Why is LEFT JOIN and INNER JOIN returning exact results?












2















Somebody has to know why this happens...



The first two scripts are almost exactly the same, the only difference is that one is a left join and the other one is an inner join. But they both return the same exact rows:



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
select 'aaa', 1, 400 union
select 'aaa', 2, 400 union
select 'aaa', 3, 400 union
select 'aaa', 4, 400 union
select 'bbb', 1, 500 union
select 'bbb', 3, 500 union
select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthnum, w.id, w.monthnum, w.total
from @calendar c inner join @whatjoins w on
c.monthNum = w.monthnum
order by c.monthNum, w.monthnum, id


The same script with a left join, returns the same number of rows:



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
select 'aaa', 1, 400 union
select 'aaa', 2, 400 union
select 'aaa', 3, 400 union
select 'aaa', 4, 400 union
select 'bbb', 1, 500 union
select 'bbb', 3, 500 union
select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthnum, w.id, w.monthnum, w.total
from @calendar c left join @whatjoins w on
c.monthNum = w.monthnum
order by c.monthNum, w.monthnum, id


The next, and 3rd, script, correctly displays the left join. The only difference between this script and the previous one is that I commented the inserts so that @whatjoins only has 'ccc'.



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
--select 'aaa', 1, 400 union
--select 'aaa', 2, 400 union
--select 'aaa', 3, 400 union
--select 'aaa', 4, 400 union
--select 'bbb', 1, 500 union
--select 'bbb', 3, 500 union
--select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthnum, w.id, w.monthnum, w.total
from @calendar c left join @whatjoins w on
c.monthNum = w.monthnum
order by c.monthNum, w.monthnum, id


My main question: why are the first 2 scripts returning the same data?



My secondary question: is there some similar way to use the left join that will return all 12 rows (10 matches and 2 rows with null)?



This is the result I'm looking for:



1   bbb     1       500
2 NULL NULL NULL
3 bbb 3 500
4 bbb 4 999
1 ccc 1 999
2 ccc 2 999
3 NULL NULL NULL
4 ccc 4 999
1 aaa 1 400
2 aaa 2 400
3 aaa 3 400
4 aaa 4 400









share|improve this question

























  • What is the criteria for getting NULL in your expected result? Left join is working as expected.

    – WhoamI
    Nov 13 '18 at 14:18











  • The second query is an inner join. It returns the 10 rows that match with both tables. If it were a left join it would've ideally returned all 12 rows.

    – fdkgfosfskjdlsjdlkfsf
    Nov 13 '18 at 14:28


















2















Somebody has to know why this happens...



The first two scripts are almost exactly the same, the only difference is that one is a left join and the other one is an inner join. But they both return the same exact rows:



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
select 'aaa', 1, 400 union
select 'aaa', 2, 400 union
select 'aaa', 3, 400 union
select 'aaa', 4, 400 union
select 'bbb', 1, 500 union
select 'bbb', 3, 500 union
select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthnum, w.id, w.monthnum, w.total
from @calendar c inner join @whatjoins w on
c.monthNum = w.monthnum
order by c.monthNum, w.monthnum, id


The same script with a left join, returns the same number of rows:



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
select 'aaa', 1, 400 union
select 'aaa', 2, 400 union
select 'aaa', 3, 400 union
select 'aaa', 4, 400 union
select 'bbb', 1, 500 union
select 'bbb', 3, 500 union
select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthnum, w.id, w.monthnum, w.total
from @calendar c left join @whatjoins w on
c.monthNum = w.monthnum
order by c.monthNum, w.monthnum, id


The next, and 3rd, script, correctly displays the left join. The only difference between this script and the previous one is that I commented the inserts so that @whatjoins only has 'ccc'.



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
--select 'aaa', 1, 400 union
--select 'aaa', 2, 400 union
--select 'aaa', 3, 400 union
--select 'aaa', 4, 400 union
--select 'bbb', 1, 500 union
--select 'bbb', 3, 500 union
--select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthnum, w.id, w.monthnum, w.total
from @calendar c left join @whatjoins w on
c.monthNum = w.monthnum
order by c.monthNum, w.monthnum, id


My main question: why are the first 2 scripts returning the same data?



