Plot asymptote in grotwth curve in R
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How can I plot the line asymptote off this curve above?
# Create Data
Conc <- c(0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000)
Response <- c(167.11246201, 53.96960486, 128.42857143, 43.67173252, 4.51975684, 0.34042553, 120.10334347, 101.14589666, 155.17629179, 35.31306991, 8.56534954, 1.71124620, 146.34954407, 108.50151976, 163.60182371, 64.70212766, 2.88145897, 0.50759878, 82.92401216, 109.80547112, 116.69300912, 26.85410334, 3.01519757, 0.37386018, 87.06990881, 84.82978723, 118.36474164, 27.52279635, 2.34650456, 0.10638298, 89.47720365, 109.47112462, 85.43161094, 17.69300912, 2.31306991, 0.07294833)
df <- data.frame(Conc = Conc, Response = Response)
#Make Modell
library(drc)
#adjust model
drm <- drm(Response ~ Conc, data = df, fct = LL.4())
#plot
plot(drm)
This is an exemple of what I mean?
enter image description here
r math statistics
add a comment |
How can I plot the line asymptote off this curve above?
# Create Data
Conc <- c(0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000)
Response <- c(167.11246201, 53.96960486, 128.42857143, 43.67173252, 4.51975684, 0.34042553, 120.10334347, 101.14589666, 155.17629179, 35.31306991, 8.56534954, 1.71124620, 146.34954407, 108.50151976, 163.60182371, 64.70212766, 2.88145897, 0.50759878, 82.92401216, 109.80547112, 116.69300912, 26.85410334, 3.01519757, 0.37386018, 87.06990881, 84.82978723, 118.36474164, 27.52279635, 2.34650456, 0.10638298, 89.47720365, 109.47112462, 85.43161094, 17.69300912, 2.31306991, 0.07294833)
df <- data.frame(Conc = Conc, Response = Response)
#Make Modell
library(drc)
#adjust model
drm <- drm(Response ~ Conc, data = df, fct = LL.4())
#plot
plot(drm)
This is an exemple of what I mean?
enter image description here
r math statistics
tryabline
witha= asymptote
andb=0
– Jrakru56
Nov 16 '18 at 14:48
Unfortunately it did not work, that is the mensagem: Error in abline(a = asymptote, b = 0) : object 'asymptote' not found
– Vitor Muller Anunciato
Nov 16 '18 at 14:57
Sorry, I was not clear. I meant assign the value of the asymptote to the parametera
. See below
– Jrakru56
Nov 16 '18 at 15:00
add a comment |
How can I plot the line asymptote off this curve above?
# Create Data
Conc <- c(0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000)
Response <- c(167.11246201, 53.96960486, 128.42857143, 43.67173252, 4.51975684, 0.34042553, 120.10334347, 101.14589666, 155.17629179, 35.31306991, 8.56534954, 1.71124620, 146.34954407, 108.50151976, 163.60182371, 64.70212766, 2.88145897, 0.50759878, 82.92401216, 109.80547112, 116.69300912, 26.85410334, 3.01519757, 0.37386018, 87.06990881, 84.82978723, 118.36474164, 27.52279635, 2.34650456, 0.10638298, 89.47720365, 109.47112462, 85.43161094, 17.69300912, 2.31306991, 0.07294833)
df <- data.frame(Conc = Conc, Response = Response)
#Make Modell
library(drc)
#adjust model
drm <- drm(Response ~ Conc, data = df, fct = LL.4())
#plot
plot(drm)
This is an exemple of what I mean?
enter image description here
r math statistics
How can I plot the line asymptote off this curve above?
