Explode and Set if condition php
up vote
0
down vote
favorite
Array ( [0] => 1 [1] => 2 )
I'm trying to set an if condition based on user permission, the idea is to show menu based on given values, if it is 1, one menu will be displayed and 2 second menu will be displayed, if its both then all values will be displayed. So far for single values i have gotten it right but how to do it for array of values
This is my code
<?php
$userid = $this->phpsession->get("user_id");
$userrole = $this->phpsession->get("user_type");
$query = $this->db->select("role_empid,role_permissions")->from('hw_role')->where('role_empid', $userid)->get()->result();
$data = $query[0]->role_permissions;
if($data == 1){
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }else if($data == 2){ ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php } ?>
</ul>
php codeigniter
edited Nov 12 at 6:21
ariefbayu
17k85581
asked Nov 12 at 6:06
Amal Joseph
115
|
show 1 more comment
up vote
0
down vote
favorite
Array ( [0] => 1 [1] => 2 )
I'm trying to set an if condition based on user permission, the idea is to show menu based on given values, if it is 1, one menu will be displayed and 2 second menu will be displayed, if its both then all values will be displayed. So far for single values i have gotten it right but how to do it for array of values
This is my code
<?php
$userid = $this->phpsession->get("user_id");
$userrole = $this->phpsession->get("user_type");
$query = $this->db->select("role_empid,role_permissions")->from('hw_role')->where('role_empid', $userid)->get()->result();
$data = $query[0]->role_permissions;
if($data == 1){
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }else if($data == 2){ ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php } ?>
</ul>
php codeigniter
edited Nov 12 at 6:21
ariefbayu
17k85581
asked Nov 12 at 6:06
Amal Joseph
115
Look atin_array- php.net/manual/en/function.in-array.php
– fubar
Nov 12 at 6:07
ok @fubar can you share an example
– Amal Joseph
Nov 12 at 6:09
what is the value in "role_permissions" if it contain multiple value array or json?
– Poonam Navapara
Nov 12 at 6:11
Array ( [0] => 1 [1] => 2 ) value of role permission @PoonamNavapara
– Amal Joseph
Nov 12 at 6:15
What is the issue with your current condition?
– Sachin
Nov 12 at 6:27
|
show 1 more comment
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Array ( [0] => 1 [1] => 2 )
I'm trying to set an if condition based on user permission, the idea is to show menu based on given values, if it is 1, one menu will be displayed and 2 second menu will be displayed, if its both then all values will be displayed. So far for single values i have gotten it right but how to do it for array of values
This is my code
<?php
$userid = $this->phpsession->get("user_id");
$userrole = $this->phpsession->get("user_type");
$query = $this->db->select("role_empid,role_permissions")->from('hw_role')->where('role_empid', $userid)->get()->result();
$data = $query[0]->role_permissions;
if($data == 1){
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }else if($data == 2){ ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php } ?>
</ul>
php codeigniter
edited Nov 12 at 6:21
ariefbayu
17k85581
asked Nov 12 at 6:06
Amal Joseph
115
Array ( [0] => 1 [1] => 2 )
I'm trying to set an if condition based on user permission, the idea is to show menu based on given values, if it is 1, one menu will be displayed and 2 second menu will be displayed, if its both then all values will be displayed. So far for single values i have gotten it right but how to do it for array of values
This is my code
<?php
$userid = $this->phpsession->get("user_id");
$userrole = $this->phpsession->get("user_type");
$query = $this->db->select("role_empid,role_permissions")->from('hw_role')->where('role_empid', $userid)->get()->result();
$data = $query[0]->role_permissions;
if($data == 1){
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }else if($data == 2){ ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php } ?>
</ul>
php codeigniter
php codeigniter
edited Nov 12 at 6:21
ariefbayu
17k85581
asked Nov 12 at 6:06
Amal Joseph
115
edited Nov 12 at 6:21
ariefbayu
17k85581
asked Nov 12 at 6:06
Amal Joseph
115
edited Nov 12 at 6:21
ariefbayu
17k85581
edited Nov 12 at 6:21
ariefbayu
17k85581
edited Nov 12 at 6:21
ariefbayu
17k85581
17k85581
asked Nov 12 at 6:06
Amal Joseph
115
asked Nov 12 at 6:06
Amal Joseph
115
asked Nov 12 at 6:06
Amal Joseph
115
115
Look atin_array- php.net/manual/en/function.in-array.php
– fubar
Nov 12 at 6:07
ok @fubar can you share an example
– Amal Joseph
Nov 12 at 6:09
what is the value in "role_permissions" if it contain multiple value array or json?
