python: extract float from a python list of string( AUD 31.99)












2














python: extract float from a python list of string( AUD 31.99).
I used openpyxl to read from an excel file the amount list. and i saved it in a list but the list is in string form like this: 



['31.40 AUD', ' 32.99 AUD', '37.24 AUD']


I need to get the float from the string item list so that i can later save it in a new list to get the total of them.



Desired output:



[31.40, 32.99, 37.24]


I have already tried these:



newList = re.findall("d+.d+", tot[0])

print(newList)


Output:



[31.40]


But How can I use this for all the item elements?



I am new to python, this is just for some work i do, wanted to see the total using python instead of using excel`s find & replace option.
thanks






python regex excel list openpyxl







share|improve this question
























  • Take a look here: book.pythontips.com/en/latest/map_filter.html
    – Julio
    Nov 13 '18 at 8:24






  • 1




    You should do the conversion before creating the list.
    – Charlie Clark
    Nov 13 '18 at 8:25










  • You are close.. but you are just passing tot[0].
    – Anton vBR
    Nov 13 '18 at 8:26






  • 3




    try [item.split()[0] for item in ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']]
    – Andersson
    Nov 13 '18 at 8:26






  • 1




    Is it mandatory to use regex?
    – Vasilis G.
    Nov 13 '18 at 8:28
















2














python: extract float from a python list of string( AUD 31.99).
I used openpyxl to read from an excel file the amount list. and i saved it in a list but the list is in string form like this: 



['31.40 AUD', ' 32.99 AUD', '37.24 AUD']


I need to get the float from the string item list so that i can later save it in a new list to get the total of them.



Desired output:



[31.40, 32.99, 37.24]


I have already tried these:



newList = re.findall("d+.d+", tot[0])

print(newList)


Output:



[31.40]


But How can I use this for all the item elements?



I am new to python, this is just for some work i do, wanted to see the total using python instead of using excel`s find & replace option.
thanks






python regex excel list openpyxl







share|improve this question
























  • Take a look here: book.pythontips.com/en/latest/map_filter.html
    – Julio
    Nov 13 '18 at 8:24






  • 1




    You should do the conversion before creating the list.
    – Charlie Clark
    Nov 13 '18 at 8:25










  • You are close.. but you are just passing tot[0].
    – Anton vBR
    Nov 13 '18 at 8:26






  • 3




    try [item.split()[0] for item in ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']]
    – Andersson
    Nov 13 '18 at 8:26






  • 1




    Is it mandatory to use regex?
    – Vasilis G.
    Nov 13 '18 at 8:28














2












2








2







python: extract float from a python list of string( AUD 31.99).
I used openpyxl to read from an excel file the amount list. and i saved it in a list but the list is in string form like this: 



['31.40 AUD', ' 32.99 AUD', '37.24 AUD']


I need to get the float from the string item list so that i can later save it in a new list to get the total of them.



Desired output:



[31.40, 32.99, 37.24]


I have already tried these:



newList = re.findall("d+.d+", tot[0])

print(newList)


Output:



[31.40]


But How can I use this for all the item elements?



I am new to python, this is just for some work i do, wanted to see the total using python instead of using excel`s find & replace option.
thanks






python regex excel list openpyxl







share|improve this question















python: extract float from a python list of string( AUD 31.99).
I used openpyxl to read from an excel file the amount list. and i saved it in a list but the list is in string form like this: 



['31.40 AUD', ' 32.99 AUD', '37.24 AUD']


I need to get the float from the string item list so that i can later save it in a new list to get the total of them.



Desired output:



[31.40, 32.99, 37.24]


I have already tried these:



newList = re.findall("d+.d+", tot[0])

print(newList)


Output:



[31.40]


But How can I use this for all the item elements?



I am new to python, this is just for some work i do, wanted to see the total using python instead of using excel`s find & replace option.
thanks






python regex excel list openpyxl




python regex excel list openpyxl






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 8:26









Vasilis G.