# Create Data
Conc <- c(0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000, 0.03125, 0.06250, 0.12500, 0.25000, 0.50000, 1.00000)
Response <- c(167.11246201, 53.96960486, 128.42857143, 43.67173252, 4.51975684, 0.34042553, 120.10334347, 101.14589666, 155.17629179, 35.31306991, 8.56534954, 1.71124620, 146.34954407, 108.50151976, 163.60182371, 64.70212766, 2.88145897, 0.50759878, 82.92401216, 109.80547112, 116.69300912, 26.85410334, 3.01519757, 0.37386018, 87.06990881, 84.82978723, 118.36474164, 27.52279635, 2.34650456, 0.10638298, 89.47720365, 109.47112462, 85.43161094, 17.69300912, 2.31306991, 0.07294833)
df <- data.frame(Conc = Conc, Response = Response)
#Make Modell
library(drc)
#adjust model
drm <- drm(Response ~ Conc, data = df, fct = LL.4())
#plot
plot(drm)
This is an exemple of what I mean?
enter image description here
r math statistics
r math statistics
asked Nov 16 '18 at 14:34
Vitor Muller AnunciatoVitor Muller Anunciato
54
54
tryabline
witha= asymptote
andb=0
– Jrakru56
Nov 16 '18 at 14:48
Unfortunately it did not work, that is the mensagem: Error in abline(a = asymptote, b = 0) : object 'asymptote' not found
– Vitor Muller Anunciato
Nov 16 '18 at 14:57
Sorry, I was not clear. I meant assign the value of the asymptote to the parametera
. See below
– Jrakru56
Nov 16 '18 at 15:00
add a comment |
tryabline
witha= asymptote
andb=0
– Jrakru56
Nov 16 '18 at 14:48
Unfortunately it did not work, that is the mensagem: Error in abline(a = asymptote, b = 0) : object 'asymptote' not found
– Vitor Muller Anunciato
Nov 16 '18 at 14:57
Sorry, I was not clear. I meant assign the value of the asymptote to the parametera
. See below
– Jrakru56
Nov 16 '18 at 15:00
try
abline
with a= asymptote
and b=0
– Jrakru56
Nov 16 '18 at 14:48
try
abline
with a= asymptote
and b=0
– Jrakru56
Nov 16 '18 at 14:48
Unfortunately it did not work, that is the mensagem: Error in abline(a = asymptote, b = 0) : object 'asymptote' not found
– Vitor Muller Anunciato
Nov 16 '18 at 14:57
Unfortunately it did not work, that is the mensagem: Error in abline(a = asymptote, b = 0) : object 'asymptote' not found
– Vitor Muller Anunciato
Nov 16 '18 at 14:57
Sorry, I was not clear. I meant assign the value of the asymptote to the parameter
a
. See below– Jrakru56
Nov 16 '18 at 15:00
Sorry, I was not clear. I meant assign the value of the asymptote to the parameter
a
. See below– Jrakru56
Nov 16 '18 at 15:00
add a comment |
3 Answers
3
active
oldest
votes
I am not sure what is the right way here, but I usually do it like this:
Logistic funtion
Still don't know how to use LL.4()
for this purpose
flogis <- function(x, b, c, d, e){
c + (d - c)/(1 + exp(b*(log(x) - log(e))))
}
Dataset
Make some example data:
dose <- rep(exp(seq(-5, 5, length.out = 10)), each = 3)
dat <- data.frame(
dose = dose,
response = flogis(dose, -1, 0, 1, .5) + rnorm(length(dose), 0, .05)
)
head(dat)
# dose response
#1 0.006737947 0.01310683
#2 0.006737947 0.08292573
#3 0.006737947 0.03263079
#4 0.020468076 0.02763111
#5 0.020468076 0.01934260
#6 0.020468076 0.01296994
Fitting 4-parameters log-logistic model
library(drc)
model <- drm(response ~ dose, data = dat, fct = LL.4())
summary(model)
#Model fitted: Log-logistic (ED50 as parameter) (4 parms)
