Calculating Average Monthly Consumption





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I'm working on an self improvement inventory management project in Laravel 4 but can't figure out the best way to perform the average monthly consumption (AMC) calculation.



I have two tables i.e commodities table (id,item_name,price) and stockcard (id, item_id, qty_in, qty_out,transaction_date) from which i should derive the AMC calculation.



FORMULA = (sum of current month's qty_out + sum of previous two month's qty_out) / 3 


Can anyone bail me out on how to go about it in plain PHP and mysql?










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  • 2





    Please provide a relevant and minimal sample data showcasing your requirements, and expected output. Refer this link on how to frame a good SQL question: Why should I provide an MCVE for what seems to me to be a very simple SQL query?

    – Madhur Bhaiya
    Nov 16 '18 at 12:58


















-1















I'm working on an self improvement inventory management project in Laravel 4 but can't figure out the best way to perform the average monthly consumption (AMC) calculation.



I have two tables i.e commodities table (id,item_name,price) and stockcard (id, item_id, qty_in, qty_out,transaction_date) from which i should derive the AMC calculation.



FORMULA = (sum of current month's qty_out + sum of previous two month's qty_out) / 3 


Can anyone bail me out on how to go about it in plain PHP and mysql?










share|improve this question




















  • 2





    Please provide a relevant and minimal sample data showcasing your requirements, and expected output. Refer this link on how to frame a good SQL question: Why should I provide an MCVE for what seems to me to be a very simple SQL query?

    – Madhur Bhaiya
    Nov 16 '18 at 12:58














-1












-1








-1








I'm working on an self improvement inventory management project in Laravel 4 but can't figure out the best way to perform the average monthly consumption (AMC) calculation.



I have two tables i.e commodities table (id,item_name,price) and stockcard (id, item_id, qty_in, qty_out,transaction_date) from which i should derive the AMC calculation.



FORMULA = (sum of current month's qty_out + sum of previous two month's qty_out) / 3 


Can anyone bail me out on how to go about it in plain PHP and mysql?










share|improve this question
















I'm working on an self improvement inventory management project in Laravel 4 but can't figure out the best way to perform the average monthly consumption (AMC) calculation.



I have two tables i.e commodities table (id,item_name,price) and stockcard (id, item_id, qty_in, qty_out,transaction_date) from which i should derive the AMC calculation.



FORMULA = (sum of current month's qty_out + sum of previous two month's qty_out) / 3 


Can anyone bail me out on how to go about it in plain PHP and mysql?







php mysql laravel laravel-4






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edited Nov 16 '18 at 12:57









Madhur Bhaiya

19.6k62336




19.6k62336










asked Nov 16 '18 at 12:54









O'ByronO'Byron

308




308








  • 2





    Please provide a relevant and minimal sample data showcasing your requirements, and expected output. Refer this link on how to frame a good SQL question: Why should I provide an MCVE for what seems to me to be a very simple SQL query?

    – Madhur Bhaiya
    Nov 16 '18 at 12:58














  • 2





    Please provide a relevant and minimal sample data showcasing your requirements, and expected output. Refer this link on how to frame a good SQL question: Why should I provide an MCVE for what seems to me to be a very simple SQL query?

    – Madhur Bhaiya
    Nov 16 '18 at 12:58








2




2





Please provide a relevant and minimal sample data showcasing your requirements, and expected output. Refer this link on how to frame a good SQL question: Why should I provide an MCVE for what seems to me to be a very simple SQL query?

– Madhur Bhaiya
Nov 16 '18 at 12:58





Please provide a relevant and minimal sample data showcasing your requirements, and expected output. Refer this link on how to frame a good SQL question: Why should I provide an MCVE for what seems to me to be a very simple SQL query?

– Madhur Bhaiya
Nov 16 '18 at 12:58












1 Answer
1






active

oldest

votes


















2














You should be able to do this using conditional aggregation for example



   drop table if exists t;

create table t(item int,qty_out int , dt date);

insert into t values
(1,1,'2018-09-01'),(1,1,'2018-10-01'),(1,1,'2018-11-01');

select item,
sum(case when year(dt)*12 + month(dt) = year(now()) * 12 + month(now()) then qty_out else 0 end) thismm,
sum(case when year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -1) or
year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -2) then qty_out else 0 end) last2mm,
(sum(case when year(dt)*12 + month(dt) = year(now()) * 12 + month(now()) then qty_out else 0 end) +
sum(case when year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -1) or
year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -2) then qty_out else 0 end)
) / 3 amc
from t
where year(dt)*12 + month(dt) >= (year(now()) * 12 + month(now()) -2)
group by item ;
+------+-----------+-------+--------+
| item | thismonth | last2 | amc |
+------+-----------+-------+--------+
| 1 | 1 | 2 | 1.0000 |
+------+-----------+-------+--------+
1 row in set (0.01 sec)


