Click event only displays data after 2nd click












0















I was looking at the jQuery.ajax() method to store a piece of JSON data in var d. I noticed in the console that after the initial button click, the var is stored but it will not display until the 2nd click. Can someone elaborate on this and propose a solution?



    var d;
$(document).ready(function () {
$('#Weather').click(function () {
var requestData = $('#City').val() + ',' + $('#Country').val();
var unit = 'imperial';
var key = '..........................';
$.ajax({
url: 'http://api.openweathermap.org/data/2.5/weather',
method: 'get',
data: { q: requestData, units: unit, APPID: key },
dataType: 'json',
success: function (data) {
d = data.main.temp;
}
});
if (d >= 40) {
document.getElementById("Text").value = "Value = " + d + " °";
}
else if (d < 40) {
document.getElementById("Text1").value = "Value = " + d + " °";
}
});
});

<table>
<tr>
<td>Enter City</td>
<td><input type="text" id="City" /></td>
</tr>
<tr>
<td>Enter Country</td>
<td><input type="text" id="Country" /></td>
</tr>
</table>
<button id="Weather" >Get d</button>
<input type="text" id="Text" value="T °" />
<input type="text" id="Text1" value="T °" />


This is the JSON



    "main": {
"temp": 37.38,
"pressure": 1030,
"humidity": 36,
"temp_min": 35.06,
"temp_max": 39.2
},


Thanks.










share|improve this question



























    0















    I was looking at the jQuery.ajax() method to store a piece of JSON data in var d. I noticed in the console that after the initial button click, the var is stored but it will not display until the 2nd click. Can someone elaborate on this and propose a solution?



        var d;
    $(document).ready(function () {
    $('#Weather').click(function () {
    var requestData = $('#City').val() + ',' + $('#Country').val();
    var unit = 'imperial';
    var key = '..........................';
    $.ajax({
    url: 'http://api.openweathermap.org/data/2.5/weather',
    method: 'get',
    data: { q: requestData, units: unit, APPID: key },
    dataType: 'json',
    success: function (data) {
    d = data.main.temp;
    }
    });
    if (d >= 40) {
    document.getElementById("Text").value = "Value = " + d + " °";
    }
    else if (d < 40) {
    document.getElementById("Text1").value = "Value = " + d + " °";
    }
    });
    });

    <table>
    <tr>
    <td>Enter City</td>
    <td><input type="text" id="City" /></td>
    </tr>
    <tr>
    <td>Enter Country</td>
    <td><input type="text" id="Country" /></td>
    </tr>
    </table>
    <button id="Weather" >Get d</button>
    <input type="text" id="Text" value="T °" />
    <input type="text" id="Text1" value="T °" />


    This is the JSON



        "main": {
    "temp": 37.38,
    "pressure": 1030,
    "humidity": 36,
    "temp_min": 35.06,
    "temp_max": 39.2
    },


    Thanks.










    share|improve this question

























      0












      0








      0








      I was looking at the jQuery.ajax() method to store a piece of JSON data in var d. I noticed in the console that after the initial button click, the var is stored but it will not display until the 2nd click. Can someone elaborate on this and propose a solution?



          var d;
      $(document).ready(function () {
      $('#Weather').click(function () {
      var requestData = $('#City').val() + ',' + $('#Country').val();
      var unit = 'imperial';
      var key = '..........................';
      $.ajax({
      url: 'http://api.openweathermap.org/data/2.5/weather',
      method: 'get',
      data: { q: requestData, units: unit, APPID: key },
      dataType: 'json',
      success: function (data) {
      d = data.main.temp;
      }
      });
      if (d >= 40) {
      document.getElementById("Text").value = "Value = " + d + " °";
      }
      else if (d < 40) {
      document.getElementById("Text1").value = "Value = " + d + " °";
      }
      });
      });

      <table>
      <tr>
      <td>Enter City</td>
      <td><input type="text" id="City" /></td>
      </tr>
      <tr>
      <td>Enter Country</td>
      <td><input type="text" id="Country" /></td>
      </tr>
      </table>
      <button id="Weather" >Get d</button>
      <input type="text" id="Text" value="T °" />
      <input type="text" id="Text1" value="T °" />


      This is the JSON



          "main": {
      "temp": 37.38,
      "pressure": 1030,
      "humidity": 36,
      "temp_min": 35.06,
      "temp_max": 39.2
      },


      Thanks.










      share|improve this question














      I was looking at the jQuery.ajax() method to store a piece of JSON data in var d. I noticed in the console that after the initial button click, the var is stored but it will not display until the 2nd click. Can someone elaborate on this and propose a solution?



          var d;
      $(document).ready(function () {
      $('#Weather').click(function () {
      var requestData = $('#City').val() + ',' + $('#Country').val();
      var unit = 'imperial';
      var key = '..........................';
      $.ajax({
      url: 'http://api.openweathermap.org/data/2.5/weather',
      method: 'get',
      data: { q: requestData, units: unit, APPID: key },
      dataType: 'json',
      success: function (data) {
      d = data.main.temp;
      }
      });
      if (d >= 40) {
      document.getElementById("Text").value = "Value = " + d + " °";
      }
      else if (d < 40) {
      document.getElementById("Text1").value = "Value = " + d + " °";
      }
      });
      });