#
#Parameter estimates:
#
# Estimate Std. Error t-value p-value
#b:(Intercept) -1.0012680 0.0887792 -11.2782 1.637e-11 ***
#c:(Intercept) 0.0049506 0.0243151 0.2036 0.8402
#d:(Intercept) 0.9889417 0.0163848 60.3573 < 2.2e-16 ***
#e:(Intercept) 0.4054848 0.0419639 9.6627 4.310e-10 ***
#---
#Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
#
#Residual standard error:
#
#0.04466107 (26 degrees of freedom)
Grab model parameters for use with ggplot
coefs <- setNames(coef(model), c("b", "c", "d", "e"))
y50 <- predict(model, newdata = data.frame(dose = coefs["e"]))
Plot data
(Sorry, have no time to play with text labels, and don't understand what phi2 + phi3
means on the example plot, but pretty sure that is something which is going on around EC50)
ggplot(dat, aes(x = dose, y = response)) +
stat_function(fun = function(x, b, c, d, e){
c + (d - c)/(1 + exp(b*(log(x) - log(e))))
}, args = coefs, col = "skyblue", lwd = 1) +
geom_point(pch = 21, fill = "white") +
geom_hline(yintercept = coefs[c("c", "d")], lty = 2, colour = "gray50") +
geom_segment(aes(x = coefs["e"], y = 0, xend = coefs["e"], yend = y50),
lty = 2, colour = "gray50") +
geom_segment(aes(x = coefs["e"], y = y50, xend = 0, yend = y50),
lty = 2, colour = "gray50") +
scale_x_log10(
breaks = scales::trans_breaks("log10", function(x) 10^x),
labels = scales::trans_format("log10", scales::math_format(10^.x))
) +
annotation_logticks(sides = "b") +
labs(x = "Dose",
y = "Response"
) +
expand_limits(y = 1) +
ggthemes::theme_few()
add a comment |
try this :
library(drc)
#adjust model
drm <- drm(Response ~ Conc, data = df, fct = LL.4())
#plot
plot(drm)
abline(a=112.6868 , 0)
add a comment |
You can extract the value of the asymptote from the drm
object:
asymptote <- coef(drm)[3]
This value can be used for plotting:
plot(drm)
abline(asymptote, 0)
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
I am not sure what is the right way here, but I usually do it like this:
Logistic funtion
Still don't know how to use LL.4()
for this purpose
flogis <- function(x, b, c, d, e){
c + (d - c)/(1 + exp(b*(log(x) - log(e))))
}
Dataset
Make some example data:
dose <- rep(exp(seq(-5, 5, length.out = 10)), each = 3)
dat <- data.frame(
dose = dose,
response = flogis(dose, -1, 0, 1, .5) + rnorm(length(dose), 0, .05)
)
head(dat)
# dose response
#1 0.006737947 0.01310683
#2 0.006737947 0.08292573
#3 0.006737947 0.03263079
#4 0.020468076 0.02763111
#5 0.020468076 0.01934260
#6 0.020468076 0.01296994
Fitting 4-parameters log-logistic model
library(drc)
model <- drm(response ~ dose, data = dat, fct = LL.4())
summary(model)
#Model fitted: Log-logistic (ED50 as parameter) (4 parms)
#
#Parameter estimates:
#
# Estimate Std. Error t-value p-value
#b:(Intercept) -1.0012680 0.0887792 -11.2782 1.637e-11 ***
#c:(Intercept) 0.0049506 0.0243151 0.2036 0.8402
#d:(Intercept) 0.9889417 0.0163848 60.3573 < 2.2e-16 ***
#e:(Intercept) 0.4054848 0.0419639 9.6627 4.310e-10 ***
#---
#Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
#
#Residual standard error:
#
#0.04466107 (26 degrees of freedom)
Grab model parameters for use with ggplot
coefs <- setNames(coef(model), c("b", "c", "d", "e"))
y50 <- predict(model, newdata = data.frame(dose = coefs["e"]))
Plot data
