Conditionally Select Rows within a Group with Data.Table











up vote
3
down vote

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I am looking for solutions using data.table ― I have a data.table with the following columns:



data <- data.frame(GROUP=c(3,3,4,4,5,6),
YEAR=c(1979,1985,1999,2011,2012,1994),
NAME=c("S","A","J","L","G","A"))

data <- as.data.table(data)


Data.table:



GROUP  YEAR    NAME
3 1979 Smith
3 1985 Anderson
4 1999 James
4 2011 Liam
5 2012 George
6 1994 Adams


For each group we want to select one row using the following rule:




  • If there is a year > 2000, select the row with minimum year above 2000.

  • If there not a year > 2000, select the row with the maximum year.


Desired output:



GROUP  YEAR    NAME
3 1985 Anderson
4 2011 Liam
5 2012 George
6 1994 Adams


Thanks! I have been struggling with this for a while.










share|improve this question




























    up vote
    3
    down vote

    favorite












    I am looking for solutions using data.table ― I have a data.table with the following columns:



    data <- data.frame(GROUP=c(3,3,4,4,5,6),
    YEAR=c(1979,1985,1999,2011,2012,1994),
    NAME=c("S","A","J","L","G","A"))

    data <- as.data.table(data)


    Data.table:



    GROUP  YEAR    NAME
    3 1979 Smith
    3 1985 Anderson
    4 1999 James
    4 2011 Liam
    5 2012 George
    6 1994 Adams


    For each group we want to select one row using the following rule:




    • If there is a year > 2000, select the row with minimum year above 2000.

    • If there not a year > 2000, select the row with the maximum year.


    Desired output:



    GROUP  YEAR    NAME
    3 1985 Anderson
    4 2011 Liam
    5 2012 George
    6 1994 Adams


    Thanks! I have been struggling with this for a while.










    share|improve this question


























      up vote
      3
      down vote

      favorite









      up vote
      3
      down vote

      favorite











      I am looking for solutions using data.table ― I have a data.table with the following columns:



      data <- data.frame(GROUP=c(3,3,4,4,5,6),
      YEAR=c(1979,1985,1999,2011,2012,1994),
      NAME=c("S","A","J","L","G","A"))

      data <- as.data.table(data)


      Data.table:



      GROUP  YEAR    NAME
      3 1979 Smith
      3 1985 Anderson
      4 1999 James
      4 2011 Liam
      5 2012 George
      6 1994 Adams


      For each group we want to select one row using the following rule:




      • If there is a year > 2000, select the row with minimum year above 2000.

      • If there not a year > 2000, select the row with the maximum year.


      Desired output:



      GROUP  YEAR    NAME
      3 1985 Anderson
      4 2011 Liam
      5 2012 George
      6 1994 Adams


      Thanks! I have been struggling with this for a while.










      share|improve this question















      I am looking for solutions using data.table ― I have a data.table with the following columns:



      data <- data.frame(GROUP=c(3,3,4,4,5,6),
      YEAR=c(1979,1985,1999,2011,2012,1994),
      NAME=c("S","A","J","L","G","A"))

      data <- as.data.table(data)


      Data.table:



      GROUP  YEAR    NAME
      3 1979 Smith
      3 1985 Anderson
      4 1999 James
      4 2011 Liam
      5 2012 George
      6 1994 Adams


      For each group we want to select one row using the following rule:




      • If there is a year > 2000, select the row with minimum year above 2000.

      • If there not a year > 2000, select the row with the maximum year.


      Desired output:



      GROUP  YEAR    NAME
      3 1985 Anderson
      4 2011 Liam
      5 2012 George
      6 1994 Adams


      Thanks! I have been struggling with this for a while.







      r data.table






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 12 at 6:01

























      asked Nov 12 at 4:16









      CFB

      544




      544
























          3 Answers
          3






          active

          oldest

          votes

















          up vote
          5
          down vote



          accepted










          data.table should be a lot simpler if you subset the special .I row counter:



          library(data.table)
          setDT(data)
          data[
          data[
          ,
          if(any(YEAR > 2000))
          .I[which.min(2000 - YEAR)] else
          .I[which.max(YEAR)],
          by=GROUP
          ]$V1
          ]
          # GROUP YEAR NAME
          #1: 3 1985 A
          #2: 4 2011 L
          #3: 5 2012 G
          #4: 6 1994 A


          Thanks to @r2evans for the background info -




          .I is an integer vector equivalent to seq_len(nrow(x)).

