Reentering an if loop after else condition is met Python3












-1















I have a csv file with gene start and end sites. I want to loop though the file, condensing overlapping regions of transcription. My data is formatted as a list of short lists (containing "chromosome number", "start site", "end site"). In my code, I'm reading in lists from the list and condensing them under a loop the specifies that they must be on the same chromosome, else exit the loop. after I exit the loop though, I was to be able take a new chromosome number as the base line and restart the loop using it. Is there a way that I can do this?










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  • hello, please provide a minimal working example stackoverflow.com/help/mcve

    – vencaslac
    Nov 13 '18 at 17:47
















-1















I have a csv file with gene start and end sites. I want to loop though the file, condensing overlapping regions of transcription. My data is formatted as a list of short lists (containing "chromosome number", "start site", "end site"). In my code, I'm reading in lists from the list and condensing them under a loop the specifies that they must be on the same chromosome, else exit the loop. after I exit the loop though, I was to be able take a new chromosome number as the base line and restart the loop using it. Is there a way that I can do this?










share|improve this question























  • hello, please provide a minimal working example stackoverflow.com/help/mcve

    – vencaslac
    Nov 13 '18 at 17:47














-1












-1








-1








I have a csv file with gene start and end sites. I want to loop though the file, condensing overlapping regions of transcription. My data is formatted as a list of short lists (containing "chromosome number", "start site", "end site"). In my code, I'm reading in lists from the list and condensing them under a loop the specifies that they must be on the same chromosome, else exit the loop. after I exit the loop though, I was to be able take a new chromosome number as the base line and restart the loop using it. Is there a way that I can do this?










share|improve this question














I have a csv file with gene start and end sites. I want to loop though the file, condensing overlapping regions of transcription. My data is formatted as a list of short lists (containing "chromosome number", "start site", "end site"). In my code, I'm reading in lists from the list and condensing them under a loop the specifies that they must be on the same chromosome, else exit the loop. after I exit the loop though, I was to be able take a new chromosome number as the base line and restart the loop using it. Is there a way that I can do this?







python-3.x if-statement






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asked Nov 13 '18 at 17:35









O'Briain LauraO'Briain Laura

1




1













  • hello, please provide a minimal working example stackoverflow.com/help/mcve

    – vencaslac
    Nov 13 '18 at 17:47



















  • hello, please provide a minimal working example stackoverflow.com/help/mcve

    – vencaslac
    Nov 13 '18 at 17:47

















hello, please provide a minimal working example stackoverflow.com/help/mcve

– vencaslac
Nov 13 '18 at 17:47





hello, please provide a minimal working example stackoverflow.com/help/mcve

– vencaslac
Nov 13 '18 at 17:47












1 Answer
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It seems to me that you would be best suited to use a function in this case. Your function can take a Chromosome number and a list as parameters. It would then process the data depending on the particular information you pass to it.



def loop_it(chromosome_number, _list):
condensed_list =
for item in _list:
if item[0] == chromosome_number:
condensed_list.append(item)
else:
pass
return condensed_list


Then you can define your list and pass it to the function along with the chromosome number you are hoping to find it on. so say you have a list:



data_list = [[7, "ATG", "GCG"],[2, "AGG", "GCG"]] #format ->["chromosome number", "start site", "end site"]



Now, you can iterate the list over and over using different chromosome numbers.



chrome7 = loop_it(7, data_list) and chrome2 = loop_it(2, data_list)






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    It seems to me that you would be best suited to use a function in this case. Your function can take a Chromosome number and a list as parameters. It would then process the data depending on the particular information you pass to it.



    def loop_it(chromosome_number, _list):
    condensed_list =
    for item in _list:
    if item[0] == chromosome_number:
    condensed_list.append(item)
    else:
    pass
    return condensed_list


    Then you can define your list and pass it to the function along with the chromosome number you are hoping to find it on. so say you have a list:



    data_list = [[7, "ATG", "GCG"],[2, "AGG", "GCG"]] #format ->["chromosome number", "start site", "end site"]



    Now, you can iterate the list over and over using different chromosome numbers.



    chrome7 = loop_it(7, data_list) and chrome2 = loop_it(2, data_list)






    share|improve this answer




























      0














      It seems to me that you would be best suited to use a function in this case. Your function can take a Chromosome number and a list as parameters. It would then process the data depending on the particular information you pass to it.



      def loop_it(chromosome_number, _list):
      condensed_list =
      for item in _list:
      if item[0] == chromosome_number:
      condensed_list.append(item)
      else:
      pass
      return condensed_list


      Then you can define your list and pass it to the function along with the chromosome number you are hoping to find it on. so say you have a list:



      data_list = [[7, "ATG", "GCG"],[2, "AGG", "GCG"]] #format ->["chromosome number", "start site", "end site"]



      Now, you can iterate the list over and over using different chromosome numbers.



      chrome7 = loop_it(7, data_list) and chrome2 = loop_it(2, data_list)






      share|improve this answer


























        0












        0








        0







        It seems to me that you would be best suited to use a function in this case. Your function can take a Chromosome number and a list as parameters. It would then process the data depending on the particular information you pass to it.



        def loop_it(chromosome_number, _list):
        condensed_list =
        for item in _list:
        if item[0] == chromosome_number:
        condensed_list.append(item)
        else:
        pass
        return condensed_list


        Then you can define your list and pass it to the function along with the chromosome number you are hoping to find it on. so say you have a list:



        data_list = [[7, "ATG", "GCG"],[2, "AGG", "GCG"]] #format ->["chromosome number", "start site", "end site"]



        Now, you can iterate the list over and over using different chromosome numbers.



        chrome7 = loop_it(7, data_list) and chrome2 = loop_it(2, data_list)






        share|improve this answer













        It seems to me that you would be best suited to use a function in this case. Your function can take a Chromosome number and a list as parameters. It would then process the data depending on the particular information you pass to it.



        def loop_it(chromosome_number, _list):
        condensed_list =
        for item in _list:
        if item[0] == chromosome_number:
        condensed_list.append(item)
        else:
        pass
        return condensed_list


        Then you can define your list and pass it to the function along with the chromosome number you are hoping to find it on. so say you have a list:



        data_list = [[7, "ATG", "GCG"],[2, "AGG", "GCG"]] #format ->["chromosome number", "start site", "end site"]



        Now, you can iterate the list over and over using different chromosome numbers.



        chrome7 = loop_it(7, data_list) and chrome2 = loop_it(2, data_list)







        share|improve this answer












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        share|improve this answer










        answered Nov 13 '18 at 18:34









        jk622jk622

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