Mips, hexadecimal to binary conversion
I've been trying to do some conversion in mips assembly to try and turn hexadecimals to binary but I'm not sure how I would implement it. Here's the fragment of my code that's relevant to the conversion
.data
operand: .asciiz "nEnter correct value to be converted: "
result: .asciiz "nYour result is: "
hexstore: .space 8
.globl main
.text
main:
li $v0, 4 #display welcome message
la $a0, welcome
syscall
li $v0, 5 #get int for type of operation
syscall
move $t0, $v0 #store result in t0, now compare t0 to t1 in order to get a branching result
addi $t1, $zero, 0 #set t1 to 0
addi $t1, $t1, 1 #set t1 to 1
beq $t0, $t1, hexatobinary #jump to hextobinary if t0 is 1
hexatobinary:
la $a0, operand #prompt for input
li $v0, 4
syscall
li $v0, 5 #integer input
syscall
add $t0, $v0, $zero #Move to t0
addi $t1, $zero, 0
sw $t0, hexstore($t1)
So pretty much my thought process is to store the user inputted hex value, then try and read one bit at a time in a for loop and through 16 branches putting the correct binary values in a register, then after the loop is complete I would print the register and the conversion would complete. Is this the correct implementation? What code would I need in order to actually do that? Could i convert binary to hex through the same process? Thanks!
assembly low-level mips32
asked Nov 15 '18 at 20:40
MarcelMarcel
1
add a comment |
I've been trying to do some conversion in mips assembly to try and turn hexadecimals to binary but I'm not sure how I would implement it. Here's the fragment of my code that's relevant to the conversion
.data
operand: .asciiz "nEnter correct value to be converted: "
result: .asciiz "nYour result is: "
hexstore: .space 8
.globl main
.text
main:
li $v0, 4 #display welcome message
la $a0, welcome
syscall
li $v0, 5 #get int for type of operation
syscall
move $t0, $v0 #store result in t0, now compare t0 to t1 in order to get a branching result
addi $t1, $zero, 0 #set t1 to 0
addi $t1, $t1, 1 #set t1 to 1
beq $t0, $t1, hexatobinary #jump to hextobinary if t0 is 1
hexatobinary:
la $a0, operand #prompt for input
li $v0, 4
syscall
li $v0, 5 #integer input
syscall
add $t0, $v0, $zero #Move to t0
addi $t1, $zero, 0
sw $t0, hexstore($t1)
So pretty much my thought process is to store the user inputted hex value, then try and read one bit at a time in a for loop and through 16 branches putting the correct binary values in a register, then after the loop is complete I would print the register and the conversion would complete. Is this the correct implementation? What code would I need in order to actually do that? Could i convert binary to hex through the same process? Thanks!
assembly low-level mips32
asked Nov 15 '18 at 20:40
MarcelMarcel
1
The read-int system call (v0=5) already takes care of converting from an ASCII hex string to a binary integer in a register. (If it supports hex at all?) Hex is a text / human-readable serialization format for numbers. Anyway yes, then you just need to isolate each binary bit in a register into0/1(usually with a shift / AND) and convert to ASCII'0'/'1'. (Or use a print-int function to do that last part for you.)
– Peter Cordes
Nov 15 '18 at 20:50
add a comment |
I've been trying to do some conversion in mips assembly to try and turn hexadecimals to binary but I'm not sure how I would implement it. Here's the fragment of my code that's relevant to the conversion
.data
operand: .asciiz "nEnter correct value to be converted: "
result: .asciiz "nYour result is: "
hexstore: .space 8
.globl main
.text
main:
li $v0, 4 #display welcome message
la $a0, welcome
syscall
li $v0, 5 #get int for type of operation
syscall
move $t0, $v0 #store result in t0, now compare t0 to t1 in order to get a branching result
addi $t1, $zero, 0 #set t1 to 0
addi $t1, $t1, 1 #set t1 to 1
beq $t0, $t1, hexatobinary #jump to hextobinary if t0 is 1
hexatobinary:
la $a0, operand #prompt for input
li $v0, 4
syscall
li $v0, 5 #integer input
syscall
add $t0, $v0, $zero #Move to t0
addi $t1, $zero, 0
sw $t0, hexstore($t1)
So pretty much my thought process is to store the user inputted hex value, then try and read one bit at a time in a for loop and through 16 branches putting the correct binary values in a register, then after the loop is complete I would print the register and the conversion would complete. Is this the correct implementation? What code would I need in order to actually do that? Could i convert binary to hex through the same process? Thanks!
