Suppress “val it” output in Standard ML
I'm writing a "script" in Standard ML (SML/NJ) that sets up the interactive environment to my liking. The last thing the script does is print out a message indicating everything went smoothly. Essentially, the last line is this:
print "SML is ready.n";
When I run the script, all goes well but the SML interpreter displays the return value from the print function.
SML is ready.
val it = () : unit
-
Since I'm merely printing something to the screen, how can I suppress the "val it = () : unit" output so that all I see is the "SML is ready" message followed by the interpreter prompt?
sml smlnj
asked Aug 12 '09 at 9:30
Barry BrownBarry Brown
13.5k116098
add a comment |
I'm writing a "script" in Standard ML (SML/NJ) that sets up the interactive environment to my liking. The last thing the script does is print out a message indicating everything went smoothly. Essentially, the last line is this:
print "SML is ready.n";
When I run the script, all goes well but the SML interpreter displays the return value from the print function.
SML is ready.
val it = () : unit
-
Since I'm merely printing something to the screen, how can I suppress the "val it = () : unit" output so that all I see is the "SML is ready" message followed by the interpreter prompt?
sml smlnj
asked Aug 12 '09 at 9:30
Barry BrownBarry Brown
13.5k116098
add a comment |
I'm writing a "script" in Standard ML (SML/NJ) that sets up the interactive environment to my liking. The last thing the script does is print out a message indicating everything went smoothly. Essentially, the last line is this:
print "SML is ready.n";
When I run the script, all goes well but the SML interpreter displays the return value from the print function.
SML is ready.
val it = () : unit
-
Since I'm merely printing something to the screen, how can I suppress the "val it = () : unit" output so that all I see is the "SML is ready" message followed by the interpreter prompt?
sml smlnj
asked Aug 12 '09 at 9:30
Barry BrownBarry Brown
13.5k116098
I'm writing a "script" in Standard ML (SML/NJ) that sets up the interactive environment to my liking. The last thing the script does is print out a message indicating everything went smoothly. Essentially, the last line is this:
print "SML is ready.n";
When I run the script, all goes well but the SML interpreter displays the return value from the print function.
SML is ready.
val it = () : unit
-
Since I'm merely printing something to the screen, how can I suppress the "val it = () : unit" output so that all I see is the "SML is ready" message followed by the interpreter prompt?
sml smlnj
sml smlnj
asked Aug 12 '09 at 9:30
Barry BrownBarry Brown
13.5k116098
asked Aug 12 '09 at 9:30
Barry BrownBarry Brown
13.5k116098
edited Aug 12 '09 at 18:08
Barry Brown
asked Aug 12 '09 at 9:30
Barry BrownBarry Brown
13.5k116098
asked Aug 12 '09 at 9:30
Barry BrownBarry Brown
13.5k116098
asked Aug 12 '09 at 9:30
Barry BrownBarry Brown
13.5k116098
13.5k116098
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
To surpress the SML-NJ prompt and response, use the following assignment.
Compiler.Control.Print.out := {say=fn _=>(), flush=fn()=>()};
print "I don't show my type";
I don't show my type
although I don't see why the print function returning the type is bad.
The say function controls what is printed out.
There is a larger example in the following SML/NJ notes http://www.cs.cornell.edu/riccardo/prog-smlnj/notes-011001.pdf
The useSilently function can be used to load a file but without displaying any output
associated with the loading
fun useSilently (s) = let
val saved = !Compiler.Control.Print.out
fun done () = Compiler.Control.Print.out := saved
in
Compiler.Control.Print.out := {say = fn _ => (), flush = fn () => ()}
(use (s); done ()) handle _ => done ()
end
This is essentially changing the say function to do nothing and then setting it back at the end.
answered Aug 15 '09 at 19:17
pjppjp
12.5k32851
add a comment |
Use this:
val _ = print "I don't show my type";
edited Jan 18 '13 at 1:32
Andreas Rossberg
27.1k24865
answered Jan 17 '13 at 22:14
VerbalVerbal
311
add a comment |
In Moscow ML you can run the REPL without declaration output with
mosml -quietdec file.sml
answered Nov 16 '18 at 6:58
Simon ShineSimon Shine
9,92413049
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
To surpress the SML-NJ prompt and response, use the following assignment.
Compiler.Control.Print.out := {say=fn _=>(), flush=fn()=>()};
print "I don't show my type";
I don't show my type
although I don't see why the print function returning the type is bad.
The say function controls what is printed out.
There is a larger example in the following SML/NJ notes http://www.cs.cornell.edu/riccardo/prog-smlnj/notes-011001.pdf
The useSilently function can be used to load a file but without displaying any output
associated with the loading
fun useSilently (s) = let
val saved = !Compiler.Control.Print.out
fun done () = Compiler.Control.Print.out := saved
in
Compiler.Control.Print.out := {say = fn _ => (), flush = fn () => ()}
(use (s); done ()) handle _ => done ()
end
This is essentially changing the say function to do nothing and then setting it back at the end.
answered Aug 15 '09 at 19:17
pjppjp
12.5k32851
add a comment |
To surpress the SML-NJ prompt and response, use the following assignment.
Compiler.Control.Print.out := {say=fn _=>(), flush=fn()=>()};
print "I don't show my type";
I don't show my type
although I don't see why the print function returning the type is bad.