3,4082722




3,4082722










asked Nov 13 '18 at 8:22









Anamul ChoudhuryAnamul Choudhury

266




266












  • Take a look here: book.pythontips.com/en/latest/map_filter.html
    – Julio
    Nov 13 '18 at 8:24






  • 1




    You should do the conversion before creating the list.
    – Charlie Clark
    Nov 13 '18 at 8:25










  • You are close.. but you are just passing tot[0].
    – Anton vBR
    Nov 13 '18 at 8:26






  • 3




    try [item.split()[0] for item in ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']]
    – Andersson
    Nov 13 '18 at 8:26






  • 1




    Is it mandatory to use regex?
    – Vasilis G.
    Nov 13 '18 at 8:28


















  • Take a look here: book.pythontips.com/en/latest/map_filter.html
    – Julio
    Nov 13 '18 at 8:24






  • 1




    You should do the conversion before creating the list.
    – Charlie Clark
    Nov 13 '18 at 8:25










  • You are close.. but you are just passing tot[0].
    – Anton vBR
    Nov 13 '18 at 8:26






  • 3




    try [item.split()[0] for item in ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']]
    – Andersson
    Nov 13 '18 at 8:26






  • 1




    Is it mandatory to use regex?
    – Vasilis G.
    Nov 13 '18 at 8:28
















Take a look here: book.pythontips.com/en/latest/map_filter.html
– Julio
Nov 13 '18 at 8:24




Take a look here: book.pythontips.com/en/latest/map_filter.html
– Julio
Nov 13 '18 at 8:24




1




1




You should do the conversion before creating the list.
– Charlie Clark
Nov 13 '18 at 8:25




You should do the conversion before creating the list.
– Charlie Clark
Nov 13 '18 at 8:25












You are close.. but you are just passing tot[0].
– Anton vBR
Nov 13 '18 at 8:26




You are close.. but you are just passing tot[0].
– Anton vBR
Nov 13 '18 at 8:26




3




3




try [item.split()[0] for item in ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']]
– Andersson
Nov 13 '18 at 8:26




try [item.split()[0] for item in ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']]
– Andersson
Nov 13 '18 at 8:26




1




1




Is it mandatory to use regex?
– Vasilis G.
Nov 13 '18 at 8:28




Is it mandatory to use regex?
– Vasilis G.
Nov 13 '18 at 8:28












4 Answers
4






active

oldest

votes


















1














You can use the map function:



inList = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']

output = list(map(lambda elem: float(elem.split()[0]), inList))

print(output)


Output:



[31.4, 32.99, 37.24]





share|improve this answer





















  • This one solved the problem, Thanks alot.
    – Anamul Choudhury
    Nov 13 '18 at 8:36










  • @AnamulChoudhury you're welcome. Feel free to accept it as an answer if it helped you :)
    – Vasilis G.
    Nov 13 '18 at 8:48



















1














If you want to get list of values with regex, try



tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']

newList = [float(re.search('d+.d+', fl).group(0)) for fl in tot]

print(newList)

# [31.40, 32.99, 37.24]


but using split seem to be easier solution in this case 



tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']

newList = [float(item.split()[0]) for item in tot] 

print(newList)

# [31.40, 32.99, 37.24]


If second substring is always the same ("AUD") you can also try



tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']

newList = [float(item.rstrip(' AUD')) for item in tot] 

print(newList)

# [31.40, 32.99, 37.24]





share|improve this answer































    0














    Is it possible to use a string split instead? I think it would be much simpler 



    ls1 = ['32.46 AUD', '17.34 AUD']
    

    
myFloats = 
    
for aString in ls1:
    
    aFloat = float(aString.split()[0])
    
    myFloats.append(aFloat)





    share|improve this answer





























      0














      You should consider handling errors. Here is one way for instance:



      import re
      
import math
      

      
def float_from_string(str_):
      
