How do I make a webpage think its images are done loading?











up vote
4
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To give you some background, many (if not all) websites load their images one by one, so if there are a lot of images, and/or you have a slow computer, most of the images wont show up. This is avoidable for the most part, however if you're running a script to exact image URLs, then you don't need to see the image, you just want its URL. My question is as follows:



Is it possible to trick a webpage into thinking an image is done loading so that it will start loading the next one?










share|improve this question






















  • You should scrape only the web page HTML and load it in a DOM parser utility. This should be done in a command line application and not in browser...
    – Niloct
    Nov 5 at 19:28










  • What is the purpose? Do you want the images take the place it should take even if it didn't yet completely load?
    – A. Meshu
    Nov 5 at 19:32










  • I want to extract the image URLs into a text file.
    – Jack Kasbrack
    Nov 5 at 20:20










  • This doesn't make much sense. Can you provide the link to the website in question?
    – Unglückspilz
    Nov 12 at 11:50















up vote
4
down vote

favorite












To give you some background, many (if not all) websites load their images one by one, so if there are a lot of images, and/or you have a slow computer, most of the images wont show up. This is avoidable for the most part, however if you're running a script to exact image URLs, then you don't need to see the image, you just want its URL. My question is as follows:



Is it possible to trick a webpage into thinking an image is done loading so that it will start loading the next one?










share|improve this question






















  • You should scrape only the web page HTML and load it in a DOM parser utility. This should be done in a command line application and not in browser...
    – Niloct
    Nov 5 at 19:28










  • What is the purpose? Do you want the images take the place it should take even if it didn't yet completely load?
    – A. Meshu
    Nov 5 at 19:32










  • I want to extract the image URLs into a text file.
    – Jack Kasbrack
    Nov 5 at 20:20










  • This doesn't make much sense. Can you provide the link to the website in question?
    – Unglückspilz
    Nov 12 at 11:50













up vote
4
down vote

favorite









up vote
4
down vote

favorite











To give you some background, many (if not all) websites load their images one by one, so if there are a lot of images, and/or you have a slow computer, most of the images wont show up. This is avoidable for the most part, however if you're running a script to exact image URLs, then you don't need to see the image, you just want its URL. My question is as follows:



Is it possible to trick a webpage into thinking an image is done loading so that it will start loading the next one?










share|improve this question













To give you some background, many (if not all) websites load their images one by one, so if there are a lot of images, and/or you have a slow computer, most of the images wont show up. This is avoidable for the most part, however if you're running a script to exact image URLs, then you don't need to see the image, you just want its URL. My question is as follows:



Is it possible to trick a webpage into thinking an image is done loading so that it will start loading the next one?







javascript image loading






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 5 at 19:03









Jack Kasbrack

13814




13814












  • You should scrape only the web page HTML and load it in a DOM parser utility. This should be done in a command line application and not in browser...
    – Niloct
    Nov 5 at 19:28










  • What is the purpose? Do you want the images take the place it should take even if it didn't yet completely load?
    – A. Meshu
    Nov 5 at 19:32










  • I want to extract the image URLs into a text file.
    – Jack Kasbrack
    Nov 5 at 20:20










  • This doesn't make much sense. Can you provide the link to the website in question?
    – Unglückspilz
    Nov 12 at 11:50


















  • You should scrape only the web page HTML and load it in a DOM parser utility. This should be done in a command line application and not in browser...
    – Niloct
    Nov 5 at 19:28










  • What is the purpose? Do you want the images take the place it should take even if it didn't yet completely load?
    – A. Meshu
    Nov 5 at 19:32










  • I want to extract the image URLs into a text file.
    – Jack Kasbrack
    Nov 5 at 20:20










  • This doesn't make much sense. Can you provide the link to the website in question?
    – Unglückspilz
    Nov 12 at 11:50
















You should scrape only the web page HTML and load it in a DOM parser utility. This should be done in a command line application and not in browser...
– Niloct
Nov 5 at 19:28




You should scrape only the web page HTML and load it in a DOM parser utility. This should be done in a command line application and not in browser...
– Niloct
Nov 5 at 19:28












What is the purpose? Do you want the images take the place it should take even if it didn't yet completely load?
– A. Meshu
Nov 5 at 19:32




What is the purpose? Do you want the images take the place it should take even if it didn't yet completely load?
– A. Meshu
Nov 5 at 19:32












I want to extract the image URLs into a text file.
– Jack Kasbrack
Nov 5 at 20:20




I want to extract the image URLs into a text file.
– Jack Kasbrack
Nov 5 at 20:20












This doesn't make much sense. Can you provide the link to the website in question?
– Unglückspilz
Nov 12 at 11:50




This doesn't make much sense. Can you provide the link to the website in question?
– Unglückspilz
Nov 12 at 11:50












6 Answers
6






active

oldest

votes

















up vote
1
down vote



accepted










use a plugin called lazy load. what it does is it will load the whole webpage and will just load the image later on. it will only load the image when the user scroll on it.






share|improve this answer





















  • do you have a link?
    – Jack Kasbrack
    Nov 17 at 22:41










  • check this link, ive used it before, very simple to implement: jquery.eisbehr.de/lazy
    – kapitan
    Nov 18 at 11:41












  • is this a chrome extension? how do I set it up?
    – Jack Kasbrack
    Nov 18 at 17:57










  • you just have to download and include the js file (jquery.lazy.min.js) on your webpage, then give all of your images a class (example: <img src='' class='lazyimg' />) then put this inside the script tag $(function() { $('.lazyimg').lazy(); }); - you also need jquery of course =)
    – kapitan
    Nov 19 at 1:03






  • 1




    oh, apologies, now i understand. then you should use the Chrome extension i am using for that exact purpose. search for "Text Mode", it's a google chrome extension. what it does is that it simply doesnt load any images of any webpage. i used this at work so that i can browse any website more safely.
    – kapitan
    Nov 21 at 0:17


















up vote
5
down vote



+25










Typically browser will not wait for one image to be downloaded before requesting the next image. It will request all images simultaneously, as soon as it gets the srcs of those images.



