sql python The value entered in the table is set first, the second is null
0
i create table
def sql_table_strategy():
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
cursor.execute("CREATE TABLE IF NOT EXISTS strategy"
"(stra TEXT NOT NULL,"
"probability TEXT NOT NULL,"
" chat_id INTEGER UNIQUE)")
conn.commit()
cursor.close()
conn.close()
integraite strategy
def strategy_add(stra, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (stra, ChatID)
sql = "INSERT OR IGNORE INTO strategy (stra,chat_id) VALUES (?,?)"
cursor.execute(sql, val)
conn.commit()
cursor.close()
conn.close()
add probability
def pr_add(probability, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (probability,ChatID)
sql = "INSERT OR IGNORE INTO strategy (probability,chat_id) VALUES (?,?)"
cursor.execute(sql, val)
conn.close()
conn.close()
when I add the first strategy and then I add probability but in Columns probability is null
python sql bots telegram
edited Nov 16 '18 at 9:35
Luke Woodward
45.7k126688
asked Nov 16 '18 at 8:51
Georgy GaguaGeorgy Gagua
1
add a comment |
0
i create table
def sql_table_strategy():
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
cursor.execute("CREATE TABLE IF NOT EXISTS strategy"
"(stra TEXT NOT NULL,"
"probability TEXT NOT NULL,"
" chat_id INTEGER UNIQUE)")
conn.commit()
cursor.close()
conn.close()
integraite strategy
def strategy_add(stra, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (stra, ChatID)
sql = "INSERT OR IGNORE INTO strategy (stra,chat_id) VALUES (?,?)"
cursor.execute(sql, val)
conn.commit()
cursor.close()
conn.close()
add probability
def pr_add(probability, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (probability,ChatID)
sql = "INSERT OR IGNORE INTO strategy (probability,chat_id) VALUES (?,?)"
cursor.execute(sql, val)
conn.close()
conn.close()
when I add the first strategy and then I add probability but in Columns probability is null
python sql bots telegram
edited Nov 16 '18 at 9:35
Luke Woodward
45.7k126688
asked Nov 16 '18 at 8:51
Georgy GaguaGeorgy Gagua
1
you cant insert a value in an existing row using insert. if you want to change an existing column use update w3schools.com/sql/sql_update.asp.
– Florian H
Nov 16 '18 at 8:55
add a comment |
0
0
0
i create table
def sql_table_strategy():
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
cursor.execute("CREATE TABLE IF NOT EXISTS strategy"
"(stra TEXT NOT NULL,"
"probability TEXT NOT NULL,"
" chat_id INTEGER UNIQUE)")
conn.commit()
cursor.close()
conn.close()
integraite strategy
def strategy_add(stra, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (stra, ChatID)
sql = "INSERT OR IGNORE INTO strategy (stra,chat_id) VALUES (?,?)"
cursor.execute(sql, val)
conn.commit()
cursor.close()
conn.close()
add probability
def pr_add(probability, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (probability,ChatID)
sql = "INSERT OR IGNORE INTO strategy (probability,chat_id) VALUES (?,?)"
cursor.execute(sql, val)
conn.close()
conn.close()
when I add the first strategy and then I add probability but in Columns probability is null
python sql bots telegram
edited Nov 16 '18 at 9:35
Luke Woodward
45.7k126688
asked Nov 16 '18 at 8:51
Georgy GaguaGeorgy Gagua
1
i create table
def sql_table_strategy():
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
cursor.execute("CREATE TABLE IF NOT EXISTS strategy"
"(stra TEXT NOT NULL,"
"probability TEXT NOT NULL,"
" chat_id INTEGER UNIQUE)")
conn.commit()
cursor.close()
conn.close()
integraite strategy
def strategy_add(stra, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (stra, ChatID)
sql = "INSERT OR IGNORE INTO strategy (stra,chat_id) VALUES (?,?)"
cursor.execute(sql, val)
conn.commit()
cursor.close()
conn.close()
add probability
def pr_add(probability, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (probability,ChatID)
sql = "INSERT OR IGNORE INTO strategy (probability,chat_id) VALUES (?,?)"