Note the conversion to month number to simplify where dates go over a year end.
Of course if you are looking for a 3 month rolling average then that would be a different question.






share|improve this answer
























  • You are a life saver. This is exactly what i was looking for and works perfectly

    – O'Byron
    Nov 17 '18 at 9:06











  • @O'Byron If an answer has helped you. You should consider marking it as accepted answer (click on checkmark besides the answer to turn it green). Please see: How to accept an answer for closure. You get points for it as well. Thanks :)

    – Madhur Bhaiya
    Nov 18 '18 at 15:45













  • Hadn't seen that. thanks @MadhurBhaiya

    – O'Byron
    Nov 19 '18 at 14:14












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














You should be able to do this using conditional aggregation for example



   drop table if exists t;

create table t(item int,qty_out int , dt date);

insert into t values
(1,1,'2018-09-01'),(1,1,'2018-10-01'),(1,1,'2018-11-01');

select item,
sum(case when year(dt)*12 + month(dt) = year(now()) * 12 + month(now()) then qty_out else 0 end) thismm,
sum(case when year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -1) or
year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -2) then qty_out else 0 end) last2mm,
(sum(case when year(dt)*12 + month(dt) = year(now()) * 12 + month(now()) then qty_out else 0 end) +
sum(case when year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -1) or
year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -2) then qty_out else 0 end)
) / 3 amc
from t
where year(dt)*12 + month(dt) >= (year(now()) * 12 + month(now()) -2)
group by item ;
+------+-----------+-------+--------+
| item | thismonth | last2 | amc |
+------+-----------+-------+--------+
| 1 | 1 | 2 | 1.0000 |
+------+-----------+-------+--------+
1 row in set (0.01 sec)


Note the conversion to month number to simplify where dates go over a year end.
Of course if you are looking for a 3 month rolling average then that would be a different question.






share|improve this answer
























  • You are a life saver. This is exactly what i was looking for and works perfectly

    – O'Byron
    Nov 17 '18 at 9:06











  • @O'Byron If an answer has helped you. You should consider marking it as accepted answer (click on checkmark besides the answer to turn it green). Please see: How to accept an answer for closure. You get points for it as well. Thanks :)

    – Madhur Bhaiya
    Nov 18 '18 at 15:45













  • Hadn't seen that. thanks @MadhurBhaiya

    – O'Byron
    Nov 19 '18 at 14:14
















2














You should be able to do this using conditional aggregation for example



   drop table if exists t;

create table t(item int,qty_out int , dt date);

insert into t values
(1,1,'2018-09-01'),(1,1,'2018-10-01'),(1,1,'2018-11-01');

select item,
sum(case when year(dt)*12 + month(dt) = year(now()) * 12 + month(now()) then qty_out else 0 end) thismm,
sum(case when year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -1) or
year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -2) then qty_out else 0 end) last2mm,
(sum(case when year(dt)*12 + month(dt) = year(now()) * 12 + month(now()) then qty_out else 0 end) +
sum(case when year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -1) or
year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -2) then qty_out else 0 end)
) / 3 amc
from t
where year(dt)*12 + month(dt) >= (year(now()) * 12 + month(now()) -2)
group by item ;
+------+-----------+-------+--------+
| item | thismonth | last2 | amc |
+------+-----------+-------+--------+
| 1 | 1 | 2 | 1.0000 |
+------+-----------+-------+--------+
1 row in set (0.01 sec)


Note the conversion to month number to simplify where dates go over a year end.
Of course if you are looking for a 3 month rolling average then that would be a different question.






share|improve this answer
























  • You are a life saver. This is exactly what i was looking for and works perfectly

    – O'Byron
    Nov 17 '18 at 9:06











  • @O'Byron If an answer has helped you. You should consider marking it as accepted answer (click on checkmark besides the answer to turn it green). Please see: How to accept an answer for closure. You get points for it as well. Thanks :)

