Count() on blank space XQUERY
I want to count how many books I have listed
I have:
books = "book-one book-two book-three ..."
If i use
count(books)
it only returns 1 no matter how long my string is, since count separates on , I'm guessing.
How can I count separating on blank-space instead?
xml count xquery
asked Nov 14 '18 at 11:53
SaraSara
223
add a comment |
I want to count how many books I have listed
I have:
books = "book-one book-two book-three ..."
If i use
count(books)
it only returns 1 no matter how long my string is, since count separates on , I'm guessing.
How can I count separating on blank-space instead?
xml count xquery
asked Nov 14 '18 at 11:53
SaraSara
223
add a comment |
I want to count how many books I have listed
I have:
books = "book-one book-two book-three ..."
If i use
count(books)
it only returns 1 no matter how long my string is, since count separates on , I'm guessing.
How can I count separating on blank-space instead?
xml count xquery
asked Nov 14 '18 at 11:53
SaraSara
223
I want to count how many books I have listed
I have:
books = "book-one book-two book-three ..."
If i use
count(books)
it only returns 1 no matter how long my string is, since count separates on , I'm guessing.
How can I count separating on blank-space instead?
xml count xquery
xml count xquery
asked Nov 14 '18 at 11:53
SaraSara
223
asked Nov 14 '18 at 11:53
SaraSara
223
asked Nov 14 '18 at 11:53
SaraSara
223
asked Nov 14 '18 at 11:53
SaraSara
223
asked Nov 14 '18 at 11:53
SaraSara
223
223
add a comment |
add a comment |
1 Answer
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Assuming the books are separated by a space, you can split the string into a sequence of strings using the fn:tokenize() function:
fn:tokenize("book-one book-two book-three", " ")
This will return a sequence of the books:
("book-one", "book-two", "book-three")
The fn:tokenize() function can work with literal strings like " ", or it can take regular expressions like "s+" (to mean "one or more whitespace characters"). This allows for some pretty sophisticated pattern matching.
For the canonical description of this function, see https://www.w3.org/TR/xpath-functions-31/#func-tokenize, and for more on regular expressions in XPath and XQuery, see https://www.w3.org/TR/xpath-functions-31/#string.match.
answered Nov 14 '18 at 12:42
joewizjoewiz
3,9571120
1
Note that the XQuery 1.0 version of the function requires a regular expression as the second argument, and it's best to callnormalize-space()first to get rid of any leading or trailing whitespace, as the count may otherwise be misleading. XQuery 3.1 has a single-argumenttokenize()function that tokenizes on whitespace after (effectively) doing an implicit normalize-space().
– Michael Kay
Nov 14 '18 at 14:59
add a comment |
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1 Answer
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1 Answer
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active
oldest
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Assuming the books are separated by a space, you can split the string into a sequence of strings using the fn:tokenize() function:
fn:tokenize("book-one book-two book-three", " ")
This will return a sequence of the books:
("book-one", "book-two", "book-three")
The fn:tokenize() function can work with literal strings like " ", or it can take regular expressions like "s+" (to mean "one or more whitespace characters"). This allows for some pretty sophisticated pattern matching.
For the canonical description of this function, see https://www.w3.org/TR/xpath-functions-31/#func-tokenize, and for more on regular expressions in XPath and XQuery, see https://www.w3.org/TR/xpath-functions-31/#string.match.
answered Nov 14 '18 at 12:42
joewizjoewiz
3,9571120
1
Note that the XQuery 1.0 version of the function requires a regular expression as the second argument, and it's best to callnormalize-space()first to get rid of any leading or trailing whitespace, as the count may otherwise be misleading. XQuery 3.1 has a single-argumenttokenize()function that tokenizes on whitespace after (effectively) doing an implicit normalize-space().
– Michael Kay
Nov 14 '18 at 14:59
add a comment |
Assuming the books are separated by a space, you can split the string into a sequence of strings using the fn:tokenize() function:
fn:tokenize("book-one book-two book-three", " ")
This will return a sequence of the books:
("book-one", "book-two", "book-three")
The fn:tokenize() function can work with literal strings like " ", or it can take regular expressions like "s+" (to mean "one or more whitespace characters"). This allows for some pretty sophisticated pattern matching.