    # Try to extract a floating number, if fail return nan
      
    r = re.search('d+.d+', str_)
      
    return float(r.group()) if r else math.nan
      

      
tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD', ' nonumberhere AUD']
      
totfloat = [float_from_string(i) for i in tot]
      

      
print(totfloat)


      Returns:



      [31.4, 32.99, 37.24, nan]





      share|improve this answer





















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        4 Answers
        4






        active

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        4 Answers
        4






        active

        oldest

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        active

        oldest

        votes






        active

        oldest

        votes









        1














        You can use the map function:



        inList = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
        
output = list(map(lambda elem: float(elem.split()[0]), inList))
        
print(output)


        Output:



        [31.4, 32.99, 37.24]





        share|improve this answer





















        • This one solved the problem, Thanks alot.
          – Anamul Choudhury
          Nov 13 '18 at 8:36










        • @AnamulChoudhury you're welcome. Feel free to accept it as an answer if it helped you :)
          – Vasilis G.
          Nov 13 '18 at 8:48
















        1














        You can use the map function:



        inList = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
        
output = list(map(lambda elem: float(elem.split()[0]), inList))
        
print(output)


        Output:



        [31.4, 32.99, 37.24]





        share|improve this answer





















        • This one solved the problem, Thanks alot.
          – Anamul Choudhury
          Nov 13 '18 at 8:36










        • @AnamulChoudhury you're welcome. Feel free to accept it as an answer if it helped you :)
          – Vasilis G.
          Nov 13 '18 at 8:48














        1












        1








        1






        You can use the map function:



        inList = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
        
output = list(map(lambda elem: float(elem.split()[0]), inList))
        
print(output)


        Output:



        [31.4, 32.99, 37.24]





        share|improve this answer












        You can use the map function:



        inList = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
        
output = list(map(lambda elem: float(elem.split()[0]), inList))
        
print(output)


        Output:



        [31.4, 32.99, 37.24]






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 13 '18 at 8:31









        Vasilis G.Vasilis G.

        3,4082722




        3,4082722












        • This one solved the problem, Thanks alot.
          – Anamul Choudhury
          Nov 13 '18 at 8:36










        • @AnamulChoudhury you're welcome. Feel free to accept it as an answer if it helped you :)
          – Vasilis G.
          Nov 13 '18 at 8:48


















        • This one solved the problem, Thanks alot.
          – Anamul Choudhury
          Nov 13 '18 at 8:36










        • @AnamulChoudhury you're welcome. Feel free to accept it as an answer if it helped you :)
          – Vasilis G.
          Nov 13 '18 at 8:48
















        This one solved the problem, Thanks alot.
        – Anamul Choudhury
        Nov 13 '18 at 8:36




        This one solved the problem, Thanks alot.
        – Anamul Choudhury
        Nov 13 '18 at 8:36












        @AnamulChoudhury you're welcome. Feel free to accept it as an answer if it helped you :)
        – Vasilis G.
        Nov 13 '18 at 8:48




        @AnamulChoudhury you're welcome. Feel free to accept it as an answer if it helped you :)
        – Vasilis G.
        Nov 13 '18 at 8:48













        1














        If you want to get list of values with regex, try



        tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
        
newList = [float(re.search('d+.d+', fl).group(0)) for fl in tot]
        
print(newList)
        
# [31.40, 32.99, 37.24]


        but using split seem to be easier solution in this case 



        tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
        
newList = [float(item.split()[0]) for item in tot] 
        
print(newList)
        
# [31.40, 32.99, 37.24]


        If second substring is always the same ("AUD") you can also try



        tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
        
newList = [float(item.rstrip(' AUD')) for item in tot] 
        
print(newList)
        
# [31.40, 32.99, 37.24]





        share|improve this answer




























          1














          If you want to get list of values with regex, try



          tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
          
newList = [float(re.search('d+.d+', fl).group(0)) for fl in tot]
          
print(newList)
          
