Python dictionary rename key and group












0















I am trying to rename some keys and group the values for the grouped keys. My content looks like this:



text_image_old = {10_pdf 10_pdf0: "some text", 10_pdf 10_pdf1: "more text", 10_pdf 10_pdf2: "even more text"}


Using regex, I can iteratively replace the names, such that only 10_pdf would be left, but due to the loop, the text would just contain the values "even more text" (e.g. the last value): 



text_image_new =  {re.sub('[a-zA-Z0-9_]+.pdf[0-9]', '', k): v for k, v in text_image_old.items()}


How could i replace the keys and group the values? Thank you!



Edit: the expected output should look like this 



text_image_new = {10_pdf :"some text" "more text" "even more text"}


or if its easier to get:



text_image_new = {10_pdf :"some text more text even more text"}





python-3.x dictionary key







share|improve this question

























  • Can you please share your expected output?

    – Mayank Porwal
    Nov 15 '18 at 15:47











  • I have edited the question. Thank you for your comment

    – Simon
    Nov 15 '18 at 16:02
















0















I am trying to rename some keys and group the values for the grouped keys. My content looks like this:



text_image_old = {10_pdf 10_pdf0: "some text", 10_pdf 10_pdf1: "more text", 10_pdf 10_pdf2: "even more text"}


Using regex, I can iteratively replace the names, such that only 10_pdf would be left, but due to the loop, the text would just contain the values "even more text" (e.g. the last value): 



text_image_new =  {re.sub('[a-zA-Z0-9_]+.pdf[0-9]', '', k): v for k, v in text_image_old.items()}


How could i replace the keys and group the values? Thank you!



Edit: the expected output should look like this 



text_image_new = {10_pdf :"some text" "more text" "even more text"}


or if its easier to get:



text_image_new = {10_pdf :"some text more text even more text"}





python-3.x dictionary key







share|improve this question

























  • Can you please share your expected output?

    – Mayank Porwal
    Nov 15 '18 at 15:47











  • I have edited the question. Thank you for your comment

    – Simon
    Nov 15 '18 at 16:02














0












0








0








I am trying to rename some keys and group the values for the grouped keys. My content looks like this:



text_image_old = {10_pdf 10_pdf0: "some text", 10_pdf 10_pdf1: "more text", 10_pdf 10_pdf2: "even more text"}


Using regex, I can iteratively replace the names, such that only 10_pdf would be left, but due to the loop, the text would just contain the values "even more text" (e.g. the last value): 



text_image_new =  {re.sub('[a-zA-Z0-9_]+.pdf[0-9]', '', k): v for k, v in text_image_old.items()}


How could i replace the keys and group the values? Thank you!



Edit: the expected output should look like this 



text_image_new = {10_pdf :"some text" "more text" "even more text"}


or if its easier to get:



text_image_new = {10_pdf :"some text more text even more text"}





python-3.x dictionary key







share|improve this question
















I am trying to rename some keys and group the values for the grouped keys. My content looks like this:



text_image_old = {10_pdf 10_pdf0: "some text", 10_pdf 10_pdf1: "more text", 10_pdf 10_pdf2: "even more text"}


Using regex, I can iteratively replace the names, such that only 10_pdf would be left, but due to the loop, the text would just contain the values "even more text" (e.g. the last value): 



text_image_new =  {re.sub('[a-zA-Z0-9_]+.pdf[0-9]', '', k): v for k, v in text_image_old.items()}


How could i replace the keys and group the values? Thank you!



Edit: the expected output should look like this 



text_image_new = {10_pdf :"some text" "more text" "even more text"}


or if its easier to get:



text_image_new = {10_pdf :"some text more text even more text"}





python-3.x dictionary key




python-3.x dictionary key






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 16:02







Simon

















asked Nov 15 '18 at 14:54









SimonSimon

369




369













  • Can you please share your expected output?

    – Mayank Porwal
    Nov 15 '18 at 15:47











  • I have edited the question. Thank you for your comment

    – Simon
    Nov 15 '18 at 16:02



















  • Can you please share your expected output?

    – Mayank Porwal
    Nov 15 '18 at 15:47











  • I have edited the question. Thank you for your comment

    – Simon
    Nov 15 '18 at 16:02

















Can you please share your expected output?

– Mayank Porwal
Nov 15 '18 at 15:47





Can you please share your expected output?

– Mayank Porwal
Nov 15 '18 at 15:47













I have edited the question. Thank you for your comment

– Simon
Nov 15 '18 at 16:02





I have edited the question. Thank you for your comment

– Simon
Nov 15 '18 at 16:02












1 Answer
1






active

oldest

votes


















1














I hope this should work for you, or at least help solving your problem:



text_image_old = {'10_pdf 10_pdf0': "some text", '10_pdf 10_pdf1': "more text",

                  '10_pdf 10_pdf2': "even more text"}



new_dict = {}

for k, v in text_image_old.items():

    k = k.split(' ')[0]

    if k in new_dict:

        new_dict[k] += v + ' '

    else:

        new_dict[k] = v + ' '



print(new_dict)





share|improve this answer
























  • you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

    – Drako
    Nov 15 '18 at 16:34











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53322138%2fpython-dictionary-rename-key-and-group%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














