How to plot LTP vs. time from data available in a matrix in the form of Date, time, LTP
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0
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I have data in 3 columns:(as shown below
- Date Time LTP
- 20180102 09:16 1800
- ... ... ...
I wanna plot it in R so that I get time on the x-axis and LTP on the y-axis. Since there are around 360 rows every day (every minute LTP changes), the x variable shall be date:time
I am new to R and I need help in this. Thanks in anticipation
r gplots
asked Nov 12 at 4:16
krishna
31
add a comment |
up vote
0
down vote
favorite
I have data in 3 columns:(as shown below
- Date Time LTP
- 20180102 09:16 1800
- ... ... ...
I wanna plot it in R so that I get time on the x-axis and LTP on the y-axis. Since there are around 360 rows every day (every minute LTP changes), the x variable shall be date:time
I am new to R and I need help in this. Thanks in anticipation
r gplots
asked Nov 12 at 4:16
krishna
31
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have data in 3 columns:(as shown below
- Date Time LTP
- 20180102 09:16 1800
- ... ... ...
I wanna plot it in R so that I get time on the x-axis and LTP on the y-axis. Since there are around 360 rows every day (every minute LTP changes), the x variable shall be date:time
I am new to R and I need help in this. Thanks in anticipation
r gplots
asked Nov 12 at 4:16
krishna
31
I have data in 3 columns:(as shown below
- Date Time LTP
- 20180102 09:16 1800
- ... ... ...
I wanna plot it in R so that I get time on the x-axis and LTP on the y-axis. Since there are around 360 rows every day (every minute LTP changes), the x variable shall be date:time
I am new to R and I need help in this. Thanks in anticipation
r gplots
r gplots
asked Nov 12 at 4:16
krishna
31
asked Nov 12 at 4:16
krishna
31
asked Nov 12 at 4:16
krishna
31
asked Nov 12 at 4:16
krishna
31
asked Nov 12 at 4:16
krishna
31
31
add a comment |
add a comment |
1 Answer
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Try this:
library(zoo)
z <- read.zoo("myfile.dat", header = TRUE, index = 1:2, format = "%Y%m%d %H:%M", tz = "")
# classic graphics
plot(z)
# ggplot2 graphics
autoplot(z)
Note
To generate a file for the sample data provided in the question try this; however, with only one point you won't see anything on a line graph.
cat("Date Time LTPn20180102 09:16 1800", file = "myfile.dat")
answered Nov 12 at 4:27
G. Grothendieck
144k9126231
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to useplot(z, xaxt = "n")will omit X axis. Now useaxis.breakin the plotrix package.
– G. Grothendieck
Nov 12 at 12:29
And a third approach isplot(z, xaxt = "n", type = "n"). Now uselinestwice to overlay on that empty chart each subset separately.
– G. Grothendieck
Nov 12 at 12:47
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Try this:
library(zoo)
z <- read.zoo("myfile.dat", header = TRUE, index = 1:2, format = "%Y%m%d %H:%M", tz = "")
# classic graphics
plot(z)
# ggplot2 graphics
autoplot(z)
Note
To generate a file for the sample data provided in the question try this; however, with only one point you won't see anything on a line graph.
cat("Date Time LTPn20180102 09:16 1800", file = "myfile.dat")
answered Nov 12 at 4:27
G. Grothendieck
144k9126231
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to useplot(z, xaxt = "n")will omit X axis. Now useaxis.breakin the plotrix package.
– G. Grothendieck
Nov 12 at 12:29
And a third approach isplot(z, xaxt = "n", type = "n"). Now uselinestwice to overlay on that empty chart each subset separately.
– G. Grothendieck
Nov 12 at 12:47
add a comment |
up vote
0
down vote
accepted
Try this:
library(zoo)
z <- read.zoo("myfile.dat", header = TRUE, index = 1:2, format = "%Y%m%d %H:%M", tz = "")
# classic graphics
plot(z)
# ggplot2 graphics
autoplot(z)
Note
To generate a file for the sample data provided in the question try this; however, with only one point you won't see anything on a line graph.
cat("Date Time LTPn20180102 09:16 1800", file = "myfile.dat")
answered Nov 12 at 4:27
G. Grothendieck
144k9126231
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to useplot(z, xaxt = "n")will omit X axis. Now useaxis.breakin the plotrix package.
– G. Grothendieck
Nov 12 at 12:29
And a third approach isplot(z, xaxt = "n", type = "n"). Now uselinestwice to overlay on that empty chart each subset separately.
– G. Grothendieck
Nov 12 at 12:47
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Try this:
library(zoo)
z <- read.zoo("myfile.dat", header = TRUE, index = 1:2, format = "%Y%m%d %H:%M", tz = "")
# classic graphics
plot(z)
# ggplot2 graphics
autoplot(z)
Note
To generate a file for the sample data provided in the question try this; however, with only one point you won't see anything on a line graph.
cat("Date Time LTPn20180102 09:16 1800", file = "myfile.dat")
answered Nov 12 at 4:27
G. Grothendieck
144k9126231
Try this:
library(zoo)
z <- read.zoo("myfile.dat", header = TRUE, index = 1:2, format = "%Y%m%d %H:%M", tz = "")
# classic graphics
plot(z)
# ggplot2 graphics
autoplot(z)
Note
To generate a file for the sample data provided in the question try this; however, with only one point you won't see anything on a line graph.
cat("Date Time LTPn20180102 09:16 1800", file = "myfile.dat")
answered Nov 12 at 4:27
G. Grothendieck
144k9126231
answered Nov 12 at 4:27
G. Grothendieck
144k9126231
answered Nov 12 at 4:27
G. Grothendieck
144k9126231
answered Nov 12 at 4:27
G. Grothendieck
144k9126231
144k9126231
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to useplot(z, xaxt = "n")will omit X axis. Now useaxis.breakin the plotrix package.
– G. Grothendieck
Nov 12 at 12:29
And a third approach isplot(z, xaxt = "n", type = "n"). Now uselinestwice to overlay on that empty chart each subset separately.
– G. Grothendieck
Nov 12 at 12:47
add a comment |
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to useplot(z, xaxt = "n")will omit X axis. Now useaxis.breakin the plotrix package.
– G. Grothendieck
Nov 12 at 12:29
And a third approach isplot(z, xaxt = "n", type = "n"). Now uselinestwice to overlay on that empty chart each subset separately.
– G. Grothendieck
Nov 12 at 12:47
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to use
plot(z, xaxt = "n") will omit X axis. Now use axis.break in the plotrix package.– G. Grothendieck
Nov 12 at 12:29
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to use
plot(z, xaxt = "n") will omit X axis. Now use axis.break in the plotrix package.– G. Grothendieck
Nov 12 at 12:29
And a third approach is
plot(z, xaxt = "n", type = "n") . Now use lines twice to overlay on that empty chart each subset separately.– G. Grothendieck
Nov 12 at 12:47
And a third approach is
plot(z, xaxt = "n", type = "n") . Now use lines twice to overlay on that empty chart each subset separately.– G. Grothendieck
Nov 12 at 12:47
add a comment |
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