          Ref:
          http://rdrr.io/cran/data.table/man/special-symbols.html




          So, all I'm doing here is getting the matching row index for the whole of data for each of the calculations at each by= level. Then using these row indexes to subset data again.






          share|improve this answer



















          • 1




            I get an error Error in [.data.frame(data, , if (any(YEAR > 2000)) .I[which.min(2000 - : unused argument (by = GROUP) Does it work exactly as is for you?
            – RAB
            Nov 12 at 5:22








          • 2




            @user10626943 - the post is tagged data.table so I assumed OP was already working with a data.table - if not, you need to convert first. Have edited.
            – thelatemail
            Nov 12 at 5:24








          • 2




            For late-comers, .I is an integer vector equivalent to seq_len(nrow(x)). Ref: rdrr.io/cran/data.table/man/special-symbols.html (I had to look it up :-)
            – r2evans
            Nov 12 at 5:53




















          up vote
          3
          down vote













          You could also do a couple rolling joins:



          res = unique(data[, .(GROUP)])

          # get row with YEAR above 2000
          res[, w := data[c(.SD, YEAR = 2000), on=.(GROUP, YEAR), roll=-Inf, which=TRUE]]

          # if none found, get row with nearest YEAR below
          res[is.na(w), w := data[c(.SD, YEAR = 2000), on=.(GROUP, YEAR), roll=Inf, which=TRUE]]

          # subset by row numbers
          data[res$w]

          GROUP YEAR NAME
          1: 3 1985 A
          2: 4 2011 L
          3: 5 2012 G
          4: 6 1994 A





          share|improve this answer




























            up vote
            2
            down vote













            Using the dplyr package I got your output like this (though it may not be the simplest answer):



             library(dplyr)
            library(magrittr)

            data <- data.frame(GROUP=c(3,3,4,4,5,6),
            YEAR=c(1979,1985,1999,2011,2012,1994),
            NAME=c("S","A","J","L","G","A"))

            data %>%
            subset(YEAR < 2000) %>%
            group_by(GROUP) %>%
            summarise(MAX=max(YEAR)) %>%
            join(data %>%
            subset(YEAR > 2000) %>%
            group_by(GROUP) %>%
            summarise(MIN=min(YEAR)), type="full") %>%
            mutate(YEAR=ifelse(is.na(MIN), MAX, MIN)) %>%
            select(c(GROUP, YEAR)) %>%
            join(data)


            Results:



               GROUP YEAR NAME
            3 1985 A
            4 2011 L
            5 2012 G
            6 1994 A


            EDIT: Sorry, my first answer didn't take into account the min/max conditions. Hope this helps






            share|improve this answer



















            • 1




              Thanks for the tidyverse solution! and for the formatting pointers.
              – CFB
              Nov 12 at 5:47













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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            5
            down vote



            accepted










            data.table should be a lot simpler if you subset the special .I row counter:



            library(data.table)
            setDT(data)
            data[
            data[
            ,
            if(any(YEAR > 2000))
            .I[which.min(2000 - YEAR)] else
            .I[which.max(YEAR)],
            by=GROUP
            ]$V1
            ]
            # GROUP YEAR NAME
            #1: 3 1985 A
            #2: 4 2011 L
            #3: 5 2012 G
            #4: 6 1994 A


            Thanks to @r2evans for the background info -




            .I is an integer vector equivalent to seq_len(nrow(x)).

            Ref:
            http://rdrr.io/cran/data.table/man/special-symbols.html




            So, all I'm doing here is getting the matching row index for the whole of data for each of the calculations at each by= level. Then using these row indexes to subset data again.






            share|improve this answer



















            • 1




              I get an error Error in [.data.frame(data, , if (any(YEAR > 2000)) .I[which.min(2000 - : unused argument (by = GROUP) Does it work exactly as is for you?
              – RAB
              Nov 12 at 5:22








            • 2




              @user10626943 - the post is tagged data.table so I assumed OP was already working with a data.table - if not, you need to convert first. Have edited.
              – thelatemail
              Nov 12 at 5:24








            • 2




              For late-comers, .I is an integer vector equivalent to seq_len(nrow(x)). Ref: rdrr.io/cran/data.table/man/special-symbols.html (I had to look it up :-)
              – r2evans
              Nov 12 at 5:53

















            up vote
            5
            down vote



            accepted










            data.table should be a lot simpler if you subset the special .I row counter:



            library(data.table)
            setDT(data)
            data[
            data[
            ,
            if(any(YEAR > 2000))
            .I[which.min(2000 - YEAR)] else
            .I[which.max(YEAR)],
            by=GROUP
            ]$V1
            ]
            # GROUP YEAR NAME
            #1: 3 1985 A
            #2: 4 2011 L
            #3: 5 2012 G
            #4: 6 1994 A


            Thanks to @r2evans for the background info -




            .I is an integer vector equivalent to seq_len(nrow(x)).