Are you sure that the images are indeed waiting for previous image to download or are they waiting for a specific time interval?



In case if you are sure that it depends on download of previous image, then what you can do is, route all your requests through some proxy server / firewall and configure it to return an empty file with HTTP status 200 whenever an image is requested from that site.



That way the browser (or actually the website code) will assume that it has downloaded the image successfully.




how do I do that? – Jack Kasbrack




That's actually a very open ended / opinion based question. It will also depend on your OS, browser, system permissions etc. Assuming you are using Windows and have sufficient permissions, you can try using Fiddler. It has an AutoResponder functionality that you can use.



(I've no affiliation with Fiddler / Telerik as such. I'm suggesting it only as an example and because I've used it in the past and know that it can be used for the aforementioned purpose. There will be many more products that provide similar functionality and you should use the product of your choice.)






share|improve this answer























  • how do I do that?
    – Jack Kasbrack
    Nov 12 at 15:48






  • 1




    @JackKasbrack Updated my answer.
    – Vivek Athalye
    Nov 13 at 15:53










  • Okay, I will try it tomorrow. Thank you for your time.
    – Jack Kasbrack
    Nov 14 at 2:19










  • it didn't work.
    – Jack Kasbrack
    Nov 15 at 14:33


















up vote
0
down vote













To extract all image URLs to a text file maybe you could use something like this,
If you execute this script inside any website it will list the URLs of the images



document.querySelectorAll('*[src]').forEach((item) => {
const isImage = item.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);

if (isImage) console.log(item.src);
});


You could also use the same idea to read Style from elements and get images from background url or something, like that:



document.querySelectorAll('*').forEach((item) => {
const computedItem = getComputedStyle(item);

Object.keys(computedItem).forEach((attr) => {
const style = computedItem[attr];
const image = style.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);
if (image) console.log(image[0]);
});
});


So, at the end of the day you could do some function like that, which will return an array of all images on the site



function getImageURLS() {
let images = ;
document.querySelectorAll('*').forEach((item) => {
const computedItem = getComputedStyle(item);

Object.keys(computedItem).forEach((attr) => {
const style = computedItem[attr];
const image = style.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);
if (image) images.push(image[0]);
});
});

document.querySelectorAll('*[src]').forEach((item) => {
const isImage = item.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);

if (isImage) images.push(item.src);
});
return images;
}


It can probably be optimized but, well you get the idea..






share|improve this answer























  • The issue is that the site I'm trying to get the images from doesn't load an image or it's URL until the previous one is done loading. I'm looking for a way to make the site think it's images are done loading, so that I can keep all the image URLs.
    – Jack Kasbrack
    Nov 11 at 21:22










  • yes, I get the idea, but if I try to run this code, or similar code before the page is done loading, I get a file called blank.gif.
    – Jack Kasbrack
    Nov 13 at 17:04


















up vote
0
down vote













If you just want to extract images once. You can use some tools like



1) Chrome Extension



2) Software



3) Online website



If you want to run it multiple times. Probably use the above code https://stackoverflow.com/a/53245330/4674358 wrapped in if condition






if(document.readyState === "complete") {
extractURL();
}
else {
//Add onload or DOMContentLoaded event listeners here: for example,
window.addEventListener("onload", function () {
extractURL();
}, false);
//or
/*document.addEventListener("DOMContentLoaded", function () {
extractURL();
}, false);*/
}

extractURL() {
//code mentioned above
}








share|improve this answer





















  • I created my own chrome extension to do it. The problem is that you can't extract images that aren't loaded
    – Jack Kasbrack
    Nov 15 at 23:45






  • 1




    You can very well get the full DOM in chrome extension. then parse it and load urls using above code.There is no need to wait for images to download. Check out stackoverflow.com/a/7641233/4674358
    – Shubham
    Nov 16 at 0:08


















up vote
0
down vote













You want the "DOMContentLoaded" event docs. It fires as soon as the document is fully parsed, but before everything has been loaded.



let addIfImage = (list, image) => image.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g) ?
[image.src, ...list] :
list;

let getSrcFromTags= (tag = 'img') => Array.from(document.getElementsByTagName(tag))
.reduce(addIfImage, );

if (document.readyState === "loading") {
document.addEventListener("DOMContentLoaded", doSomething);
} else { // `DOMContentLoaded` already fired
doSomething();
}





share|improve this answer























  • okay, I'll try that.
    – Jack Kasbrack
    Nov 16 at 14:34










  • nope. Still getting "blank.gif"
    – Jack Kasbrack
    Nov 18 at 21:38


















up vote
0
down vote













I am using this, works as expected:



var imageLoading = function(n) {
var image = document.images[n];
var downloadingImage = new Image();

downloadingImage.onload = function(){
image.src = this.src;
console.log('Image ' + n + ' loaded');

if (document.images[++n]) {
imageLoading(n);
}
};

downloadingImage.src = image.getAttribute("data-src");
}

document.addEventListener("DOMContentLoaded", function(event) {
setTimeout(function() {
imageLoading(0);
}, 0);
});


And change every src attribute of image element to data-src






share|improve this answer





















  • data-src is undefined
    – Jack Kasbrack
    Nov 18 at 21:44










  • Have you changed every src attribute of image element to data-src and is filled ?
    – ribrow
    Nov 20 at 13:18










