Get shared folder permissions
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Im quite new with powershell and I need to do a shared folders permission report. I've the following code:
$path = \servershared_folder
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.fullname; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
But the output is:
\servershared_folderfolder1;FileSystemRights;AccessControlType;IsInherited;InheritanceFlags;PropagationFlags
\servershared_folderfolder2;FileSystemRights;AccessControlType;IsInherited;InheritanceFlags;PropagationFlags
I need the following output:
\servershared_folder;FileSystemRights;AccessControlType;IsInherited;InheritanceFlags;PropagationFlags
Why is doing the "dir" recursiveley if I do not specify it? If I am specifying where im telling to do so?
powershell
asked Nov 16 '18 at 12:49
QuironQuiron
149111
add a comment |
Im quite new with powershell and I need to do a shared folders permission report. I've the following code:
$path = \servershared_folder
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.fullname; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
But the output is:
\servershared_folderfolder1;FileSystemRights;AccessControlType;IsInherited;InheritanceFlags;PropagationFlags
\servershared_folderfolder2;FileSystemRights;AccessControlType;IsInherited;InheritanceFlags;PropagationFlags
I need the following output:
\servershared_folder;FileSystemRights;AccessControlType;IsInherited;InheritanceFlags;PropagationFlags
Why is doing the "dir" recursiveley if I do not specify it? If I am specifying where im telling to do so?
powershell
asked Nov 16 '18 at 12:49
QuironQuiron
149111
add a comment |
Im quite new with powershell and I need to do a shared folders permission report. I've the following code:
$path = \servershared_folder
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.fullname; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
But the output is:
\servershared_folderfolder1;FileSystemRights;AccessControlType;IsInherited;InheritanceFlags;PropagationFlags
\servershared_folderfolder2;FileSystemRights;AccessControlType;IsInherited;InheritanceFlags;PropagationFlags
I need the following output:
\servershared_folder;FileSystemRights;AccessControlType;IsInherited;InheritanceFlags;PropagationFlags
Why is doing the "dir" recursiveley if I do not specify it? If I am specifying where im telling to do so?
powershell
asked Nov 16 '18 at 12:49
QuironQuiron
149111
Im quite new with powershell and I need to do a shared folders permission report. I've the following code:
$path = \servershared_folder
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.fullname; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
But the output is:
\servershared_folderfolder1;FileSystemRights;AccessControlType;IsInherited;InheritanceFlags;PropagationFlags
\servershared_folderfolder2;FileSystemRights;AccessControlType;IsInherited;InheritanceFlags;PropagationFlags
I need the following output:
\servershared_folder;FileSystemRights;AccessControlType;IsInherited;InheritanceFlags;PropagationFlags
Why is doing the "dir" recursiveley if I do not specify it? If I am specifying where im telling to do so?
powershell
powershell
asked Nov 16 '18 at 12:49
QuironQuiron
149111
asked Nov 16 '18 at 12:49
QuironQuiron
149111
asked Nov 16 '18 at 12:49
QuironQuiron
149111
asked Nov 16 '18 at 12:49
QuironQuiron
149111
asked Nov 16 '18 at 12:49
QuironQuiron
149111
149111
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
To get the exact answer you are asking for:
$path = "\servershared_folder"
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.Root; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
Notice the "$_.Root" after the ForEach-Object (%). But in my opinion the following is better because this way you see the foldername under '.Application Data':
$path = "\servershared_folder"
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.Name; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
Hope this helps, because your question is not very clear imo.
