Java 8 Exception: com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer has no default (no arg)...
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0
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I have a model class that has a field:
@JsonDeserialize(using = InstantDeserializer.class)
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSZ")
private OffsetDateTime offsetDt;
When a request of this model is sent to the server, my controller throws an exception:
Caused by: java.lang.IllegalArgumentException:
Class com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer
has no default (no arg) constructor
The pom.xml has the dependency of version 2.8.11:
<dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
</dependency>
I understand that it is caused by @JsonDeserialize requiring no-arg constructor, but is there a workaround? Many thanks.
java json jackson fasterxml jsr310
asked Nov 9 at 20:03
jlp
4091822
|
show 5 more comments
up vote
0
down vote
favorite
I have a model class that has a field:
@JsonDeserialize(using = InstantDeserializer.class)
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSZ")
private OffsetDateTime offsetDt;
When a request of this model is sent to the server, my controller throws an exception:
Caused by: java.lang.IllegalArgumentException:
Class com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer
has no default (no arg) constructor
The pom.xml has the dependency of version 2.8.11:
<dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
</dependency>
I understand that it is caused by @JsonDeserialize requiring no-arg constructor, but is there a workaround? Many thanks.
java json jackson fasterxml jsr310
asked Nov 9 at 20:03
jlp
4091822
InstantDeserializer.classis custom deserializer class?, if i believe in that class you may declared some arg constructor without no-arg constructor
– Deadpool
Nov 9 at 20:08
@Deadpool no, it is not a custom class.. com.fasterxml.jackson.datatype.jsr310.deser
– jlp
Nov 9 at 20:10
what does your POM look like?
– Darren Forsythe
Nov 9 at 20:15
1
Look at this answer stackoverflow.com/a/45215515/4727666, you need a class with a constructor that takes no arguments, so you can extend InstantDeserializer to create your own.
– Julio Daniel Reyes
Nov 9 at 21:31
1
For the arguments, take a look at this github.com/FasterXML/jackson-datatype-jsr310/blob/master/src/…
– Julio Daniel Reyes
Nov 9 at 21:35
|
show 5 more comments
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have a model class that has a field:
@JsonDeserialize(using = InstantDeserializer.class)
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSZ")
private OffsetDateTime offsetDt;
When a request of this model is sent to the server, my controller throws an exception:
Caused by: java.lang.IllegalArgumentException:
Class com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer
has no default (no arg) constructor
The pom.xml has the dependency of version 2.8.11:
<dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
</dependency>
I understand that it is caused by @JsonDeserialize requiring no-arg constructor, but is there a workaround? Many thanks.
java json jackson fasterxml jsr310
asked Nov 9 at 20:03
jlp
4091822
I have a model class that has a field:
@JsonDeserialize(using = InstantDeserializer.class)
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSZ")
private OffsetDateTime offsetDt;
When a request of this model is sent to the server, my controller throws an exception:
Caused by: java.lang.IllegalArgumentException:
Class com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer
has no default (no arg) constructor
The pom.xml has the dependency of version 2.8.11:
<dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
</dependency>
I understand that it is caused by @JsonDeserialize requiring no-arg constructor, but is there a workaround? Many thanks.
java json jackson fasterxml jsr310
java json jackson fasterxml jsr310
asked Nov 9 at 20:03
jlp
4091822
asked Nov 9 at 20:03
jlp
4091822
edited Nov 9 at 20:50
asked Nov 9 at 20:03
jlp
4091822
asked Nov 9 at 20:03
jlp
4091822
asked Nov 9 at 20:03
jlp
4091822
4091822
InstantDeserializer.classis custom deserializer class?, if i believe in that class you may declared some arg constructor without no-arg constructor
– Deadpool
Nov 9 at 20:08
@Deadpool no, it is not a custom class.. com.fasterxml.jackson.datatype.jsr310.deser
– jlp
Nov 9 at 20:10
what does your POM look like?
– Darren Forsythe
Nov 9 at 20:15
1
Look at this answer stackoverflow.com/a/45215515/4727666, you need a class with a constructor that takes no arguments, so you can extend InstantDeserializer to create your own.