      <table>
      <tr>
      <td>Enter City</td>
      <td><input type="text" id="City" /></td>
      </tr>
      <tr>
      <td>Enter Country</td>
      <td><input type="text" id="Country" /></td>
      </tr>
      </table>
      <button id="Weather" >Get d</button>
      <input type="text" id="Text" value="T °" />
      <input type="text" id="Text1" value="T °" />


      This is the JSON



          "main": {
      "temp": 37.38,
      "pressure": 1030,
      "humidity": 36,
      "temp_min": 35.06,
      "temp_max": 39.2
      },


      Thanks.







      javascript jquery






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      asked Nov 16 '18 at 6:55









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          With if/else outside the AJAX call, it gets executed immediately after sending the call i.e. d is undefined then and both conditions fails.



          Hence, move if/else inside success callback as the value of d has been updated by then.



          $('#Weather').click(function () {
          var requestData = $('#City').val() + ',' + $('#Country').val();
          var unit = 'imperial';
          var key = '..........................';
          $.ajax({
          url: 'http://api.openweathermap.org/data/2.5/weather',
          method: 'get',
          data: { q: requestData, units: unit, APPID: key },
          dataType: 'json',
          success: function (data) {
          d = data.main.temp;
          if (d >= 40) {
          document.getElementById("Text").value = "Value = " + d + " °";
          }
          else if (d < 40) {
          document.getElementById("Text1").value = "Value = " + d + " °";
          }
          }
          });

          });





          share|improve this answer























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            active

            oldest

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            active

            oldest

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            1














            With if/else outside the AJAX call, it gets executed immediately after sending the call i.e. d is undefined then and both conditions fails.



            Hence, move if/else inside success callback as the value of d has been updated by then.



            $('#Weather').click(function () {
            var requestData = $('#City').val() + ',' + $('#Country').val();
            var unit = 'imperial';
            var key = '..........................';
            $.ajax({
            url: 'http://api.openweathermap.org/data/2.5/weather',
            method: 'get',
            data: { q: requestData, units: unit, APPID: key },
            dataType: 'json',
            success: function (data) {
            d = data.main.temp;
            if (d >= 40) {
            document.getElementById("Text").value = "Value = " + d + " °";
            }
            else if (d < 40) {
            document.getElementById("Text1").value = "Value = " + d + " °";
            }
            }
            });

            });





            share|improve this answer




























              1














              With if/else outside the AJAX call, it gets executed immediately after sending the call i.e. d is undefined then and both conditions fails.



              Hence, move if/else inside success callback as the value of d has been updated by then.



              $('#Weather').click(function () {
              var requestData = $('#City').val() + ',' + $('#Country').val();
              var unit = 'imperial';
              var key = '..........................';
              $.ajax({
              url: 'http://api.openweathermap.org/data/2.5/weather',
              method: 'get',
              data: { q: requestData, units: unit, APPID: key },
              dataType: 'json',
              success: function (data) {
              d = data.main.temp;
              if (d >= 40) {
              document.getElementById("Text").value = "Value = " + d + " °";
              }
              else if (d < 40) {
              document.getElementById("Text1").value = "Value = " + d + " °";
              }
              }
              });

              });





              share|improve this answer


























                1












                1








                1







                With if/else outside the AJAX call, it gets executed immediately after sending the call i.e. d is undefined then and both conditions fails.



                Hence, move if/else inside success callback as the value of d has been updated by then.



                $('#Weather').click(function () {
                var requestData = $('#City').val() + ',' + $('#Country').val();
                var unit = 'imperial';
                var key = '..........................';
                $.ajax({
                url: 'http://api.openweathermap.org/data/2.5/weather',
                method: 'get',
                data: { q: requestData, units: unit, APPID: key },
                dataType: 'json',
                success: function (data) {
                d = data.main.temp;
                if (d >= 40) {
                document.getElementById("Text").value = "Value = " + d + " °";
                }
                else if (d < 40) {
                document.getElementById("Text1").value = "Value = " + d + " °";
                }
                }
                });

                });





                share|improve this answer













                With if/else outside the AJAX call, it gets executed immediately after sending the call i.e. d is undefined then and both conditions fails.



                Hence, move if/else inside success callback as the value of d has been updated by then.



                $('#Weather').click(function () {
                var requestData = $('#City').val() + ',' + $('#Country').val();
                var unit = 'imperial';
                var key = '..........................';
                $.ajax({
                url: 'http://api.openweathermap.org/data/2.5/weather',
                method: 'get',
                data: { q: requestData, units: unit, APPID: key },
                dataType: 'json',
                success: function (data) {
                d = data.main.temp;
                if (d >= 40) {
                document.getElementById("Text").value = "Value = " + d + " °";
                }
                else if (d < 40) {
                document.getElementById("Text1").value = "Value = " + d + " °";
                }
                }
                });

                });






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 16 '18 at 6:57









                Nikhil AggarwalNikhil Aggarwal

                24.1k32848




                24.1k32848
































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