Read all the text files in a folder and change a character in a string if it presents












0















I have a folder with csv formated documents with a .arw extension. Files are named as 1.arw, 2.arw, 3.arw ... etc.



I would like to write a code that reads all the files, checks and replaces the forwardslash / with a dash -. And finally creates new files with the replaced character.



The code I wrote as follows:



for i in range(1,6):
my_file=open("/path/"+str(i)+".arw", "r+")
str=my_file.read()

if "/" not in str:
print("There is no forwardslash")
else:
str_new = str.replace("/","-")
print(str_new)

f = open("/path/new"+str(i)+".arw", "w")
f.write(str_new)
my_file.close()


But I get an error saying:




'str' object is not callable.




How can I make it work for all the files in a folder? Apparently my for loop does not work.










share|improve this question

























  • You should not use str as a variable name, since python already uses it.

    – Bernhard
    Nov 16 '18 at 7:50






  • 1





    Any reason you prefer Python here instead of sed or awk?

    – l'L'l
    Nov 16 '18 at 7:50











  • Your code has obvious syntax errors, could you please edit to fix the indentation?

    – tripleee
    Nov 16 '18 at 7:50






  • 1





    @lagom Your edit is obviously well-intentioned, but second-guessing the OP's actual code is something we try to avoid. meta.stackoverflow.com/questions/348957/…

    – tripleee
    Nov 16 '18 at 8:04






  • 1





    My guess would be similar to yours, but again, we are not really supposed to be guessing these things. Eventually close as unclear if the OP is unable to post exactly the actual code they are having problems with.

    – tripleee
    Nov 16 '18 at 8:15
















0















I have a folder with csv formated documents with a .arw extension. Files are named as 1.arw, 2.arw, 3.arw ... etc.



I would like to write a code that reads all the files, checks and replaces the forwardslash / with a dash -. And finally creates new files with the replaced character.



The code I wrote as follows:



for i in range(1,6):
my_file=open("/path/"+str(i)+".arw", "r+")
str=my_file.read()

if "/" not in str:
print("There is no forwardslash")
else:
str_new = str.replace("/","-")
print(str_new)

f = open("/path/new"+str(i)+".arw", "w")
f.write(str_new)
my_file.close()


But I get an error saying:




'str' object is not callable.




How can I make it work for all the files in a folder? Apparently my for loop does not work.










share|improve this question

























  • You should not use str as a variable name, since python already uses it.

    – Bernhard
    Nov 16 '18 at 7:50






  • 1





    Any reason you prefer Python here instead of sed or awk?

    – l'L'l
    Nov 16 '18 at 7:50











  • Your code has obvious syntax errors, could you please edit to fix the indentation?

    – tripleee
    Nov 16 '18 at 7:50






  • 1





    @lagom Your edit is obviously well-intentioned, but second-guessing the OP's actual code is something we try to avoid. meta.stackoverflow.com/questions/348957/…

    – tripleee
    Nov 16 '18 at 8:04






  • 1





    My guess would be similar to yours, but again, we are not really supposed to be guessing these things. Eventually close as unclear if the OP is unable to post exactly the actual code they are having problems with.

    – tripleee
    Nov 16 '18 at 8:15














0












0








0








I have a folder with csv formated documents with a .arw extension. Files are named as 1.arw, 2.arw, 3.arw ... etc.



I would like to write a code that reads all the files, checks and replaces the forwardslash / with a dash -. And finally creates new files with the replaced character.



The code I wrote as follows:



for i in range(1,6):
my_file=open("/path/"+str(i)+".arw", "r+")
str=my_file.read()

if "/" not in str:
print("There is no forwardslash")
else:
str_new = str.replace("/","-")
print(str_new)

f = open("/path/new"+str(i)+".arw", "w")
f.write(str_new)
my_file.close()


But I get an error saying:




'str' object is not callable.




How can I make it work for all the files in a folder? Apparently my for loop does not work.










share|improve this question
















I have a folder with csv formated documents with a .arw extension. Files are named as 1.arw, 2.arw, 3.arw ... etc.



I would like to write a code that reads all the files, checks and replaces the forwardslash / with a dash -. And finally creates new files with the replaced character.