– Julio Daniel Reyes
Nov 9 at 21:31
1
For the arguments, take a look at this github.com/FasterXML/jackson-datatype-jsr310/blob/master/src/…
– Julio Daniel Reyes
Nov 9 at 21:35
|
show 5 more comments
InstantDeserializer.classis custom deserializer class?, if i believe in that class you may declared some arg constructor without no-arg constructor
– Deadpool
Nov 9 at 20:08
@Deadpool no, it is not a custom class.. com.fasterxml.jackson.datatype.jsr310.deser
– jlp
Nov 9 at 20:10
what does your POM look like?
– Darren Forsythe
Nov 9 at 20:15
1
Look at this answer stackoverflow.com/a/45215515/4727666, you need a class with a constructor that takes no arguments, so you can extend InstantDeserializer to create your own.
– Julio Daniel Reyes
Nov 9 at 21:31
1
For the arguments, take a look at this github.com/FasterXML/jackson-datatype-jsr310/blob/master/src/…
– Julio Daniel Reyes
Nov 9 at 21:35
InstantDeserializer.class is custom deserializer class?, if i believe in that class you may declared some arg constructor without no-arg constructor– Deadpool
Nov 9 at 20:08
InstantDeserializer.class is custom deserializer class?, if i believe in that class you may declared some arg constructor without no-arg constructor– Deadpool
Nov 9 at 20:08
@Deadpool no, it is not a custom class.. com.fasterxml.jackson.datatype.jsr310.deser
– jlp
Nov 9 at 20:10
@Deadpool no, it is not a custom class.. com.fasterxml.jackson.datatype.jsr310.deser
– jlp
Nov 9 at 20:10
what does your POM look like?
– Darren Forsythe
Nov 9 at 20:15
what does your POM look like?
– Darren Forsythe
Nov 9 at 20:15
1
1
Look at this answer stackoverflow.com/a/45215515/4727666, you need a class with a constructor that takes no arguments, so you can extend InstantDeserializer to create your own.
– Julio Daniel Reyes
Nov 9 at 21:31
Look at this answer stackoverflow.com/a/45215515/4727666, you need a class with a constructor that takes no arguments, so you can extend InstantDeserializer to create your own.
– Julio Daniel Reyes
Nov 9 at 21:31
1
1
For the arguments, take a look at this github.com/FasterXML/jackson-datatype-jsr310/blob/master/src/…
– Julio Daniel Reyes
Nov 9 at 21:35
For the arguments, take a look at this github.com/FasterXML/jackson-datatype-jsr310/blob/master/src/…
– Julio Daniel Reyes
Nov 9 at 21:35
|
show 5 more comments
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
The error says that you need a class with no arg constructor, so you could extend from InstantDeserializer. (Take as example the code in InstantDeserializer for the arguments of super())
public class DefaultInstantDeserializer extends InstantDeserializer<OffsetDateTime> {
public DefaultInstantDeserializer() {
super(OffsetDateTime.class, DateTimeFormatter.ISO_OFFSET_DATE_TIME,
OffsetDateTime::from,
a -> OffsetDateTime.ofInstant(Instant.ofEpochMilli(a.value), a.zoneId),
a -> OffsetDateTime.ofInstant(Instant.ofEpochSecond(a.integer, a.fraction), a.zoneId),
(d, z) -> d.withOffsetSameInstant(z.getRules().getOffset(d.toLocalDateTime())),
true);
}
}
Then you can use it:
@JsonDeserialize(using = DefaultInstantDeserializer.class)
answered Nov 12 at 4:30
Julio Daniel Reyes
2,072815
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
The error says that you need a class with no arg constructor, so you could extend from InstantDeserializer. (Take as example the code in InstantDeserializer for the arguments of super())
public class DefaultInstantDeserializer extends InstantDeserializer<OffsetDateTime> {
public DefaultInstantDeserializer() {
super(OffsetDateTime.class, DateTimeFormatter.ISO_OFFSET_DATE_TIME,
OffsetDateTime::from,
a -> OffsetDateTime.ofInstant(Instant.ofEpochMilli(a.value), a.zoneId),