I hope this should work for you, or at least help solving your problem:



text_image_old = {'10_pdf 10_pdf0': "some text", '10_pdf 10_pdf1': "more text",

                  '10_pdf 10_pdf2': "even more text"}



new_dict = {}

for k, v in text_image_old.items():

    k = k.split(' ')[0]

    if k in new_dict:

        new_dict[k] += v + ' '

    else:

        new_dict[k] = v + ' '



print(new_dict)





share|improve this answer
























  • you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

    – Drako
    Nov 15 '18 at 16:34
















1














I hope this should work for you, or at least help solving your problem:



text_image_old = {'10_pdf 10_pdf0': "some text", '10_pdf 10_pdf1': "more text",

                  '10_pdf 10_pdf2': "even more text"}



new_dict = {}

for k, v in text_image_old.items():

    k = k.split(' ')[0]

    if k in new_dict:

        new_dict[k] += v + ' '

    else:

        new_dict[k] = v + ' '



print(new_dict)





share|improve this answer
























  • you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

    – Drako
    Nov 15 '18 at 16:34














1












1








1







I hope this should work for you, or at least help solving your problem:



text_image_old = {'10_pdf 10_pdf0': "some text", '10_pdf 10_pdf1': "more text",

                  '10_pdf 10_pdf2': "even more text"}



new_dict = {}

for k, v in text_image_old.items():

    k = k.split(' ')[0]

    if k in new_dict:

        new_dict[k] += v + ' '

    else:

        new_dict[k] = v + ' '



print(new_dict)





share|improve this answer













I hope this should work for you, or at least help solving your problem:



text_image_old = {'10_pdf 10_pdf0': "some text", '10_pdf 10_pdf1': "more text",

                  '10_pdf 10_pdf2': "even more text"}



new_dict = {}

for k, v in text_image_old.items():

    k = k.split(' ')[0]

    if k in new_dict:

        new_dict[k] += v + ' '

    else:

        new_dict[k] = v + ' '



print(new_dict)






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 15 '18 at 16:30









DrakoDrako

501415




501415













  • you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

    – Drako
    Nov 15 '18 at 16:34



















  • you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

    – Drako
    Nov 15 '18 at 16:34

















you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

– Drako
Nov 15 '18 at 16:34





you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

– Drako
Nov 15 '18 at 16:34




















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid …



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53322138%2fpython-dictionary-rename-key-and-group%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







-

Popular posts from this blog

Bressuire

Image
Subprefecture and commune in Nouvelle-Aquitaine, France Bressuire Subprefecture and commune Chateau de Bressuire and the Eglise Notre-Dame Coat of arms Location of Bressuire Bressuire Show map of France Bressuire Show map of Nouvelle-Aquitaine Coordinates: 46°50′27″N 0°29′14″W  /  46.8408°N 0.4872°W  / 46.8408; -0.4872 Coordinates: 46°50′27″N 0°29′14″W  /  46.8408°N 0.4872°W  / 46.8408; -0.4872 Country France Region Nouvelle-Aquitaine Department Deux-Sèvres Arrondissement Bressuire Canton Bressuire Government  • Mayor .mw-parser-output .nobold{font-weight:normal} (2014–20) Jean Michel Bernier Area 1 180.59 km 2 (69.73 sq mi) Population (2014) 2 19,300  • Density 110/km 2 (280/sq mi) Time zone UTC+01:00 (CET)  • Summer (DST) UTC+02:00 (CEST) INSEE/Postal code 79049 /79300 Elevation 98–236 m (322–774 ft) (avg. 173 m or 568 ft) 1 French Land Register data, which exclude
Read more

Vorschmack

Image
Vorschmack Ukrainian Jewish-style vorschmack served on rye bread Course Hors d'oeuvre Region or state Eastern Europe Associated national cuisine Ashkenazi Jewish, Finnish, German, Ukrainian, Polish, Russian Main ingredients Ground meat and/or fish Cookbook: Vorschmack   Media: Vorschmack Vorschmack or forshmak (Yiddish: פֿאָרשמאַק ‎, from archaic German Vorschmack , "foretaste" [1] or "appetizer" [2] ) is an originally East European dish made of salty minced fish or meat. Different variants of this dish are especially common in Ashkenazi Jewish and Finnish cuisine. Some varieties are also known in Russian and Polish cuisine. Contents 1 In Jewish cuisine 2 In Russian cuisine 3 In Polish cuisine 4 In Finnish cuisine 5 See also 6 References In Jewish cuisine According to Gil Marks, the German name points to the possible Germanic origin of this dish. [1] William Pokhlyobkin descr
Read more

Quarantine

Image
For other uses, see Quarantine (disambiguation). Signal flag "Lima" called the "Yellow Jack" which when flown in harbor means ship is under quarantine. A simple yellow flag (also called the "Yellow Jack") had historically been used to signal quarantine (it stands for Q among signal flags), but now indicates the opposite, as a signal of a ship free of disease that requests boarding and inspection. A quarantine is used to separate and restrict the movement of people; it is 'a restraint upon the activities or communication of persons or the transport of goods designed to prevent the spread of disease or pests', for a certain period of time. [1] This is often used in connection to disease and illness, such as those who may possibly have been exposed to a communicable disease. [2] The term is often erroneously used to mean medical isolation, which is "to separate ill persons who have a communicable disease from those who are healthy
Read more