The code I wrote as follows:



for i in range(1,6):
my_file=open("/path/"+str(i)+".arw", "r+")
str=my_file.read()

if "/" not in str:
print("There is no forwardslash")
else:
str_new = str.replace("/","-")
print(str_new)

f = open("/path/new"+str(i)+".arw", "w")
f.write(str_new)
my_file.close()


But I get an error saying:




'str' object is not callable.




How can I make it work for all the files in a folder? Apparently my for loop does not work.







python string replace






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 '18 at 8:00









atline

3,159102138




3,159102138










asked Nov 16 '18 at 7:48









Yigit AltayYigit Altay

206




206













  • You should not use str as a variable name, since python already uses it.

    – Bernhard
    Nov 16 '18 at 7:50






  • 1





    Any reason you prefer Python here instead of sed or awk?

    – l'L'l
    Nov 16 '18 at 7:50











  • Your code has obvious syntax errors, could you please edit to fix the indentation?

    – tripleee
    Nov 16 '18 at 7:50






  • 1





    @lagom Your edit is obviously well-intentioned, but second-guessing the OP's actual code is something we try to avoid. meta.stackoverflow.com/questions/348957/…

    – tripleee
    Nov 16 '18 at 8:04






  • 1





    My guess would be similar to yours, but again, we are not really supposed to be guessing these things. Eventually close as unclear if the OP is unable to post exactly the actual code they are having problems with.

    – tripleee
    Nov 16 '18 at 8:15



















  • You should not use str as a variable name, since python already uses it.

    – Bernhard
    Nov 16 '18 at 7:50






  • 1





    Any reason you prefer Python here instead of sed or awk?

    – l'L'l
    Nov 16 '18 at 7:50











  • Your code has obvious syntax errors, could you please edit to fix the indentation?

    – tripleee
    Nov 16 '18 at 7:50






  • 1





    @lagom Your edit is obviously well-intentioned, but second-guessing the OP's actual code is something we try to avoid. meta.stackoverflow.com/questions/348957/…

    – tripleee
    Nov 16 '18 at 8:04






  • 1





    My guess would be similar to yours, but again, we are not really supposed to be guessing these things. Eventually close as unclear if the OP is unable to post exactly the actual code they are having problems with.

    – tripleee
    Nov 16 '18 at 8:15

















You should not use str as a variable name, since python already uses it.

– Bernhard
Nov 16 '18 at 7:50





You should not use str as a variable name, since python already uses it.

– Bernhard
Nov 16 '18 at 7:50




1




1





Any reason you prefer Python here instead of sed or awk?

– l'L'l
Nov 16 '18 at 7:50





Any reason you prefer Python here instead of sed or awk?

– l'L'l
Nov 16 '18 at 7:50













Your code has obvious syntax errors, could you please edit to fix the indentation?

– tripleee
Nov 16 '18 at 7:50





Your code has obvious syntax errors, could you please edit to fix the indentation?

– tripleee
Nov 16 '18 at 7:50




1




1





@lagom Your edit is obviously well-intentioned, but second-guessing the OP's actual code is something we try to avoid. meta.stackoverflow.com/questions/348957/…

– tripleee
Nov 16 '18 at 8:04





@lagom Your edit is obviously well-intentioned, but second-guessing the OP's actual code is something we try to avoid. meta.stackoverflow.com/questions/348957/…

– tripleee
Nov 16 '18 at 8:04




1




1





My guess would be similar to yours, but again, we are not really supposed to be guessing these things. Eventually close as unclear if the OP is unable to post exactly the actual code they are having problems with.

– tripleee
Nov 16 '18 at 8:15





My guess would be similar to yours, but again, we are not really supposed to be guessing these things. Eventually close as unclear if the OP is unable to post exactly the actual code they are having problems with.

– tripleee
Nov 16 '18 at 8:15












2 Answers
2






active

oldest

votes


















1














The actual error is that you are replacing the built-in str with your own variable with the same name, then try to use the built-in str() after that.



