How to split a list of vectors to sub-lists by increasing order.
up vote
1
down vote
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I have a list of n vectors. I would like to split it to sub-list where the number of the vectors at each list is different. The number of the vectors is increased sequentially from one list to another. For example,
if I have a list with 6 vectors. Then, I would like to split it to several list as follows:
The first list contains one vector. Then, the second list contains 2 vectors and so on. For example,
Suppose I have the list x as follows:
x <- list(x1=c(1,2,3), x2=c(1,4,3), x3=c(3,4,6), x4=c(4,8,4), x5=c(4,33,4), x6=c(9,6,7))
Then, I would like to split it into 3 lists,
list1 = x1
list2 = list(x2, x3)
list3 = list(x4,x5, x6)
I have similar question (How to splitting a list of vectors to small lists in decreasing order in r) but in a decreasing order.
How I can generate it to arbitrary number of vectors. For example, how if I have 10 or 20 vectors?
Any idea, please?
r
asked Nov 12 at 6:00
Maryam
18211
add a comment |
up vote
1
down vote
favorite
I have a list of n vectors. I would like to split it to sub-list where the number of the vectors at each list is different. The number of the vectors is increased sequentially from one list to another. For example,
if I have a list with 6 vectors. Then, I would like to split it to several list as follows:
The first list contains one vector. Then, the second list contains 2 vectors and so on. For example,
Suppose I have the list x as follows:
x <- list(x1=c(1,2,3), x2=c(1,4,3), x3=c(3,4,6), x4=c(4,8,4), x5=c(4,33,4), x6=c(9,6,7))
Then, I would like to split it into 3 lists,
list1 = x1
list2 = list(x2, x3)
list3 = list(x4,x5, x6)
I have similar question (How to splitting a list of vectors to small lists in decreasing order in r) but in a decreasing order.
How I can generate it to arbitrary number of vectors. For example, how if I have 10 or 20 vectors?
Any idea, please?
r
asked Nov 12 at 6:00
Maryam
18211
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have a list of n vectors. I would like to split it to sub-list where the number of the vectors at each list is different. The number of the vectors is increased sequentially from one list to another. For example,
if I have a list with 6 vectors. Then, I would like to split it to several list as follows:
The first list contains one vector. Then, the second list contains 2 vectors and so on. For example,
Suppose I have the list x as follows:
x <- list(x1=c(1,2,3), x2=c(1,4,3), x3=c(3,4,6), x4=c(4,8,4), x5=c(4,33,4), x6=c(9,6,7))
Then, I would like to split it into 3 lists,
list1 = x1
list2 = list(x2, x3)
list3 = list(x4,x5, x6)
I have similar question (How to splitting a list of vectors to small lists in decreasing order in r) but in a decreasing order.
How I can generate it to arbitrary number of vectors. For example, how if I have 10 or 20 vectors?
Any idea, please?
r
asked Nov 12 at 6:00
Maryam
18211
I have a list of n vectors. I would like to split it to sub-list where the number of the vectors at each list is different. The number of the vectors is increased sequentially from one list to another. For example,
if I have a list with 6 vectors. Then, I would like to split it to several list as follows:
The first list contains one vector. Then, the second list contains 2 vectors and so on. For example,
Suppose I have the list x as follows:
x <- list(x1=c(1,2,3), x2=c(1,4,3), x3=c(3,4,6), x4=c(4,8,4), x5=c(4,33,4), x6=c(9,6,7))
Then, I would like to split it into 3 lists,
list1 = x1
list2 = list(x2, x3)
list3 = list(x4,x5, x6)
I have similar question (How to splitting a list of vectors to small lists in decreasing order in r) but in a decreasing order.
How I can generate it to arbitrary number of vectors. For example, how if I have 10 or 20 vectors?
Any idea, please?
r
r
asked Nov 12 at 6:00
Maryam
18211
asked Nov 12 at 6:00
Maryam
18211
asked Nov 12 at 6:00
Maryam
18211
asked Nov 12 at 6:00
Maryam
18211
asked Nov 12 at 6:00
Maryam
18211
18211
add a comment |
add a comment |
2 Answers
2
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up vote
3
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accepted
I'd stick them all in a list of lists
MyLists <- list()
i <- 1
for (inc in 1:3){
MyLists[[inc]] <- x[i:(i+inc-1)]
i <- i+inc
}
Now MyLists[[1]] is list1, etc.
answered Nov 12 at 6:10
farnsy
1,5021317
add a comment |
up vote
1
down vote
Building off farnsy's answer, If you need each list in a separate indexed list in the global environment you could do something like this.