– Poonam Navapara
Nov 12 at 6:11
Array ( [0] => 1 [1] => 2 ) value of role permission @PoonamNavapara
– Amal Joseph
Nov 12 at 6:15
What is the issue with your current condition?
– Sachin
Nov 12 at 6:27
|
show 1 more comment
Look atin_array- php.net/manual/en/function.in-array.php
– fubar
Nov 12 at 6:07
ok @fubar can you share an example
– Amal Joseph
Nov 12 at 6:09
what is the value in "role_permissions" if it contain multiple value array or json?
– Poonam Navapara
Nov 12 at 6:11
Array ( [0] => 1 [1] => 2 ) value of role permission @PoonamNavapara
– Amal Joseph
Nov 12 at 6:15
What is the issue with your current condition?
– Sachin
Nov 12 at 6:27
Look at
in_array - php.net/manual/en/function.in-array.php– fubar
Nov 12 at 6:07
Look at
in_array - php.net/manual/en/function.in-array.php– fubar
Nov 12 at 6:07
ok @fubar can you share an example
– Amal Joseph
Nov 12 at 6:09
ok @fubar can you share an example
– Amal Joseph
Nov 12 at 6:09
what is the value in "role_permissions" if it contain multiple value array or json?
– Poonam Navapara
Nov 12 at 6:11
what is the value in "role_permissions" if it contain multiple value array or json?
– Poonam Navapara
Nov 12 at 6:11
Array ( [0] => 1 [1] => 2 ) value of role permission @PoonamNavapara
– Amal Joseph
Nov 12 at 6:15
Array ( [0] => 1 [1] => 2 ) value of role permission @PoonamNavapara
– Amal Joseph
Nov 12 at 6:15
What is the issue with your current condition?
– Sachin
Nov 12 at 6:27
What is the issue with your current condition?
– Sachin
Nov 12 at 6:27
|
show 1 more comment
3 Answers
3
active
oldest
votes
up vote
0
down vote
if role_permission contain json object that first convert it into the array like
$data = $query[0]->role_permissions;
$data=json_decode($data);
otherwise direct check the condition for
$data = $query[0]->role_permissions;
if(in_array(1,$data) && in_array(2,$data))
{
}
else if(in_array(1,$data))
{
}
else if(in_array(2,$data))
{
}
answered Nov 12 at 6:17
Poonam Navapara
18618
ok let me check if it works ,thanks for your time
– Amal Joseph
Nov 12 at 6:18
A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
– Amal Joseph
Nov 12 at 6:21
Yes, $data must be contain array value
– Poonam Navapara
Nov 12 at 6:23
what should i do then?
– Amal Joseph
Nov 12 at 6:26
i exploded the value now it works
– Amal Joseph
Nov 12 at 6:27
add a comment |
up vote
0
down vote
If $query[0]->role_permissions is an array that has distinct value, then you can try :
<ul>
<?php for($i = 0; $i<count($data);$i++) {
if($data[$i] == 1){ ?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }
if($data[$i] == 2){ ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php }} ?>
</ul>
answered Nov 12 at 6:21
arisalsaila
37416
when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
– Amal Joseph
Nov 12 at 6:25
updated my answer @AmalJoseph, just removeelse
– arisalsaila
Nov 12 at 6:28
ok let me check @arisalsaila thanks
– Amal Joseph
Nov 12 at 6:36
add a comment |
up vote
0
down vote
Try This
<?php
if(in_array(1,$data)){
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }
if(in_array(2,$data)){
?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php } ?>
answered Nov 12 at 6:44
Sachin
610411
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
if role_permission contain json object that first convert it into the array like
$data = $query[0]->role_permissions;
$data=json_decode($data);
otherwise direct check the condition for
$data = $query[0]->role_permissions;
if(in_array(1,$data) && in_array(2,$data))
{
}
else if(in_array(1,$data))
{
}
else if(in_array(2,$data))
{
}
answered Nov 12 at 6:17
Poonam Navapara
18618
ok let me check if it works ,thanks for your time
– Amal Joseph
Nov 12 at 6:18
A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
– Amal Joseph
Nov 12 at 6:21
Yes, $data must be contain array value
– Poonam Navapara
Nov 12 at 6:23
what should i do then?
