update object property without rewriting

I have a method which takes two parameters key for property name and value for the property value. And when I use it I want to update data[key] and add as many values there as I call the method setData. I need not rewrite value with the same key, but update it and add a new one, so the final object can look like this:

{

    patients:

       formValue: […],

       filtersValue: {}

}

current realization:

const data = {}



setData(key, value) {

  Object.assign(this.data[key] = {}, value);

}





setData(this.stateName, { firstItemsValue: this.itemsCopy });

setData(this.stateName, { secondItemsValue: this.itemsCopy });

edited Nov 15 '18 at 9:51

asked Nov 15 '18 at 8:26

Bogdan Tushevskyi

14814

1

what about data[key] = value?

– Aprillion
Nov 15 '18 at 8:28

Add an input and an output example of your method to make it more clear

– Panos K
Nov 15 '18 at 8:31

@Aprillion data[key] = value will rewrite it on every method call

– Bogdan Tushevskyi
Nov 15 '18 at 8:40

add a comment |

{

    patients:

       formValue: […],

       filtersValue: {}

}

current realization:

const data = {}



setData(key, value) {

  Object.assign(this.data[key] = {}, value);

}





setData(this.stateName, { firstItemsValue: this.itemsCopy });

setData(this.stateName, { secondItemsValue: this.itemsCopy });

edited Nov 15 '18 at 9:51

asked Nov 15 '18 at 8:26

Bogdan Tushevskyi

14814

1

what about data[key] = value?

– Aprillion
Nov 15 '18 at 8:28

Add an input and an output example of your method to make it more clear

– Panos K
Nov 15 '18 at 8:31

@Aprillion data[key] = value will rewrite it on every method call

– Bogdan Tushevskyi
Nov 15 '18 at 8:40

add a comment |

{

    patients:

       formValue: […],

       filtersValue: {}

}

current realization:

const data = {}



setData(key, value) {

  Object.assign(this.data[key] = {}, value);

}





setData(this.stateName, { firstItemsValue: this.itemsCopy });

setData(this.stateName, { secondItemsValue: this.itemsCopy });

edited Nov 15 '18 at 9:51

asked Nov 15 '18 at 8:26

Bogdan Tushevskyi

14814

{

    patients:

       formValue: […],

       filtersValue: {}

}

current realization:

const data = {}



setData(key, value) {

  Object.assign(this.data[key] = {}, value);

}





setData(this.stateName, { firstItemsValue: this.itemsCopy });

setData(this.stateName, { secondItemsValue: this.itemsCopy });

javascript object

edited Nov 15 '18 at 9:51

asked Nov 15 '18 at 8:26

Bogdan Tushevskyi

14814

edited Nov 15 '18 at 9:51

asked Nov 15 '18 at 8:26

Bogdan Tushevskyi

14814

edited Nov 15 '18 at 9:51

asked Nov 15 '18 at 8:26

Bogdan Tushevskyi

14814

asked Nov 15 '18 at 8:26

Bogdan Tushevskyi

14814

asked Nov 15 '18 at 8:26

Bogdan Tushevskyi

14814

1

what about data[key] = value?

– Aprillion
Nov 15 '18 at 8:28

Add an input and an output example of your method to make it more clear

– Panos K
Nov 15 '18 at 8:31

@Aprillion data[key] = value will rewrite it on every method call

– Bogdan Tushevskyi
Nov 15 '18 at 8:40

add a comment |

1

what about data[key] = value?

– Aprillion
Nov 15 '18 at 8:28

Add an input and an output example of your method to make it more clear

– Panos K
Nov 15 '18 at 8:31

@Aprillion data[key] = value will rewrite it on every method call

– Bogdan Tushevskyi
Nov 15 '18 at 8:40

what about data[key] = value?

