How to find specific value using generator in python












0















I created a generator that returns a tuple, for instance the name of an item and the price.



output = ('apple',$2)


I want to find the tuple when the price is the maximum, out of all outputs of the generator.



I know how to get the maximum of the second item when the tuple is not an output of the generator, but I don't know when the generator needs to be looped.



Should I append the looped outcomes and create a super list first? For instance, [('apple',$2),('pear',$1) ... ]










share|improve this question

























  • $2 is illegal python .. me thinks - either it is a string or a number w/o the $ sign

    – Patrick Artner
    Nov 13 '18 at 17:48


















0















I created a generator that returns a tuple, for instance the name of an item and the price.



output = ('apple',$2)


I want to find the tuple when the price is the maximum, out of all outputs of the generator.



I know how to get the maximum of the second item when the tuple is not an output of the generator, but I don't know when the generator needs to be looped.



Should I append the looped outcomes and create a super list first? For instance, [('apple',$2),('pear',$1) ... ]










share|improve this question

























  • $2 is illegal python .. me thinks - either it is a string or a number w/o the $ sign

    – Patrick Artner
    Nov 13 '18 at 17:48
















0












0








0








I created a generator that returns a tuple, for instance the name of an item and the price.



output = ('apple',$2)


I want to find the tuple when the price is the maximum, out of all outputs of the generator.



I know how to get the maximum of the second item when the tuple is not an output of the generator, but I don't know when the generator needs to be looped.



Should I append the looped outcomes and create a super list first? For instance, [('apple',$2),('pear',$1) ... ]










share|improve this question
















I created a generator that returns a tuple, for instance the name of an item and the price.



output = ('apple',$2)


I want to find the tuple when the price is the maximum, out of all outputs of the generator.



I know how to get the maximum of the second item when the tuple is not an output of the generator, but I don't know when the generator needs to be looped.



Should I append the looped outcomes and create a super list first? For instance, [('apple',$2),('pear',$1) ... ]







python python-3.x generator iterable






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edited Nov 13 '18 at 17:42









jpp

96.1k2157109




96.1k2157109










asked Nov 13 '18 at 17:36









song0089song0089

87231235




87231235













  • $2 is illegal python .. me thinks - either it is a string or a number w/o the $ sign

    – Patrick Artner
    Nov 13 '18 at 17:48





















  • $2 is illegal python .. me thinks - either it is a string or a number w/o the $ sign

    – Patrick Artner
    Nov 13 '18 at 17:48



















$2 is illegal python .. me thinks - either it is a string or a number w/o the $ sign

– Patrick Artner
Nov 13 '18 at 17:48







$2 is illegal python .. me thinks - either it is a string or a number w/o the $ sign

– Patrick Artner
Nov 13 '18 at 17:48














1 Answer
1






active

oldest

votes


















3














max accepts any iterable. A generator is an iterable. You can supply a custom key function so that max considers only the 1st index:



from operator import itemgetter

# generator expression below can also be a generator function
gen = (i for i in (('apple', 2), ('pear', 1)))

res = max(gen, key=itemgetter(1)) # ('apple', 2)





share|improve this answer


























  • That works if tup[1] is an int, otherwise a custom function to cast as int is needed

    – Dalvenjia
    Nov 13 '18 at 18:01











  • @Dalvenjia, Agreed, in that case, you can use lambda x: int(x[1]) (if it's a string).

    – jpp
    Nov 13 '18 at 18:02













  • or lambda x: int(x[1].strip('$')) if the amount is in dollars as stated in the question

    – Dalvenjia
    Nov 13 '18 at 18:04











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














max accepts any iterable. A generator is an iterable. You can supply a custom key function so that max considers only the 1st index:



from operator import itemgetter

# generator expression below can also be a generator function
gen = (i for i in (('apple', 2), ('pear', 1)))

res = max(gen, key=itemgetter(1)) # ('apple', 2)





share|improve this answer


























  • That works if tup[1] is an int, otherwise a custom function to cast as int is needed

    – Dalvenjia
    Nov 13 '18 at 18:01











  • @Dalvenjia, Agreed, in that case, you can use lambda x: int(x[1]) (if it's a string).

    – jpp
    Nov 13 '18 at 18:02













  • or lambda x: int(x[1].strip('$')) if the amount is in dollars as stated in the question

    – Dalvenjia
    Nov 13 '18 at 18:04
















3














max accepts any iterable. A generator is an iterable. You can supply a custom key function so that max considers only the 1st index:



from operator import itemgetter

# generator expression below can also be a generator function
gen = (i for i in (('apple', 2), ('pear', 1)))

res = max(gen, key=itemgetter(1)) # ('apple', 2)





share|improve this answer


























  • That works if tup[1] is an int, otherwise a custom function to cast as int is needed

    – Dalvenjia
    Nov 13 '18 at 18:01











  • @Dalvenjia, Agreed, in that case, you can use lambda x: int(x[1]) (if it's a string).

    – jpp
    Nov 13 '18 at 18:02













  • or lambda x: int(x[1].strip('$')) if the amount is in dollars as stated in the question

    – Dalvenjia
    Nov 13 '18 at 18:04














3












3








3







max accepts any iterable. A generator is an iterable. You can supply a custom key function so that max considers only the 1st index:



from operator import itemgetter

# generator expression below can also be a generator function
gen = (i for i in (('apple', 2), ('pear', 1)))

res = max(gen, key=itemgetter(1)) # ('apple', 2)





share|improve this answer















max accepts any iterable. A generator is an iterable. You can supply a custom key function so that max considers only the 1st index:



from operator import itemgetter

# generator expression below can also be a generator function
gen = (i for i in (('apple', 2), ('pear', 1)))

res = max(gen, key=itemgetter(1)) # ('apple', 2)






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 13 '18 at 17:48

























answered Nov 13 '18 at 17:40









jppjpp

96.1k2157109




96.1k2157109













  • That works if tup[1] is an int, otherwise a custom function to cast as int is needed

    – Dalvenjia
    Nov 13 '18 at 18:01











  • @Dalvenjia, Agreed, in that case, you can use lambda x: int(x[1]) (if it's a string).

    – jpp
    Nov 13 '18 at 18:02













  • or lambda x: int(x[1].strip('$')) if the amount is in dollars as stated in the question

    – Dalvenjia
    Nov 13 '18 at 18:04



















  • That works if tup[1] is an int, otherwise a custom function to cast as int is needed

    – Dalvenjia
    Nov 13 '18 at 18:01











  • @Dalvenjia, Agreed, in that case, you can use lambda x: int(x[1]) (if it's a string).

    – jpp
    Nov 13 '18 at 18:02













  • or lambda x: int(x[1].strip('$')) if the amount is in dollars as stated in the question

    – Dalvenjia
    Nov 13 '18 at 18:04

















That works if tup[1] is an int, otherwise a custom function to cast as int is needed

– Dalvenjia
Nov 13 '18 at 18:01





That works if tup[1] is an int, otherwise a custom function to cast as int is needed

– Dalvenjia
Nov 13 '18 at 18:01













@Dalvenjia, Agreed, in that case, you can use lambda x: int(x[1]) (if it's a string).

– jpp
Nov 13 '18 at 18:02







@Dalvenjia, Agreed, in that case, you can use lambda x: int(x[1]) (if it's a string).

– jpp
Nov 13 '18 at 18:02















or lambda x: int(x[1].strip('$')) if the amount is in dollars as stated in the question

– Dalvenjia
Nov 13 '18 at 18:04





or lambda x: int(x[1].strip('$')) if the amount is in dollars as stated in the question

– Dalvenjia
Nov 13 '18 at 18:04


















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