# [31.40, 32.99, 37.24]


          but using split seem to be easier solution in this case 



          tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
          
newList = [float(item.split()[0]) for item in tot] 
          
print(newList)
          
# [31.40, 32.99, 37.24]


          If second substring is always the same ("AUD") you can also try



          tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
          
newList = [float(item.rstrip(' AUD')) for item in tot] 
          
print(newList)
          
# [31.40, 32.99, 37.24]





          share|improve this answer


























            1












            1








            1






            If you want to get list of values with regex, try



            tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
            
newList = [float(re.search('d+.d+', fl).group(0)) for fl in tot]
            
print(newList)
            
# [31.40, 32.99, 37.24]


            but using split seem to be easier solution in this case 



            tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
            
newList = [float(item.split()[0]) for item in tot] 
            
print(newList)
            
# [31.40, 32.99, 37.24]


            If second substring is always the same ("AUD") you can also try



            tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
            
newList = [float(item.rstrip(' AUD')) for item in tot] 
            
print(newList)
            
# [31.40, 32.99, 37.24]





            share|improve this answer














            If you want to get list of values with regex, try



            tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
            
newList = [float(re.search('d+.d+', fl).group(0)) for fl in tot]
            
print(newList)
            
# [31.40, 32.99, 37.24]


            but using split seem to be easier solution in this case 



            tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
            
newList = [float(item.split()[0]) for item in tot] 
            
print(newList)
            
# [31.40, 32.99, 37.24]


            If second substring is always the same ("AUD") you can also try



            tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD']
            
newList = [float(item.rstrip(' AUD')) for item in tot] 
            
print(newList)
            
# [31.40, 32.99, 37.24]






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 13 '18 at 8:39

























            answered Nov 13 '18 at 8:33









            AnderssonAndersson

            37.6k103266




            37.6k103266























                0














                Is it possible to use a string split instead? I think it would be much simpler 



                ls1 = ['32.46 AUD', '17.34 AUD']
                

                
myFloats = 
                
for aString in ls1:
                
    aFloat = float(aString.split()[0])
                
    myFloats.append(aFloat)





                share|improve this answer


























                  0














                  Is it possible to use a string split instead? I think it would be much simpler 



                  ls1 = ['32.46 AUD', '17.34 AUD']
                  

                  
myFloats = 
                  
for aString in ls1:
                  
    aFloat = float(aString.split()[0])
                  
    myFloats.append(aFloat)





                  share|improve this answer
























                    0












                    0








                    0






                    Is it possible to use a string split instead? I think it would be much simpler 



                    ls1 = ['32.46 AUD', '17.34 AUD']
                    

                    
myFloats = 
                    
for aString in ls1:
                    
    aFloat = float(aString.split()[0])
                    
    myFloats.append(aFloat)





                    share|improve this answer












                    Is it possible to use a string split instead? I think it would be much simpler 



                    ls1 = ['32.46 AUD', '17.34 AUD']
                    

                    
myFloats = 
                    
for aString in ls1:
                    
    aFloat = float(aString.split()[0])
                    
    myFloats.append(aFloat)






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 13 '18 at 8:28









                    DavidhallDavidhall

                    259




                    259























                        0














                        You should consider handling errors. Here is one way for instance:



                        import re
                        
import math
                        

                        
def float_from_string(str_):
                        
    # Try to extract a floating number, if fail return nan
                        
    r = re.search('d+.d+', str_)
                        
    return float(r.group()) if r else math.nan
                        

                        
tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD', ' nonumberhere AUD']
                        
totfloat = [float_from_string(i) for i in tot]
                        

                        
print(totfloat)


                        Returns:



                        [31.4, 32.99, 37.24, nan]





                        share|improve this answer


























                          0














                          You should consider handling errors. Here is one way for instance:



                          import re
                          
import math
                          

                          
def float_from_string(str_):
                          