  • none of them have a data-src attribute
    – Jack Kasbrack
    Nov 20 at 14:25










  • I said change them, or more specifically replace them...
    – ribrow
    Nov 20 at 15:30












  • There''s nothing to replace, it doesn't exist. Do I just add it?
    – Jack Kasbrack
    Nov 20 at 18:05











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6 Answers
6






active

oldest

votes








6 Answers
6






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










use a plugin called lazy load. what it does is it will load the whole webpage and will just load the image later on. it will only load the image when the user scroll on it.






share|improve this answer





















  • do you have a link?
    – Jack Kasbrack
    Nov 17 at 22:41










  • check this link, ive used it before, very simple to implement: jquery.eisbehr.de/lazy
    – kapitan
    Nov 18 at 11:41












  • is this a chrome extension? how do I set it up?
    – Jack Kasbrack
    Nov 18 at 17:57










  • you just have to download and include the js file (jquery.lazy.min.js) on your webpage, then give all of your images a class (example: <img src='' class='lazyimg' />) then put this inside the script tag $(function() { $('.lazyimg').lazy(); }); - you also need jquery of course =)
    – kapitan
    Nov 19 at 1:03






  • 1




    oh, apologies, now i understand. then you should use the Chrome extension i am using for that exact purpose. search for "Text Mode", it's a google chrome extension. what it does is that it simply doesnt load any images of any webpage. i used this at work so that i can browse any website more safely.
    – kapitan
    Nov 21 at 0:17















up vote
1
down vote



accepted










use a plugin called lazy load. what it does is it will load the whole webpage and will just load the image later on. it will only load the image when the user scroll on it.






share|improve this answer





















  • do you have a link?
    – Jack Kasbrack
    Nov 17 at 22:41










  • check this link, ive used it before, very simple to implement: jquery.eisbehr.de/lazy
    – kapitan
    Nov 18 at 11:41












  • is this a chrome extension? how do I set it up?
    – Jack Kasbrack
    Nov 18 at 17:57










  • you just have to download and include the js file (jquery.lazy.min.js) on your webpage, then give all of your images a class (example: <img src='' class='lazyimg' />) then put this inside the script tag $(function() { $('.lazyimg').lazy(); }); - you also need jquery of course =)
    – kapitan
    Nov 19 at 1:03






  • 1




    oh, apologies, now i understand. then you should use the Chrome extension i am using for that exact purpose. search for "Text Mode", it's a google chrome extension. what it does is that it simply doesnt load any images of any webpage. i used this at work so that i can browse any website more safely.
    – kapitan
    Nov 21 at 0:17













up vote
1
down vote



accepted







up vote
1
down vote



accepted






use a plugin called lazy load. what it does is it will load the whole webpage and will just load the image later on. it will only load the image when the user scroll on it.






share|improve this answer












use a plugin called lazy load. what it does is it will load the whole webpage and will just load the image later on. it will only load the image when the user scroll on it.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 17 at 14:28









kapitan

31819




31819












  • do you have a link?
    – Jack Kasbrack
    Nov 17 at 22:41










  • check this link, ive used it before, very simple to implement: jquery.eisbehr.de/lazy
    – kapitan
    Nov 18 at 11:41












  • is this a chrome extension? how do I set it up?
    – Jack Kasbrack
    Nov 18 at 17:57










  • you just have to download and include the js file (jquery.lazy.min.js) on your webpage, then give all of your images a class (example: <img src='' class='lazyimg' />) then put this inside the script tag $(function() { $('.lazyimg').lazy(); }); - you also need jquery of course =)
    – kapitan
    Nov 19 at 1:03






  • 1




    oh, apologies, now i understand. then you should use the Chrome extension i am using for that exact purpose. search for "Text Mode", it's a google chrome extension. what it does is that it simply doesnt load any images of any webpage. i used this at work so that i can browse any website more safely.
    – kapitan
    Nov 21 at 0:17


















  • do you have a link?
    – Jack Kasbrack
    Nov 17 at 22:41










  • check this link, ive used it before, very simple to implement: jquery.eisbehr.de/lazy
    – kapitan
    Nov 18 at 11:41












  • is this a chrome extension? how do I set it up?
    – Jack Kasbrack
    Nov 18 at 17:57










  • you just have to download and include the js file (jquery.lazy.min.js) on your webpage, then give all of your images a class (example: <img src='' class='lazyimg' />) then put this inside the script tag $(function() { $('.lazyimg').lazy(); }); - you also need jquery of course =)
    – kapitan
    Nov 19 at 1:03






  • 1




    oh, apologies, now i understand. then you should use the Chrome extension i am using for that exact purpose. search for "Text Mode", it's a google chrome extension. what it does is that it simply doesnt load any images of any webpage. i used this at work so that i can browse any website more safely.
    – kapitan
    Nov 21 at 0:17
















do you have a link?
– Jack Kasbrack
Nov 17 at 22:41




do you have a link?
– Jack Kasbrack
Nov 17 at 22:41












check this link, ive used it before, very simple to implement: jquery.eisbehr.de/lazy
– kapitan
Nov 18 at 11:41






check this link, ive used it before, very simple to implement: jquery.eisbehr.de/lazy
– kapitan
Nov 18 at 11:41














is this a chrome extension? how do I set it up?
– Jack Kasbrack
Nov 18 at 17:57




is this a chrome extension? how do I set it up?
– Jack Kasbrack
Nov 18 at 17:57












you just have to download and include the js file (jquery.lazy.min.js) on your webpage, then give all of your images a class (example: <img src='' class='lazyimg' />) then put this inside the script tag $(function() { $('.lazyimg').lazy(); }); - you also need jquery of course =)
– kapitan
Nov 19 at 1:03




you just have to download and include the js file (jquery.lazy.min.js) on your webpage, then give all of your images a class (example: <img src='' class='lazyimg' />) then put this inside the script tag $(function() { $('.lazyimg').lazy(); }); - you also need jquery of course =)
– kapitan
Nov 19 at 1:03




