Validate if row exist, if not insert - MYSQL TRIGGER
I have a script that allows me to detect if the inserted record already exists in the database, it is assumed that the script runs, but when it detects that this script exists for the entire insertion loop and does not proceed with the following ones that may not be duplicated.
How can I do so that the script does not stop and continue reviewing the next inserted data, since it does not detect that one is duplicated, it stops and does not allow to check if the following ones are not
BEGIN
DECLARE registro INT;
set registro = (select count(*) from Leads
WHERE nombres = NEW.nombres and
apellidos = NEW.apellidos and
n_documento = NEW.n_documento and
programa = NEW.programa);
IF(registro > 0) THEN
INSERT INTO Leads VALUES (
null,
new.nombres,
new.apellidos,
new.n_documento,
new.fecha_de_nacimiento,
new.telefono,
new.email,
new.ciudad,
new.pais,
new.anos_de_experiencia,
new.origen,
new.informacion_adicional,
new.fecha,
new.programa,
new.estado,
new.fecha_charla,
new.grado_de_estudio,
new.empresa,
new.cargo,
null
);
END IF;
mysql triggers
edited Nov 17 '18 at 11:39
Madhur Bhaiya
19.6k62236
asked Nov 14 '18 at 20:52
Bryan RiveraBryan Rivera
83
add a comment |
I have a script that allows me to detect if the inserted record already exists in the database, it is assumed that the script runs, but when it detects that this script exists for the entire insertion loop and does not proceed with the following ones that may not be duplicated.
How can I do so that the script does not stop and continue reviewing the next inserted data, since it does not detect that one is duplicated, it stops and does not allow to check if the following ones are not
BEGIN
DECLARE registro INT;
set registro = (select count(*) from Leads
WHERE nombres = NEW.nombres and
apellidos = NEW.apellidos and
n_documento = NEW.n_documento and
programa = NEW.programa);
IF(registro > 0) THEN
INSERT INTO Leads VALUES (
null,
new.nombres,
new.apellidos,
new.n_documento,
new.fecha_de_nacimiento,
new.telefono,
new.email,
new.ciudad,
new.pais,
new.anos_de_experiencia,
new.origen,
new.informacion_adicional,
new.fecha,
new.programa,
new.estado,
new.fecha_charla,
new.grado_de_estudio,
new.empresa,
new.cargo,
null
);
END IF;
mysql triggers
edited Nov 17 '18 at 11:39
Madhur Bhaiya
19.6k62236
asked Nov 14 '18 at 20:52
Bryan RiveraBryan Rivera
83
A trigger for this is really heavy handed. Why not just insert and deal with the potential error, orINSERT IGNORE, orINSERT ... ON DUPLICATE KEYto handle a collision.
– tadman
Nov 14 '18 at 20:55
@tadman dou u have a example please?
– Bryan Rivera
Nov 14 '18 at 21:16
It's all in the documentation if you search for the right things.
– tadman
Nov 14 '18 at 21:38
@BryanRivera do you haveUNIQUEor composite Primary Key defined on(nombres, apellidos, n_documento, programa)?
– Madhur Bhaiya
Nov 17 '18 at 11:39
add a comment |
I have a script that allows me to detect if the inserted record already exists in the database, it is assumed that the script runs, but when it detects that this script exists for the entire insertion loop and does not proceed with the following ones that may not be duplicated.
How can I do so that the script does not stop and continue reviewing the next inserted data, since it does not detect that one is duplicated, it stops and does not allow to check if the following ones are not
BEGIN
DECLARE registro INT;
set registro = (select count(*) from Leads
WHERE nombres = NEW.nombres and
apellidos = NEW.apellidos and
n_documento = NEW.n_documento and
programa = NEW.programa);
IF(registro > 0) THEN
INSERT INTO Leads VALUES (
null,
new.nombres,
new.apellidos,
new.n_documento,
new.fecha_de_nacimiento,
new.telefono,
new.email,
new.ciudad,
new.pais,
new.anos_de_experiencia,
new.origen,
new.informacion_adicional,
new.fecha,
new.programa,
new.estado,
new.fecha_charla,
new.grado_de_estudio,
new.empresa,
new.cargo,
null
);
END IF;
mysql triggers
edited Nov 17 '18 at 11:39
Madhur Bhaiya
19.6k62236
asked Nov 14 '18 at 20:52
Bryan RiveraBryan Rivera
83
I have a script that allows me to detect if the inserted record already exists in the database, it is assumed that the script runs, but when it detects that this script exists for the entire insertion loop and does not proceed with the following ones that may not be duplicated.