(Sorry, have no time to play with text labels, and don't understand what phi2 + phi3
means on the example plot, but pretty sure that is something which is going on around EC50)
ggplot(dat, aes(x = dose, y = response)) +
stat_function(fun = function(x, b, c, d, e){
c + (d - c)/(1 + exp(b*(log(x) - log(e))))
}, args = coefs, col = "skyblue", lwd = 1) +
geom_point(pch = 21, fill = "white") +
geom_hline(yintercept = coefs[c("c", "d")], lty = 2, colour = "gray50") +
geom_segment(aes(x = coefs["e"], y = 0, xend = coefs["e"], yend = y50),
lty = 2, colour = "gray50") +
geom_segment(aes(x = coefs["e"], y = y50, xend = 0, yend = y50),
lty = 2, colour = "gray50") +
scale_x_log10(
breaks = scales::trans_breaks("log10", function(x) 10^x),
labels = scales::trans_format("log10", scales::math_format(10^.x))
) +
annotation_logticks(sides = "b") +
labs(x = "Dose",
y = "Response"
) +
expand_limits(y = 1) +
ggthemes::theme_few()
add a comment |
I am not sure what is the right way here, but I usually do it like this:
Logistic funtion
Still don't know how to use LL.4()
for this purpose
flogis <- function(x, b, c, d, e){
c + (d - c)/(1 + exp(b*(log(x) - log(e))))
}
Dataset
Make some example data:
dose <- rep(exp(seq(-5, 5, length.out = 10)), each = 3)
dat <- data.frame(
dose = dose,
response = flogis(dose, -1, 0, 1, .5) + rnorm(length(dose), 0, .05)
)
head(dat)
# dose response
#1 0.006737947 0.01310683
#2 0.006737947 0.08292573
#3 0.006737947 0.03263079
#4 0.020468076 0.02763111
#5 0.020468076 0.01934260
#6 0.020468076 0.01296994
Fitting 4-parameters log-logistic model
library(drc)
model <- drm(response ~ dose, data = dat, fct = LL.4())
summary(model)
#Model fitted: Log-logistic (ED50 as parameter) (4 parms)
#
#Parameter estimates:
#
# Estimate Std. Error t-value p-value
#b:(Intercept) -1.0012680 0.0887792 -11.2782 1.637e-11 ***
#c:(Intercept) 0.0049506 0.0243151 0.2036 0.8402
#d:(Intercept) 0.9889417 0.0163848 60.3573 < 2.2e-16 ***
#e:(Intercept) 0.4054848 0.0419639 9.6627 4.310e-10 ***
#---
#Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
#
#Residual standard error:
#
#0.04466107 (26 degrees of freedom)
Grab model parameters for use with ggplot
coefs <- setNames(coef(model), c("b", "c", "d", "e"))
y50 <- predict(model, newdata = data.frame(dose = coefs["e"]))
Plot data
(Sorry, have no time to play with text labels, and don't understand what phi2 + phi3
means on the example plot, but pretty sure that is something which is going on around EC50)
ggplot(dat, aes(x = dose, y = response)) +
stat_function(fun = function(x, b, c, d, e){
c + (d - c)/(1 + exp(b*(log(x) - log(e))))
}, args = coefs, col = "skyblue", lwd = 1) +
geom_point(pch = 21, fill = "white") +
geom_hline(yintercept = coefs[c("c", "d")], lty = 2, colour = "gray50") +
geom_segment(aes(x = coefs["e"], y = 0, xend = coefs["e"], yend = y50),
lty = 2, colour = "gray50") +
geom_segment(aes(x = coefs["e"], y = y50, xend = 0, yend = y50),
lty = 2, colour = "gray50") +
scale_x_log10(
breaks = scales::trans_breaks("log10", function(x) 10^x),
labels = scales::trans_format("log10", scales::math_format(10^.x))
) +
annotation_logticks(sides = "b") +
labs(x = "Dose",
y = "Response"
) +
expand_limits(y = 1) +
ggthemes::theme_few()
add a comment |