– Aprillion
Nov 15 '18 at 8:28

Add an input and an output example of your method to make it more clear

– Panos K
Nov 15 '18 at 8:31

@Aprillion data[key] = value will rewrite it on every method call

– Bogdan Tushevskyi
Nov 15 '18 at 8:40

add a comment |

5 Answers
5

active

oldest

votes

The solution is:

setData(key, value) {

  this.data[key] = { ...this.data[key], ...value };

}

answered Nov 15 '18 at 14:44

Bogdan Tushevskyi

14814

spread operator? why not ... ?

– Tornike Shavishvili
Nov 15 '18 at 15:29

@TornikeShavishvili what is the difference between the spread operator and '...'?

– Bogdan Tushevskyi
Nov 16 '18 at 8:42

In your case three dots are spread operator. In javascript three dots '...' have basically two meanings, 1. If used in function declaration it defines "rest prameters", please see following doxumentations: Functions Rest Parameters 2. In other cases it is interpreted as spread operator. Please see Expressions - Spread syntax

– Tornike Shavishvili
Nov 16 '18 at 8:52

@TornikeShavishvili yes, I know this, I don't understand your first question

– Bogdan Tushevskyi
Nov 16 '18 at 8:54

I think my comment confused you. I meant that spread operator is good to use. I have to be more clear next time.

– Tornike Shavishvili
Nov 16 '18 at 8:55

|
show 1 more comment

You have mentioned that you want to add as many values as youi call setData. That sounds like a job for array.

You could use follwoing code:

function setData(targetObj, propName, valueToAdd){



    if(typeof targetObj[propName] === 'undefined'){

        targetObj[propName] = ;

    }

    if(Array.isArray(targetObj[propName])){

        targetObj[propName].push(valueToAdd);

    }else{

         console.log('property '+propName +' already exists and is not an array');

    }

}

answered Nov 15 '18 at 8:37

Tornike Shavishvili

61021122

add a comment |

Use like this:

const data = {}



setData(key, value) {

  Object.assign(data, {[key]: value});

}

BTW, You can simply set the data like:

setData(key, value) {

  data[key] = value

}

edited Nov 15 '18 at 8:38

answered Nov 15 '18 at 8:31

Bhojendra Rauniyar

51.7k2079128

1

Is there a reason for Object.assign over plain bracket notation? (also, key in your code will refer to the literal string key, not the variable)

– CertainPerformance
Nov 15 '18 at 8:32

you can change it to { [key] : value } and it should compute the value.

– Lloyd
Nov 15 '18 at 8:33

Thanks for the catch.

– Bhojendra Rauniyar
Nov 15 '18 at 8:33

@CertainPerformance Sorry, what do you mean? Is there a reason for Object.assign over plain bracket notation?

– Bhojendra Rauniyar
Nov 15 '18 at 8:34

If you don't need to merge objects, or create a new object or something like that, Object.assign seems really weird to use over just data[key] = value IMO

– CertainPerformance
Nov 15 '18 at 8:36

|
show 2 more comments

What you're trying to do is to implement a HashMap or a Dictionary.

I'd just do it like so:

function setData(key, value) 

{

    if (data[key])

        data[key].push(value)

    else  

        data[key] = [ value ]

}

answered Nov 15 '18 at 8:45

AlexL

813

you are talking about Hashmap/Dictionary (a.k.a. "Object" in JS), but created an Array in your code

– Aprillion
Nov 17 '18 at 11:00

add a comment |

-1

Check this solution

const data = {}

var fun = (key, value)=>{



data[key] = value;

}

fun('kk',123);

console.log(data);

answered Nov 15 '18 at 8:49

GAURAV

11211

add a comment |

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5 Answers
5

active

oldest

votes

5 Answers
5

active

oldest

votes

The solution is:

setData(key, value) {

  this.data[key] = { ...this.data[key], ...value };

}

answered Nov 15 '18 at 14:44

Bogdan Tushevskyi

14814

spread operator? why not ... ?

– Tornike Shavishvili
Nov 15 '18 at 15:29

@TornikeShavishvili what is the difference between the spread operator and '...'?