            Ref:
            http://rdrr.io/cran/data.table/man/special-symbols.html




            So, all I'm doing here is getting the matching row index for the whole of data for each of the calculations at each by= level. Then using these row indexes to subset data again.






            share|improve this answer



















            • 1




              I get an error Error in [.data.frame(data, , if (any(YEAR > 2000)) .I[which.min(2000 - : unused argument (by = GROUP) Does it work exactly as is for you?
              – RAB
              Nov 12 at 5:22








            • 2




              @user10626943 - the post is tagged data.table so I assumed OP was already working with a data.table - if not, you need to convert first. Have edited.
              – thelatemail
              Nov 12 at 5:24








            • 2




              For late-comers, .I is an integer vector equivalent to seq_len(nrow(x)). Ref: rdrr.io/cran/data.table/man/special-symbols.html (I had to look it up :-)
              – r2evans
              Nov 12 at 5:53















            up vote
            5
            down vote



            accepted







            up vote
            5
            down vote



            accepted






            data.table should be a lot simpler if you subset the special .I row counter:



            library(data.table)
            setDT(data)
            data[
            data[
            ,
            if(any(YEAR > 2000))
            .I[which.min(2000 - YEAR)] else
            .I[which.max(YEAR)],
            by=GROUP
            ]$V1
            ]
            # GROUP YEAR NAME
            #1: 3 1985 A
            #2: 4 2011 L
            #3: 5 2012 G
            #4: 6 1994 A


            Thanks to @r2evans for the background info -




            .I is an integer vector equivalent to seq_len(nrow(x)).

            Ref:
            http://rdrr.io/cran/data.table/man/special-symbols.html




            So, all I'm doing here is getting the matching row index for the whole of data for each of the calculations at each by= level. Then using these row indexes to subset data again.






            share|improve this answer














            data.table should be a lot simpler if you subset the special .I row counter:



            library(data.table)
            setDT(data)
            data[
            data[
            ,
            if(any(YEAR > 2000))
            .I[which.min(2000 - YEAR)] else
            .I[which.max(YEAR)],
            by=GROUP
            ]$V1
            ]
            # GROUP YEAR NAME
            #1: 3 1985 A
            #2: 4 2011 L
            #3: 5 2012 G
            #4: 6 1994 A


            Thanks to @r2evans for the background info -




            .I is an integer vector equivalent to seq_len(nrow(x)).

            Ref:
            http://rdrr.io/cran/data.table/man/special-symbols.html




            So, all I'm doing here is getting the matching row index for the whole of data for each of the calculations at each by= level. Then using these row indexes to subset data again.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 12 at 6:05

























            answered Nov 12 at 5:09









            thelatemail

            66.6k881149




            66.6k881149








            • 1




              I get an error Error in [.data.frame(data, , if (any(YEAR > 2000)) .I[which.min(2000 - : unused argument (by = GROUP) Does it work exactly as is for you?
              – RAB
              Nov 12 at 5:22








            • 2




              @user10626943 - the post is tagged data.table so I assumed OP was already working with a data.table - if not, you need to convert first. Have edited.
              – thelatemail
              Nov 12 at 5:24








            • 2




              For late-comers, .I is an integer vector equivalent to seq_len(nrow(x)). Ref: rdrr.io/cran/data.table/man/special-symbols.html (I had to look it up :-)
              – r2evans
              Nov 12 at 5:53
















            • 1




              I get an error Error in [.data.frame(data, , if (any(YEAR > 2000)) .I[which.min(2000 - : unused argument (by = GROUP) Does it work exactly as is for you?
              – RAB
              Nov 12 at 5:22








            • 2




              @user10626943 - the post is tagged data.table so I assumed OP was already working with a data.table - if not, you need to convert first. Have edited.
              – thelatemail
              Nov 12 at 5:24








            • 2




              For late-comers, .I is an integer vector equivalent to seq_len(nrow(x)). Ref: rdrr.io/cran/data.table/man/special-symbols.html (I had to look it up :-)
              – r2evans
              Nov 12 at 5:53










            1




            1




            I get an error Error in [.data.frame(data, , if (any(YEAR > 2000)) .I[which.min(2000 - : unused argument (by = GROUP) Does it work exactly as is for you?
            – RAB
            Nov 12 at 5:22