1




1




oh, apologies, now i understand. then you should use the Chrome extension i am using for that exact purpose. search for "Text Mode", it's a google chrome extension. what it does is that it simply doesnt load any images of any webpage. i used this at work so that i can browse any website more safely.
– kapitan
Nov 21 at 0:17




oh, apologies, now i understand. then you should use the Chrome extension i am using for that exact purpose. search for "Text Mode", it's a google chrome extension. what it does is that it simply doesnt load any images of any webpage. i used this at work so that i can browse any website more safely.
– kapitan
Nov 21 at 0:17












up vote
5
down vote



+25










Typically browser will not wait for one image to be downloaded before requesting the next image. It will request all images simultaneously, as soon as it gets the srcs of those images.



Are you sure that the images are indeed waiting for previous image to download or are they waiting for a specific time interval?



In case if you are sure that it depends on download of previous image, then what you can do is, route all your requests through some proxy server / firewall and configure it to return an empty file with HTTP status 200 whenever an image is requested from that site.



That way the browser (or actually the website code) will assume that it has downloaded the image successfully.




how do I do that? – Jack Kasbrack




That's actually a very open ended / opinion based question. It will also depend on your OS, browser, system permissions etc. Assuming you are using Windows and have sufficient permissions, you can try using Fiddler. It has an AutoResponder functionality that you can use.



(I've no affiliation with Fiddler / Telerik as such. I'm suggesting it only as an example and because I've used it in the past and know that it can be used for the aforementioned purpose. There will be many more products that provide similar functionality and you should use the product of your choice.)






share|improve this answer























  • how do I do that?
    – Jack Kasbrack
    Nov 12 at 15:48






  • 1




    @JackKasbrack Updated my answer.
    – Vivek Athalye
    Nov 13 at 15:53










  • Okay, I will try it tomorrow. Thank you for your time.
    – Jack Kasbrack
    Nov 14 at 2:19










  • it didn't work.
    – Jack Kasbrack
    Nov 15 at 14:33















up vote
5
down vote



+25










Typically browser will not wait for one image to be downloaded before requesting the next image. It will request all images simultaneously, as soon as it gets the srcs of those images.



Are you sure that the images are indeed waiting for previous image to download or are they waiting for a specific time interval?



In case if you are sure that it depends on download of previous image, then what you can do is, route all your requests through some proxy server / firewall and configure it to return an empty file with HTTP status 200 whenever an image is requested from that site.



That way the browser (or actually the website code) will assume that it has downloaded the image successfully.




how do I do that? – Jack Kasbrack




That's actually a very open ended / opinion based question. It will also depend on your OS, browser, system permissions etc. Assuming you are using Windows and have sufficient permissions, you can try using Fiddler. It has an AutoResponder functionality that you can use.



(I've no affiliation with Fiddler / Telerik as such. I'm suggesting it only as an example and because I've used it in the past and know that it can be used for the aforementioned purpose. There will be many more products that provide similar functionality and you should use the product of your choice.)






share|improve this answer























  • how do I do that?
    – Jack Kasbrack
    Nov 12 at 15:48






  • 1




    @JackKasbrack Updated my answer.
    – Vivek Athalye
    Nov 13 at 15:53










  • Okay, I will try it tomorrow. Thank you for your time.
    – Jack Kasbrack
    Nov 14 at 2:19










  • it didn't work.
    – Jack Kasbrack
    Nov 15 at 14:33













up vote
5
down vote



+25







up vote
5
down vote



+25




+25




Typically browser will not wait for one image to be downloaded before requesting the next image. It will request all images simultaneously, as soon as it gets the srcs of those images.



Are you sure that the images are indeed waiting for previous image to download or are they waiting for a specific time interval?



In case if you are sure that it depends on download of previous image, then what you can do is, route all your requests through some proxy server / firewall and configure it to return an empty file with HTTP status 200 whenever an image is requested from that site.



That way the browser (or actually the website code) will assume that it has downloaded the image successfully.




how do I do that? – Jack Kasbrack




That's actually a very open ended / opinion based question. It will also depend on your OS, browser, system permissions etc. Assuming you are using Windows and have sufficient permissions, you can try using Fiddler. It has an AutoResponder functionality that you can use.



(I've no affiliation with Fiddler / Telerik as such. I'm suggesting it only as an example and because I've used it in the past and know that it can be used for the aforementioned purpose. There will be many more products that provide similar functionality and you should use the product of your choice.)






share|improve this answer














Typically browser will not wait for one image to be downloaded before requesting the next image. It will request all images simultaneously, as soon as it gets the srcs of those images.



Are you sure that the images are indeed waiting for previous image to download or are they waiting for a specific time interval?



In case if you are sure that it depends on download of previous image, then what you can do is, route all your requests through some proxy server / firewall and configure it to return an empty file with HTTP status 200 whenever an image is requested from that site.



That way the browser (or actually the website code) will assume that it has downloaded the image successfully.




how do I do that? – Jack Kasbrack




That's actually a very open ended / opinion based question. It will also depend on your OS, browser, system permissions etc. Assuming you are using Windows and have sufficient permissions, you can try using Fiddler. It has an AutoResponder functionality that you can use.



(I've no affiliation with Fiddler / Telerik as such. I'm suggesting it only as an example and because I've used it in the past and know that it can be used for the aforementioned purpose. There will be many more products that provide similar functionality and you should use the product of your choice.)