– Bogdan Tushevskyi
Nov 16 '18 at 8:42

In your case three dots are spread operator. In javascript three dots '...' have basically two meanings, 1. If used in function declaration it defines "rest prameters", please see following doxumentations: Functions Rest Parameters 2. In other cases it is interpreted as spread operator. Please see Expressions - Spread syntax

– Tornike Shavishvili
Nov 16 '18 at 8:52

@TornikeShavishvili yes, I know this, I don't understand your first question

– Bogdan Tushevskyi
Nov 16 '18 at 8:54

I think my comment confused you. I meant that spread operator is good to use. I have to be more clear next time.

– Tornike Shavishvili
Nov 16 '18 at 8:55

|
show 1 more comment

The solution is:

setData(key, value) {

  this.data[key] = { ...this.data[key], ...value };

}

answered Nov 15 '18 at 14:44

Bogdan Tushevskyi

14814

spread operator? why not ... ?

– Tornike Shavishvili
Nov 15 '18 at 15:29

@TornikeShavishvili what is the difference between the spread operator and '...'?

– Bogdan Tushevskyi
Nov 16 '18 at 8:42

In your case three dots are spread operator. In javascript three dots '...' have basically two meanings, 1. If used in function declaration it defines "rest prameters", please see following doxumentations: Functions Rest Parameters 2. In other cases it is interpreted as spread operator. Please see Expressions - Spread syntax

– Tornike Shavishvili
Nov 16 '18 at 8:52

@TornikeShavishvili yes, I know this, I don't understand your first question

– Bogdan Tushevskyi
Nov 16 '18 at 8:54

I think my comment confused you. I meant that spread operator is good to use. I have to be more clear next time.

– Tornike Shavishvili
Nov 16 '18 at 8:55

|
show 1 more comment

The solution is:

setData(key, value) {

  this.data[key] = { ...this.data[key], ...value };

}

answered Nov 15 '18 at 14:44

Bogdan Tushevskyi

14814

The solution is:

setData(key, value) {

  this.data[key] = { ...this.data[key], ...value };

}

answered Nov 15 '18 at 14:44

Bogdan Tushevskyi

14814

answered Nov 15 '18 at 14:44

Bogdan Tushevskyi

14814

answered Nov 15 '18 at 14:44

Bogdan Tushevskyi

14814

answered Nov 15 '18 at 14:44

Bogdan Tushevskyi

14814

spread operator? why not ... ?

– Tornike Shavishvili
Nov 15 '18 at 15:29

@TornikeShavishvili what is the difference between the spread operator and '...'?

– Bogdan Tushevskyi
Nov 16 '18 at 8:42

In your case three dots are spread operator. In javascript three dots '...' have basically two meanings, 1. If used in function declaration it defines "rest prameters", please see following doxumentations: Functions Rest Parameters 2. In other cases it is interpreted as spread operator. Please see Expressions - Spread syntax

– Tornike Shavishvili
Nov 16 '18 at 8:52

@TornikeShavishvili yes, I know this, I don't understand your first question

– Bogdan Tushevskyi
Nov 16 '18 at 8:54

I think my comment confused you. I meant that spread operator is good to use. I have to be more clear next time.

– Tornike Shavishvili
Nov 16 '18 at 8:55

|
show 1 more comment

spread operator? why not ... ?

– Tornike Shavishvili
Nov 15 '18 at 15:29

@TornikeShavishvili what is the difference between the spread operator and '...'?

– Bogdan Tushevskyi
Nov 16 '18 at 8:42

In your case three dots are spread operator. In javascript three dots '...' have basically two meanings, 1. If used in function declaration it defines "rest prameters", please see following doxumentations: Functions Rest Parameters 2. In other cases it is interpreted as spread operator. Please see Expressions - Spread syntax

– Tornike Shavishvili
Nov 16 '18 at 8:52

@TornikeShavishvili yes, I know this, I don't understand your first question

– Bogdan Tushevskyi
Nov 16 '18 at 8:54

I think my comment confused you. I meant that spread operator is good to use. I have to be more clear next time.

– Tornike Shavishvili
Nov 16 '18 at 8:55

spread operator? why not ... ?