#your Stater list
x <- list(x1=c(1,2,3), x2=c(1,4,3), x3=c(3,4,6),
x4=c(4,8,4), x5=c(4,33,4), x6=c(9,6,7))
#using a paste parse eval approach to evaluate a string
i<-1
for(inc in 1:3){
eval(parse(text =
paste0("list", inc, "<-list(",
paste0("x$",names(x)[i:(i+inc-1)],collapse = ","),
")")
))
i <- i+inc
}
answered Nov 12 at 7:14
Kgrey
1613
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
I'd stick them all in a list of lists
MyLists <- list()
i <- 1
for (inc in 1:3){
MyLists[[inc]] <- x[i:(i+inc-1)]
i <- i+inc
}
Now MyLists[[1]] is list1, etc.
answered Nov 12 at 6:10
farnsy
1,5021317
add a comment |
up vote
3
down vote
accepted
I'd stick them all in a list of lists
MyLists <- list()
i <- 1
for (inc in 1:3){
MyLists[[inc]] <- x[i:(i+inc-1)]
i <- i+inc
}
Now MyLists[[1]] is list1, etc.
answered Nov 12 at 6:10
farnsy
1,5021317
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
I'd stick them all in a list of lists
MyLists <- list()
i <- 1
for (inc in 1:3){
MyLists[[inc]] <- x[i:(i+inc-1)]
i <- i+inc
}
Now MyLists[[1]] is list1, etc.
answered Nov 12 at 6:10
farnsy
1,5021317
I'd stick them all in a list of lists
MyLists <- list()
i <- 1
for (inc in 1:3){
MyLists[[inc]] <- x[i:(i+inc-1)]
i <- i+inc
}
Now MyLists[[1]] is list1, etc.
answered Nov 12 at 6:10
farnsy
1,5021317
answered Nov 12 at 6:10
farnsy
1,5021317
answered Nov 12 at 6:10
farnsy
1,5021317
answered Nov 12 at 6:10
farnsy
1,5021317
1,5021317
add a comment |
add a comment |
up vote
1
down vote
Building off farnsy's answer, If you need each list in a separate indexed list in the global environment you could do something like this.
#your Stater list
x <- list(x1=c(1,2,3), x2=c(1,4,3), x3=c(3,4,6),
x4=c(4,8,4), x5=c(4,33,4), x6=c(9,6,7))
#using a paste parse eval approach to evaluate a string
i<-1
for(inc in 1:3){
eval(parse(text =
paste0("list", inc, "<-list(",
paste0("x$",names(x)[i:(i+inc-1)],collapse = ","),
")")
))
i <- i+inc
}
answered Nov 12 at 7:14
Kgrey
1613
add a comment |
up vote
1
down vote
Building off farnsy's answer, If you need each list in a separate indexed list in the global environment you could do something like this.
#your Stater list
x <- list(x1=c(1,2,3), x2=c(1,4,3), x3=c(3,4,6),
x4=c(4,8,4), x5=c(4,33,4), x6=c(9,6,7))
#using a paste parse eval approach to evaluate a string
i<-1
for(inc in 1:3){
eval(parse(text =
paste0("list", inc, "<-list(",
paste0("x$",names(x)[i:(i+inc-1)],collapse = ","),
")")
))
i <- i+inc
}
answered Nov 12 at 7:14
Kgrey
1613
add a comment |
up vote
1
down vote
up vote
1
down vote
Building off farnsy's answer, If you need each list in a separate indexed list in the global environment you could do something like this.
#your Stater list
x <- list(x1=c(1,2,3), x2=c(1,4,3), x3=c(3,4,6),
x4=c(4,8,4), x5=c(4,33,4), x6=c(9,6,7))
#using a paste parse eval approach to evaluate a string
i<-1
for(inc in 1:3){
eval(parse(text =
paste0("list", inc, "<-list(",
paste0("x$",names(x)[i:(i+inc-1)],collapse = ","),
")")
))
i <- i+inc
}
answered Nov 12 at 7:14
Kgrey
1613
Building off farnsy's answer, If you need each list in a separate indexed list in the global environment you could do something like this.
#your Stater list
x <- list(x1=c(1,2,3), x2=c(1,4,3), x3=c(3,4,6),
x4=c(4,8,4), x5=c(4,33,4), x6=c(9,6,7))
#using a paste parse eval approach to evaluate a string
i<-1
for(inc in 1:3){
eval(parse(text =
paste0("list", inc, "<-list(",
paste0("x$",names(x)[i:(i+inc-1)],collapse = ","),
")")
))
i <- i+inc
}
answered Nov 12 at 7:14
Kgrey
1613
answered Nov 12 at 7:14
Kgrey
1613
answered Nov 12 at 7:14
Kgrey
1613
answered Nov 12 at 7:14
Kgrey
1613
1613
add a comment |
add a comment |
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