How can I do so that the script does not stop and continue reviewing the next inserted data, since it does not detect that one is duplicated, it stops and does not allow to check if the following ones are not
BEGIN
DECLARE registro INT;
set registro = (select count(*) from Leads
WHERE nombres = NEW.nombres and
apellidos = NEW.apellidos and
n_documento = NEW.n_documento and
programa = NEW.programa);
IF(registro > 0) THEN
INSERT INTO Leads VALUES (
null,
new.nombres,
new.apellidos,
new.n_documento,
new.fecha_de_nacimiento,
new.telefono,
new.email,
new.ciudad,
new.pais,
new.anos_de_experiencia,
new.origen,
new.informacion_adicional,
new.fecha,
new.programa,
new.estado,
new.fecha_charla,
new.grado_de_estudio,
new.empresa,
new.cargo,
null
);
END IF;
mysql triggers
mysql triggers
edited Nov 17 '18 at 11:39
Madhur Bhaiya
19.6k62236
asked Nov 14 '18 at 20:52
Bryan RiveraBryan Rivera
83
edited Nov 17 '18 at 11:39
Madhur Bhaiya
19.6k62236
asked Nov 14 '18 at 20:52
Bryan RiveraBryan Rivera
83
edited Nov 17 '18 at 11:39
Madhur Bhaiya
19.6k62236
edited Nov 17 '18 at 11:39
Madhur Bhaiya
19.6k62236
edited Nov 17 '18 at 11:39
Madhur Bhaiya
19.6k62236
19.6k62236
asked Nov 14 '18 at 20:52
Bryan RiveraBryan Rivera
83
asked Nov 14 '18 at 20:52
Bryan RiveraBryan Rivera
83
asked Nov 14 '18 at 20:52
Bryan RiveraBryan Rivera
83
83
A trigger for this is really heavy handed. Why not just insert and deal with the potential error, orINSERT IGNORE, orINSERT ... ON DUPLICATE KEYto handle a collision.
– tadman
Nov 14 '18 at 20:55
@tadman dou u have a example please?
– Bryan Rivera
Nov 14 '18 at 21:16
It's all in the documentation if you search for the right things.
– tadman
Nov 14 '18 at 21:38
@BryanRivera do you haveUNIQUEor composite Primary Key defined on(nombres, apellidos, n_documento, programa)?
– Madhur Bhaiya
Nov 17 '18 at 11:39
add a comment |
A trigger for this is really heavy handed. Why not just insert and deal with the potential error, orINSERT IGNORE, orINSERT ... ON DUPLICATE KEYto handle a collision.
– tadman
Nov 14 '18 at 20:55
@tadman dou u have a example please?
– Bryan Rivera
Nov 14 '18 at 21:16
It's all in the documentation if you search for the right things.
– tadman
Nov 14 '18 at 21:38
@BryanRivera do you haveUNIQUEor composite Primary Key defined on(nombres, apellidos, n_documento, programa)?
– Madhur Bhaiya
Nov 17 '18 at 11:39
A trigger for this is really heavy handed. Why not just insert and deal with the potential error, or
INSERT IGNORE, or INSERT ... ON DUPLICATE KEY to handle a collision.– tadman
Nov 14 '18 at 20:55
A trigger for this is really heavy handed. Why not just insert and deal with the potential error, or
INSERT IGNORE, or INSERT ... ON DUPLICATE KEY to handle a collision.– tadman
Nov 14 '18 at 20:55
@tadman dou u have a example please?
– Bryan Rivera
Nov 14 '18 at 21:16
@tadman dou u have a example please?
– Bryan Rivera
Nov 14 '18 at 21:16
It's all in the documentation if you search for the right things.
– tadman
Nov 14 '18 at 21:38
It's all in the documentation if you search for the right things.
– tadman
Nov 14 '18 at 21:38
@BryanRivera do you have
UNIQUE or composite Primary Key defined on (nombres, apellidos, n_documento, programa) ?– Madhur Bhaiya
Nov 17 '18 at 11:39
@BryanRivera do you have
UNIQUE or composite Primary Key defined on (nombres, apellidos, n_documento, programa) ?– Madhur Bhaiya
Nov 17 '18 at 11:39
add a comment |
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A trigger for this is really heavy handed. Why not just insert and deal with the potential error, or
INSERT IGNORE, orINSERT ... ON DUPLICATE KEYto handle a collision.– tadman
Nov 14 '18 at 20:55
@tadman dou u have a example please?
– Bryan Rivera
Nov 14 '18 at 21:16
It's all in the documentation if you search for the right things.
– tadman
Nov 14 '18 at 21:38
@BryanRivera do you have
UNIQUEor composite Primary Key defined on(nombres, apellidos, n_documento, programa)?– Madhur Bhaiya
Nov 17 '18 at 11:39