– Tornike Shavishvili
Nov 15 '18 at 15:29

@TornikeShavishvili what is the difference between the spread operator and '...'?

– Bogdan Tushevskyi
Nov 16 '18 at 8:42

In your case three dots are spread operator. In javascript three dots '...' have basically two meanings, 1. If used in function declaration it defines "rest prameters", please see following doxumentations: Functions Rest Parameters 2. In other cases it is interpreted as spread operator. Please see Expressions - Spread syntax

– Tornike Shavishvili
Nov 16 '18 at 8:52

@TornikeShavishvili yes, I know this, I don't understand your first question

– Bogdan Tushevskyi
Nov 16 '18 at 8:54

I think my comment confused you. I meant that spread operator is good to use. I have to be more clear next time.

– Tornike Shavishvili
Nov 16 '18 at 8:55

|
show 1 more comment

You have mentioned that you want to add as many values as youi call setData. That sounds like a job for array.

You could use follwoing code:

function setData(targetObj, propName, valueToAdd){



    if(typeof targetObj[propName] === 'undefined'){

        targetObj[propName] = ;

    }

    if(Array.isArray(targetObj[propName])){

        targetObj[propName].push(valueToAdd);

    }else{

         console.log('property '+propName +' already exists and is not an array');

    }

}

answered Nov 15 '18 at 8:37

Tornike Shavishvili

61021122

add a comment |

You have mentioned that you want to add as many values as youi call setData. That sounds like a job for array.

You could use follwoing code:

function setData(targetObj, propName, valueToAdd){



    if(typeof targetObj[propName] === 'undefined'){

        targetObj[propName] = ;

    }

    if(Array.isArray(targetObj[propName])){

        targetObj[propName].push(valueToAdd);

    }else{

         console.log('property '+propName +' already exists and is not an array');

    }

}

answered Nov 15 '18 at 8:37

Tornike Shavishvili

61021122

add a comment |

You have mentioned that you want to add as many values as youi call setData. That sounds like a job for array.

You could use follwoing code:

function setData(targetObj, propName, valueToAdd){



    if(typeof targetObj[propName] === 'undefined'){

        targetObj[propName] = ;

    }

    if(Array.isArray(targetObj[propName])){

        targetObj[propName].push(valueToAdd);

    }else{

         console.log('property '+propName +' already exists and is not an array');

    }

}

answered Nov 15 '18 at 8:37

Tornike Shavishvili

61021122

You have mentioned that you want to add as many values as youi call setData. That sounds like a job for array.

You could use follwoing code:

function setData(targetObj, propName, valueToAdd){



    if(typeof targetObj[propName] === 'undefined'){

        targetObj[propName] = ;

    }

    if(Array.isArray(targetObj[propName])){

        targetObj[propName].push(valueToAdd);

    }else{

         console.log('property '+propName +' already exists and is not an array');

    }

}

answered Nov 15 '18 at 8:37

Tornike Shavishvili

61021122

answered Nov 15 '18 at 8:37

Tornike Shavishvili

61021122

answered Nov 15 '18 at 8:37

Tornike Shavishvili

61021122

answered Nov 15 '18 at 8:37

Tornike Shavishvili

61021122

add a comment |

Use like this:

const data = {}



setData(key, value) {

  Object.assign(data, {[key]: value});

}

BTW, You can simply set the data like:

setData(key, value) {

  data[key] = value

}

edited Nov 15 '18 at 8:38

answered Nov 15 '18 at 8:31

Bhojendra Rauniyar

51.7k2079128

1

Is there a reason for Object.assign over plain bracket notation? (also, key in your code will refer to the literal string key, not the variable)

– CertainPerformance
Nov 15 '18 at 8:32

you can change it to { [key] : value } and it should compute the value.

– Lloyd
Nov 15 '18 at 8:33

Thanks for the catch.

– Bhojendra Rauniyar
Nov 15 '18 at 8:33

@CertainPerformance Sorry, what do you mean? Is there a reason for Object.assign over plain bracket notation?