assembly low-level mips32
asked Nov 15 '18 at 20:40
MarcelMarcel
1
I've been trying to do some conversion in mips assembly to try and turn hexadecimals to binary but I'm not sure how I would implement it. Here's the fragment of my code that's relevant to the conversion
.data
operand: .asciiz "nEnter correct value to be converted: "
result: .asciiz "nYour result is: "
hexstore: .space 8
.globl main
.text
main:
li $v0, 4 #display welcome message
la $a0, welcome
syscall
li $v0, 5 #get int for type of operation
syscall
move $t0, $v0 #store result in t0, now compare t0 to t1 in order to get a branching result
addi $t1, $zero, 0 #set t1 to 0
addi $t1, $t1, 1 #set t1 to 1
beq $t0, $t1, hexatobinary #jump to hextobinary if t0 is 1
hexatobinary:
la $a0, operand #prompt for input
li $v0, 4
syscall
li $v0, 5 #integer input
syscall
add $t0, $v0, $zero #Move to t0
addi $t1, $zero, 0
sw $t0, hexstore($t1)
So pretty much my thought process is to store the user inputted hex value, then try and read one bit at a time in a for loop and through 16 branches putting the correct binary values in a register, then after the loop is complete I would print the register and the conversion would complete. Is this the correct implementation? What code would I need in order to actually do that? Could i convert binary to hex through the same process? Thanks!
assembly low-level mips32
assembly low-level mips32
asked Nov 15 '18 at 20:40
MarcelMarcel
1
asked Nov 15 '18 at 20:40
MarcelMarcel
1
asked Nov 15 '18 at 20:40
MarcelMarcel
1
asked Nov 15 '18 at 20:40
MarcelMarcel
1
asked Nov 15 '18 at 20:40
MarcelMarcel
1
1
The read-int system call (v0=5) already takes care of converting from an ASCII hex string to a binary integer in a register. (If it supports hex at all?) Hex is a text / human-readable serialization format for numbers. Anyway yes, then you just need to isolate each binary bit in a register into0/1(usually with a shift / AND) and convert to ASCII'0'/'1'. (Or use a print-int function to do that last part for you.)
– Peter Cordes
Nov 15 '18 at 20:50
add a comment |
The read-int system call (v0=5) already takes care of converting from an ASCII hex string to a binary integer in a register. (If it supports hex at all?) Hex is a text / human-readable serialization format for numbers. Anyway yes, then you just need to isolate each binary bit in a register into0/1(usually with a shift / AND) and convert to ASCII'0'/'1'. (Or use a print-int function to do that last part for you.)
– Peter Cordes
Nov 15 '18 at 20:50
The read-int system call (v0=5) already takes care of converting from an ASCII hex string to a binary integer in a register. (If it supports hex at all?) Hex is a text / human-readable serialization format for numbers. Anyway yes, then you just need to isolate each binary bit in a register into
0/1 (usually with a shift / AND) and convert to ASCII '0' / '1'. (Or use a print-int function to do that last part for you.)– Peter Cordes
Nov 15 '18 at 20:50
The read-int system call (v0=5) already takes care of converting from an ASCII hex string to a binary integer in a register. (If it supports hex at all?) Hex is a text / human-readable serialization format for numbers. Anyway yes, then you just need to isolate each binary bit in a register into
0/1 (usually with a shift / AND) and convert to ASCII '0' / '1'. (Or use a print-int function to do that last part for you.)– Peter Cordes
Nov 15 '18 at 20:50
add a comment |
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The read-int system call (v0=5) already takes care of converting from an ASCII hex string to a binary integer in a register. (If it supports hex at all?) Hex is a text / human-readable serialization format for numbers. Anyway yes, then you just need to isolate each binary bit in a register into
0/1(usually with a shift / AND) and convert to ASCII'0'/'1'. (Or use a print-int function to do that last part for you.)– Peter Cordes
Nov 15 '18 at 20:50