How to sum values within a field with Arrays in JSON with MYSQL?
I have a table with a field that sometimes has multiple arrays in JSON.
MYSQL 8.0.11
DLL
CREATE TABLE T
(`user` varchar(4), `sales` int, `reference` varchar(400) DEFAULT NULL, `quantity` float DEFAULT NULL, `orders` int)
;
Data
INSERT INTO T
(`user`, `sales`, `reference`, `quantity`, `orders`)
VALUES
('xx01', 100, '[{"productid":"80000052","quantity":"1","reference":"ML-41"},{"quantity":1,"reference":"ML-32","productid":"ML-52"},{"productid":"80000052","quantity":3,"reference":"ML-11"}]', 0, 0),
('xx02', 200, '[{"productid":"80000052","quantity":2}]', 0, 0),
('xx02', 400, '[{"productid":"80000052","quantity":3}]', 0, 0),
('xx03', 300, '[{"productid":"80000052","quantity":4}]', 0, 0),
('xx03', 500, '[{"productid":"80000052","quantity":5}]', 0, 0)
;
The following query updates field "quantity" with the value of "quantity" in the "reference" field JSON array(s):
UPDATE T t2,
( SELECT sales, quant FROM T, JSON_TABLE(T.reference,
"$[*]" COLUMNS(
quant VARCHAR(400) PATH "$.quantity"
)
) AS jt1
) t1
SET t2.quantity = t1.quant
WHERE t1.sales = t2.sales;
The query takes the "quantity" in the first array of the first row and ignores the following 2 arrays in that row's "reference" field.
Is there a way to sum the "quantity" of all 3 arrays of "reference" field of the first row?
mysql
asked Nov 13 '18 at 8:46
BaliJackBaliJack
4917
add a comment |
I have a table with a field that sometimes has multiple arrays in JSON.
MYSQL 8.0.11
DLL
CREATE TABLE T
(`user` varchar(4), `sales` int, `reference` varchar(400) DEFAULT NULL, `quantity` float DEFAULT NULL, `orders` int)
;
Data
INSERT INTO T
(`user`, `sales`, `reference`, `quantity`, `orders`)
VALUES
('xx01', 100, '[{"productid":"80000052","quantity":"1","reference":"ML-41"},{"quantity":1,"reference":"ML-32","productid":"ML-52"},{"productid":"80000052","quantity":3,"reference":"ML-11"}]', 0, 0),
('xx02', 200, '[{"productid":"80000052","quantity":2}]', 0, 0),
('xx02', 400, '[{"productid":"80000052","quantity":3}]', 0, 0),
('xx03', 300, '[{"productid":"80000052","quantity":4}]', 0, 0),
('xx03', 500, '[{"productid":"80000052","quantity":5}]', 0, 0)
;
The following query updates field "quantity" with the value of "quantity" in the "reference" field JSON array(s):
UPDATE T t2,
( SELECT sales, quant FROM T, JSON_TABLE(T.reference,
"$[*]" COLUMNS(
quant VARCHAR(400) PATH "$.quantity"
)
) AS jt1
) t1
SET t2.quantity = t1.quant
WHERE t1.sales = t2.sales;
The query takes the "quantity" in the first array of the first row and ignores the following 2 arrays in that row's "reference" field.
Is there a way to sum the "quantity" of all 3 arrays of "reference" field of the first row?
mysql
asked Nov 13 '18 at 8:46
BaliJackBaliJack
4917
add a comment |
I have a table with a field that sometimes has multiple arrays in JSON.
MYSQL 8.0.11
DLL
CREATE TABLE T
(`user` varchar(4), `sales` int, `reference` varchar(400) DEFAULT NULL, `quantity` float DEFAULT NULL, `orders` int)
;
Data
INSERT INTO T
(`user`, `sales`, `reference`, `quantity`, `orders`)
VALUES
('xx01', 100, '[{"productid":"80000052","quantity":"1","reference":"ML-41"},{"quantity":1,"reference":"ML-32","productid":"ML-52"},{"productid":"80000052","quantity":3,"reference":"ML-11"}]', 0, 0),
('xx02', 200, '[{"productid":"80000052","quantity":2}]', 0, 0),
('xx02', 400, '[{"productid":"80000052","quantity":3}]', 0, 0),
('xx03', 300, '[{"productid":"80000052","quantity":4}]', 0, 0),
('xx03', 500, '[{"productid":"80000052","quantity":5}]', 0, 0)
;
The following query updates field "quantity" with the value of "quantity" in the "reference" field JSON array(s):
UPDATE T t2,
( SELECT sales, quant FROM T, JSON_TABLE(T.reference,
"$[*]" COLUMNS(
quant VARCHAR(400) PATH "$.quantity"
)
) AS jt1
) t1
SET t2.quantity = t1.quant
WHERE t1.sales = t2.sales;
The query takes the "quantity" in the first array of the first row and ignores the following 2 arrays in that row's "reference" field.
Is there a way to sum the "quantity" of all 3 arrays of "reference" field of the first row?
mysql
asked Nov 13 '18 at 8:46
BaliJackBaliJack
4917
I have a table with a field that sometimes has multiple arrays in JSON.
