c# implemented interface variable used in derived class
I am trying to implement an interface method in class A, and through that realization I want to give variable g value from input and then be able to read that g value in other derived classes. The problem is, non of the derived classes are able to see that value. What seems to be the problem?
interface ISomething
{
void something(string some);
}
public class A : ISomething
{
public string g;
public void something(string some)
{
g = some;
}
}
public class B : A
{
public void methodB()
{
Console.WriteLine($"Printing g value from method B: {g}");
}
}
public class C : A
{
public void methodC()
{
Console.WriteLine($"Printing g value from method C: {g}");
}
}
public class D : B
{
public void methodD()
{
Console.WriteLine($"Printing g value from method D: {g}");
}
}
static void Main(string args)
{
Console.WriteLine("Input something: ");
string x = Console.ReadLine();
A a = new A();
a.something(x);
B b = new B();
C c = new C();
D d = new D();
b.methodB();
c.methodC();
d.methodD();
Console.ReadKey();
}
class variables interface implementation derived
asked Nov 13 '18 at 17:35
Marijus BražiūnasMarijus Bražiūnas
101
add a comment |
I am trying to implement an interface method in class A, and through that realization I want to give variable g value from input and then be able to read that g value in other derived classes. The problem is, non of the derived classes are able to see that value. What seems to be the problem?
interface ISomething
{
void something(string some);
}
public class A : ISomething
{
public string g;
public void something(string some)
{
g = some;
}
}
public class B : A
{
public void methodB()
{
Console.WriteLine($"Printing g value from method B: {g}");
}
}
public class C : A
{
public void methodC()
{
Console.WriteLine($"Printing g value from method C: {g}");
}
}
public class D : B
{
public void methodD()
{
Console.WriteLine($"Printing g value from method D: {g}");
}
}
static void Main(string args)
{
Console.WriteLine("Input something: ");
string x = Console.ReadLine();
A a = new A();
a.something(x);
B b = new B();
C c = new C();
D d = new D();
b.methodB();
c.methodC();
d.methodD();
Console.ReadKey();
}
class variables interface implementation derived
asked Nov 13 '18 at 17:35
Marijus BražiūnasMarijus Bražiūnas
101
add a comment |
I am trying to implement an interface method in class A, and through that realization I want to give variable g value from input and then be able to read that g value in other derived classes. The problem is, non of the derived classes are able to see that value. What seems to be the problem?
interface ISomething
{
void something(string some);
}
public class A : ISomething
{
public string g;
public void something(string some)
{
g = some;
}
}
public class B : A
{
public void methodB()
{
Console.WriteLine($"Printing g value from method B: {g}");
}
}
public class C : A
{
public void methodC()
{
Console.WriteLine($"Printing g value from method C: {g}");
}
}
public class D : B
{
public void methodD()
{
Console.WriteLine($"Printing g value from method D: {g}");
}
}
static void Main(string args)
{
Console.WriteLine("Input something: ");
string x = Console.ReadLine();
A a = new A();
a.something(x);
B b = new B();
C c = new C();
D d = new D();
b.methodB();
c.methodC();
d.methodD();
Console.ReadKey();
}
class variables interface implementation derived
asked Nov 13 '18 at 17:35
Marijus BražiūnasMarijus Bražiūnas
101
I am trying to implement an interface method in class A, and through that realization I want to give variable g value from input and then be able to read that g value in other derived classes. The problem is, non of the derived classes are able to see that value. What seems to be the problem?