– Bhojendra Rauniyar
Nov 15 '18 at 8:34

If you don't need to merge objects, or create a new object or something like that, Object.assign seems really weird to use over just data[key] = value IMO

– CertainPerformance
Nov 15 '18 at 8:36

|
show 2 more comments

Use like this:

const data = {}



setData(key, value) {

  Object.assign(data, {[key]: value});

}

BTW, You can simply set the data like:

setData(key, value) {

  data[key] = value

}

edited Nov 15 '18 at 8:38

answered Nov 15 '18 at 8:31

Bhojendra Rauniyar

51.7k2079128

1

Is there a reason for Object.assign over plain bracket notation? (also, key in your code will refer to the literal string key, not the variable)

– CertainPerformance
Nov 15 '18 at 8:32

you can change it to { [key] : value } and it should compute the value.

– Lloyd
Nov 15 '18 at 8:33

Thanks for the catch.

– Bhojendra Rauniyar
Nov 15 '18 at 8:33

@CertainPerformance Sorry, what do you mean? Is there a reason for Object.assign over plain bracket notation?

– Bhojendra Rauniyar
Nov 15 '18 at 8:34

If you don't need to merge objects, or create a new object or something like that, Object.assign seems really weird to use over just data[key] = value IMO

– CertainPerformance
Nov 15 '18 at 8:36

|
show 2 more comments

Use like this:

const data = {}



setData(key, value) {

  Object.assign(data, {[key]: value});

}

BTW, You can simply set the data like:

setData(key, value) {

  data[key] = value

}

edited Nov 15 '18 at 8:38

answered Nov 15 '18 at 8:31

Bhojendra Rauniyar

51.7k2079128

Use like this:

const data = {}



setData(key, value) {

  Object.assign(data, {[key]: value});

}

BTW, You can simply set the data like:

setData(key, value) {

  data[key] = value

}

edited Nov 15 '18 at 8:38

answered Nov 15 '18 at 8:31

Bhojendra Rauniyar

51.7k2079128

edited Nov 15 '18 at 8:38

answered Nov 15 '18 at 8:31

Bhojendra Rauniyar

51.7k2079128

answered Nov 15 '18 at 8:31

Bhojendra Rauniyar

51.7k2079128

answered Nov 15 '18 at 8:31

Bhojendra Rauniyar

51.7k2079128

1

Is there a reason for Object.assign over plain bracket notation? (also, key in your code will refer to the literal string key, not the variable)

– CertainPerformance
Nov 15 '18 at 8:32

you can change it to { [key] : value } and it should compute the value.

– Lloyd
Nov 15 '18 at 8:33

Thanks for the catch.

– Bhojendra Rauniyar
Nov 15 '18 at 8:33

@CertainPerformance Sorry, what do you mean? Is there a reason for Object.assign over plain bracket notation?

– Bhojendra Rauniyar
Nov 15 '18 at 8:34

If you don't need to merge objects, or create a new object or something like that, Object.assign seems really weird to use over just data[key] = value IMO

– CertainPerformance
Nov 15 '18 at 8:36

|
show 2 more comments

1

Is there a reason for Object.assign over plain bracket notation? (also, key in your code will refer to the literal string key, not the variable)

– CertainPerformance
Nov 15 '18 at 8:32

you can change it to { [key] : value } and it should compute the value.

– Lloyd
Nov 15 '18 at 8:33

Thanks for the catch.

– Bhojendra Rauniyar
Nov 15 '18 at 8:33

@CertainPerformance Sorry, what do you mean? Is there a reason for Object.assign over plain bracket notation?

– Bhojendra Rauniyar
Nov 15 '18 at 8:34

If you don't need to merge objects, or create a new object or something like that, Object.assign seems really weird to use over just data[key] = value IMO

– CertainPerformance
Nov 15 '18 at 8:36

Is there a reason for Object.assign over plain bracket notation? (also, key in your code will refer to the literal string key, not the variable)

– CertainPerformance
Nov 15 '18 at 8:32

you can change it to { [key] : value } and it should compute the value.