    – Madhur Bhaiya
    Nov 18 '18 at 15:45













  • Hadn't seen that. thanks @MadhurBhaiya

    – O'Byron
    Nov 19 '18 at 14:14














2












2








2







You should be able to do this using conditional aggregation for example



   drop table if exists t;

create table t(item int,qty_out int , dt date);

insert into t values
(1,1,'2018-09-01'),(1,1,'2018-10-01'),(1,1,'2018-11-01');

select item,
sum(case when year(dt)*12 + month(dt) = year(now()) * 12 + month(now()) then qty_out else 0 end) thismm,
sum(case when year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -1) or
year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -2) then qty_out else 0 end) last2mm,
(sum(case when year(dt)*12 + month(dt) = year(now()) * 12 + month(now()) then qty_out else 0 end) +
sum(case when year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -1) or
year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -2) then qty_out else 0 end)
) / 3 amc
from t
where year(dt)*12 + month(dt) >= (year(now()) * 12 + month(now()) -2)
group by item ;
+------+-----------+-------+--------+
| item | thismonth | last2 | amc |
+------+-----------+-------+--------+
| 1 | 1 | 2 | 1.0000 |
+------+-----------+-------+--------+
1 row in set (0.01 sec)


Note the conversion to month number to simplify where dates go over a year end.
Of course if you are looking for a 3 month rolling average then that would be a different question.






share|improve this answer













You should be able to do this using conditional aggregation for example



   drop table if exists t;

create table t(item int,qty_out int , dt date);

insert into t values
(1,1,'2018-09-01'),(1,1,'2018-10-01'),(1,1,'2018-11-01');

select item,
sum(case when year(dt)*12 + month(dt) = year(now()) * 12 + month(now()) then qty_out else 0 end) thismm,
sum(case when year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -1) or
year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -2) then qty_out else 0 end) last2mm,
(sum(case when year(dt)*12 + month(dt) = year(now()) * 12 + month(now()) then qty_out else 0 end) +
sum(case when year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -1) or
year(dt)*12 + month(dt) = (year(now()) * 12 + month(now()) -2) then qty_out else 0 end)
) / 3 amc
from t
where year(dt)*12 + month(dt) >= (year(now()) * 12 + month(now()) -2)
group by item ;
+------+-----------+-------+--------+
| item | thismonth | last2 | amc |
+------+-----------+-------+--------+
| 1 | 1 | 2 | 1.0000 |
+------+-----------+-------+--------+
1 row in set (0.01 sec)


Note the conversion to month number to simplify where dates go over a year end.
Of course if you are looking for a 3 month rolling average then that would be a different question.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 16 '18 at 13:22









P.SalmonP.Salmon

8,1102515




8,1102515













  • You are a life saver. This is exactly what i was looking for and works perfectly

    – O'Byron
    Nov 17 '18 at 9:06











  • @O'Byron If an answer has helped you. You should consider marking it as accepted answer (click on checkmark besides the answer to turn it green). Please see: How to accept an answer for closure. You get points for it as well. Thanks :)

    – Madhur Bhaiya
    Nov 18 '18 at 15:45













  • Hadn't seen that. thanks @MadhurBhaiya

    – O'Byron
    Nov 19 '18 at 14:14



















  • You are a life saver. This is exactly what i was looking for and works perfectly

    – O'Byron
    Nov 17 '18 at 9:06











  • @O'Byron If an answer has helped you. You should consider marking it as accepted answer (click on checkmark besides the answer to turn it green). Please see: How to accept an answer for closure. You get points for it as well. Thanks :)

    – Madhur Bhaiya
    Nov 18 '18 at 15:45













  • Hadn't seen that. thanks @MadhurBhaiya

    – O'Byron
    Nov 19 '18 at 14:14

















You are a life saver. This is exactly what i was looking for and works perfectly

– O'Byron
Nov 17 '18 at 9:06





You are a life saver. This is exactly what i was looking for and works perfectly

– O'Byron
Nov 17 '18 at 9:06













@O'Byron If an answer has helped you. You should consider marking it as accepted answer (click on checkmark besides the answer to turn it green). Please see: How to accept an answer for closure. You get points for it as well. Thanks :)

– Madhur Bhaiya
Nov 18 '18 at 15:45







@O'Byron If an answer has helped you. You should consider marking it as accepted answer (click on checkmark besides the answer to turn it green). Please see: How to accept an answer for closure. You get points for it as well. Thanks :)

– Madhur Bhaiya
Nov 18 '18 at 15:45















Hadn't seen that. thanks @MadhurBhaiya

– O'Byron
Nov 19 '18 at 14:14





Hadn't seen that. thanks @MadhurBhaiya

– O'Byron
Nov 19 '18 at 14:14




















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