My secondary question: is there some similar way to use the left join that will return all 12 rows (10 matches and 2 rows with null)?



This is the result I'm looking for:



1   bbb     1       500
2 NULL NULL NULL
3 bbb 3 500
4 bbb 4 999
1 ccc 1 999
2 ccc 2 999
3 NULL NULL NULL
4 ccc 4 999
1 aaa 1 400
2 aaa 2 400
3 aaa 3 400
4 aaa 4 400









share|improve this question

























  • What is the criteria for getting NULL in your expected result? Left join is working as expected.

    – WhoamI
    Nov 13 '18 at 14:18











  • The second query is an inner join. It returns the 10 rows that match with both tables. If it were a left join it would've ideally returned all 12 rows.

    – fdkgfosfskjdlsjdlkfsf
    Nov 13 '18 at 14:28
















2












2








2








Somebody has to know why this happens...



The first two scripts are almost exactly the same, the only difference is that one is a left join and the other one is an inner join. But they both return the same exact rows:



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
select 'aaa', 1, 400 union
select 'aaa', 2, 400 union
select 'aaa', 3, 400 union
select 'aaa', 4, 400 union
select 'bbb', 1, 500 union
select 'bbb', 3, 500 union
select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthnum, w.id, w.monthnum, w.total
from @calendar c inner join @whatjoins w on
c.monthNum = w.monthnum
order by c.monthNum, w.monthnum, id


The same script with a left join, returns the same number of rows:



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
select 'aaa', 1, 400 union
select 'aaa', 2, 400 union
select 'aaa', 3, 400 union
select 'aaa', 4, 400 union
select 'bbb', 1, 500 union
select 'bbb', 3, 500 union
select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthnum, w.id, w.monthnum, w.total
from @calendar c left join @whatjoins w on
c.monthNum = w.monthnum
order by c.monthNum, w.monthnum, id


The next, and 3rd, script, correctly displays the left join. The only difference between this script and the previous one is that I commented the inserts so that @whatjoins only has 'ccc'.



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
--select 'aaa', 1, 400 union
--select 'aaa', 2, 400 union
--select 'aaa', 3, 400 union
--select 'aaa', 4, 400 union
--select 'bbb', 1, 500 union
--select 'bbb', 3, 500 union
--select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthnum, w.id, w.monthnum, w.total
from @calendar c left join @whatjoins w on
c.monthNum = w.monthnum
order by c.monthNum, w.monthnum, id


My main question: why are the first 2 scripts returning the same data?



My secondary question: is there some similar way to use the left join that will return all 12 rows (10 matches and 2 rows with null)?



This is the result I'm looking for:



1   bbb     1       500
2 NULL NULL NULL
3 bbb 3 500
4 bbb 4 999
1 ccc 1 999
2 ccc 2 999
3 NULL NULL NULL
4 ccc 4 999
1 aaa 1 400
2 aaa 2 400
3 aaa 3 400
4 aaa 4 400









share|improve this question
















Somebody has to know why this happens...



The first two scripts are almost exactly the same, the only difference is that one is a left join and the other one is an inner join. But they both return the same exact rows:



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
select 'aaa', 1, 400 union
select 'aaa', 2, 400 union
select 'aaa', 3, 400 union
select 'aaa', 4, 400 union
select 'bbb', 1, 500 union
select 'bbb', 3, 500 union
select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthnum, w.id, w.monthnum, w.total
from @calendar c inner join @whatjoins w on
c.monthNum = w.monthnum
order by c.monthNum, w.monthnum, id


The same script with a left join, returns the same number of rows:



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
select 'aaa', 1, 400 union
select 'aaa', 2, 400 union
select 'aaa', 3, 400 union
select 'aaa', 4, 400 union
select 'bbb', 1, 500 union
select 'bbb', 3, 500 union
select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthnum, w.id, w.monthnum, w.total
from @calendar c left join @whatjoins w on
c.monthNum = w.monthnum
order by c.monthNum, w.monthnum, id


The next, and 3rd, script, correctly displays the left join. The only difference between this script and the previous one is that I commented the inserts so that @whatjoins only has 'ccc'.