interface ISomething
{
void something(string some);
}
public class A : ISomething
{
public string g;
public void something(string some)
{
g = some;
}
}
public class B : A
{
public void methodB()
{
Console.WriteLine($"Printing g value from method B: {g}");
}
}
public class C : A
{
public void methodC()
{
Console.WriteLine($"Printing g value from method C: {g}");
}
}
public class D : B
{
public void methodD()
{
Console.WriteLine($"Printing g value from method D: {g}");
}
}
static void Main(string args)
{
Console.WriteLine("Input something: ");
string x = Console.ReadLine();
A a = new A();
a.something(x);
B b = new B();
C c = new C();
D d = new D();
b.methodB();
c.methodC();
d.methodD();
Console.ReadKey();
}
class variables interface implementation derived
class variables interface implementation derived
asked Nov 13 '18 at 17:35
Marijus BražiūnasMarijus Bražiūnas
101
asked Nov 13 '18 at 17:35
Marijus BražiūnasMarijus Bražiūnas
101
asked Nov 13 '18 at 17:35
Marijus BražiūnasMarijus Bražiūnas
101
asked Nov 13 '18 at 17:35
Marijus BražiūnasMarijus Bražiūnas
101
asked Nov 13 '18 at 17:35
Marijus BražiūnasMarijus Bražiūnas
101
101
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Just because B, C, D inherit from A does not mean their field g will get initialized to anything. Each object created is still an independent object, just because you declared an object of type A does not mean every class instance that inherit from A are going to hold the same field value as the instance of A that you create. You should be setting the field g of each derived class by calling the something() method, so change your code to this:
B b = new B();
C c = new C();
D d = new D();
d.something(x);
c.something(x);
b.something(x);
b.methodB();
c.methodC();
d.methodD();
answered Nov 13 '18 at 17:40
Ryan WilsonRyan Wilson
3,8391518
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just because B, C, D inherit from A does not mean their field g will get initialized to anything. Each object created is still an independent object, just because you declared an object of type A does not mean every class instance that inherit from A are going to hold the same field value as the instance of A that you create. You should be setting the field g of each derived class by calling the something() method, so change your code to this:
B b = new B();
C c = new C();
D d = new D();
d.something(x);
c.something(x);
b.something(x);
b.methodB();
c.methodC();
d.methodD();
answered Nov 13 '18 at 17:40
Ryan WilsonRyan Wilson
3,8391518
add a comment |
Just because B, C, D inherit from A does not mean their field g will get initialized to anything. Each object created is still an independent object, just because you declared an object of type A does not mean every class instance that inherit from A are going to hold the same field value as the instance of A that you create. You should be setting the field g of each derived class by calling the something() method, so change your code to this:
B b = new B();
C c = new C();
D d = new D();
d.something(x);
c.something(x);
b.something(x);
b.methodB();
c.methodC();
d.methodD();
answered Nov 13 '18 at 17:40
Ryan WilsonRyan Wilson
3,8391518
add a comment |
Just because B, C, D inherit from A does not mean their field g will get initialized to anything. Each object created is still an independent object, just because you declared an object of type A does not mean every class instance that inherit from A are going to hold the same field value as the instance of A that you create. You should be setting the field g of each derived class by calling the something() method, so change your code to this:
B b = new B();
C c = new C();
D d = new D();
d.something(x);
c.something(x);
b.something(x);
b.methodB();
c.methodC();
d.methodD();
answered Nov 13 '18 at 17:40
Ryan WilsonRyan Wilson
3,8391518
Just because B, C, D inherit from A does not mean their field g will get initialized to anything. Each object created is still an independent object, just because you declared an object of type A does not mean every class instance that inherit from A are going to hold the same field value as the instance of A that you create. You should be setting the field g of each derived class by calling the something() method, so change your code to this:
B b = new B();
C c = new C();
D d = new D();
d.something(x);
c.something(x);
b.something(x);
b.methodB();
c.methodC();
d.methodD();
answered Nov 13 '18 at 17:40
Ryan WilsonRyan Wilson
3,8391518
answered Nov 13 '18 at 17:40
Ryan WilsonRyan Wilson
3,8391518
answered Nov 13 '18 at 17:40
Ryan WilsonRyan Wilson
3,8391518
answered Nov 13 '18 at 17:40
Ryan WilsonRyan Wilson
3,8391518
3,8391518
add a comment |
add a comment |
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