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 13 at 15:52

























answered Nov 12 at 15:45









Vivek Athalye

2,50611629




2,50611629












  • how do I do that?
    – Jack Kasbrack
    Nov 12 at 15:48






  • 1




    @JackKasbrack Updated my answer.
    – Vivek Athalye
    Nov 13 at 15:53










  • Okay, I will try it tomorrow. Thank you for your time.
    – Jack Kasbrack
    Nov 14 at 2:19










  • it didn't work.
    – Jack Kasbrack
    Nov 15 at 14:33


















  • how do I do that?
    – Jack Kasbrack
    Nov 12 at 15:48






  • 1




    @JackKasbrack Updated my answer.
    – Vivek Athalye
    Nov 13 at 15:53










  • Okay, I will try it tomorrow. Thank you for your time.
    – Jack Kasbrack
    Nov 14 at 2:19










  • it didn't work.
    – Jack Kasbrack
    Nov 15 at 14:33
















how do I do that?
– Jack Kasbrack
Nov 12 at 15:48




how do I do that?
– Jack Kasbrack
Nov 12 at 15:48




1




1




@JackKasbrack Updated my answer.
– Vivek Athalye
Nov 13 at 15:53




@JackKasbrack Updated my answer.
– Vivek Athalye
Nov 13 at 15:53












Okay, I will try it tomorrow. Thank you for your time.
– Jack Kasbrack
Nov 14 at 2:19




Okay, I will try it tomorrow. Thank you for your time.
– Jack Kasbrack
Nov 14 at 2:19












it didn't work.
– Jack Kasbrack
Nov 15 at 14:33




it didn't work.
– Jack Kasbrack
Nov 15 at 14:33










up vote
0
down vote













To extract all image URLs to a text file maybe you could use something like this,
If you execute this script inside any website it will list the URLs of the images



document.querySelectorAll('*[src]').forEach((item) => {
const isImage = item.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);

if (isImage) console.log(item.src);
});


You could also use the same idea to read Style from elements and get images from background url or something, like that:



document.querySelectorAll('*').forEach((item) => {
const computedItem = getComputedStyle(item);

Object.keys(computedItem).forEach((attr) => {
const style = computedItem[attr];
const image = style.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);
if (image) console.log(image[0]);
});
});


So, at the end of the day you could do some function like that, which will return an array of all images on the site



function getImageURLS() {
let images = ;
document.querySelectorAll('*').forEach((item) => {
const computedItem = getComputedStyle(item);

Object.keys(computedItem).forEach((attr) => {
const style = computedItem[attr];
const image = style.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);
if (image) images.push(image[0]);
});
});

document.querySelectorAll('*[src]').forEach((item) => {
const isImage = item.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);

if (isImage) images.push(item.src);
});
return images;
}


It can probably be optimized but, well you get the idea..






share|improve this answer























  • The issue is that the site I'm trying to get the images from doesn't load an image or it's URL until the previous one is done loading. I'm looking for a way to make the site think it's images are done loading, so that I can keep all the image URLs.
    – Jack Kasbrack
    Nov 11 at 21:22










  • yes, I get the idea, but if I try to run this code, or similar code before the page is done loading, I get a file called blank.gif.
    – Jack Kasbrack
    Nov 13 at 17:04















up vote
0
down vote













To extract all image URLs to a text file maybe you could use something like this,
If you execute this script inside any website it will list the URLs of the images



document.querySelectorAll('*[src]').forEach((item) => {
const isImage = item.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);

if (isImage) console.log(item.src);
});


You could also use the same idea to read Style from elements and get images from background url or something, like that:



document.querySelectorAll('*').forEach((item) => {
const computedItem = getComputedStyle(item);

Object.keys(computedItem).forEach((attr) => {
const style = computedItem[attr];
const image = style.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);
if (image) console.log(image[0]);
});
});


So, at the end of the day you could do some function like that, which will return an array of all images on the site



function getImageURLS() {
let images = ;
document.querySelectorAll('*').forEach((item) => {
const computedItem = getComputedStyle(item);

Object.keys(computedItem).forEach((attr) => {
const style = computedItem[attr];
const image = style.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);
if (image) images.push(image[0]);
});
});

document.querySelectorAll('*[src]').forEach((item) => {
const isImage = item.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);

if (isImage) images.push(item.src);
});
return images;
}


It can probably be optimized but, well you get the idea..






share|improve this answer























  • The issue is that the site I'm trying to get the images from doesn't load an image or it's URL until the previous one is done loading. I'm looking for a way to make the site think it's images are done loading, so that I can keep all the image URLs.
    – Jack Kasbrack
    Nov 11 at 21:22










  • yes, I get the idea, but if I try to run this code, or similar code before the page is done loading, I get a file called blank.gif.
    – Jack Kasbrack
    Nov 13 at 17:04













up vote
0
down vote










up vote
0
down vote









To extract all image URLs to a text file maybe you could use something like this,
If you execute this script inside any website it will list the URLs of the images



document.querySelectorAll('*[src]').forEach((item) => {
const isImage = item.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);

if (isImage) console.log(item.src);
});


You could also use the same idea to read Style from elements and get images from background url or something, like that:



document.querySelectorAll('*').forEach((item) => {
const computedItem = getComputedStyle(item);

Object.keys(computedItem).forEach((attr) => {
const style = computedItem[attr];
const image = style.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);
if (image) console.log(image[0]);
});
});


So, at the end of the day you could do some function like that, which will return an array of all images on the site



function getImageURLS() {
let images = ;
document.querySelectorAll('*').forEach((item) => {
const computedItem = getComputedStyle(item);

Object.keys(computedItem).forEach((attr) => {
const style = computedItem[attr];
const image = style.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);
if (image) images.push(image[0]);
});
});

document.querySelectorAll('*[src]').forEach((item) => {
const isImage = item.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);

if (isImage) images.push(item.src);
});
return images;
}


It can probably be optimized but, well you get the idea..