Simply renaming the variable fixes the immediate problem, but you really want to refactor the code to avoid reading the entire file into memory.



import logging
import os

for i in range(1,6):
seen_slash = False
input_filename = "/path/"+str(i)+".arw"
output_filename = "/path/new"+str(i)+".arw"
with open(input_filename, "r+") as input, open(output_filename, "w") as output:
for line in input:
if not seen_slash and "/" in line:
seen_slash = True
line_new = line.replace("/","-")
print(line_new.rstrip('n')) # don't duplicate newline
output.write(line_new)
if not seen_slash:
logging.warn("{0}: No slash found".format(input_filename))
os.unlink(output_filename)


Using logging instead of print for error messages helps because you keep standard output (the print output) separate from the diagnostics (the logging output). Notice also how the diagnostic message includes the name of the file we found the problem in.



Going back and deleting the output filename when you have examined the entire input file and not found any slashes is a mild wart, but should typically be more efficient.






share|improve this answer































    2














    This is how I would do it:



    for i in range(1,6):
    with open((str(i)+'.arw'), 'r') as f:
    data = f.readlines()

    for element in data:
    element.replace('/', '-')
    f.close()
    with open((str(i)+'.arw'), 'w') as f:
    for element in data:
    f.write(element)
    f.close()


    this is assuming from your post that you know that you have 6 files



    if you don't know how many files you have you can use the OS module to find the files in the directory.






    share|improve this answer


























    • Reading the data into a list and iterating over that list is inefficient because (a) you effectively loop over it twice, and (b) if the file is big, you use a lot of memory.

      – tripleee
      Nov 16 '18 at 8:05






    • 1





      it is an effective and easily understandable solution to the problem, as well as this, the str.replace() method is effectively the same. I am also assuming that as he is doing this his files are not too big. Thanks for the feedback though

      – hhaefliger
      Nov 16 '18 at 8:09











    • The file contents are not huge. So this works ok as well. But the strategy suggested by @triplee below is even better just in case the content is big.

      – Yigit Altay
      Nov 16 '18 at 9:10













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    2 Answers
    2






    active

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    The actual error is that you are replacing the built-in str with your own variable with the same name, then try to use the built-in str() after that.



    Simply renaming the variable fixes the immediate problem, but you really want to refactor the code to avoid reading the entire file into memory.



    import logging
    import os

    for i in range(1,6):
    seen_slash = False
    input_filename = "/path/"+str(i)+".arw"
    output_filename = "/path/new"+str(i)+".arw"
    with open(input_filename, "r+") as input, open(output_filename, "w") as output:
    for line in input:
    if not seen_slash and "/" in line:
    seen_slash = True
    line_new = line.replace("/","-")
    print(line_new.rstrip('n')) # don't duplicate newline
    output.write(line_new)
    if not seen_slash:
    logging.warn("{0}: No slash found".format(input_filename))
    os.unlink(output_filename)


    Using logging instead of print for error messages helps because you keep standard output (the print output) separate from the diagnostics (the logging output). Notice also how the diagnostic message includes the name of the file we found the problem in.



    Going back and deleting the output filename when you have examined the entire input file and not found any slashes is a mild wart, but should typically be more efficient.






    share|improve this answer




























      1














      The actual error is that you are replacing the built-in str with your own variable with the same name, then try to use the built-in str() after that.



      Simply renaming the variable fixes the immediate problem, but you really want to refactor the code to avoid reading the entire file into memory.



      import logging
      import os

      for i in range(1,6):
      seen_slash = False
      input_filename = "/path/"+str(i)+".arw"
      output_filename = "/path/new"+str(i)+".arw"
      with open(input_filename, "r+") as input, open(output_filename, "w") as output:
      for line in input:
      if not seen_slash and "/" in line:
      seen_slash = True
      line_new = line.replace("/","-")
      print(line_new.rstrip('n')) # don't duplicate newline
      output.write(line_new)
      if not seen_slash:
      logging.warn("{0}: No slash found".format(input_filename))
      os.unlink(output_filename)


      Using logging instead of print for error messages helps because you keep standard output (the print output) separate from the diagnostics (the logging output). Notice also how the diagnostic message includes the name of the file we found the problem in.



