Why the regular expression is not working properly
-1
I have a validation for first name and while I'm running the "Start*" it will not pass through the code while I pass the "Start$" then it will pass the string. below is the program:-
package main
import (
"fmt"
"regexp"
)
func main() {
FirstName := "Star*"
var validName = regexp.MustCompile("^[\p{L}0-9-_&$.,’'x60()!/ ]*$")
if !validName.MatchString(FirstName) {
fmt.Println("--------------", FirstName)
} else {
fmt.Println(FirstName)
}
FirstName2 := "Star$"
if !validName.MatchString(FirstName2) {
fmt.Println("--------------", FirstName2)
} else {
fmt.Println(FirstName2)
}
}
Play ground link
regex go
edited Nov 16 '18 at 8:30
Vorsprung
23.4k32246
asked Nov 16 '18 at 7:41
stackstack
165
add a comment |
-1
I have a validation for first name and while I'm running the "Start*" it will not pass through the code while I pass the "Start$" then it will pass the string. below is the program:-
package main
import (
"fmt"
"regexp"
)
func main() {
FirstName := "Star*"
var validName = regexp.MustCompile("^[\p{L}0-9-_&$.,’'x60()!/ ]*$")
if !validName.MatchString(FirstName) {
fmt.Println("--------------", FirstName)
} else {
fmt.Println(FirstName)
}
FirstName2 := "Star$"
if !validName.MatchString(FirstName2) {
fmt.Println("--------------", FirstName2)
} else {
fmt.Println(FirstName2)
}
}
Play ground link
regex go
edited Nov 16 '18 at 8:30
Vorsprung
23.4k32246
asked Nov 16 '18 at 7:41
stackstack
165
add a comment |
-1
-1
-1
I have a validation for first name and while I'm running the "Start*" it will not pass through the code while I pass the "Start$" then it will pass the string. below is the program:-
package main
import (
"fmt"
"regexp"
)
func main() {
FirstName := "Star*"
var validName = regexp.MustCompile("^[\p{L}0-9-_&$.,’'x60()!/ ]*$")
if !validName.MatchString(FirstName) {
fmt.Println("--------------", FirstName)
} else {
fmt.Println(FirstName)
}
FirstName2 := "Star$"
if !validName.MatchString(FirstName2) {
fmt.Println("--------------", FirstName2)
} else {
fmt.Println(FirstName2)
}
}
Play ground link
regex go
edited Nov 16 '18 at 8:30
Vorsprung
23.4k32246
asked Nov 16 '18 at 7:41
stackstack
165
I have a validation for first name and while I'm running the "Start*" it will not pass through the code while I pass the "Start$" then it will pass the string. below is the program:-
package main
import (
"fmt"
"regexp"
)
func main() {
FirstName := "Star*"
var validName = regexp.MustCompile("^[\p{L}0-9-_&$.,’'x60()!/ ]*$")
if !validName.MatchString(FirstName) {
fmt.Println("--------------", FirstName)
} else {
fmt.Println(FirstName)
}
FirstName2 := "Star$"
if !validName.MatchString(FirstName2) {
fmt.Println("--------------", FirstName2)
} else {
fmt.Println(FirstName2)
}
}
Play ground link
regex go
regex go
edited Nov 16 '18 at 8:30
Vorsprung
23.4k32246
asked Nov 16 '18 at 7:41
stackstack
165
edited Nov 16 '18 at 8:30
Vorsprung
23.4k32246
asked Nov 16 '18 at 7:41
stackstack
165
edited Nov 16 '18 at 8:30
Vorsprung
23.4k32246
edited Nov 16 '18 at 8:30
Vorsprung
23.4k32246
edited Nov 16 '18 at 8:30
Vorsprung
23.4k32246
23.4k32246
asked Nov 16 '18 at 7:41
stackstack
165
asked Nov 16 '18 at 7:41
stackstack
165
asked Nov 16 '18 at 7:41
stackstack
165
165
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
2
Delete the use $ inside of the
^[\p{L}0-9-_&$.,’'x60()!/ ]*$ so it would be ^[\p{L}0-9-_&.,’'x60()!/ ]*$.
answered Nov 16 '18 at 7:57
VizjereiVizjerei
629312
1
$ is a normal character inside thebraces of a character class, so that's not it
– Vorsprung
Nov 16 '18 at 8:09
@vorsprung you are correct. I've edited my answer.
– Vizjerei
Nov 16 '18 at 8:20
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
Delete the use $ inside of the
^[\p{L}0-9-_&$.,’'x60()!/ ]*$ so it would be ^[\p{L}0-9-_&.,’'x60()!/ ]*$.
answered Nov 16 '18 at 7:57
VizjereiVizjerei
629312
1
$ is a normal character inside thebraces of a character class, so that's not it
– Vorsprung
Nov 16 '18 at 8:09
@vorsprung you are correct. I've edited my answer.
– Vizjerei
Nov 16 '18 at 8:20
add a comment |
2
Delete the use $ inside of the
^[\p{L}0-9-_&$.,’'x60()!/ ]*$ so it would be ^[\p{L}0-9-_&.,’'x60()!/ ]*$.
answered Nov 16 '18 at 7:57
VizjereiVizjerei
629312
1
$ is a normal character inside thebraces of a character class, so that's not it
– Vorsprung
Nov 16 '18 at 8:09
@vorsprung you are correct. I've edited my answer.
– Vizjerei
Nov 16 '18 at 8:20
add a comment |
2
2
2
Delete the use $ inside of the
^[\p{L}0-9-_&$.,’'x60()!/ ]*$ so it would be ^[\p{L}0-9-_&.,’'x60()!/ ]*$.
answered Nov 16 '18 at 7:57
VizjereiVizjerei
629312
Delete the use $ inside of the
^[\p{L}0-9-_&$.,’'x60()!/ ]*$ so it would be ^[\p{L}0-9-_&.,’'x60()!/ ]*$.
answered Nov 16 '18 at 7:57
VizjereiVizjerei
629312
edited Nov 16 '18 at 8:19
answered Nov 16 '18 at 7:57
VizjereiVizjerei
629312
answered Nov 16 '18 at 7:57
VizjereiVizjerei
629312
answered Nov 16 '18 at 7:57
VizjereiVizjerei
629312
629312
1
$ is a normal character inside thebraces of a character class, so that's not it
– Vorsprung
Nov 16 '18 at 8:09
@vorsprung you are correct. I've edited my answer.
– Vizjerei
Nov 16 '18 at 8:20
add a comment |
1
$ is a normal character inside thebraces of a character class, so that's not it
– Vorsprung
Nov 16 '18 at 8:09
@vorsprung you are correct. I've edited my answer.
– Vizjerei
Nov 16 '18 at 8:20
1
1
$ is a normal character inside the
– Vorsprung
Nov 16 '18 at 8:09
$ is a normal character inside the
– Vorsprung
Nov 16 '18 at 8:09
@vorsprung you are correct. I've edited my answer.
– Vizjerei
Nov 16 '18 at 8:20
@vorsprung you are correct. I've edited my answer.
– Vizjerei
Nov 16 '18 at 8:20
add a comment |
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