I am not sure what is the right way here, but I usually do it like this:
Logistic funtion
Still don't know how to use LL.4()
for this purpose
flogis <- function(x, b, c, d, e){
c + (d - c)/(1 + exp(b*(log(x) - log(e))))
}
Dataset
Make some example data:
dose <- rep(exp(seq(-5, 5, length.out = 10)), each = 3)
dat <- data.frame(
dose = dose,
response = flogis(dose, -1, 0, 1, .5) + rnorm(length(dose), 0, .05)
)
head(dat)
# dose response
#1 0.006737947 0.01310683
#2 0.006737947 0.08292573
#3 0.006737947 0.03263079
#4 0.020468076 0.02763111
#5 0.020468076 0.01934260
#6 0.020468076 0.01296994
Fitting 4-parameters log-logistic model
library(drc)
model <- drm(response ~ dose, data = dat, fct = LL.4())
summary(model)
#Model fitted: Log-logistic (ED50 as parameter) (4 parms)
#
#Parameter estimates:
#
# Estimate Std. Error t-value p-value
#b:(Intercept) -1.0012680 0.0887792 -11.2782 1.637e-11 ***
#c:(Intercept) 0.0049506 0.0243151 0.2036 0.8402
#d:(Intercept) 0.9889417 0.0163848 60.3573 < 2.2e-16 ***
#e:(Intercept) 0.4054848 0.0419639 9.6627 4.310e-10 ***
#---
#Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
#
#Residual standard error:
#
#0.04466107 (26 degrees of freedom)
Grab model parameters for use with ggplot
coefs <- setNames(coef(model), c("b", "c", "d", "e"))
y50 <- predict(model, newdata = data.frame(dose = coefs["e"]))
Plot data
(Sorry, have no time to play with text labels, and don't understand what phi2 + phi3
means on the example plot, but pretty sure that is something which is going on around EC50)
ggplot(dat, aes(x = dose, y = response)) +
stat_function(fun = function(x, b, c, d, e){
c + (d - c)/(1 + exp(b*(log(x) - log(e))))
}, args = coefs, col = "skyblue", lwd = 1) +
geom_point(pch = 21, fill = "white") +
geom_hline(yintercept = coefs[c("c", "d")], lty = 2, colour = "gray50") +
geom_segment(aes(x = coefs["e"], y = 0, xend = coefs["e"], yend = y50),
lty = 2, colour = "gray50") +
geom_segment(aes(x = coefs["e"], y = y50, xend = 0, yend = y50),
lty = 2, colour = "gray50") +
scale_x_log10(
breaks = scales::trans_breaks("log10", function(x) 10^x),
labels = scales::trans_format("log10", scales::math_format(10^.x))
) +
annotation_logticks(sides = "b") +
labs(x = "Dose",
y = "Response"
) +
expand_limits(y = 1) +
ggthemes::theme_few()
I am not sure what is the right way here, but I usually do it like this:
Logistic funtion
Still don't know how to use LL.4()
for this purpose
flogis <- function(x, b, c, d, e){
c + (d - c)/(1 + exp(b*(log(x) - log(e))))
}
Dataset
Make some example data:
dose <- rep(exp(seq(-5, 5, length.out = 10)), each = 3)
dat <- data.frame(
dose = dose,
response = flogis(dose, -1, 0, 1, .5) + rnorm(length(dose), 0, .05)
)
head(dat)
# dose response
#1 0.006737947 0.01310683
#2 0.006737947 0.08292573
#3 0.006737947 0.03263079
#4 0.020468076 0.02763111
#5 0.020468076 0.01934260
#6 0.020468076 0.01296994
Fitting 4-parameters log-logistic model
library(drc)
model <- drm(response ~ dose, data = dat, fct = LL.4())
summary(model)
#Model fitted: Log-logistic (ED50 as parameter) (4 parms)
#
#Parameter estimates:
#
# Estimate Std. Error t-value p-value
#b:(Intercept) -1.0012680 0.0887792 -11.2782 1.637e-11 ***
#c:(Intercept) 0.0049506 0.0243151 0.2036 0.8402
