Dictionary value

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def get_neighbors_link_cost(source_id, network_topology):

    nodes = network_topology['nodes']





# get network topology links

links = network_topology['links'].keys()

#print(links)



# get the link costs in network topology

link_cost = network_topology['links']

#print(link_cost)



# make an empty dictionary for neighbor_link_cost

#neighbor_link_cost = None

neighbor_link_cost = {}



# add the cost to the source_id as zero

#neighbor_link_cost[None] = None

neighbor_link_cost[source_id] = 0

#print(neighbor_link_cost)



# go through the link

for link in links:

    # if source id is not in the link, skip it

    if source_id not in link:

        continue

    # get the neighbor information and cost for this neighbor

    neighbor = link[0] if source_id == link[1] else link[1]

    #neighbor_link_cost[None] = None

    #neighbor_link_cost[neighbor] = 3

    neighbor_link_cost[neighbor] = link(source_id,neighbor)

    #neighbor_link_cost[neighbor] = link_cost.get('z','x')

    #print(neighbor_link_cost[neighbor])



return neighbor_link_cost



network_topology = {'nodes': set(['z','x','y','w','v','u','t']),

              'links': {('z','x'): 8,

                        ('z','y'): 12,

                        ('x','y'): 6,

                        ('x','w'): 6,

                        ('x','v'): 3,

                        ('y','t'): 7,

                        ('y','v'): 8,

                        ('v','t'): 4,

                        ('v','w'): 4,

                        ('v','u'): 3,

                        ('t','u'): 2,

                        ('w','u'): 3

                       }

                   }



source_id = 'v'

get_neighbors_link_cost(source_id, network_top)

Expected output should be:

Expected output: {'v': 0, 'x': 3, 'y': 8, 't': 4, 'w': 4, 'u': 3}

What should be this line to get expected output? Thank you in advance

edited Nov 12 at 4:36

Mayank Porwal

3,9651621

asked Nov 12 at 4:21

Kuntal Shah

add a comment |

up vote
0
down vote

favorite

def get_neighbors_link_cost(source_id, network_topology):

    nodes = network_topology['nodes']





# get network topology links

links = network_topology['links'].keys()

#print(links)



# get the link costs in network topology

link_cost = network_topology['links']

#print(link_cost)



# make an empty dictionary for neighbor_link_cost

#neighbor_link_cost = None

neighbor_link_cost = {}



# add the cost to the source_id as zero

#neighbor_link_cost[None] = None

neighbor_link_cost[source_id] = 0

#print(neighbor_link_cost)



# go through the link

for link in links:

    # if source id is not in the link, skip it

    if source_id not in link:

        continue

    # get the neighbor information and cost for this neighbor

    neighbor = link[0] if source_id == link[1] else link[1]

    #neighbor_link_cost[None] = None

    #neighbor_link_cost[neighbor] = 3

    neighbor_link_cost[neighbor] = link(source_id,neighbor)

    #neighbor_link_cost[neighbor] = link_cost.get('z','x')

    #print(neighbor_link_cost[neighbor])



return neighbor_link_cost



network_topology = {'nodes': set(['z','x','y','w','v','u','t']),

              'links': {('z','x'): 8,

                        ('z','y'): 12,

                        ('x','y'): 6,

                        ('x','w'): 6,

                        ('x','v'): 3,

                        ('y','t'): 7,

                        ('y','v'): 8,

                        ('v','t'): 4,

                        ('v','w'): 4,

                        ('v','u'): 3,

                        ('t','u'): 2,

                        ('w','u'): 3

                       }

                   }



source_id = 'v'

get_neighbors_link_cost(source_id, network_top)

Expected output should be:

Expected output: {'v': 0, 'x': 3, 'y': 8, 't': 4, 'w': 4, 'u': 3}

What should be this line to get expected output? Thank you in advance

edited Nov 12 at 4:36

Mayank Porwal

3,9651621

asked Nov 12 at 4:21

Kuntal Shah

add a comment |

up vote
0
down vote

favorite

def get_neighbors_link_cost(source_id, network_topology):

    nodes = network_topology['nodes']





# get network topology links

links = network_topology['links'].keys()

#print(links)



# get the link costs in network topology

link_cost = network_topology['links']

#print(link_cost)