            I get an error Error in [.data.frame(data, , if (any(YEAR > 2000)) .I[which.min(2000 - : unused argument (by = GROUP) Does it work exactly as is for you?
            – RAB
            Nov 12 at 5:22






            2




            2




            @user10626943 - the post is tagged data.table so I assumed OP was already working with a data.table - if not, you need to convert first. Have edited.
            – thelatemail
            Nov 12 at 5:24






            @user10626943 - the post is tagged data.table so I assumed OP was already working with a data.table - if not, you need to convert first. Have edited.
            – thelatemail
            Nov 12 at 5:24






            2




            2




            For late-comers, .I is an integer vector equivalent to seq_len(nrow(x)). Ref: rdrr.io/cran/data.table/man/special-symbols.html (I had to look it up :-)
            – r2evans
            Nov 12 at 5:53






            For late-comers, .I is an integer vector equivalent to seq_len(nrow(x)). Ref: rdrr.io/cran/data.table/man/special-symbols.html (I had to look it up :-)
            – r2evans
            Nov 12 at 5:53














            up vote
            3
            down vote













            You could also do a couple rolling joins:



            res = unique(data[, .(GROUP)])

            # get row with YEAR above 2000
            res[, w := data[c(.SD, YEAR = 2000), on=.(GROUP, YEAR), roll=-Inf, which=TRUE]]

            # if none found, get row with nearest YEAR below
            res[is.na(w), w := data[c(.SD, YEAR = 2000), on=.(GROUP, YEAR), roll=Inf, which=TRUE]]

            # subset by row numbers
            data[res$w]

            GROUP YEAR NAME
            1: 3 1985 A
            2: 4 2011 L
            3: 5 2012 G
            4: 6 1994 A





            share|improve this answer

























              up vote
              3
              down vote













              You could also do a couple rolling joins:



              res = unique(data[, .(GROUP)])

              # get row with YEAR above 2000
              res[, w := data[c(.SD, YEAR = 2000), on=.(GROUP, YEAR), roll=-Inf, which=TRUE]]

              # if none found, get row with nearest YEAR below
              res[is.na(w), w := data[c(.SD, YEAR = 2000), on=.(GROUP, YEAR), roll=Inf, which=TRUE]]

              # subset by row numbers
              data[res$w]

              GROUP YEAR NAME
              1: 3 1985 A
              2: 4 2011 L
              3: 5 2012 G
              4: 6 1994 A





              share|improve this answer























                up vote
                3
                down vote










                up vote
                3
                down vote









                You could also do a couple rolling joins:



                res = unique(data[, .(GROUP)])

                # get row with YEAR above 2000
                res[, w := data[c(.SD, YEAR = 2000), on=.(GROUP, YEAR), roll=-Inf, which=TRUE]]

                # if none found, get row with nearest YEAR below
                res[is.na(w), w := data[c(.SD, YEAR = 2000), on=.(GROUP, YEAR), roll=Inf, which=TRUE]]

                # subset by row numbers
                data[res$w]

                GROUP YEAR NAME
                1: 3 1985 A
                2: 4 2011 L
                3: 5 2012 G
                4: 6 1994 A





                share|improve this answer












                You could also do a couple rolling joins:



                res = unique(data[, .(GROUP)])

                # get row with YEAR above 2000
                res[, w := data[c(.SD, YEAR = 2000), on=.(GROUP, YEAR), roll=-Inf, which=TRUE]]

                # if none found, get row with nearest YEAR below
                res[is.na(w), w := data[c(.SD, YEAR = 2000), on=.(GROUP, YEAR), roll=Inf, which=TRUE]]

                # subset by row numbers
                data[res$w]

                GROUP YEAR NAME
                1: 3 1985 A
                2: 4 2011 L
                3: 5 2012 G
                4: 6 1994 A






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 12 at 14:22









                Frank

                53.6k653126




                53.6k653126






















                    up vote
                    2
                    down vote













                    Using the dplyr package I got your output like this (though it may not be the simplest answer):



                     library(dplyr)
                    library(magrittr)

                    data <- data.frame(GROUP=c(3,3,4,4,5,6),
                    YEAR=c(1979,1985,1999,2011,2012,1994),
                    NAME=c("S","A","J","L","G","A"))

                    data %>%
                    subset(YEAR < 2000) %>%
                    group_by(GROUP) %>%
                    summarise(MAX=max(YEAR)) %>%
                    join(data %>%
                    subset(YEAR > 2000) %>%
                    group_by(GROUP) %>%
                    summarise(MIN=min(YEAR)), type="full") %>%
                    mutate(YEAR=ifelse(is.na(MIN), MAX, MIN)) %>%
                    select(c(GROUP, YEAR)) %>%
                    join(data)


