dynamic path in java application












1















I want to specify the path dynamically. myapp/CopyFolder and myapp/RunFolder's are inside application like myapp/WEB-INF. The code I have given below is in .java file(in eclipse) and in .class file(in tomcat inside myapp/WEB-INF/classname/packagename/). My deployment is in tomcat.



 try {
functionNamesObject.Integration(
".txt",
path+"\CopyFolder",
path+"\RunFolder",
"app.exe",
"Input.txt"
);


I want path to be dynamic when I call above function. I tried with getResource("MyClass.class") ,new File("").getAbsolutePath(); and System.getProperty("user.dir") but no use. Is there any other way?










share|improve this question























  • I answered this in another one of your questions. CopyFolder won't exist by default on an installation. You will need to create it manually. As such you will know where you create it, so hard code it into your app.

    – Sotirios Delimanolis
    Sep 10 '13 at 16:11











  • do you want to know the deployment directory (webapps/application) or the WEB-INF folder of your deployed app?

    – Katona
    Sep 10 '13 at 16:28











  • @Katona I want to know deployment directory (webapps/application)

    – niren
    Sep 10 '13 at 16:40













  • @SotiriosDelimanolis yes I have to create CopyFolder and RunFolder then I will place the files I want to use there.

    – niren
    Sep 10 '13 at 16:41











  • @niren I think you can get it with getServletContext.getRealPath("") in your servlet.

    – Katona
    Sep 10 '13 at 16:45
















1















I want to specify the path dynamically. myapp/CopyFolder and myapp/RunFolder's are inside application like myapp/WEB-INF. The code I have given below is in .java file(in eclipse) and in .class file(in tomcat inside myapp/WEB-INF/classname/packagename/). My deployment is in tomcat.



 try {
functionNamesObject.Integration(
".txt",
path+"\CopyFolder",
path+"\RunFolder",
"app.exe",
"Input.txt"
);


I want path to be dynamic when I call above function. I tried with getResource("MyClass.class") ,new File("").getAbsolutePath(); and System.getProperty("user.dir") but no use. Is there any other way?










share|improve this question























  • I answered this in another one of your questions. CopyFolder won't exist by default on an installation. You will need to create it manually. As such you will know where you create it, so hard code it into your app.

    – Sotirios Delimanolis
    Sep 10 '13 at 16:11











  • do you want to know the deployment directory (webapps/application) or the WEB-INF folder of your deployed app?

    – Katona
    Sep 10 '13 at 16:28











  • @Katona I want to know deployment directory (webapps/application)

    – niren
    Sep 10 '13 at 16:40













  • @SotiriosDelimanolis yes I have to create CopyFolder and RunFolder then I will place the files I want to use there.

    – niren
    Sep 10 '13 at 16:41











  • @niren I think you can get it with getServletContext.getRealPath("") in your servlet.

    – Katona
    Sep 10 '13 at 16:45














1












1








1








I want to specify the path dynamically. myapp/CopyFolder and myapp/RunFolder's are inside application like myapp/WEB-INF. The code I have given below is in .java file(in eclipse) and in .class file(in tomcat inside myapp/WEB-INF/classname/packagename/). My deployment is in tomcat.



 try {
functionNamesObject.Integration(
".txt",
path+"\CopyFolder",
path+"\RunFolder",
"app.exe",
"Input.txt"
);


I want path to be dynamic when I call above function. I tried with getResource("MyClass.class") ,new File("").getAbsolutePath(); and System.getProperty("user.dir") but no use. Is there any other way?










share|improve this question














I want to specify the path dynamically. myapp/CopyFolder and myapp/RunFolder's are inside application like myapp/WEB-INF. The code I have given below is in .java file(in eclipse) and in .class file(in tomcat inside myapp/WEB-INF/classname/packagename/). My deployment is in tomcat.



 try {
functionNamesObject.Integration(
".txt",
path+"\CopyFolder",
path+"\RunFolder",
"app.exe",
"Input.txt"
);


I want path to be dynamic when I call above function. I tried with getResource("MyClass.class") ,new File("").getAbsolutePath(); and System.getProperty("user.dir") but no use. Is there any other way?







java eclipse tomcat






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Sep 10 '13 at 16:00









nirenniren

1,37742547




1,37742547













  • I answered this in another one of your questions. CopyFolder won't exist by default on an installation. You will need to create it manually. As such you will know where you create it, so hard code it into your app.

    – Sotirios Delimanolis
    Sep 10 '13 at 16:11











  • do you want to know the deployment directory (webapps/application) or the WEB-INF folder of your deployed app?