For the canonical description of this function, see https://www.w3.org/TR/xpath-functions-31/#func-tokenize, and for more on regular expressions in XPath and XQuery, see https://www.w3.org/TR/xpath-functions-31/#string.match.
answered Nov 14 '18 at 12:42
joewizjoewiz
3,9571120
1
Note that the XQuery 1.0 version of the function requires a regular expression as the second argument, and it's best to callnormalize-space()first to get rid of any leading or trailing whitespace, as the count may otherwise be misleading. XQuery 3.1 has a single-argumenttokenize()function that tokenizes on whitespace after (effectively) doing an implicit normalize-space().
– Michael Kay
Nov 14 '18 at 14:59
add a comment |
Assuming the books are separated by a space, you can split the string into a sequence of strings using the fn:tokenize() function:
fn:tokenize("book-one book-two book-three", " ")
This will return a sequence of the books:
("book-one", "book-two", "book-three")
The fn:tokenize() function can work with literal strings like " ", or it can take regular expressions like "s+" (to mean "one or more whitespace characters"). This allows for some pretty sophisticated pattern matching.
For the canonical description of this function, see https://www.w3.org/TR/xpath-functions-31/#func-tokenize, and for more on regular expressions in XPath and XQuery, see https://www.w3.org/TR/xpath-functions-31/#string.match.
answered Nov 14 '18 at 12:42
joewizjoewiz
3,9571120
Assuming the books are separated by a space, you can split the string into a sequence of strings using the fn:tokenize() function:
fn:tokenize("book-one book-two book-three", " ")
This will return a sequence of the books:
("book-one", "book-two", "book-three")
The fn:tokenize() function can work with literal strings like " ", or it can take regular expressions like "s+" (to mean "one or more whitespace characters"). This allows for some pretty sophisticated pattern matching.
For the canonical description of this function, see https://www.w3.org/TR/xpath-functions-31/#func-tokenize, and for more on regular expressions in XPath and XQuery, see https://www.w3.org/TR/xpath-functions-31/#string.match.
answered Nov 14 '18 at 12:42
joewizjoewiz
3,9571120
answered Nov 14 '18 at 12:42
joewizjoewiz
3,9571120
answered Nov 14 '18 at 12:42
joewizjoewiz
3,9571120
answered Nov 14 '18 at 12:42
joewizjoewiz
3,9571120
3,9571120
1
Note that the XQuery 1.0 version of the function requires a regular expression as the second argument, and it's best to callnormalize-space()first to get rid of any leading or trailing whitespace, as the count may otherwise be misleading. XQuery 3.1 has a single-argumenttokenize()function that tokenizes on whitespace after (effectively) doing an implicit normalize-space().
– Michael Kay
Nov 14 '18 at 14:59
add a comment |
1
Note that the XQuery 1.0 version of the function requires a regular expression as the second argument, and it's best to callnormalize-space()first to get rid of any leading or trailing whitespace, as the count may otherwise be misleading. XQuery 3.1 has a single-argumenttokenize()function that tokenizes on whitespace after (effectively) doing an implicit normalize-space().
– Michael Kay
Nov 14 '18 at 14:59
1
1
Note that the XQuery 1.0 version of the function requires a regular expression as the second argument, and it's best to call
normalize-space() first to get rid of any leading or trailing whitespace, as the count may otherwise be misleading. XQuery 3.1 has a single-argument tokenize() function that tokenizes on whitespace after (effectively) doing an implicit normalize-space().– Michael Kay
Nov 14 '18 at 14:59
Note that the XQuery 1.0 version of the function requires a regular expression as the second argument, and it's best to call
normalize-space() first to get rid of any leading or trailing whitespace, as the count may otherwise be misleading. XQuery 3.1 has a single-argument tokenize() function that tokenizes on whitespace after (effectively) doing an implicit normalize-space().– Michael Kay
Nov 14 '18 at 14:59
add a comment |
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