share|improve this answer














To extract all image URLs to a text file maybe you could use something like this,
If you execute this script inside any website it will list the URLs of the images



document.querySelectorAll('*[src]').forEach((item) => {
const isImage = item.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);

if (isImage) console.log(item.src);
});


You could also use the same idea to read Style from elements and get images from background url or something, like that:



document.querySelectorAll('*').forEach((item) => {
const computedItem = getComputedStyle(item);

Object.keys(computedItem).forEach((attr) => {
const style = computedItem[attr];
const image = style.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);
if (image) console.log(image[0]);
});
});


So, at the end of the day you could do some function like that, which will return an array of all images on the site



function getImageURLS() {
let images = ;
document.querySelectorAll('*').forEach((item) => {
const computedItem = getComputedStyle(item);

Object.keys(computedItem).forEach((attr) => {
const style = computedItem[attr];
const image = style.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);
if (image) images.push(image[0]);
});
});

document.querySelectorAll('*[src]').forEach((item) => {
const isImage = item.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g);

if (isImage) images.push(item.src);
});
return images;
}


It can probably be optimized but, well you get the idea..







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 11 at 2:52

























answered Nov 11 at 2:27









el Corleone

11




11












  • The issue is that the site I'm trying to get the images from doesn't load an image or it's URL until the previous one is done loading. I'm looking for a way to make the site think it's images are done loading, so that I can keep all the image URLs.
    – Jack Kasbrack
    Nov 11 at 21:22










  • yes, I get the idea, but if I try to run this code, or similar code before the page is done loading, I get a file called blank.gif.
    – Jack Kasbrack
    Nov 13 at 17:04


















  • The issue is that the site I'm trying to get the images from doesn't load an image or it's URL until the previous one is done loading. I'm looking for a way to make the site think it's images are done loading, so that I can keep all the image URLs.
    – Jack Kasbrack
    Nov 11 at 21:22










  • yes, I get the idea, but if I try to run this code, or similar code before the page is done loading, I get a file called blank.gif.
    – Jack Kasbrack
    Nov 13 at 17:04
















The issue is that the site I'm trying to get the images from doesn't load an image or it's URL until the previous one is done loading. I'm looking for a way to make the site think it's images are done loading, so that I can keep all the image URLs.
– Jack Kasbrack
Nov 11 at 21:22




The issue is that the site I'm trying to get the images from doesn't load an image or it's URL until the previous one is done loading. I'm looking for a way to make the site think it's images are done loading, so that I can keep all the image URLs.
– Jack Kasbrack
Nov 11 at 21:22












yes, I get the idea, but if I try to run this code, or similar code before the page is done loading, I get a file called blank.gif.
– Jack Kasbrack
Nov 13 at 17:04




yes, I get the idea, but if I try to run this code, or similar code before the page is done loading, I get a file called blank.gif.
– Jack Kasbrack
Nov 13 at 17:04










up vote
0
down vote













If you just want to extract images once. You can use some tools like



1) Chrome Extension



2) Software



3) Online website



If you want to run it multiple times. Probably use the above code https://stackoverflow.com/a/53245330/4674358 wrapped in if condition






if(document.readyState === "complete") {
extractURL();
}
else {
//Add onload or DOMContentLoaded event listeners here: for example,
window.addEventListener("onload", function () {
extractURL();
}, false);
//or
/*document.addEventListener("DOMContentLoaded", function () {
extractURL();
}, false);*/
}

extractURL() {
//code mentioned above
}








share|improve this answer





















  • I created my own chrome extension to do it. The problem is that you can't extract images that aren't loaded
    – Jack Kasbrack
    Nov 15 at 23:45






  • 1




    You can very well get the full DOM in chrome extension. then parse it and load urls using above code.There is no need to wait for images to download. Check out stackoverflow.com/a/7641233/4674358
    – Shubham
    Nov 16 at 0:08















up vote
0
down vote













If you just want to extract images once. You can use some tools like



1) Chrome Extension



2) Software



3) Online website



If you want to run it multiple times. Probably use the above code https://stackoverflow.com/a/53245330/4674358 wrapped in if condition






if(document.readyState === "complete") {
extractURL();
}
else {
//Add onload or DOMContentLoaded event listeners here: for example,
window.addEventListener("onload", function () {
extractURL();
}, false);
//or
/*document.addEventListener("DOMContentLoaded", function () {
extractURL();
}, false);*/
}

extractURL() {
//code mentioned above
}








share|improve this answer





















  • I created my own chrome extension to do it. The problem is that you can't extract images that aren't loaded
    – Jack Kasbrack
    Nov 15 at 23:45






  • 1




    You can very well get the full DOM in chrome extension. then parse it and load urls using above code.There is no need to wait for images to download. Check out stackoverflow.com/a/7641233/4674358
    – Shubham
    Nov 16 at 0:08













up vote
0
down vote










up vote
0
down vote









If you just want to extract images once. You can use some tools like



1) Chrome Extension



2) Software



3) Online website



If you want to run it multiple times. Probably use the above code https://stackoverflow.com/a/53245330/4674358 wrapped in if condition






if(document.readyState === "complete") {
extractURL();
}
else {
//Add onload or DOMContentLoaded event listeners here: for example,
window.addEventListener("onload", function () {
extractURL();
}, false);
//or
/*document.addEventListener("DOMContentLoaded", function () {
extractURL();
}, false);*/
}

extractURL() {
//code mentioned above
}








share|improve this answer












If you just want to extract images once. You can use some tools like



1) Chrome Extension



2) Software



3) Online website



If you want to run it multiple times. Probably use the above code https://stackoverflow.com/a/53245330/4674358 wrapped in if condition