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
--select 'aaa', 1, 400 union
--select 'aaa', 2, 400 union
--select 'aaa', 3, 400 union
--select 'aaa', 4, 400 union
--select 'bbb', 1, 500 union
--select 'bbb', 3, 500 union
--select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthnum, w.id, w.monthnum, w.total
from @calendar c left join @whatjoins w on
c.monthNum = w.monthnum
order by c.monthNum, w.monthnum, id


My main question: why are the first 2 scripts returning the same data?



My secondary question: is there some similar way to use the left join that will return all 12 rows (10 matches and 2 rows with null)?



This is the result I'm looking for:



1   bbb     1       500
2 NULL NULL NULL
3 bbb 3 500
4 bbb 4 999
1 ccc 1 999
2 ccc 2 999
3 NULL NULL NULL
4 ccc 4 999
1 aaa 1 400
2 aaa 2 400
3 aaa 3 400
4 aaa 4 400






sql sql-server tsql sql-server-2008






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 20 '18 at 19:27







fdkgfosfskjdlsjdlkfsf

















asked Nov 13 '18 at 13:36









fdkgfosfskjdlsjdlkfsffdkgfosfskjdlsjdlkfsf

1,147937




1,147937













  • What is the criteria for getting NULL in your expected result? Left join is working as expected.

    – WhoamI
    Nov 13 '18 at 14:18











  • The second query is an inner join. It returns the 10 rows that match with both tables. If it were a left join it would've ideally returned all 12 rows.

    – fdkgfosfskjdlsjdlkfsf
    Nov 13 '18 at 14:28





















  • What is the criteria for getting NULL in your expected result? Left join is working as expected.

    – WhoamI
    Nov 13 '18 at 14:18











  • The second query is an inner join. It returns the 10 rows that match with both tables. If it were a left join it would've ideally returned all 12 rows.

    – fdkgfosfskjdlsjdlkfsf
    Nov 13 '18 at 14:28



















What is the criteria for getting NULL in your expected result? Left join is working as expected.

– WhoamI
Nov 13 '18 at 14:18





What is the criteria for getting NULL in your expected result? Left join is working as expected.

– WhoamI
Nov 13 '18 at 14:18













The second query is an inner join. It returns the 10 rows that match with both tables. If it were a left join it would've ideally returned all 12 rows.

– fdkgfosfskjdlsjdlkfsf
Nov 13 '18 at 14:28







The second query is an inner join. It returns the 10 rows that match with both tables. If it were a left join it would've ideally returned all 12 rows.

– fdkgfosfskjdlsjdlkfsf
Nov 13 '18 at 14:28














2 Answers
2






active

oldest

votes


















0














Not an efficient one, but works.



declare @calendar table 
(
monthNum int
)
insert into @calendar
select 1 union
select 2 union
select 3 union
select 4

declare @whatjoins table
(
id varchar(3),
monthnum int,
total int
)
insert into @whatjoins
select 'aaa', 1, 400 union
select 'aaa', 2, 400 union
select 'aaa', 3, 400 union
select 'aaa', 4, 400 union
select 'bbb', 1, 500 union
select 'bbb', 3, 500 union
select 'bbb', 4, 999 union
select 'ccc', 1, 999 union
select 'ccc', 2, 999 union
select 'ccc', 4, 999


select
c.monthNum,w2.*
from @calendar c CROSS JOIN (SELECT DISTINCT id FROM @whatjoins w)w
LEFT JOIN @whatjoins w2 ON w2.id = w.id AND c.monthNum=w2.monthnum
ORDER BY id


Only thing is I can't figure out an order by for this for the exact output you asked



ORDER BY ROW_NUMBER() OVER(PARTITION BY c.monthNum ORDER BY c.monthNum)


this is something I have come across but still not valid






share|improve this answer































    0














    You need CROSS JOIN before LEFT JOIN because of you want to repeat all monthnums for each ids :



    select distinct c.monthNum, w.id, w1.monthnum, w1.total 
    from @whatjoins w cross join
    @calendar c left join
    @whatjoins w1
    on w1.id = w.id and w1.monthnum = c.monthNum
    order by w.id, c.monthNum;





    share|improve this answer























      Your Answer






      StackExchange.ifUsing("editor", function () {
      StackExchange.using("externalEditor", function () {
      StackExchange.using("snippets", function () {
      StackExchange.snippets.init();
      });
      });
      }, "code-snippets");

