Python dictionary rename key and group












0















I am trying to rename some keys and group the values for the grouped keys. My content looks like this:



text_image_old = {10_pdf 10_pdf0: "some text", 10_pdf 10_pdf1: "more text", 10_pdf 10_pdf2: "even more text"}


Using regex, I can iteratively replace the names, such that only 10_pdf would be left, but due to the loop, the text would just contain the values "even more text" (e.g. the last value): 



text_image_new =  {re.sub('[a-zA-Z0-9_]+.pdf[0-9]', '', k): v for k, v in text_image_old.items()}


How could i replace the keys and group the values? Thank you!



Edit: the expected output should look like this 



text_image_new = {10_pdf :"some text" "more text" "even more text"}


or if its easier to get:



text_image_new = {10_pdf :"some text more text even more text"}





python-3.x dictionary key







share|improve this question

























  • Can you please share your expected output?

    – Mayank Porwal
    Nov 15 '18 at 15:47











  • I have edited the question. Thank you for your comment

    – Simon
    Nov 15 '18 at 16:02
















0















I am trying to rename some keys and group the values for the grouped keys. My content looks like this:



text_image_old = {10_pdf 10_pdf0: "some text", 10_pdf 10_pdf1: "more text", 10_pdf 10_pdf2: "even more text"}


Using regex, I can iteratively replace the names, such that only 10_pdf would be left, but due to the loop, the text would just contain the values "even more text" (e.g. the last value): 



text_image_new =  {re.sub('[a-zA-Z0-9_]+.pdf[0-9]', '', k): v for k, v in text_image_old.items()}


How could i replace the keys and group the values? Thank you!



Edit: the expected output should look like this 



text_image_new = {10_pdf :"some text" "more text" "even more text"}


or if its easier to get:



text_image_new = {10_pdf :"some text more text even more text"}





python-3.x dictionary key







share|improve this question

























  • Can you please share your expected output?

    – Mayank Porwal
    Nov 15 '18 at 15:47











  • I have edited the question. Thank you for your comment

    – Simon
    Nov 15 '18 at 16:02














0












0








0








I am trying to rename some keys and group the values for the grouped keys. My content looks like this:



text_image_old = {10_pdf 10_pdf0: "some text", 10_pdf 10_pdf1: "more text", 10_pdf 10_pdf2: "even more text"}


Using regex, I can iteratively replace the names, such that only 10_pdf would be left, but due to the loop, the text would just contain the values "even more text" (e.g. the last value): 



text_image_new =  {re.sub('[a-zA-Z0-9_]+.pdf[0-9]', '', k): v for k, v in text_image_old.items()}


How could i replace the keys and group the values? Thank you!



Edit: the expected output should look like this 



text_image_new = {10_pdf :"some text" "more text" "even more text"}


or if its easier to get:



text_image_new = {10_pdf :"some text more text even more text"}





python-3.x dictionary key







share|improve this question
















I am trying to rename some keys and group the values for the grouped keys. My content looks like this:



text_image_old = {10_pdf 10_pdf0: "some text", 10_pdf 10_pdf1: "more text", 10_pdf 10_pdf2: "even more text"}


Using regex, I can iteratively replace the names, such that only 10_pdf would be left, but due to the loop, the text would just contain the values "even more text" (e.g. the last value): 



text_image_new =  {re.sub('[a-zA-Z0-9_]+.pdf[0-9]', '', k): v for k, v in text_image_old.items()}


How could i replace the keys and group the values? Thank you!



Edit: the expected output should look like this 



text_image_new = {10_pdf :"some text" "more text" "even more text"}


or if its easier to get:



text_image_new = {10_pdf :"some text more text even more text"}





python-3.x dictionary key




python-3.x dictionary key






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 16:02







Simon

















asked Nov 15 '18 at 14:54









SimonSimon

369




369













  • Can you please share your expected output?

    – Mayank Porwal
    Nov 15 '18 at 15:47











  • I have edited the question. Thank you for your comment

    – Simon
    Nov 15 '18 at 16:02



















  • Can you please share your expected output?

    – Mayank Porwal
    Nov 15 '18 at 15:47











  • I have edited the question. Thank you for your comment

    – Simon
    Nov 15 '18 at 16:02

















Can you please share your expected output?

– Mayank Porwal
Nov 15 '18 at 15:47





Can you please share your expected output?

– Mayank Porwal
Nov 15 '18 at 15:47













I have edited the question. Thank you for your comment

– Simon
Nov 15 '18 at 16:02





I have edited the question. Thank you for your comment

– Simon
Nov 15 '18 at 16:02












1 Answer
1






active

oldest

votes


















1














I hope this should work for you, or at least help solving your problem:



text_image_old = {'10_pdf 10_pdf0': "some text", '10_pdf 10_pdf1': "more text",

                  '10_pdf 10_pdf2': "even more text"}



new_dict = {}

for k, v in text_image_old.items():

    k = k.split(' ')[0]

    if k in new_dict:

        new_dict[k] += v + ' '

    else:

        new_dict[k] = v + ' '



print(new_dict)





share|improve this answer
























  • you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

    – Drako
    Nov 15 '18 at 16:34











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














I hope this should work for you, or at least help solving your problem:



text_image_old = {'10_pdf 10_pdf0': "some text", '10_pdf 10_pdf1': "more text",

                  '10_pdf 10_pdf2': "even more text"}



new_dict = {}

for k, v in text_image_old.items():

    k = k.split(' ')[0]

    if k in new_dict:

        new_dict[k] += v + ' '

    else:

        new_dict[k] = v + ' '



print(new_dict)





share|improve this answer
























  • you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

    – Drako
    Nov 15 '18 at 16:34
















1














I hope this should work for you, or at least help solving your problem:



text_image_old = {'10_pdf 10_pdf0': "some text", '10_pdf 10_pdf1': "more text",

                  '10_pdf 10_pdf2': "even more text"}



new_dict = {}

for k, v in text_image_old.items():

    k = k.split(' ')[0]

    if k in new_dict:

        new_dict[k] += v + ' '

    else:

        new_dict[k] = v + ' '



print(new_dict)





share|improve this answer
























  • you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

    – Drako
    Nov 15 '18 at 16:34














1












1








1







I hope this should work for you, or at least help solving your problem:



text_image_old = {'10_pdf 10_pdf0': "some text", '10_pdf 10_pdf1': "more text",

                  '10_pdf 10_pdf2': "even more text"}



new_dict = {}

for k, v in text_image_old.items():

    k = k.split(' ')[0]

    if k in new_dict:

        new_dict[k] += v + ' '

    else:

        new_dict[k] = v + ' '



print(new_dict)





share|improve this answer













I hope this should work for you, or at least help solving your problem:



text_image_old = {'10_pdf 10_pdf0': "some text", '10_pdf 10_pdf1': "more text",

                  '10_pdf 10_pdf2': "even more text"}



new_dict = {}

for k, v in text_image_old.items():

    k = k.split(' ')[0]

    if k in new_dict:

        new_dict[k] += v + ' '

    else:

        new_dict[k] = v + ' '



print(new_dict)






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 15 '18 at 16:30









DrakoDrako

501415




501415













  • you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

    – Drako
    Nov 15 '18 at 16:34



















  • you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

    – Drako
    Nov 15 '18 at 16:34

















you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

– Drako
Nov 15 '18 at 16:34





you can still implement you regex here if necessary, I just use split because from what you provide in question it seems doing the job here

– Drako
Nov 15 '18 at 16:34




















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