– Lloyd
Nov 15 '18 at 8:33

Thanks for the catch.

– Bhojendra Rauniyar
Nov 15 '18 at 8:33

@CertainPerformance Sorry, what do you mean? Is there a reason for Object.assign over plain bracket notation?

– Bhojendra Rauniyar
Nov 15 '18 at 8:34

If you don't need to merge objects, or create a new object or something like that, Object.assign seems really weird to use over just data[key] = value IMO

– CertainPerformance
Nov 15 '18 at 8:36

|
show 2 more comments

What you're trying to do is to implement a HashMap or a Dictionary.

I'd just do it like so:

function setData(key, value) 

{

    if (data[key])

        data[key].push(value)

    else  

        data[key] = [ value ]

}

answered Nov 15 '18 at 8:45

AlexL

813

you are talking about Hashmap/Dictionary (a.k.a. "Object" in JS), but created an Array in your code

– Aprillion
Nov 17 '18 at 11:00

add a comment |

What you're trying to do is to implement a HashMap or a Dictionary.

I'd just do it like so:

function setData(key, value) 

{

    if (data[key])

        data[key].push(value)

    else  

        data[key] = [ value ]

}

answered Nov 15 '18 at 8:45

AlexL

813

you are talking about Hashmap/Dictionary (a.k.a. "Object" in JS), but created an Array in your code

– Aprillion
Nov 17 '18 at 11:00

add a comment |

What you're trying to do is to implement a HashMap or a Dictionary.

I'd just do it like so:

function setData(key, value) 

{

    if (data[key])

        data[key].push(value)

    else  

        data[key] = [ value ]

}

answered Nov 15 '18 at 8:45

AlexL

813

What you're trying to do is to implement a HashMap or a Dictionary.

I'd just do it like so:

function setData(key, value) 

{

    if (data[key])

        data[key].push(value)

    else  

        data[key] = [ value ]

}

answered Nov 15 '18 at 8:45

AlexL

813

answered Nov 15 '18 at 8:45

AlexL

813

answered Nov 15 '18 at 8:45

AlexL

813

answered Nov 15 '18 at 8:45

AlexL

813

you are talking about Hashmap/Dictionary (a.k.a. "Object" in JS), but created an Array in your code

– Aprillion
Nov 17 '18 at 11:00

add a comment |

you are talking about Hashmap/Dictionary (a.k.a. "Object" in JS), but created an Array in your code

– Aprillion
Nov 17 '18 at 11:00

you are talking about Hashmap/Dictionary (a.k.a. "Object" in JS), but created an Array in your code

– Aprillion
Nov 17 '18 at 11:00

add a comment |

-1

Check this solution

const data = {}

var fun = (key, value)=>{



data[key] = value;

}

fun('kk',123);

console.log(data);

answered Nov 15 '18 at 8:49

GAURAV

11211

add a comment |

-1

Check this solution

const data = {}

var fun = (key, value)=>{



data[key] = value;

}

fun('kk',123);

console.log(data);

answered Nov 15 '18 at 8:49

GAURAV

11211

add a comment |

-1

Check this solution

const data = {}

var fun = (key, value)=>{



data[key] = value;

}

fun('kk',123);

console.log(data);

answered Nov 15 '18 at 8:49

GAURAV

11211

Check this solution

const data = {}

var fun = (key, value)=>{



data[key] = value;

}

fun('kk',123);

console.log(data);

const data = {}

var fun = (key, value)=>{



data[key] = value;

}

fun('kk',123);

console.log(data);

const data = {}

var fun = (key, value)=>{



data[key] = value;

}

fun('kk',123);

console.log(data);

answered Nov 15 '18 at 8:49

GAURAV

11211

answered Nov 15 '18 at 8:49

GAURAV

11211

answered Nov 15 '18 at 8:49

GAURAV

11211

answered Nov 15 '18 at 8:49

GAURAV

11211

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