      StackExchange.ready(function() {
      var channelOptions = {
      tags: "".split(" "),
      id: "1"
      };
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function() {
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled) {
      StackExchange.using("snippets", function() {
      createEditor();
      });
      }
      else {
      createEditor();
      }
      });

      function createEditor() {
      StackExchange.prepareEditor({
      heartbeatType: 'answer',
      autoActivateHeartbeat: false,
      convertImagesToLinks: true,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: 10,
      bindNavPrevention: true,
      postfix: "",
      imageUploader: {
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      },
      onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      });


      }
      });














      draft saved

      draft discarded


















      StackExchange.ready(
      function () {
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53282237%2fwhy-is-left-join-and-inner-join-returning-exact-results%23new-answer', 'question_page');
      }
      );

      Post as a guest















      Required, but never shown

























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      Not an efficient one, but works.



      declare @calendar table 
      (
      monthNum int
      )
      insert into @calendar
      select 1 union
      select 2 union
      select 3 union
      select 4

      declare @whatjoins table
      (
      id varchar(3),
      monthnum int,
      total int
      )
      insert into @whatjoins
      select 'aaa', 1, 400 union
      select 'aaa', 2, 400 union
      select 'aaa', 3, 400 union
      select 'aaa', 4, 400 union
      select 'bbb', 1, 500 union
      select 'bbb', 3, 500 union
      select 'bbb', 4, 999 union
      select 'ccc', 1, 999 union
      select 'ccc', 2, 999 union
      select 'ccc', 4, 999


      select
      c.monthNum,w2.*
      from @calendar c CROSS JOIN (SELECT DISTINCT id FROM @whatjoins w)w
      LEFT JOIN @whatjoins w2 ON w2.id = w.id AND c.monthNum=w2.monthnum
      ORDER BY id


      Only thing is I can't figure out an order by for this for the exact output you asked



      ORDER BY ROW_NUMBER() OVER(PARTITION BY c.monthNum ORDER BY c.monthNum)


      this is something I have come across but still not valid






      share|improve this answer




























        0














        Not an efficient one, but works.



        declare @calendar table 
        (
        monthNum int
        )
        insert into @calendar
        select 1 union
        select 2 union
        select 3 union
        select 4

        declare @whatjoins table
        (
        id varchar(3),
        monthnum int,
        total int
        )
        insert into @whatjoins
        select 'aaa', 1, 400 union
        select 'aaa', 2, 400 union
        select 'aaa', 3, 400 union
        select 'aaa', 4, 400 union
        select 'bbb', 1, 500 union
        select 'bbb', 3, 500 union
        select 'bbb', 4, 999 union
        select 'ccc', 1, 999 union
        select 'ccc', 2, 999 union
        select 'ccc', 4, 999


        select
        c.monthNum,w2.*
        from @calendar c CROSS JOIN (SELECT DISTINCT id FROM @whatjoins w)w
        LEFT JOIN @whatjoins w2 ON w2.id = w.id AND c.monthNum=w2.monthnum
        ORDER BY id


        Only thing is I can't figure out an order by for this for the exact output you asked



        ORDER BY ROW_NUMBER() OVER(PARTITION BY c.monthNum ORDER BY c.monthNum)


        this is something I have come across but still not valid






        share|improve this answer


























          0












          0








          0







          Not an efficient one, but works.



          declare @calendar table 
          (
          monthNum int
          )
          insert into @calendar
          select 1 union
          select 2 union
          select 3 union
          select 4

          declare @whatjoins table
          (
          id varchar(3),
          monthnum int,
          total int
          )
          insert into @whatjoins
          select 'aaa', 1, 400 union
          select 'aaa', 2, 400 union
          select 'aaa', 3, 400 union
          select 'aaa', 4, 400 union
          select 'bbb', 1, 500 union
          select 'bbb', 3, 500 union
          select 'bbb', 4, 999 union
          select 'ccc', 1, 999 union
          select 'ccc', 2, 999 union
          select 'ccc', 4, 999


          select
          c.monthNum,w2.*
          from @calendar c CROSS JOIN (SELECT DISTINCT id FROM @whatjoins w)w
          LEFT JOIN @whatjoins w2 ON w2.id = w.id AND c.monthNum=w2.monthnum
          ORDER BY id


