the Saxon parser
– Francisco José Letterio
Nov 17 '18 at 21:00
I'm using the Saxon parser
– Francisco José Letterio
Nov 17 '18 at 21:00
Which version of Saxon?
– joewiz
Nov 17 '18 at 21:03
Which version of Saxon?
– joewiz
Nov 17 '18 at 21:03
1
1
For serializing with Saxon in versions that did not yet support XPath 3.0, see the
saxon:serialize() function: saxonica.com/html/documentation/functions/saxon/serialize.html. But if you're using Saxon 7.1 or newer, fn:serialize() is supported. You may need an alternative form for specifying the serialization parameters. I'll amend the answer showing this alternate form.– joewiz
Nov 17 '18 at 22:04
For serializing with Saxon in versions that did not yet support XPath 3.0, see the
saxon:serialize() function: saxonica.com/html/documentation/functions/saxon/serialize.html. But if you're using Saxon 7.1 or newer, fn:serialize() is supported. You may need an alternative form for specifying the serialization parameters. I'll amend the answer showing this alternate form.– joewiz
Nov 17 '18 at 22:04
add a comment |
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