# make an empty dictionary for neighbor_link_cost

#neighbor_link_cost = None

neighbor_link_cost = {}



# add the cost to the source_id as zero

#neighbor_link_cost[None] = None

neighbor_link_cost[source_id] = 0

#print(neighbor_link_cost)



# go through the link

for link in links:

    # if source id is not in the link, skip it

    if source_id not in link:

        continue

    # get the neighbor information and cost for this neighbor

    neighbor = link[0] if source_id == link[1] else link[1]

    #neighbor_link_cost[None] = None

    #neighbor_link_cost[neighbor] = 3

    neighbor_link_cost[neighbor] = link(source_id,neighbor)

    #neighbor_link_cost[neighbor] = link_cost.get('z','x')

    #print(neighbor_link_cost[neighbor])



return neighbor_link_cost



network_topology = {'nodes': set(['z','x','y','w','v','u','t']),

              'links': {('z','x'): 8,

                        ('z','y'): 12,

                        ('x','y'): 6,

                        ('x','w'): 6,

                        ('x','v'): 3,

                        ('y','t'): 7,

                        ('y','v'): 8,

                        ('v','t'): 4,

                        ('v','w'): 4,

                        ('v','u'): 3,

                        ('t','u'): 2,

                        ('w','u'): 3

                       }

                   }



source_id = 'v'

get_neighbors_link_cost(source_id, network_top)

Expected output should be:

Expected output: {'v': 0, 'x': 3, 'y': 8, 't': 4, 'w': 4, 'u': 3}

What should be this line to get expected output? Thank you in advance

edited Nov 12 at 4:36

Mayank Porwal

3,9651621

asked Nov 12 at 4:21

Kuntal Shah

def get_neighbors_link_cost(source_id, network_topology):

    nodes = network_topology['nodes']





# get network topology links

links = network_topology['links'].keys()

#print(links)



# get the link costs in network topology

link_cost = network_topology['links']

#print(link_cost)



# make an empty dictionary for neighbor_link_cost

#neighbor_link_cost = None

neighbor_link_cost = {}



# add the cost to the source_id as zero

#neighbor_link_cost[None] = None

neighbor_link_cost[source_id] = 0

#print(neighbor_link_cost)



# go through the link

for link in links:

    # if source id is not in the link, skip it

    if source_id not in link:

        continue

    # get the neighbor information and cost for this neighbor

    neighbor = link[0] if source_id == link[1] else link[1]

    #neighbor_link_cost[None] = None

    #neighbor_link_cost[neighbor] = 3

    neighbor_link_cost[neighbor] = link(source_id,neighbor)

    #neighbor_link_cost[neighbor] = link_cost.get('z','x')

    #print(neighbor_link_cost[neighbor])



return neighbor_link_cost



network_topology = {'nodes': set(['z','x','y','w','v','u','t']),

              'links': {('z','x'): 8,

                        ('z','y'): 12,

                        ('x','y'): 6,

                        ('x','w'): 6,

                        ('x','v'): 3,

                        ('y','t'): 7,

                        ('y','v'): 8,

                        ('v','t'): 4,

                        ('v','w'): 4,

                        ('v','u'): 3,

                        ('t','u'): 2,

                        ('w','u'): 3

                       }

                   }



source_id = 'v'

get_neighbors_link_cost(source_id, network_top)

Expected output should be:

Expected output: {'v': 0, 'x': 3, 'y': 8, 't': 4, 'w': 4, 'u': 3}

What should be this line to get expected output? Thank you in advance

python dictionary bellman-ford

edited Nov 12 at 4:36

Mayank Porwal

3,9651621

asked Nov 12 at 4:21

Kuntal Shah

edited Nov 12 at 4:36

Mayank Porwal

3,9651621

asked Nov 12 at 4:21

Kuntal Shah

edited Nov 12 at 4:36

Mayank Porwal

3,9651621

edited Nov 12 at 4:36

Mayank Porwal

3,9651621

edited Nov 12 at 4:36

Mayank Porwal

3,9651621

asked Nov 12 at 4:21

Kuntal Shah

asked Nov 12 at 4:21

Kuntal Shah

asked Nov 12 at 4:21

Kuntal Shah

add a comment |

2 Answers
2

active

oldest

votes

up vote
0
down vote

neighbor_link_cost[neighbor] = link(source_id,neighbor)

