Shell/terminal/bash command or script for copying list of files from one project to another
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Let's say I have a project called my-project/ that lives in it's own directory and has the following file structure.
my-project/
.
├── src
│ ├── index.html
│ ├── main.js
│ ├── normalize.js
│ ├── routes
│ │ ├── index.js
│ │ └── Home
│ │ ├── index.js
│ │ └── assets
│ ├── static
│ ├── store
│ │ ├── createStore.js
│ │ └── reducers.js
│ └── styles
└── project.config.js
Now let's say I have a new project called my-new-project that also lives in it's own directory and has the same file structure as my-project but it contains an additional file called my-files-to-copy.txt
my-new-project/
.
├── src
│ ├── index.html
│ ├── main.js
│ ├── normalize.js
│ ├── routes
│ │ ├── index.js
│ │ └── Home
│ │ ├── index.js
│ │ └── assets
│ ├── static
│ ├── store
│ │ ├── createStore.js
│ │ └── reducers.js
│ └── styles
├── project.config.js
└── my-files-to-copy.txt # new file added to tree
my-new-project/ has the same file structure but different file contents than my-project/
Now let's say my-files-to-copy.txt contains a list of files I want to copy from my-project/ and write to the same path in my-new-project/ to overwrite the existing files in my-new-project/ at those locations.
my-files-to-copy.txt
src/main.js
src/routes/index.js
src/store/reducers.js
project.config.js
How can I accomplish this with a terminal/bash/shell command or script?
edit:
I think I might be able to do:
cp my-project/src/main.js my-new-project/src/main.js
cp my-project/src/routes/index.js my-new-project/src/routes/index.js
cp my-project/src/store/reducers.js my-new-project/src/store/reducers.js
cp my-project/project.config.js my-new-project/project.config.js
But as the number of files scales, this method will become less efficient. I was looking for a more efficient solution that would allow me to leverage the file that contains the list of files (or at least a script) without having to write a separate command for each one.
bash shell terminal
asked Nov 11 at 0:45
Mowzer
5,195639103
add a comment |
up vote
-2
down vote
favorite
Let's say I have a project called my-project/ that lives in it's own directory and has the following file structure.
my-project/
.
├── src
│ ├── index.html
│ ├── main.js
│ ├── normalize.js
│ ├── routes
│ │ ├── index.js
│ │ └── Home
│ │ ├── index.js
│ │ └── assets
│ ├── static
│ ├── store
│ │ ├── createStore.js
│ │ └── reducers.js
│ └── styles
└── project.config.js
Now let's say I have a new project called my-new-project that also lives in it's own directory and has the same file structure as my-project but it contains an additional file called my-files-to-copy.txt
my-new-project/
.
├── src
│ ├── index.html
│ ├── main.js
│ ├── normalize.js
│ ├── routes
│ │ ├── index.js
│ │ └── Home
│ │ ├── index.js
│ │ └── assets
│ ├── static
│ ├── store
│ │ ├── createStore.js
│ │ └── reducers.js
│ └── styles
├── project.config.js
└── my-files-to-copy.txt # new file added to tree
my-new-project/ has the same file structure but different file contents than my-project/
Now let's say my-files-to-copy.txt contains a list of files I want to copy from my-project/ and write to the same path in my-new-project/ to overwrite the existing files in my-new-project/ at those locations.
my-files-to-copy.txt
src/main.js
src/routes/index.js
src/store/reducers.js
project.config.js
How can I accomplish this with a terminal/bash/shell command or script?
edit:
I think I might be able to do:
cp my-project/src/main.js my-new-project/src/main.js
cp my-project/src/routes/index.js my-new-project/src/routes/index.js
cp my-project/src/store/reducers.js my-new-project/src/store/reducers.js
cp my-project/project.config.js my-new-project/project.config.js
But as the number of files scales, this method will become less efficient. I was looking for a more efficient solution that would allow me to leverage the file that contains the list of files (or at least a script) without having to write a separate command for each one.
bash shell terminal
asked Nov 11 at 0:45
Mowzer
5,195639103
Maybe try usingrsync...
– l'L'l
Nov 11 at 0:47
Welcome to SO. Stack Overflow is a question and answer site for professional and enthusiast programmers. The goal is that you add some code of your own to your question to show at least the research effort you made to solve this yourself.
– Cyrus
Nov 11 at 0:50
add a comment |
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
Let's say I have a project called my-project/ that lives in it's own directory and has the following file structure.
my-project/
.
├── src
│ ├── index.html
│ ├── main.js
│ ├── normalize.js
│ ├── routes
│ │ ├── index.js
│ │ └── Home
│ │ ├── index.js
│ │ └── assets
│ ├── static
│ ├── store
│ │ ├── createStore.js
│ │ └── reducers.js
│ └── styles
└── project.config.js
Now let's say I have a new project called my-new-project that also lives in it's own directory and has the same file structure as my-project but it contains an additional file called my-files-to-copy.txt
my-new-project/
.
├── src
│ ├── index.html
│ ├── main.js
│ ├── normalize.js
│ ├── routes
│ │ ├── index.js
│ │ └── Home
│ │ ├── index.js
│ │ └── assets
│ ├── static
│ ├── store
│ │ ├── createStore.js
│ │ └── reducers.js
│ └── styles
├── project.config.js
└── my-files-to-copy.txt # new file added to tree
my-new-project/ has the same file structure but different file contents than my-project/
Now let's say my-files-to-copy.txt contains a list of files I want to copy from my-project/ and write to the same path in my-new-project/ to overwrite the existing files in my-new-project/ at those locations.
my-files-to-copy.txt
src/main.js
src/routes/index.js
src/store/reducers.js
project.config.js
How can I accomplish this with a terminal/bash/shell command or script?
edit:
I think I might be able to do:
cp my-project/src/main.js my-new-project/src/main.js
cp my-project/src/routes/index.js my-new-project/src/routes/index.js
cp my-project/src/store/reducers.js my-new-project/src/store/reducers.js
cp my-project/project.config.js my-new-project/project.config.js
But as the number of files scales, this method will become less efficient. I was looking for a more efficient solution that would allow me to leverage the file that contains the list of files (or at least a script) without having to write a separate command for each one.
bash shell terminal
asked Nov 11 at 0:45
Mowzer
5,195639103
Let's say I have a project called my-project/ that lives in it's own directory and has the following file structure.
my-project/
.