The say function controls what is printed out.
There is a larger example in the following SML/NJ notes http://www.cs.cornell.edu/riccardo/prog-smlnj/notes-011001.pdf
The useSilently function can be used to load a file but without displaying any output
associated with the loading
fun useSilently (s) = let
val saved = !Compiler.Control.Print.out
fun done () = Compiler.Control.Print.out := saved
in
Compiler.Control.Print.out := {say = fn _ => (), flush = fn () => ()}
(use (s); done ()) handle _ => done ()
end
This is essentially changing the say function to do nothing and then setting it back at the end.
answered Aug 15 '09 at 19:17
pjppjp
12.5k32851
add a comment |
To surpress the SML-NJ prompt and response, use the following assignment.
Compiler.Control.Print.out := {say=fn _=>(), flush=fn()=>()};
print "I don't show my type";
I don't show my type
although I don't see why the print function returning the type is bad.
The say function controls what is printed out.
There is a larger example in the following SML/NJ notes http://www.cs.cornell.edu/riccardo/prog-smlnj/notes-011001.pdf
The useSilently function can be used to load a file but without displaying any output
associated with the loading
fun useSilently (s) = let
val saved = !Compiler.Control.Print.out
fun done () = Compiler.Control.Print.out := saved
in
Compiler.Control.Print.out := {say = fn _ => (), flush = fn () => ()}
(use (s); done ()) handle _ => done ()
end
This is essentially changing the say function to do nothing and then setting it back at the end.
answered Aug 15 '09 at 19:17
pjppjp
12.5k32851
To surpress the SML-NJ prompt and response, use the following assignment.
Compiler.Control.Print.out := {say=fn _=>(), flush=fn()=>()};
print "I don't show my type";
I don't show my type
although I don't see why the print function returning the type is bad.
The say function controls what is printed out.
There is a larger example in the following SML/NJ notes http://www.cs.cornell.edu/riccardo/prog-smlnj/notes-011001.pdf
The useSilently function can be used to load a file but without displaying any output
associated with the loading
fun useSilently (s) = let
val saved = !Compiler.Control.Print.out
fun done () = Compiler.Control.Print.out := saved
in
Compiler.Control.Print.out := {say = fn _ => (), flush = fn () => ()}
(use (s); done ()) handle _ => done ()
end
This is essentially changing the say function to do nothing and then setting it back at the end.
answered Aug 15 '09 at 19:17
pjppjp
12.5k32851
edited Aug 17 '09 at 17:01
answered Aug 15 '09 at 19:17
pjppjp
12.5k32851
answered Aug 15 '09 at 19:17
pjppjp
12.5k32851
answered Aug 15 '09 at 19:17
pjppjp
12.5k32851
12.5k32851
add a comment |
add a comment |
Use this:
val _ = print "I don't show my type";
edited Jan 18 '13 at 1:32
Andreas Rossberg
27.1k24865
answered Jan 17 '13 at 22:14
VerbalVerbal
311
add a comment |
Use this:
val _ = print "I don't show my type";
edited Jan 18 '13 at 1:32
Andreas Rossberg
27.1k24865
answered Jan 17 '13 at 22:14
VerbalVerbal
311
add a comment |
Use this:
val _ = print "I don't show my type";
edited Jan 18 '13 at 1:32
Andreas Rossberg
27.1k24865
answered Jan 17 '13 at 22:14
VerbalVerbal
311
Use this:
val _ = print "I don't show my type";
edited Jan 18 '13 at 1:32
Andreas Rossberg
27.1k24865
answered Jan 17 '13 at 22:14
VerbalVerbal
311
edited Jan 18 '13 at 1:32
Andreas Rossberg
27.1k24865
edited Jan 18 '13 at 1:32
Andreas Rossberg
27.1k24865
edited Jan 18 '13 at 1:32
Andreas Rossberg
27.1k24865
27.1k24865
answered Jan 17 '13 at 22:14
VerbalVerbal
311
answered Jan 17 '13 at 22:14
VerbalVerbal
311
answered Jan 17 '13 at 22:14
VerbalVerbal
311
311
add a comment |
add a comment |
In Moscow ML you can run the REPL without declaration output with
mosml -quietdec file.sml
answered Nov 16 '18 at 6:58
Simon ShineSimon Shine
9,92413049
add a comment |
In Moscow ML you can run the REPL without declaration output with
mosml -quietdec file.sml
answered Nov 16 '18 at 6:58
Simon ShineSimon Shine
9,92413049
add a comment |
In Moscow ML you can run the REPL without declaration output with
mosml -quietdec file.sml
answered Nov 16 '18 at 6:58
Simon ShineSimon Shine
9,92413049
In Moscow ML you can run the REPL without declaration output with
mosml -quietdec file.sml
answered Nov 16 '18 at 6:58
Simon ShineSimon Shine
9,92413049
answered Nov 16 '18 at 6:58
Simon ShineSimon Shine
9,92413049
answered Nov 16 '18 at 6:58
Simon ShineSimon Shine
9,92413049
answered Nov 16 '18 at 6:58
Simon ShineSimon Shine
9,92413049
9,92413049
add a comment |
add a comment |
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