a -> OffsetDateTime.ofInstant(Instant.ofEpochSecond(a.integer, a.fraction), a.zoneId),
(d, z) -> d.withOffsetSameInstant(z.getRules().getOffset(d.toLocalDateTime())),
true);
}
}
Then you can use it:
@JsonDeserialize(using = DefaultInstantDeserializer.class)
answered Nov 12 at 4:30
Julio Daniel Reyes
2,072815
add a comment |
up vote
1
down vote
accepted
The error says that you need a class with no arg constructor, so you could extend from InstantDeserializer. (Take as example the code in InstantDeserializer for the arguments of super())
public class DefaultInstantDeserializer extends InstantDeserializer<OffsetDateTime> {
public DefaultInstantDeserializer() {
super(OffsetDateTime.class, DateTimeFormatter.ISO_OFFSET_DATE_TIME,
OffsetDateTime::from,
a -> OffsetDateTime.ofInstant(Instant.ofEpochMilli(a.value), a.zoneId),
a -> OffsetDateTime.ofInstant(Instant.ofEpochSecond(a.integer, a.fraction), a.zoneId),
(d, z) -> d.withOffsetSameInstant(z.getRules().getOffset(d.toLocalDateTime())),
true);
}
}
Then you can use it:
@JsonDeserialize(using = DefaultInstantDeserializer.class)
answered Nov 12 at 4:30
Julio Daniel Reyes
2,072815
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
The error says that you need a class with no arg constructor, so you could extend from InstantDeserializer. (Take as example the code in InstantDeserializer for the arguments of super())
public class DefaultInstantDeserializer extends InstantDeserializer<OffsetDateTime> {
public DefaultInstantDeserializer() {
super(OffsetDateTime.class, DateTimeFormatter.ISO_OFFSET_DATE_TIME,
OffsetDateTime::from,
a -> OffsetDateTime.ofInstant(Instant.ofEpochMilli(a.value), a.zoneId),
a -> OffsetDateTime.ofInstant(Instant.ofEpochSecond(a.integer, a.fraction), a.zoneId),
(d, z) -> d.withOffsetSameInstant(z.getRules().getOffset(d.toLocalDateTime())),
true);
}
}
Then you can use it:
@JsonDeserialize(using = DefaultInstantDeserializer.class)
answered Nov 12 at 4:30
Julio Daniel Reyes
2,072815
The error says that you need a class with no arg constructor, so you could extend from InstantDeserializer. (Take as example the code in InstantDeserializer for the arguments of super())
public class DefaultInstantDeserializer extends InstantDeserializer<OffsetDateTime> {
public DefaultInstantDeserializer() {
super(OffsetDateTime.class, DateTimeFormatter.ISO_OFFSET_DATE_TIME,
OffsetDateTime::from,
a -> OffsetDateTime.ofInstant(Instant.ofEpochMilli(a.value), a.zoneId),
a -> OffsetDateTime.ofInstant(Instant.ofEpochSecond(a.integer, a.fraction), a.zoneId),
(d, z) -> d.withOffsetSameInstant(z.getRules().getOffset(d.toLocalDateTime())),
true);
}
}
Then you can use it:
@JsonDeserialize(using = DefaultInstantDeserializer.class)
answered Nov 12 at 4:30
Julio Daniel Reyes
2,072815
answered Nov 12 at 4:30
Julio Daniel Reyes
2,072815
answered Nov 12 at 4:30
Julio Daniel Reyes
2,072815
answered Nov 12 at 4:30
Julio Daniel Reyes
2,072815
2,072815
add a comment |
add a comment |
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InstantDeserializer.classis custom deserializer class?, if i believe in that class you may declared some arg constructor without no-arg constructor– Deadpool
Nov 9 at 20:08
@Deadpool no, it is not a custom class.. com.fasterxml.jackson.datatype.jsr310.deser
– jlp
Nov 9 at 20:10
what does your POM look like?
– Darren Forsythe
Nov 9 at 20:15
1
Look at this answer stackoverflow.com/a/45215515/4727666, you need a class with a constructor that takes no arguments, so you can extend InstantDeserializer to create your own.
– Julio Daniel Reyes
Nov 9 at 21:31
1
For the arguments, take a look at this github.com/FasterXML/jackson-datatype-jsr310/blob/master/src/…
– Julio Daniel Reyes
Nov 9 at 21:35