cursor.execute(sql, val)
conn.close()
conn.close()
when I add the first strategy and then I add probability but in Columns probability is null
python sql bots telegram
python sql bots telegram
edited Nov 16 '18 at 9:35
Luke Woodward
45.7k126688
asked Nov 16 '18 at 8:51
Georgy GaguaGeorgy Gagua
1
edited Nov 16 '18 at 9:35
Luke Woodward
45.7k126688
asked Nov 16 '18 at 8:51
Georgy GaguaGeorgy Gagua
1
edited Nov 16 '18 at 9:35
Luke Woodward
45.7k126688
edited Nov 16 '18 at 9:35
Luke Woodward
45.7k126688
edited Nov 16 '18 at 9:35
Luke Woodward
45.7k126688
45.7k126688
asked Nov 16 '18 at 8:51
Georgy GaguaGeorgy Gagua
1
asked Nov 16 '18 at 8:51
Georgy GaguaGeorgy Gagua
1
asked Nov 16 '18 at 8:51
Georgy GaguaGeorgy Gagua
1
1
you cant insert a value in an existing row using insert. if you want to change an existing column use update w3schools.com/sql/sql_update.asp.
– Florian H
Nov 16 '18 at 8:55
add a comment |
you cant insert a value in an existing row using insert. if you want to change an existing column use update w3schools.com/sql/sql_update.asp.
– Florian H
Nov 16 '18 at 8:55
you cant insert a value in an existing row using insert. if you want to change an existing column use update w3schools.com/sql/sql_update.asp.
– Florian H
Nov 16 '18 at 8:55
you cant insert a value in an existing row using insert. if you want to change an existing column use update w3schools.com/sql/sql_update.asp.
– Florian H
Nov 16 '18 at 8:55
add a comment |
1 Answer
1
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oldest
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A solution for your problem.
def pr_add(probability, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (probability,ChatID)
sql = "UPDATE strategy SET probability = ? WHERE chat_id = ?" --Change is here
cursor.execute(sql, val)
conn.close()
conn.close()
answered Nov 16 '18 at 9:49
Nishant GuptaNishant Gupta
2,5641513
add a comment |
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1 Answer
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1 Answer
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0
A solution for your problem.
def pr_add(probability, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (probability,ChatID)
sql = "UPDATE strategy SET probability = ? WHERE chat_id = ?" --Change is here
cursor.execute(sql, val)
conn.close()
conn.close()
answered Nov 16 '18 at 9:49
Nishant GuptaNishant Gupta
2,5641513
add a comment |
0
A solution for your problem.
def pr_add(probability, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (probability,ChatID)
sql = "UPDATE strategy SET probability = ? WHERE chat_id = ?" --Change is here
cursor.execute(sql, val)
conn.close()
conn.close()
answered Nov 16 '18 at 9:49
Nishant GuptaNishant Gupta
2,5641513
add a comment |
0
0
0
A solution for your problem.
def pr_add(probability, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (probability,ChatID)
sql = "UPDATE strategy SET probability = ? WHERE chat_id = ?" --Change is here
cursor.execute(sql, val)
conn.close()
conn.close()
answered Nov 16 '18 at 9:49
Nishant GuptaNishant Gupta
2,5641513
A solution for your problem.
def pr_add(probability, ChatID):
conn = sqlite3.connect('strategy.db', check_same_thread=False)
cursor = conn.cursor()
val = (probability,ChatID)
sql = "UPDATE strategy SET probability = ? WHERE chat_id = ?" --Change is here
cursor.execute(sql, val)
conn.close()
conn.close()
answered Nov 16 '18 at 9:49
Nishant GuptaNishant Gupta
2,5641513
edited Nov 16 '18 at 9:59
answered Nov 16 '18 at 9:49
Nishant GuptaNishant Gupta
2,5641513
answered Nov 16 '18 at 9:49
Nishant GuptaNishant Gupta
2,5641513
answered Nov 16 '18 at 9:49
Nishant GuptaNishant Gupta
2,5641513
2,5641513
add a comment |
add a comment |
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you cant insert a value in an existing row using insert. if you want to change an existing column use update w3schools.com/sql/sql_update.asp.
– Florian H
Nov 16 '18 at 8:55