– Amal Joseph
Nov 12 at 6:26
i exploded the value now it works
– Amal Joseph
Nov 12 at 6:27
add a comment |
up vote
0
down vote
if role_permission contain json object that first convert it into the array like
$data = $query[0]->role_permissions;
$data=json_decode($data);
otherwise direct check the condition for
$data = $query[0]->role_permissions;
if(in_array(1,$data) && in_array(2,$data))
{
}
else if(in_array(1,$data))
{
}
else if(in_array(2,$data))
{
}
answered Nov 12 at 6:17
Poonam Navapara
18618
ok let me check if it works ,thanks for your time
– Amal Joseph
Nov 12 at 6:18
A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
– Amal Joseph
Nov 12 at 6:21
Yes, $data must be contain array value
– Poonam Navapara
Nov 12 at 6:23
what should i do then?
– Amal Joseph
Nov 12 at 6:26
i exploded the value now it works
– Amal Joseph
Nov 12 at 6:27
add a comment |
up vote
0
down vote
up vote
0
down vote
if role_permission contain json object that first convert it into the array like
$data = $query[0]->role_permissions;
$data=json_decode($data);
otherwise direct check the condition for
$data = $query[0]->role_permissions;
if(in_array(1,$data) && in_array(2,$data))
{
}
else if(in_array(1,$data))
{
}
else if(in_array(2,$data))
{
}
answered Nov 12 at 6:17
Poonam Navapara
18618
if role_permission contain json object that first convert it into the array like
$data = $query[0]->role_permissions;
$data=json_decode($data);
otherwise direct check the condition for
$data = $query[0]->role_permissions;
if(in_array(1,$data) && in_array(2,$data))
{
}
else if(in_array(1,$data))
{
}
else if(in_array(2,$data))
{
}
answered Nov 12 at 6:17
Poonam Navapara
18618
answered Nov 12 at 6:17
Poonam Navapara
18618
answered Nov 12 at 6:17
Poonam Navapara
18618
answered Nov 12 at 6:17
Poonam Navapara
18618
18618
ok let me check if it works ,thanks for your time
– Amal Joseph
Nov 12 at 6:18
A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
– Amal Joseph
Nov 12 at 6:21
Yes, $data must be contain array value
– Poonam Navapara
Nov 12 at 6:23
what should i do then?
– Amal Joseph
Nov 12 at 6:26
i exploded the value now it works
– Amal Joseph
Nov 12 at 6:27
add a comment |
ok let me check if it works ,thanks for your time
– Amal Joseph
Nov 12 at 6:18
A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
– Amal Joseph
Nov 12 at 6:21
Yes, $data must be contain array value
– Poonam Navapara
Nov 12 at 6:23
what should i do then?
– Amal Joseph
Nov 12 at 6:26
i exploded the value now it works
– Amal Joseph
Nov 12 at 6:27
ok let me check if it works ,thanks for your time
– Amal Joseph
Nov 12 at 6:18
ok let me check if it works ,thanks for your time
– Amal Joseph
Nov 12 at 6:18
A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
– Amal Joseph
Nov 12 at 6:21
A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
– Amal Joseph
Nov 12 at 6:21
Yes, $data must be contain array value
– Poonam Navapara
Nov 12 at 6:23
Yes, $data must be contain array value
– Poonam Navapara
Nov 12 at 6:23
what should i do then?
– Amal Joseph
Nov 12 at 6:26
what should i do then?