#d:(Intercept) 0.9889417 0.0163848 60.3573 < 2.2e-16 ***
#e:(Intercept) 0.4054848 0.0419639 9.6627 4.310e-10 ***
#---
#Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
#
#Residual standard error:
#
#0.04466107 (26 degrees of freedom)
Grab model parameters for use with ggplot
coefs <- setNames(coef(model), c("b", "c", "d", "e"))
y50 <- predict(model, newdata = data.frame(dose = coefs["e"]))
Plot data
(Sorry, have no time to play with text labels, and don't understand what phi2 + phi3
means on the example plot, but pretty sure that is something which is going on around EC50)
ggplot(dat, aes(x = dose, y = response)) +
stat_function(fun = function(x, b, c, d, e){
c + (d - c)/(1 + exp(b*(log(x) - log(e))))
}, args = coefs, col = "skyblue", lwd = 1) +
geom_point(pch = 21, fill = "white") +
geom_hline(yintercept = coefs[c("c", "d")], lty = 2, colour = "gray50") +
geom_segment(aes(x = coefs["e"], y = 0, xend = coefs["e"], yend = y50),
lty = 2, colour = "gray50") +
geom_segment(aes(x = coefs["e"], y = y50, xend = 0, yend = y50),
lty = 2, colour = "gray50") +
scale_x_log10(
breaks = scales::trans_breaks("log10", function(x) 10^x),
labels = scales::trans_format("log10", scales::math_format(10^.x))
) +
annotation_logticks(sides = "b") +
labs(x = "Dose",
y = "Response"
) +
expand_limits(y = 1) +
ggthemes::theme_few()
answered Nov 16 '18 at 15:57
utubunutubun
1,8351914
1,8351914
add a comment |
add a comment |
try this :
library(drc)
#adjust model
drm <- drm(Response ~ Conc, data = df, fct = LL.4())
#plot
plot(drm)
abline(a=112.6868 , 0)
add a comment |
try this :
library(drc)
#adjust model
drm <- drm(Response ~ Conc, data = df, fct = LL.4())
#plot
plot(drm)
abline(a=112.6868 , 0)
add a comment |
try this :
library(drc)
#adjust model
drm <- drm(Response ~ Conc, data = df, fct = LL.4())
#plot
plot(drm)
abline(a=112.6868 , 0)
try this :
library(drc)
#adjust model
drm <- drm(Response ~ Conc, data = df, fct = LL.4())
#plot
plot(drm)
abline(a=112.6868 , 0)
answered Nov 16 '18 at 14:59
Jrakru56Jrakru56
609212
609212
add a comment |
add a comment |
You can extract the value of the asymptote from the drm
object:
asymptote <- coef(drm)[3]
This value can be used for plotting:
plot(drm)
abline(asymptote, 0)
add a comment |
You can extract the value of the asymptote from the drm
object:
asymptote <- coef(drm)[3]
This value can be used for plotting:
plot(drm)
abline(asymptote, 0)
add a comment |
You can extract the value of the asymptote from the drm
object:
asymptote <- coef(drm)[3]
This value can be used for plotting:
plot(drm)
abline(asymptote, 0)
You can extract the value of the asymptote from the drm
object:
asymptote <- coef(drm)[3]
This value can be used for plotting:
plot(drm)
abline(asymptote, 0)
answered Nov 16 '18 at 15:03
Sven HohensteinSven Hohenstein
66.7k12100132
66.7k12100132
add a comment |
add a comment |
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try
abline
witha= asymptote
andb=0
– Jrakru56
Nov 16 '18 at 14:48
Unfortunately it did not work, that is the mensagem: Error in abline(a = asymptote, b = 0) : object 'asymptote' not found
– Vitor Muller Anunciato
Nov 16 '18 at 14:57
Sorry, I was not clear. I meant assign the value of the asymptote to the parameter
a
. See below– Jrakru56
Nov 16 '18 at 15:00