├── src
│ ├── index.html
│ ├── main.js
│ ├── normalize.js
│ ├── routes
│ │ ├── index.js
│ │ └── Home
│ │ ├── index.js
│ │ └── assets
│ ├── static
│ ├── store
│ │ ├── createStore.js
│ │ └── reducers.js
│ └── styles
└── project.config.js
Now let's say I have a new project called my-new-project that also lives in it's own directory and has the same file structure as my-project but it contains an additional file called my-files-to-copy.txt
my-new-project/
.
├── src
│ ├── index.html
│ ├── main.js
│ ├── normalize.js
│ ├── routes
│ │ ├── index.js
│ │ └── Home
│ │ ├── index.js
│ │ └── assets
│ ├── static
│ ├── store
│ │ ├── createStore.js
│ │ └── reducers.js
│ └── styles
├── project.config.js
└── my-files-to-copy.txt # new file added to tree
my-new-project/ has the same file structure but different file contents than my-project/
Now let's say my-files-to-copy.txt contains a list of files I want to copy from my-project/ and write to the same path in my-new-project/ to overwrite the existing files in my-new-project/ at those locations.
my-files-to-copy.txt
src/main.js
src/routes/index.js
src/store/reducers.js
project.config.js
How can I accomplish this with a terminal/bash/shell command or script?
edit:
I think I might be able to do:
cp my-project/src/main.js my-new-project/src/main.js
cp my-project/src/routes/index.js my-new-project/src/routes/index.js
cp my-project/src/store/reducers.js my-new-project/src/store/reducers.js
cp my-project/project.config.js my-new-project/project.config.js
But as the number of files scales, this method will become less efficient. I was looking for a more efficient solution that would allow me to leverage the file that contains the list of files (or at least a script) without having to write a separate command for each one.
bash shell terminal
bash shell terminal
asked Nov 11 at 0:45
Mowzer
5,195639103
asked Nov 11 at 0:45
Mowzer
5,195639103
edited Nov 11 at 1:16
asked Nov 11 at 0:45
Mowzer
5,195639103
asked Nov 11 at 0:45
Mowzer
5,195639103
asked Nov 11 at 0:45
Mowzer
5,195639103
5,195639103
Maybe try usingrsync...
– l'L'l
Nov 11 at 0:47
Welcome to SO. Stack Overflow is a question and answer site for professional and enthusiast programmers. The goal is that you add some code of your own to your question to show at least the research effort you made to solve this yourself.
– Cyrus
Nov 11 at 0:50
add a comment |
Maybe try usingrsync...
– l'L'l
Nov 11 at 0:47
Welcome to SO. Stack Overflow is a question and answer site for professional and enthusiast programmers. The goal is that you add some code of your own to your question to show at least the research effort you made to solve this yourself.
– Cyrus
Nov 11 at 0:50
Maybe try using
rsync...– l'L'l
Nov 11 at 0:47
Maybe try using
rsync...– l'L'l
Nov 11 at 0:47
Welcome to SO. Stack Overflow is a question and answer site for professional and enthusiast programmers. The goal is that you add some code of your own to your question to show at least the research effort you made to solve this yourself.
– Cyrus
Nov 11 at 0:50
Welcome to SO. Stack Overflow is a question and answer site for professional and enthusiast programmers. The goal is that you add some code of your own to your question to show at least the research effort you made to solve this yourself.
– Cyrus
Nov 11 at 0:50
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
Assuming my-project and my-new-project are on the same directory:
xargs -i -a my-new-project/my-files-to-copy.txt cp my-project/{} my-new-project/{}
answered Nov 11 at 1:51
ssemilla
2,282421
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Assuming my-project and my-new-project are on the same directory:
xargs -i -a my-new-project/my-files-to-copy.txt cp my-project/{} my-new-project/{}
answered Nov 11 at 1:51
ssemilla
2,282421
add a comment |
up vote
0
down vote
Assuming my-project and my-new-project are on the same directory:
xargs -i -a my-new-project/my-files-to-copy.txt cp my-project/{} my-new-project/{}
answered Nov 11 at 1:51
ssemilla
2,282421
add a comment |
up vote
0
down vote
up vote
0
down vote
Assuming my-project and my-new-project are on the same directory:
xargs -i -a my-new-project/my-files-to-copy.txt cp my-project/{} my-new-project/{}
answered Nov 11 at 1:51
ssemilla
2,282421
Assuming my-project and my-new-project are on the same directory:
xargs -i -a my-new-project/my-files-to-copy.txt cp my-project/{} my-new-project/{}
answered Nov 11 at 1:51
ssemilla
2,282421
answered Nov 11 at 1:51
ssemilla
2,282421
answered Nov 11 at 1:51
ssemilla
2,282421
answered Nov 11 at 1:51
ssemilla
2,282421
2,282421
add a comment |
add a comment |
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Maybe try using
rsync...– l'L'l
Nov 11 at 0:47
Welcome to SO. Stack Overflow is a question and answer site for professional and enthusiast programmers. The goal is that you add some code of your own to your question to show at least the research effort you made to solve this yourself.
– Cyrus
Nov 11 at 0:50