– Amal Joseph
Nov 12 at 6:26
i exploded the value now it works
– Amal Joseph
Nov 12 at 6:27
i exploded the value now it works
– Amal Joseph
Nov 12 at 6:27
add a comment |
up vote
0
down vote
If $query[0]->role_permissions is an array that has distinct value, then you can try :
<ul>
<?php for($i = 0; $i<count($data);$i++) {
if($data[$i] == 1){ ?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }
if($data[$i] == 2){ ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php }} ?>
</ul>
answered Nov 12 at 6:21
arisalsaila
37416
when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
– Amal Joseph
Nov 12 at 6:25
updated my answer @AmalJoseph, just removeelse
– arisalsaila
Nov 12 at 6:28
ok let me check @arisalsaila thanks
– Amal Joseph
Nov 12 at 6:36
add a comment |
up vote
0
down vote
If $query[0]->role_permissions is an array that has distinct value, then you can try :
<ul>
<?php for($i = 0; $i<count($data);$i++) {
if($data[$i] == 1){ ?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }
if($data[$i] == 2){ ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php }} ?>
</ul>
answered Nov 12 at 6:21
arisalsaila
37416
when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
– Amal Joseph
Nov 12 at 6:25
updated my answer @AmalJoseph, just removeelse
– arisalsaila
Nov 12 at 6:28
ok let me check @arisalsaila thanks
– Amal Joseph
Nov 12 at 6:36
add a comment |
up vote
0
down vote
up vote
0
down vote
If $query[0]->role_permissions is an array that has distinct value, then you can try :
<ul>
<?php for($i = 0; $i<count($data);$i++) {
if($data[$i] == 1){ ?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }
if($data[$i] == 2){ ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php }} ?>
</ul>
answered Nov 12 at 6:21
arisalsaila
37416
If $query[0]->role_permissions is an array that has distinct value, then you can try :
<ul>
<?php for($i = 0; $i<count($data);$i++) {
if($data[$i] == 1){ ?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }
if($data[$i] == 2){ ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php }} ?>
</ul>
answered Nov 12 at 6:21
arisalsaila
37416
edited Nov 12 at 6:27
answered Nov 12 at 6:21
arisalsaila
37416
answered Nov 12 at 6:21
arisalsaila
37416
answered Nov 12 at 6:21
arisalsaila
37416
37416
when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
– Amal Joseph
Nov 12 at 6:25
updated my answer @AmalJoseph, just removeelse
– arisalsaila
Nov 12 at 6:28
ok let me check @arisalsaila thanks
– Amal Joseph
Nov 12 at 6:36
add a comment |
when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
– Amal Joseph
Nov 12 at 6:25
updated my answer @AmalJoseph, just removeelse
– arisalsaila
Nov 12 at 6:28
ok let me check @arisalsaila thanks
– Amal Joseph
Nov 12 at 6:36
when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
– Amal Joseph
Nov 12 at 6:25
when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
– Amal Joseph
Nov 12 at 6:25
updated my answer @AmalJoseph, just remove
else– arisalsaila
Nov 12 at 6:28
updated my answer @AmalJoseph, just remove
else– arisalsaila
Nov 12 at 6:28
ok let me check @arisalsaila thanks
– Amal Joseph
Nov 12 at 6:36
ok let me check @arisalsaila thanks
– Amal Joseph
Nov 12 at 6:36
add a comment |
up vote
0
down vote
Try This
<?php
if(in_array(1,$data)){
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }
if(in_array(2,$data)){
?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php } ?>
answered Nov 12 at 6:44
Sachin
610411
add a comment |
up vote
0
down vote
Try This
<?php
if(in_array(1,$data)){
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }
if(in_array(2,$data)){
?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php } ?>
answered Nov 12 at 6:44
Sachin
610411
add a comment |
up vote
0
down vote
up vote
0
down vote
Try This
<?php
if(in_array(1,$data)){
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }
if(in_array(2,$data)){
?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php } ?>
answered Nov 12 at 6:44
Sachin
610411
Try This
<?php
if(in_array(1,$data)){
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php }
if(in_array(2,$data)){
?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php } ?>
answered Nov 12 at 6:44
Sachin
610411
answered Nov 12 at 6:44
Sachin
610411
answered Nov 12 at 6:44
Sachin
610411
answered Nov 12 at 6:44
Sachin
610411
610411
add a comment |
add a comment |
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Look at
in_array- php.net/manual/en/function.in-array.php– fubar
Nov 12 at 6:07
ok @fubar can you share an example
– Amal Joseph
Nov 12 at 6:09
what is the value in "role_permissions" if it contain multiple value array or json?
– Poonam Navapara
Nov 12 at 6:11
Array ( [0] => 1 [1] => 2 ) value of role permission @PoonamNavapara
– Amal Joseph
Nov 12 at 6:15
What is the issue with your current condition?
– Sachin
Nov 12 at 6:27