if(document.readyState === "complete") {
extractURL();
}
else {
//Add onload or DOMContentLoaded event listeners here: for example,
window.addEventListener("onload", function () {
extractURL();
}, false);
//or
/*document.addEventListener("DOMContentLoaded", function () {
extractURL();
}, false);*/
}

extractURL() {
//code mentioned above
}








if(document.readyState === "complete") {
extractURL();
}
else {
//Add onload or DOMContentLoaded event listeners here: for example,
window.addEventListener("onload", function () {
extractURL();
}, false);
//or
/*document.addEventListener("DOMContentLoaded", function () {
extractURL();
}, false);*/
}

extractURL() {
//code mentioned above
}





if(document.readyState === "complete") {
extractURL();
}
else {
//Add onload or DOMContentLoaded event listeners here: for example,
window.addEventListener("onload", function () {
extractURL();
}, false);
//or
/*document.addEventListener("DOMContentLoaded", function () {
extractURL();
}, false);*/
}

extractURL() {
//code mentioned above
}






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 15 at 23:01









Shubham

852622




852622












  • I created my own chrome extension to do it. The problem is that you can't extract images that aren't loaded
    – Jack Kasbrack
    Nov 15 at 23:45






  • 1




    You can very well get the full DOM in chrome extension. then parse it and load urls using above code.There is no need to wait for images to download. Check out stackoverflow.com/a/7641233/4674358
    – Shubham
    Nov 16 at 0:08


















  • I created my own chrome extension to do it. The problem is that you can't extract images that aren't loaded
    – Jack Kasbrack
    Nov 15 at 23:45






  • 1




    You can very well get the full DOM in chrome extension. then parse it and load urls using above code.There is no need to wait for images to download. Check out stackoverflow.com/a/7641233/4674358
    – Shubham
    Nov 16 at 0:08
















I created my own chrome extension to do it. The problem is that you can't extract images that aren't loaded
– Jack Kasbrack
Nov 15 at 23:45




I created my own chrome extension to do it. The problem is that you can't extract images that aren't loaded
– Jack Kasbrack
Nov 15 at 23:45




1




1




You can very well get the full DOM in chrome extension. then parse it and load urls using above code.There is no need to wait for images to download. Check out stackoverflow.com/a/7641233/4674358
– Shubham
Nov 16 at 0:08




You can very well get the full DOM in chrome extension. then parse it and load urls using above code.There is no need to wait for images to download. Check out stackoverflow.com/a/7641233/4674358
– Shubham
Nov 16 at 0:08










up vote
0
down vote













You want the "DOMContentLoaded" event docs. It fires as soon as the document is fully parsed, but before everything has been loaded.



let addIfImage = (list, image) => image.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g) ?
[image.src, ...list] :
list;

let getSrcFromTags= (tag = 'img') => Array.from(document.getElementsByTagName(tag))
.reduce(addIfImage, );

if (document.readyState === "loading") {
document.addEventListener("DOMContentLoaded", doSomething);
} else { // `DOMContentLoaded` already fired
doSomething();
}





share|improve this answer























  • okay, I'll try that.
    – Jack Kasbrack
    Nov 16 at 14:34










  • nope. Still getting "blank.gif"
    – Jack Kasbrack
    Nov 18 at 21:38















up vote
0
down vote













You want the "DOMContentLoaded" event docs. It fires as soon as the document is fully parsed, but before everything has been loaded.



let addIfImage = (list, image) => image.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g) ?
[image.src, ...list] :
list;

let getSrcFromTags= (tag = 'img') => Array.from(document.getElementsByTagName(tag))
.reduce(addIfImage, );

if (document.readyState === "loading") {
document.addEventListener("DOMContentLoaded", doSomething);
} else { // `DOMContentLoaded` already fired
doSomething();
}





share|improve this answer























  • okay, I'll try that.
    – Jack Kasbrack
    Nov 16 at 14:34










  • nope. Still getting "blank.gif"
    – Jack Kasbrack
    Nov 18 at 21:38













up vote
0
down vote










up vote
0
down vote









You want the "DOMContentLoaded" event docs. It fires as soon as the document is fully parsed, but before everything has been loaded.



let addIfImage = (list, image) => image.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g) ?
[image.src, ...list] :
list;

let getSrcFromTags= (tag = 'img') => Array.from(document.getElementsByTagName(tag))
.reduce(addIfImage, );

if (document.readyState === "loading") {
document.addEventListener("DOMContentLoaded", doSomething);
} else { // `DOMContentLoaded` already fired
doSomething();
}





share|improve this answer














You want the "DOMContentLoaded" event docs. It fires as soon as the document is fully parsed, but before everything has been loaded.



let addIfImage = (list, image) => image.src.match(/(http(s?):)([/|.|w|s|-])*.(?:jpg|jpeg|gif|png|svg)/g) ?
[image.src, ...list] :
list;

let getSrcFromTags= (tag = 'img') => Array.from(document.getElementsByTagName(tag))
.reduce(addIfImage, );

if (document.readyState === "loading") {
document.addEventListener("DOMContentLoaded", doSomething);
} else { // `DOMContentLoaded` already fired
doSomething();
}