      Going back and deleting the output filename when you have examined the entire input file and not found any slashes is a mild wart, but should typically be more efficient.






      share|improve this answer


























        1












        1








        1







        The actual error is that you are replacing the built-in str with your own variable with the same name, then try to use the built-in str() after that.



        Simply renaming the variable fixes the immediate problem, but you really want to refactor the code to avoid reading the entire file into memory.



        import logging
        import os

        for i in range(1,6):
        seen_slash = False
        input_filename = "/path/"+str(i)+".arw"
        output_filename = "/path/new"+str(i)+".arw"
        with open(input_filename, "r+") as input, open(output_filename, "w") as output:
        for line in input:
        if not seen_slash and "/" in line:
        seen_slash = True
        line_new = line.replace("/","-")
        print(line_new.rstrip('n')) # don't duplicate newline
        output.write(line_new)
        if not seen_slash:
        logging.warn("{0}: No slash found".format(input_filename))
        os.unlink(output_filename)


        Using logging instead of print for error messages helps because you keep standard output (the print output) separate from the diagnostics (the logging output). Notice also how the diagnostic message includes the name of the file we found the problem in.



        Going back and deleting the output filename when you have examined the entire input file and not found any slashes is a mild wart, but should typically be more efficient.






        share|improve this answer













        The actual error is that you are replacing the built-in str with your own variable with the same name, then try to use the built-in str() after that.



        Simply renaming the variable fixes the immediate problem, but you really want to refactor the code to avoid reading the entire file into memory.



        import logging
        import os

        for i in range(1,6):
        seen_slash = False
        input_filename = "/path/"+str(i)+".arw"
        output_filename = "/path/new"+str(i)+".arw"
        with open(input_filename, "r+") as input, open(output_filename, "w") as output:
        for line in input:
        if not seen_slash and "/" in line:
        seen_slash = True
        line_new = line.replace("/","-")
        print(line_new.rstrip('n')) # don't duplicate newline
        output.write(line_new)
        if not seen_slash:
        logging.warn("{0}: No slash found".format(input_filename))
        os.unlink(output_filename)


        Using logging instead of print for error messages helps because you keep standard output (the print output) separate from the diagnostics (the logging output). Notice also how the diagnostic message includes the name of the file we found the problem in.



        Going back and deleting the output filename when you have examined the entire input file and not found any slashes is a mild wart, but should typically be more efficient.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 16 '18 at 8:16









        tripleeetripleee

        94.9k13133189




        94.9k13133189

























            2














            This is how I would do it:



            for i in range(1,6):
            with open((str(i)+'.arw'), 'r') as f:
            data = f.readlines()

            for element in data:
            element.replace('/', '-')
            f.close()
            with open((str(i)+'.arw'), 'w') as f:
            for element in data:
            f.write(element)
            f.close()


            this is assuming from your post that you know that you have 6 files



            if you don't know how many files you have you can use the OS module to find the files in the directory.






            share|improve this answer


























            • Reading the data into a list and iterating over that list is inefficient because (a) you effectively loop over it twice, and (b) if the file is big, you use a lot of memory.

              – tripleee
              Nov 16 '18 at 8:05






            • 1





              it is an effective and easily understandable solution to the problem, as well as this, the str.replace() method is effectively the same. I am also assuming that as he is doing this his files are not too big. Thanks for the feedback though

              – hhaefliger
              Nov 16 '18 at 8:09











            • The file contents are not huge. So this works ok as well. But the strategy suggested by @triplee below is even better just in case the content is big.

              – Yigit Altay
              Nov 16 '18 at 9:10


















            2














            This is how I would do it:



            for i in range(1,6):
            with open((str(i)+'.arw'), 'r') as f:
            data = f.readlines()

            for element in data:
            element.replace('/', '-')
            f.close()
            with open((str(i)+'.arw'), 'w') as f:
            for element in data:
            f.write(element)
            f.close()


            this is assuming from your post that you know that you have 6 files



            if you don't know how many files you have you can use the OS module to find the files in the directory.






            share|improve this answer


























            • Reading the data into a list and iterating over that list is inefficient because (a) you effectively loop over it twice, and (b) if the file is big, you use a lot of memory.