                    Results:



                       GROUP YEAR NAME
                    3 1985 A
                    4 2011 L
                    5 2012 G
                    6 1994 A


                    EDIT: Sorry, my first answer didn't take into account the min/max conditions. Hope this helps






                    share|improve this answer



















                    • 1




                      Thanks for the tidyverse solution! and for the formatting pointers.
                      – CFB
                      Nov 12 at 5:47

















                    up vote
                    2
                    down vote













                    Using the dplyr package I got your output like this (though it may not be the simplest answer):



                     library(dplyr)
                    library(magrittr)

                    data <- data.frame(GROUP=c(3,3,4,4,5,6),
                    YEAR=c(1979,1985,1999,2011,2012,1994),
                    NAME=c("S","A","J","L","G","A"))

                    data %>%
                    subset(YEAR < 2000) %>%
                    group_by(GROUP) %>%
                    summarise(MAX=max(YEAR)) %>%
                    join(data %>%
                    subset(YEAR > 2000) %>%
                    group_by(GROUP) %>%
                    summarise(MIN=min(YEAR)), type="full") %>%
                    mutate(YEAR=ifelse(is.na(MIN), MAX, MIN)) %>%
                    select(c(GROUP, YEAR)) %>%
                    join(data)


                    Results:



                       GROUP YEAR NAME
                    3 1985 A
                    4 2011 L
                    5 2012 G
                    6 1994 A


                    EDIT: Sorry, my first answer didn't take into account the min/max conditions. Hope this helps






                    share|improve this answer



















                    • 1




                      Thanks for the tidyverse solution! and for the formatting pointers.
                      – CFB
                      Nov 12 at 5:47















                    up vote
                    2
                    down vote










                    up vote
                    2
                    down vote









                    Using the dplyr package I got your output like this (though it may not be the simplest answer):



                     library(dplyr)
                    library(magrittr)

                    data <- data.frame(GROUP=c(3,3,4,4,5,6),
                    YEAR=c(1979,1985,1999,2011,2012,1994),
                    NAME=c("S","A","J","L","G","A"))

                    data %>%
                    subset(YEAR < 2000) %>%
                    group_by(GROUP) %>%
                    summarise(MAX=max(YEAR)) %>%
                    join(data %>%
                    subset(YEAR > 2000) %>%
                    group_by(GROUP) %>%
                    summarise(MIN=min(YEAR)), type="full") %>%
                    mutate(YEAR=ifelse(is.na(MIN), MAX, MIN)) %>%
                    select(c(GROUP, YEAR)) %>%
                    join(data)


                    Results:



                       GROUP YEAR NAME
                    3 1985 A
                    4 2011 L
                    5 2012 G
                    6 1994 A


                    EDIT: Sorry, my first answer didn't take into account the min/max conditions. Hope this helps






                    share|improve this answer














                    Using the dplyr package I got your output like this (though it may not be the simplest answer):



                     library(dplyr)
                    library(magrittr)

                    data <- data.frame(GROUP=c(3,3,4,4,5,6),
                    YEAR=c(1979,1985,1999,2011,2012,1994),
                    NAME=c("S","A","J","L","G","A"))

                    data %>%
                    subset(YEAR < 2000) %>%
                    group_by(GROUP) %>%
                    summarise(MAX=max(YEAR)) %>%
                    join(data %>%
                    subset(YEAR > 2000) %>%
                    group_by(GROUP) %>%
                    summarise(MIN=min(YEAR)), type="full") %>%
                    mutate(YEAR=ifelse(is.na(MIN), MAX, MIN)) %>%
                    select(c(GROUP, YEAR)) %>%
                    join(data)


                    Results:



                       GROUP YEAR NAME
                    3 1985 A
                    4 2011 L
                    5 2012 G
                    6 1994 A


                    EDIT: Sorry, my first answer didn't take into account the min/max conditions. Hope this helps







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Nov 12 at 4:48

























                    answered Nov 12 at 4:33









                    RAB

                    46511




                    46511








                    • 1




                      Thanks for the tidyverse solution! and for the formatting pointers.
                      – CFB
                      Nov 12 at 5:47
















                    • 1




                      Thanks for the tidyverse solution! and for the formatting pointers.
                      – CFB
                      Nov 12 at 5:47










                    1




                    1




                    Thanks for the tidyverse solution! and for the formatting pointers.
                    – CFB
                    Nov 12 at 5:47






                    Thanks for the tidyverse solution! and for the formatting pointers.
                    – CFB
                    Nov 12 at 5:47




















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