answered Nov 16 '18 at 13:15
Bernard MoeskopsBernard Moeskops
35327
This output is better than mine. Thanks a lot! Let me try to wirte a better explanation...Given a shares list, I need a report of each share permissions (overall groups and rights), but not the children folders... Hope this explanation is clearer than first one... Sorry about my English :(
– Quiron
Nov 16 '18 at 13:28
add a comment |
Also please do yourself a favour and write the code in PowerShell ISE and use the PowerShell StyleGuide guidelines:
$path = "\servershared_folder"
$shares = Get-ChildItem $path | Where-Object { $_.PsIsContainer }
$data = foreach($share in $shares){
$path = $share.Name
$acls = Get-Acl $share.Fullname
foreach($acl in $acls){
$acl.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path -passthru
}
}
$data | Export-Csv $reportpath
This makes the code readable and makes it easier to troubleshoot or modify the code later on. This version does not output ChildItems of the folders inside the shared folder. Only the folders placed inside "servershared_folder".
answered Nov 16 '18 at 13:41
Bernard MoeskopsBernard Moeskops
35327
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
To get the exact answer you are asking for:
$path = "\servershared_folder"
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.Root; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
Notice the "$_.Root" after the ForEach-Object (%). But in my opinion the following is better because this way you see the foldername under '.Application Data':
$path = "\servershared_folder"
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.Name; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
Hope this helps, because your question is not very clear imo.
answered Nov 16 '18 at 13:15
Bernard MoeskopsBernard Moeskops
35327
This output is better than mine. Thanks a lot! Let me try to wirte a better explanation...Given a shares list, I need a report of each share permissions (overall groups and rights), but not the children folders... Hope this explanation is clearer than first one... Sorry about my English :(
– Quiron
Nov 16 '18 at 13:28
add a comment |
To get the exact answer you are asking for:
$path = "\servershared_folder"
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.Root; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
Notice the "$_.Root" after the ForEach-Object (%). But in my opinion the following is better because this way you see the foldername under '.Application Data':
$path = "\servershared_folder"
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.Name; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
Hope this helps, because your question is not very clear imo.
answered Nov 16 '18 at 13:15
Bernard MoeskopsBernard Moeskops
35327
This output is better than mine. Thanks a lot! Let me try to wirte a better explanation...Given a shares list, I need a report of each share permissions (overall groups and rights), but not the children folders... Hope this explanation is clearer than first one... Sorry about my English :(
– Quiron
Nov 16 '18 at 13:28
add a comment |
To get the exact answer you are asking for:
$path = "\servershared_folder"
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.Root; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
Notice the "$_.Root" after the ForEach-Object (%). But in my opinion the following is better because this way you see the foldername under '.Application Data':
$path = "\servershared_folder"
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.Name; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
Hope this helps, because your question is not very clear imo.
answered Nov 16 '18 at 13:15
Bernard MoeskopsBernard Moeskops
35327
To get the exact answer you are asking for:
$path = "\servershared_folder"
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.Root; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
Notice the "$_.Root" after the ForEach-Object (%). But in my opinion the following is better because this way you see the foldername under '.Application Data':
$path = "\servershared_folder"
dir $path | where { $_.PsIsContainer } | % { $path1 = $_.Name; Get-Acl $_.Fullname | % { $_.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path1 -passthru }} | Export-Csv $reportpath
Hope this helps, because your question is not very clear imo.