    – Katona
    Sep 10 '13 at 16:28











  • @Katona I want to know deployment directory (webapps/application)

    – niren
    Sep 10 '13 at 16:40













  • @SotiriosDelimanolis yes I have to create CopyFolder and RunFolder then I will place the files I want to use there.

    – niren
    Sep 10 '13 at 16:41











  • @niren I think you can get it with getServletContext.getRealPath("") in your servlet.

    – Katona
    Sep 10 '13 at 16:45



















  • I answered this in another one of your questions. CopyFolder won't exist by default on an installation. You will need to create it manually. As such you will know where you create it, so hard code it into your app.

    – Sotirios Delimanolis
    Sep 10 '13 at 16:11











  • do you want to know the deployment directory (webapps/application) or the WEB-INF folder of your deployed app?

    – Katona
    Sep 10 '13 at 16:28











  • @Katona I want to know deployment directory (webapps/application)

    – niren
    Sep 10 '13 at 16:40













  • @SotiriosDelimanolis yes I have to create CopyFolder and RunFolder then I will place the files I want to use there.

    – niren
    Sep 10 '13 at 16:41











  • @niren I think you can get it with getServletContext.getRealPath("") in your servlet.

    – Katona
    Sep 10 '13 at 16:45

















I answered this in another one of your questions. CopyFolder won't exist by default on an installation. You will need to create it manually. As such you will know where you create it, so hard code it into your app.

– Sotirios Delimanolis
Sep 10 '13 at 16:11





I answered this in another one of your questions. CopyFolder won't exist by default on an installation. You will need to create it manually. As such you will know where you create it, so hard code it into your app.

– Sotirios Delimanolis
Sep 10 '13 at 16:11













do you want to know the deployment directory (webapps/application) or the WEB-INF folder of your deployed app?

– Katona
Sep 10 '13 at 16:28





do you want to know the deployment directory (webapps/application) or the WEB-INF folder of your deployed app?

– Katona
Sep 10 '13 at 16:28













@Katona I want to know deployment directory (webapps/application)

– niren
Sep 10 '13 at 16:40







@Katona I want to know deployment directory (webapps/application)

– niren
Sep 10 '13 at 16:40















@SotiriosDelimanolis yes I have to create CopyFolder and RunFolder then I will place the files I want to use there.

– niren
Sep 10 '13 at 16:41





@SotiriosDelimanolis yes I have to create CopyFolder and RunFolder then I will place the files I want to use there.

– niren
Sep 10 '13 at 16:41













@niren I think you can get it with getServletContext.getRealPath("") in your servlet.

– Katona
Sep 10 '13 at 16:45





@niren I think you can get it with getServletContext.getRealPath("") in your servlet.

– Katona
Sep 10 '13 at 16:45












1 Answer
1






active

oldest

votes


















1














You can get the path value as below:



URL resource = getClass().getResource("/");
String path = resource.getPath();


This will return the absolute path to to your myApp/WEB-INF/classes directory.






share|improve this answer
























  • +1 for given what I want

    – niren
    Sep 10 '13 at 17:13











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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









1














You can get the path value as below:



URL resource = getClass().getResource("/");
String path = resource.getPath();


This will return the absolute path to to your myApp/WEB-INF/classes directory.






share|improve this answer
























  • +1 for given what I want

    – niren
    Sep 10 '13 at 17:13
















1














You can get the path value as below:



URL resource = getClass().getResource("/");
String path = resource.getPath();


This will return the absolute path to to your myApp/WEB-INF/classes directory.






share|improve this answer
























  • +1 for given what I want

    – niren
    Sep 10 '13 at 17:13














1












1








1







You can get the path value as below:



URL resource = getClass().getResource("/");
String path = resource.getPath();


This will return the absolute path to to your myApp/WEB-INF/classes directory.






share|improve this answer













You can get the path value as below:



URL resource = getClass().getResource("/");
String path = resource.getPath();


This will return the absolute path to to your myApp/WEB-INF/classes directory.







share|improve this answer












share|improve this answer



share|improve this answer










answered Sep 10 '13 at 16:46









Debojit SaikiaDebojit Saikia

8,61422838




8,61422838













  • +1 for given what I want

    – niren
    Sep 10 '13 at 17:13



















  • +1 for given what I want

    – niren
    Sep 10 '13 at 17:13

















+1 for given what I want

– niren
Sep 10 '13 at 17:13





+1 for given what I want

– niren
Sep 10 '13 at 17:13


















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