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 16 at 7:33

























answered Nov 16 at 7:27









Malisbad

543




543












  • okay, I'll try that.
    – Jack Kasbrack
    Nov 16 at 14:34










  • nope. Still getting "blank.gif"
    – Jack Kasbrack
    Nov 18 at 21:38


















  • okay, I'll try that.
    – Jack Kasbrack
    Nov 16 at 14:34










  • nope. Still getting "blank.gif"
    – Jack Kasbrack
    Nov 18 at 21:38
















okay, I'll try that.
– Jack Kasbrack
Nov 16 at 14:34




okay, I'll try that.
– Jack Kasbrack
Nov 16 at 14:34












nope. Still getting "blank.gif"
– Jack Kasbrack
Nov 18 at 21:38




nope. Still getting "blank.gif"
– Jack Kasbrack
Nov 18 at 21:38










up vote
0
down vote













I am using this, works as expected:



var imageLoading = function(n) {
var image = document.images[n];
var downloadingImage = new Image();

downloadingImage.onload = function(){
image.src = this.src;
console.log('Image ' + n + ' loaded');

if (document.images[++n]) {
imageLoading(n);
}
};

downloadingImage.src = image.getAttribute("data-src");
}

document.addEventListener("DOMContentLoaded", function(event) {
setTimeout(function() {
imageLoading(0);
}, 0);
});


And change every src attribute of image element to data-src






share|improve this answer





















  • data-src is undefined
    – Jack Kasbrack
    Nov 18 at 21:44










  • Have you changed every src attribute of image element to data-src and is filled ?
    – ribrow
    Nov 20 at 13:18










  • none of them have a data-src attribute
    – Jack Kasbrack
    Nov 20 at 14:25










  • I said change them, or more specifically replace them...
    – ribrow
    Nov 20 at 15:30












  • There''s nothing to replace, it doesn't exist. Do I just add it?
    – Jack Kasbrack
    Nov 20 at 18:05















up vote
0
down vote













I am using this, works as expected:



var imageLoading = function(n) {
var image = document.images[n];
var downloadingImage = new Image();

downloadingImage.onload = function(){
image.src = this.src;
console.log('Image ' + n + ' loaded');

if (document.images[++n]) {
imageLoading(n);
}
};

downloadingImage.src = image.getAttribute("data-src");
}

document.addEventListener("DOMContentLoaded", function(event) {
setTimeout(function() {
imageLoading(0);
}, 0);
});


And change every src attribute of image element to data-src






share|improve this answer





















  • data-src is undefined
    – Jack Kasbrack
    Nov 18 at 21:44










  • Have you changed every src attribute of image element to data-src and is filled ?
    – ribrow
    Nov 20 at 13:18










  • none of them have a data-src attribute
    – Jack Kasbrack
    Nov 20 at 14:25










  • I said change them, or more specifically replace them...
    – ribrow
    Nov 20 at 15:30












  • There''s nothing to replace, it doesn't exist. Do I just add it?
    – Jack Kasbrack
    Nov 20 at 18:05













up vote
0
down vote










up vote
0
down vote









I am using this, works as expected:



var imageLoading = function(n) {
var image = document.images[n];
var downloadingImage = new Image();

downloadingImage.onload = function(){
image.src = this.src;
console.log('Image ' + n + ' loaded');

if (document.images[++n]) {
imageLoading(n);
}
};

downloadingImage.src = image.getAttribute("data-src");
}

document.addEventListener("DOMContentLoaded", function(event) {
setTimeout(function() {
imageLoading(0);
}, 0);
});


And change every src attribute of image element to data-src






share|improve this answer












I am using this, works as expected:



var imageLoading = function(n) {
var image = document.images[n];
var downloadingImage = new Image();

downloadingImage.onload = function(){
image.src = this.src;
console.log('Image ' + n + ' loaded');

if (document.images[++n]) {
imageLoading(n);
}
};

downloadingImage.src = image.getAttribute("data-src");
}

document.addEventListener("DOMContentLoaded", function(event) {
setTimeout(function() {
imageLoading(0);
}, 0);
});


And change every src attribute of image element to data-src







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 17 at 10:53









ribrow

1




1












  • data-src is undefined
    – Jack Kasbrack
    Nov 18 at 21:44










  • Have you changed every src attribute of image element to data-src and is filled ?
    – ribrow
    Nov 20 at 13:18










  • none of them have a data-src attribute
    – Jack Kasbrack
    Nov 20 at 14:25










  • I said change them, or more specifically replace them...
    – ribrow
    Nov 20 at 15:30












  • There''s nothing to replace, it doesn't exist. Do I just add it?
    – Jack Kasbrack
    Nov 20 at 18:05


















  • data-src is undefined
    – Jack Kasbrack
    Nov 18 at 21:44










  • Have you changed every src attribute of image element to data-src and is filled ?
    – ribrow
    Nov 20 at 13:18










  • none of them have a data-src attribute
    – Jack Kasbrack
    Nov 20 at 14:25










  • I said change them, or more specifically replace them...
    – ribrow
    Nov 20 at 15:30












  • There''s nothing to replace, it doesn't exist. Do I just add it?
    – Jack Kasbrack
    Nov 20 at 18:05
















data-src is undefined
– Jack Kasbrack
Nov 18 at 21:44




data-src is undefined
– Jack Kasbrack
Nov 18 at 21:44












Have you changed every src attribute of image element to data-src and is filled ?
– ribrow
Nov 20 at 13:18




Have you changed every src attribute of image element to data-src and is filled ?
– ribrow
Nov 20 at 13:18












none of them have a data-src attribute
– Jack Kasbrack
Nov 20 at 14:25




none of them have a data-src attribute
– Jack Kasbrack
Nov 20 at 14:25












I said change them, or more specifically replace them...
– ribrow
Nov 20 at 15:30






I said change them, or more specifically replace them...
– ribrow
Nov 20 at 15:30














There''s nothing to replace, it doesn't exist. Do I just add it?
– Jack Kasbrack
Nov 20 at 18:05




There''s nothing to replace, it doesn't exist. Do I just add it?
– Jack Kasbrack
Nov 20 at 18:05


















 

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