          Only thing is I can't figure out an order by for this for the exact output you asked



          ORDER BY ROW_NUMBER() OVER(PARTITION BY c.monthNum ORDER BY c.monthNum)


          this is something I have come across but still not valid






          share|improve this answer













          Not an efficient one, but works.



          declare @calendar table 
          (
          monthNum int
          )
          insert into @calendar
          select 1 union
          select 2 union
          select 3 union
          select 4

          declare @whatjoins table
          (
          id varchar(3),
          monthnum int,
          total int
          )
          insert into @whatjoins
          select 'aaa', 1, 400 union
          select 'aaa', 2, 400 union
          select 'aaa', 3, 400 union
          select 'aaa', 4, 400 union
          select 'bbb', 1, 500 union
          select 'bbb', 3, 500 union
          select 'bbb', 4, 999 union
          select 'ccc', 1, 999 union
          select 'ccc', 2, 999 union
          select 'ccc', 4, 999


          select
          c.monthNum,w2.*
          from @calendar c CROSS JOIN (SELECT DISTINCT id FROM @whatjoins w)w
          LEFT JOIN @whatjoins w2 ON w2.id = w.id AND c.monthNum=w2.monthnum
          ORDER BY id


          Only thing is I can't figure out an order by for this for the exact output you asked



          ORDER BY ROW_NUMBER() OVER(PARTITION BY c.monthNum ORDER BY c.monthNum)


          this is something I have come across but still not valid







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 13 '18 at 14:11









          Biju joseBiju jose

          19719




          19719

























              0














              You need CROSS JOIN before LEFT JOIN because of you want to repeat all monthnums for each ids :



              select distinct c.monthNum, w.id, w1.monthnum, w1.total 
              from @whatjoins w cross join
              @calendar c left join
              @whatjoins w1
              on w1.id = w.id and w1.monthnum = c.monthNum
              order by w.id, c.monthNum;





              share|improve this answer




























                0














                You need CROSS JOIN before LEFT JOIN because of you want to repeat all monthnums for each ids :



                select distinct c.monthNum, w.id, w1.monthnum, w1.total 
                from @whatjoins w cross join
                @calendar c left join
                @whatjoins w1
                on w1.id = w.id and w1.monthnum = c.monthNum
                order by w.id, c.monthNum;





                share|improve this answer


























                  0












                  0








                  0







                  You need CROSS JOIN before LEFT JOIN because of you want to repeat all monthnums for each ids :



                  select distinct c.monthNum, w.id, w1.monthnum, w1.total 
                  from @whatjoins w cross join
                  @calendar c left join
                  @whatjoins w1
                  on w1.id = w.id and w1.monthnum = c.monthNum
                  order by w.id, c.monthNum;





                  share|improve this answer













                  You need CROSS JOIN before LEFT JOIN because of you want to repeat all monthnums for each ids :



                  select distinct c.monthNum, w.id, w1.monthnum, w1.total 
                  from @whatjoins w cross join
                  @calendar c left join
                  @whatjoins w1
                  on w1.id = w.id and w1.monthnum = c.monthNum
                  order by w.id, c.monthNum;






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 13 '18 at 14:22









                  Yogesh SharmaYogesh Sharma

                  28.9k51336




                  28.9k51336






























                      draft saved

                      draft discarded




















































                      Thanks for contributing an answer to Stack Overflow!


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid



                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.


                      To learn more, see our tips on writing great answers.




                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function () {
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53282237%2fwhy-is-left-join-and-inner-join-returning-exact-results%23new-answer', 'question_page');
                      }
                      );

                      Post as a guest















                      Required, but never shown





















































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown

































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown







                      Popular posts from this blog

                      Xamarin.iOS Cant Deploy on Iphone

                      Glorious Revolution

                      Dulmage-Mendelsohn matrix decomposition in Python