How to get a object key
-4
Can someone help me with some code to get a key within the object so i have this
var data =[ {
"customer_name": "Marietjie",
"customer_surname": "Short",
"times": "12:00 to 13:00",
"order_id": "241918",
"vendor": [
"Pick n Pay",
"Woolworths"
],
"customer_phone": "0609880707",
"smart_shopper": "",
"dischem_reward": "",
"woolworths_reward": ""
}]
var name = data.customer_name;
console.log(name);and i want to get the value of customer name, i tried this var name = data.customer_name but i got undefined can some help me with the code
javascript
asked Nov 15 '18 at 20:18
Jayvk1Jayvk1
164
add a comment |
-4
Can someone help me with some code to get a key within the object so i have this
var data =[ {
"customer_name": "Marietjie",
"customer_surname": "Short",
"times": "12:00 to 13:00",
"order_id": "241918",
"vendor": [
"Pick n Pay",
"Woolworths"
],
"customer_phone": "0609880707",
"smart_shopper": "",
"dischem_reward": "",
"woolworths_reward": ""
}]
var name = data.customer_name;
console.log(name);and i want to get the value of customer name, i tried this var name = data.customer_name but i got undefined can some help me with the code
javascript
asked Nov 15 '18 at 20:18
Jayvk1Jayvk1
164
data.customer_nameshould work.
– ninesalt
Nov 15 '18 at 20:21
1
Cant reproduce.
– callback
Nov 15 '18 at 20:21
1
Your code works as expected.
– connexo
Nov 15 '18 at 20:21
it works even in the OP's example :D
– Velimir Tchatchevsky
Nov 15 '18 at 20:21
1
Where does the data come from? Are you getting the data asynchronously, e.g. via AJAX? This smells like you trying to access data before it is available.
– connexo
Nov 15 '18 at 20:42
add a comment |
-4
-4
-4
Can someone help me with some code to get a key within the object so i have this
var data =[ {
"customer_name": "Marietjie",
"customer_surname": "Short",
"times": "12:00 to 13:00",
"order_id": "241918",
"vendor": [
"Pick n Pay",
"Woolworths"
],
"customer_phone": "0609880707",
"smart_shopper": "",
"dischem_reward": "",
"woolworths_reward": ""
}]
var name = data.customer_name;
console.log(name);and i want to get the value of customer name, i tried this var name = data.customer_name but i got undefined can some help me with the code
javascript
asked Nov 15 '18 at 20:18
Jayvk1Jayvk1
164
Can someone help me with some code to get a key within the object so i have this
var data =[ {
"customer_name": "Marietjie",
"customer_surname": "Short",
"times": "12:00 to 13:00",
"order_id": "241918",
"vendor": [
"Pick n Pay",
"Woolworths"
],
"customer_phone": "0609880707",
"smart_shopper": "",
"dischem_reward": "",
"woolworths_reward": ""
}]
var name = data.customer_name;
console.log(name);and i want to get the value of customer name, i tried this var name = data.customer_name but i got undefined can some help me with the code
var data =[ {
"customer_name": "Marietjie",
"customer_surname": "Short",
"times": "12:00 to 13:00",
"order_id": "241918",
"vendor": [
"Pick n Pay",
"Woolworths"
],
"customer_phone": "0609880707",
"smart_shopper": "",
"dischem_reward": "",
"woolworths_reward": ""
}]
var name = data.customer_name;
console.log(name);var data =[ {
"customer_name": "Marietjie",
"customer_surname": "Short",
"times": "12:00 to 13:00",
"order_id": "241918",
"vendor": [
"Pick n Pay",
"Woolworths"
],
"customer_phone": "0609880707",
"smart_shopper": "",
"dischem_reward": "",
"woolworths_reward": ""
}]
var name = data.customer_name;
console.log(name);javascript
javascript
asked Nov 15 '18 at 20:18
Jayvk1Jayvk1
164
asked Nov 15 '18 at 20:18
Jayvk1Jayvk1
164
edited Nov 16 '18 at 10:27
Jayvk1
asked Nov 15 '18 at 20:18
Jayvk1Jayvk1
164
asked Nov 15 '18 at 20:18
Jayvk1Jayvk1
164
asked Nov 15 '18 at 20:18
Jayvk1Jayvk1
164
164
data.customer_nameshould work.
– ninesalt
Nov 15 '18 at 20:21
1
Cant reproduce.
– callback
Nov 15 '18 at 20:21
1
Your code works as expected.
– connexo
Nov 15 '18 at 20:21
it works even in the OP's example :D
– Velimir Tchatchevsky
Nov 15 '18 at 20:21
1
Where does the data come from? Are you getting the data asynchronously, e.g. via AJAX? This smells like you trying to access data before it is available.
– connexo
Nov 15 '18 at 20:42
add a comment |
data.customer_nameshould work.
– ninesalt
Nov 15 '18 at 20:21
1
Cant reproduce.
– callback
Nov 15 '18 at 20:21
1
Your code works as expected.
– connexo
Nov 15 '18 at 20:21
it works even in the OP's example :D
– Velimir Tchatchevsky
Nov 15 '18 at 20:21
1
Where does the data come from? Are you getting the data asynchronously, e.g. via AJAX? This smells like you trying to access data before it is available.
– connexo
Nov 15 '18 at 20:42
data.customer_name should work.– ninesalt
Nov 15 '18 at 20:21
data.customer_name should work.– ninesalt
Nov 15 '18 at 20:21
1
1
Cant reproduce.
– callback
Nov 15 '18 at 20:21
Cant reproduce.
– callback
Nov 15 '18 at 20:21
1
1
Your code works as expected.
– connexo
Nov 15 '18 at 20:21
Your code works as expected.
– connexo
Nov 15 '18 at 20:21
it works even in the OP's example :D
– Velimir Tchatchevsky
Nov 15 '18 at 20:21
it works even in the OP's example :D
– Velimir Tchatchevsky
Nov 15 '18 at 20:21
1
1
Where does the data come from? Are you getting the data asynchronously, e.g. via AJAX? This smells like you trying to access data before it is available.
– connexo
Nov 15 '18 at 20:42
Where does the data come from? Are you getting the data asynchronously, e.g. via AJAX? This smells like you trying to access data before it is available.
– connexo
Nov 15 '18 at 20:42
add a comment |
1 Answer
1
active
oldest
votes
0
Your object is in an array.
You cannot just ignore the array.
var object = data[0];
var name = object.customer_name
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53327292%2fhow-to-get-a-object-key%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Your object is in an array.
You cannot just ignore the array.
var object = data[0];
var name = object.customer_name
add a comment |
0
Your object is in an array.
You cannot just ignore the array.
var object = data[0];
var name = object.customer_name
add a comment |
0
0
0
Your object is in an array.
You cannot just ignore the array.
var object = data[0];
var name = object.customer_name
Your object is in an array.
You cannot just ignore the array.
var object = data[0];
var name = object.customer_name
answered Nov 16 '18 at 10:29
community wiki
Quentin
add a comment |
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53327292%2fhow-to-get-a-object-key%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
data.customer_nameshould work.– ninesalt
Nov 15 '18 at 20:21
1
Cant reproduce.
– callback
Nov 15 '18 at 20:21
1
Your code works as expected.
– connexo
Nov 15 '18 at 20:21
it works even in the OP's example :D
– Velimir Tchatchevsky
Nov 15 '18 at 20:21
1
Where does the data come from? Are you getting the data asynchronously, e.g. via AJAX? This smells like you trying to access data before it is available.
– connexo
Nov 15 '18 at 20:42