              – tripleee
              Nov 16 '18 at 8:05






            • 1





              it is an effective and easily understandable solution to the problem, as well as this, the str.replace() method is effectively the same. I am also assuming that as he is doing this his files are not too big. Thanks for the feedback though

              – hhaefliger
              Nov 16 '18 at 8:09











            • The file contents are not huge. So this works ok as well. But the strategy suggested by @triplee below is even better just in case the content is big.

              – Yigit Altay
              Nov 16 '18 at 9:10
















            2












            2








            2







            This is how I would do it:



            for i in range(1,6):
            with open((str(i)+'.arw'), 'r') as f:
            data = f.readlines()

            for element in data:
            element.replace('/', '-')
            f.close()
            with open((str(i)+'.arw'), 'w') as f:
            for element in data:
            f.write(element)
            f.close()


            this is assuming from your post that you know that you have 6 files



            if you don't know how many files you have you can use the OS module to find the files in the directory.






            share|improve this answer















            This is how I would do it:



            for i in range(1,6):
            with open((str(i)+'.arw'), 'r') as f:
            data = f.readlines()

            for element in data:
            element.replace('/', '-')
            f.close()
            with open((str(i)+'.arw'), 'w') as f:
            for element in data:
            f.write(element)
            f.close()


            this is assuming from your post that you know that you have 6 files



            if you don't know how many files you have you can use the OS module to find the files in the directory.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 16 '18 at 8:03









            kimo26

            806




            806










            answered Nov 16 '18 at 7:59









            hhaefligerhhaefliger

            29712




            29712













            • Reading the data into a list and iterating over that list is inefficient because (a) you effectively loop over it twice, and (b) if the file is big, you use a lot of memory.

              – tripleee
              Nov 16 '18 at 8:05






            • 1





              it is an effective and easily understandable solution to the problem, as well as this, the str.replace() method is effectively the same. I am also assuming that as he is doing this his files are not too big. Thanks for the feedback though

              – hhaefliger
              Nov 16 '18 at 8:09











            • The file contents are not huge. So this works ok as well. But the strategy suggested by @triplee below is even better just in case the content is big.

              – Yigit Altay
              Nov 16 '18 at 9:10





















            • Reading the data into a list and iterating over that list is inefficient because (a) you effectively loop over it twice, and (b) if the file is big, you use a lot of memory.

              – tripleee
              Nov 16 '18 at 8:05






            • 1





              it is an effective and easily understandable solution to the problem, as well as this, the str.replace() method is effectively the same. I am also assuming that as he is doing this his files are not too big. Thanks for the feedback though

              – hhaefliger
              Nov 16 '18 at 8:09











            • The file contents are not huge. So this works ok as well. But the strategy suggested by @triplee below is even better just in case the content is big.

              – Yigit Altay
              Nov 16 '18 at 9:10



















            Reading the data into a list and iterating over that list is inefficient because (a) you effectively loop over it twice, and (b) if the file is big, you use a lot of memory.

            – tripleee
            Nov 16 '18 at 8:05





            Reading the data into a list and iterating over that list is inefficient because (a) you effectively loop over it twice, and (b) if the file is big, you use a lot of memory.

            – tripleee
            Nov 16 '18 at 8:05




            1




            1





            it is an effective and easily understandable solution to the problem, as well as this, the str.replace() method is effectively the same. I am also assuming that as he is doing this his files are not too big. Thanks for the feedback though

            – hhaefliger
            Nov 16 '18 at 8:09





            it is an effective and easily understandable solution to the problem, as well as this, the str.replace() method is effectively the same. I am also assuming that as he is doing this his files are not too big. Thanks for the feedback though

            – hhaefliger
            Nov 16 '18 at 8:09













            The file contents are not huge. So this works ok as well. But the strategy suggested by @triplee below is even better just in case the content is big.

            – Yigit Altay
            Nov 16 '18 at 9:10







            The file contents are not huge. So this works ok as well. But the strategy suggested by @triplee below is even better just in case the content is big.

            – Yigit Altay
            Nov 16 '18 at 9:10




















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