MYSQL 8.0.11
DLL
CREATE TABLE T
(`user` varchar(4), `sales` int, `reference` varchar(400) DEFAULT NULL, `quantity` float DEFAULT NULL, `orders` int)
;
Data
INSERT INTO T
(`user`, `sales`, `reference`, `quantity`, `orders`)
VALUES
('xx01', 100, '[{"productid":"80000052","quantity":"1","reference":"ML-41"},{"quantity":1,"reference":"ML-32","productid":"ML-52"},{"productid":"80000052","quantity":3,"reference":"ML-11"}]', 0, 0),
('xx02', 200, '[{"productid":"80000052","quantity":2}]', 0, 0),
('xx02', 400, '[{"productid":"80000052","quantity":3}]', 0, 0),
('xx03', 300, '[{"productid":"80000052","quantity":4}]', 0, 0),
('xx03', 500, '[{"productid":"80000052","quantity":5}]', 0, 0)
;
The following query updates field "quantity" with the value of "quantity" in the "reference" field JSON array(s):
UPDATE T t2,
( SELECT sales, quant FROM T, JSON_TABLE(T.reference,
"$[*]" COLUMNS(
quant VARCHAR(400) PATH "$.quantity"
)
) AS jt1
) t1
SET t2.quantity = t1.quant
WHERE t1.sales = t2.sales;
The query takes the "quantity" in the first array of the first row and ignores the following 2 arrays in that row's "reference" field.
Is there a way to sum the "quantity" of all 3 arrays of "reference" field of the first row?
mysql
mysql
asked Nov 13 '18 at 8:46
BaliJackBaliJack
4917
asked Nov 13 '18 at 8:46
BaliJackBaliJack
4917
edited Nov 13 '18 at 23:19
BaliJack
asked Nov 13 '18 at 8:46
BaliJackBaliJack
4917
asked Nov 13 '18 at 8:46
BaliJackBaliJack
4917
asked Nov 13 '18 at 8:46
BaliJackBaliJack
4917
4917
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Instead of WHERE, use JOIN ... ON plus GROUP BY and SUM() AS
UPDATE T t2
JOIN (SELECT sales, SUM(quant) AS qu FROM T, JSON_TABLE(T.reference,
"$[*]" COLUMNS(
quant VARCHAR(400) PATH "$.quantity"
)
) AS jt1
GROUP BY sales) t1
ON t2.sales = t1.sales
SET t2.quantity = t1.qu;
db-fiddle
answered Nov 14 '18 at 1:16
BaliJackBaliJack
4917
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Instead of WHERE, use JOIN ... ON plus GROUP BY and SUM() AS
UPDATE T t2
JOIN (SELECT sales, SUM(quant) AS qu FROM T, JSON_TABLE(T.reference,
"$[*]" COLUMNS(
quant VARCHAR(400) PATH "$.quantity"
)
) AS jt1
GROUP BY sales) t1
ON t2.sales = t1.sales
SET t2.quantity = t1.qu;
db-fiddle
answered Nov 14 '18 at 1:16
BaliJackBaliJack
4917
add a comment |
Instead of WHERE, use JOIN ... ON plus GROUP BY and SUM() AS
UPDATE T t2
JOIN (SELECT sales, SUM(quant) AS qu FROM T, JSON_TABLE(T.reference,
"$[*]" COLUMNS(
quant VARCHAR(400) PATH "$.quantity"
)
) AS jt1
GROUP BY sales) t1
ON t2.sales = t1.sales
SET t2.quantity = t1.qu;
db-fiddle
answered Nov 14 '18 at 1:16
BaliJackBaliJack
4917
add a comment |
Instead of WHERE, use JOIN ... ON plus GROUP BY and SUM() AS
UPDATE T t2
JOIN (SELECT sales, SUM(quant) AS qu FROM T, JSON_TABLE(T.reference,
"$[*]" COLUMNS(
quant VARCHAR(400) PATH "$.quantity"
)
) AS jt1
GROUP BY sales) t1
ON t2.sales = t1.sales
SET t2.quantity = t1.qu;
db-fiddle
answered Nov 14 '18 at 1:16
BaliJackBaliJack
4917
Instead of WHERE, use JOIN ... ON plus GROUP BY and SUM() AS
UPDATE T t2
JOIN (SELECT sales, SUM(quant) AS qu FROM T, JSON_TABLE(T.reference,
"$[*]" COLUMNS(
quant VARCHAR(400) PATH "$.quantity"
)
) AS jt1
GROUP BY sales) t1
ON t2.sales = t1.sales
SET t2.quantity = t1.qu;
db-fiddle
answered Nov 14 '18 at 1:16
BaliJackBaliJack
4917
answered Nov 14 '18 at 1:16
BaliJackBaliJack
4917
answered Nov 14 '18 at 1:16
BaliJackBaliJack
4917
answered Nov 14 '18 at 1:16
BaliJackBaliJack
4917
4917
add a comment |
add a comment |
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