answered Nov 16 '18 at 13:15
Bernard MoeskopsBernard Moeskops
35327
answered Nov 16 '18 at 13:15
Bernard MoeskopsBernard Moeskops
35327
answered Nov 16 '18 at 13:15
Bernard MoeskopsBernard Moeskops
35327
answered Nov 16 '18 at 13:15
Bernard MoeskopsBernard Moeskops
35327
35327
This output is better than mine. Thanks a lot! Let me try to wirte a better explanation...Given a shares list, I need a report of each share permissions (overall groups and rights), but not the children folders... Hope this explanation is clearer than first one... Sorry about my English :(
– Quiron
Nov 16 '18 at 13:28
add a comment |
This output is better than mine. Thanks a lot! Let me try to wirte a better explanation...Given a shares list, I need a report of each share permissions (overall groups and rights), but not the children folders... Hope this explanation is clearer than first one... Sorry about my English :(
– Quiron
Nov 16 '18 at 13:28
This output is better than mine. Thanks a lot! Let me try to wirte a better explanation...Given a shares list, I need a report of each share permissions (overall groups and rights), but not the children folders... Hope this explanation is clearer than first one... Sorry about my English :(
– Quiron
Nov 16 '18 at 13:28
This output is better than mine. Thanks a lot! Let me try to wirte a better explanation...Given a shares list, I need a report of each share permissions (overall groups and rights), but not the children folders... Hope this explanation is clearer than first one... Sorry about my English :(
– Quiron
Nov 16 '18 at 13:28
add a comment |
Also please do yourself a favour and write the code in PowerShell ISE and use the PowerShell StyleGuide guidelines:
$path = "\servershared_folder"
$shares = Get-ChildItem $path | Where-Object { $_.PsIsContainer }
$data = foreach($share in $shares){
$path = $share.Name
$acls = Get-Acl $share.Fullname
foreach($acl in $acls){
$acl.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path -passthru
}
}
$data | Export-Csv $reportpath
This makes the code readable and makes it easier to troubleshoot or modify the code later on. This version does not output ChildItems of the folders inside the shared folder. Only the folders placed inside "servershared_folder".
answered Nov 16 '18 at 13:41
Bernard MoeskopsBernard Moeskops
35327
add a comment |
Also please do yourself a favour and write the code in PowerShell ISE and use the PowerShell StyleGuide guidelines:
$path = "\servershared_folder"
$shares = Get-ChildItem $path | Where-Object { $_.PsIsContainer }
$data = foreach($share in $shares){
$path = $share.Name
$acls = Get-Acl $share.Fullname
foreach($acl in $acls){
$acl.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path -passthru
}
}
$data | Export-Csv $reportpath
This makes the code readable and makes it easier to troubleshoot or modify the code later on. This version does not output ChildItems of the folders inside the shared folder. Only the folders placed inside "servershared_folder".
answered Nov 16 '18 at 13:41
Bernard MoeskopsBernard Moeskops
35327
add a comment |
Also please do yourself a favour and write the code in PowerShell ISE and use the PowerShell StyleGuide guidelines:
$path = "\servershared_folder"
$shares = Get-ChildItem $path | Where-Object { $_.PsIsContainer }
$data = foreach($share in $shares){
$path = $share.Name
$acls = Get-Acl $share.Fullname
foreach($acl in $acls){
$acl.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path -passthru
}
}
$data | Export-Csv $reportpath
This makes the code readable and makes it easier to troubleshoot or modify the code later on. This version does not output ChildItems of the folders inside the shared folder. Only the folders placed inside "servershared_folder".
answered Nov 16 '18 at 13:41
Bernard MoeskopsBernard Moeskops
35327
Also please do yourself a favour and write the code in PowerShell ISE and use the PowerShell StyleGuide guidelines:
$path = "\servershared_folder"
$shares = Get-ChildItem $path | Where-Object { $_.PsIsContainer }
$data = foreach($share in $shares){
$path = $share.Name
$acls = Get-Acl $share.Fullname
foreach($acl in $acls){
$acl.access | Add-Member -MemberType NoteProperty '.Application Data' -Value $path -passthru
}
}
$data | Export-Csv $reportpath
This makes the code readable and makes it easier to troubleshoot or modify the code later on. This version does not output ChildItems of the folders inside the shared folder. Only the folders placed inside "servershared_folder".
answered Nov 16 '18 at 13:41
Bernard MoeskopsBernard Moeskops
35327
answered Nov 16 '18 at 13:41
Bernard MoeskopsBernard Moeskops
35327
answered Nov 16 '18 at 13:41
Bernard MoeskopsBernard Moeskops
35327
answered Nov 16 '18 at 13:41
Bernard MoeskopsBernard Moeskops
35327
35327
add a comment |
add a comment |
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