    # Try to extract a floating number, if fail return nan
                          
    r = re.search('d+.d+', str_)
                          
    return float(r.group()) if r else math.nan
                          

                          
tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD', ' nonumberhere AUD']
                          
totfloat = [float_from_string(i) for i in tot]
                          

                          
print(totfloat)


                          Returns:



                          [31.4, 32.99, 37.24, nan]





                          share|improve this answer
























                            0












                            0








                            0






                            You should consider handling errors. Here is one way for instance:



                            import re
                            
import math
                            

                            
def float_from_string(str_):
                            
    # Try to extract a floating number, if fail return nan
                            
    r = re.search('d+.d+', str_)
                            
    return float(r.group()) if r else math.nan
                            

                            
tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD', ' nonumberhere AUD']
                            
totfloat = [float_from_string(i) for i in tot]
                            

                            
print(totfloat)


                            Returns:



                            [31.4, 32.99, 37.24, nan]





                            share|improve this answer












                            You should consider handling errors. Here is one way for instance:



                            import re
                            
import math
                            

                            
def float_from_string(str_):
                            
    # Try to extract a floating number, if fail return nan
                            
    r = re.search('d+.d+', str_)
                            
    return float(r.group()) if r else math.nan
                            

                            
tot = ['31.40 AUD', ' 32.99 AUD', '37.24 AUD', ' nonumberhere AUD']
                            
totfloat = [float_from_string(i) for i in tot]
                            

                            
print(totfloat)


                            Returns:



                            [31.4, 32.99, 37.24, nan]






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Nov 13 '18 at 8:37









                            Anton vBRAnton vBR

                            11.3k21022




                            11.3k21022






























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                                Xamarin.iOS Cant Deploy on Iphone

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                                .everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box; } -1 I have a windows laptop and a mac mini my problem is that It wont deploy on iphone if I use Visual Studio Xamarin on windows to install my app, but it works fine with Visual Studio For Mac. Here's what I get after build succeded on Visual Studio Xamarin on windows : 1>------ Build started: Project: FinalCustomerApp.iOS, Configuration: Debug iPhone ------ 1> Connecting to Mac server 192.168.8.100... 1> FinalCustomerApp.iOS -> C:UsersJeremy PaulDesktopFinalCustomerAppFinalCustomerAppFinalCustomerApp.iOSbiniPhoneDebugFinalCustomerApp.iOS.exe 1> Detected signing identity: 1> Code Signing Key: &quo
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                                Glorious Revolution

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                                "The Bloodless Revolution" redirects here. For a history of the vegetarian movement, see The Bloodless Revolution (book). This article is about the English revolution of 1688. For the revolution of 1868 in Spain, see Glorious Revolution (Spain). For other uses, see Glorious Revolution (disambiguation). Glorious Revolution The Prince of Orange lands at Torbay Date 1688–1689 Location British Isles Also known as Revolution of 1688 War of the English Succession Bloodless Revolution Participants English, Welsh and Scottish society, Dutch forces Outcome Replacement of James II by William III and Mary II Jacobite rising of 1689 Williamite War in Ireland War with France; England and Scotland join Grand Alliance Drafting of the Bill of Rights 1689 Part of a series on the History of England Timeline Prehistoric Britain Roman Britain Sub-Roman Britain Medieval period Economy in the Middle Ages Anglo-Saxon period
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                                Dulmage-Mendelsohn matrix decomposition in Python

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                                0 Matlab has a function called dmperm that computes the so-called Dulmage–Mendelsohn decomposition of a n x n matrix. From wikipedia, the Dulmage–Mendelsohn is a partition of the vertices of a bipartite graph into subsets, with the property that two adjacent vertices belong to the same subset if and only if they are paired with each other in a perfect matching of the graph. Looking both on scipy and numpy, I could not find this function, nor some similar version. Is it possible to implement it using basic linear algebra operations? Any idea if this is implemented in some Python package? python matlab linear-algebra graph-theory matrix-decomposition share | improve this question
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