'tuple' object is not callable

change this to

neighbor_link_cost[neighbor] = links[link]

answered Nov 12 at 4:58

Amit Karnik

524813

It doesn't work TypeError: 'dict_keys' object is not subscriptable
– Kuntal Shah
Nov 12 at 5:20

you might look into this Try
– Amit Karnik
Nov 12 at 5:24

add a comment |

up vote
0
down vote

you're really close, just need to change:

neighbor_link_cost[neighbor] = link(source_id,neighbor)

to:

neighbor_link_cost[neighbor[source_id]] = link_cost[link]

then should get expected output.

answered Nov 12 at 6:05

davedwards

5,03021131

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
0
down vote

neighbor_link_cost[neighbor] = link(source_id,neighbor)

'tuple' object is not callable

change this to

neighbor_link_cost[neighbor] = links[link]

answered Nov 12 at 4:58

Amit Karnik

524813

It doesn't work TypeError: 'dict_keys' object is not subscriptable
– Kuntal Shah
Nov 12 at 5:20

you might look into this Try
– Amit Karnik
Nov 12 at 5:24

add a comment |

up vote
0
down vote

neighbor_link_cost[neighbor] = link(source_id,neighbor)

'tuple' object is not callable

change this to

neighbor_link_cost[neighbor] = links[link]

answered Nov 12 at 4:58

Amit Karnik

524813

It doesn't work TypeError: 'dict_keys' object is not subscriptable
– Kuntal Shah
Nov 12 at 5:20

you might look into this Try
– Amit Karnik
Nov 12 at 5:24

add a comment |

up vote
0
down vote

neighbor_link_cost[neighbor] = link(source_id,neighbor)

'tuple' object is not callable

change this to

neighbor_link_cost[neighbor] = links[link]

answered Nov 12 at 4:58

Amit Karnik

524813

neighbor_link_cost[neighbor] = link(source_id,neighbor)

'tuple' object is not callable

change this to

neighbor_link_cost[neighbor] = links[link]

answered Nov 12 at 4:58

Amit Karnik

524813

answered Nov 12 at 4:58

Amit Karnik

524813

answered Nov 12 at 4:58

Amit Karnik

524813

answered Nov 12 at 4:58

Amit Karnik

524813

It doesn't work TypeError: 'dict_keys' object is not subscriptable
– Kuntal Shah
Nov 12 at 5:20

you might look into this Try
– Amit Karnik
Nov 12 at 5:24

add a comment |

It doesn't work TypeError: 'dict_keys' object is not subscriptable
– Kuntal Shah
Nov 12 at 5:20

you might look into this Try
– Amit Karnik
Nov 12 at 5:24

It doesn't work TypeError: 'dict_keys' object is not subscriptable
– Kuntal Shah
Nov 12 at 5:20

you might look into this Try
– Amit Karnik
Nov 12 at 5:24

add a comment |

up vote
0
down vote

you're really close, just need to change:

neighbor_link_cost[neighbor] = link(source_id,neighbor)

to:

neighbor_link_cost[neighbor[source_id]] = link_cost[link]

then should get expected output.

answered Nov 12 at 6:05

davedwards

5,03021131

add a comment |

up vote
0
down vote

you're really close, just need to change:

neighbor_link_cost[neighbor] = link(source_id,neighbor)

to:

neighbor_link_cost[neighbor[source_id]] = link_cost[link]

then should get expected output.

answered Nov 12 at 6:05

davedwards

5,03021131

add a comment |

up vote
0
down vote

you're really close, just need to change:

neighbor_link_cost[neighbor] = link(source_id,neighbor)

to:

neighbor_link_cost[neighbor[source_id]] = link_cost[link]

then should get expected output.

answered Nov 12 at 6:05

davedwards

5,03021131

you're really close, just need to change:

neighbor_link_cost[neighbor] = link(source_id,neighbor)

to:

neighbor_link_cost[neighbor[source_id]] = link_cost[link]

then should get expected output.

answered Nov 12 at 6:05

davedwards

5,03021131

answered Nov 12 at 6:05

davedwards

5,03021131

answered Nov 12 at 6:05

davedwards

5,03021131

answered Nov 12 at 6:05

davedwards

5,03021131

add a comment |

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